Please help I need help and please explain

Answer:

[tex](x,y) => (2.5x,2.5y)[/tex]

Step-by-step explanation:

Given

See attachment for ABCD and A'B'C'D'

Required

Determine the dilation rule

Using AB and A'B' as points of references;

[tex]AB = (-1,2)\ to\ (2,1)[/tex]

[tex]A'B' = (-2.5,5)\ to\ (5,2.5)[/tex]

The dilation factor (k) is calculated as:

[tex]k = \frac{A'B'}{AB}[/tex]

This gives:

[tex]k = \frac{(-2.5,5)}{(-1,2)} \ or\ k = \frac{(5,2.5)}{(2,1)}[/tex]

Factorize

[tex]k = \frac{2.5*(-1,2)}{(-1,2)} \ or\ k = \frac{2.5*(2,1)}{(2,1)}[/tex]

[tex]k = 2.5 \ or\ k = 2.5[/tex]

Hence, the scale factor is 2.5

The dilation rule is:

[tex](x,y) => k(x,y)[/tex]

[tex](x,y) => 2.5(x,y)[/tex]

[tex](x,y) => (2.5x,2.5y)[/tex]

Answer:

no

Step-by-step explanation:

the first two numbers is not greater than 13 so no

Answer:

1/4 of an hour is 15 minutes

Step-by-step explanation:

Answer: 1/4 of an hr

Step-by-step explanation:

15/60 is 1/4

Answer:

A

Step-by-step explanation:

Answer: I would say it's B

Step-by-step explanation: The reason is because whiskers are primary to have, Sharp claws is a tool for animals to get food, and large beaks are used to pick at the food so they don't eat the wrong things.

Answer:

a = 7. b = 24, c = 25. This is a Pythagorean triple

Step-by-step explanation:

The finite abelian group Z36 x Z48 x Z60 can be expressed as Z2^6 x Z3^4 x Z5. The finite abelian group Z8 x Z9 x Z11 x Z12 can be expressed as Z2^3 x Z3^2 x Z11 x Z2^2 x Z3.

(a) The finite abelian group Z36 x Z48 x Z60 can be expressed as the direct product of its prime power factorizations. The prime factorization of 36 is 2^2 * 3^2, 48 is 2^4 * 3, and 60 is 2^2 * 3 * 5. Therefore, the group can be written as Z2^6 x Z3^4 x Z5.

(b) The finite abelian group Z8 x Z9 x Z11 x Z12 can be expressed as the direct product of its prime power factorizations. The prime factorization of 8 is 2^3, 9 is 3^2, 11 is a prime number, and 12 is 2^2 * 3. Therefore, the group can be written as Z2^3 x Z3^2 x Z11 x Z2^2 x Z3.

In both cases, the group is expressed as the direct product of cyclic groups of prime power orders. The order of the group is the product of the orders of the individual cyclic groups, and the structure of the group is determined by the prime factors and their powers.

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Answer:

b is 10 degrees and a is 64 degrees.

Step-by-step explanation:

Properties of a parallelogram needed for this problem: Opposite angles are congruent and adjacent angles are supplementary, meaning they add to 180 degrees.

This means that in the picture, 2a and 12b+8 are equal, while 2a and 5b+2 are supplementary.

From this we can make two equations:

2a=12b+8

and

2a+5b+2=180

If we subtract 5b+2 in the second equation, both equations will equal 2a. I'll explain why that's good. We end up with:

2a=12b+8

and

2a=180-5b-2

Now, we can set the two equations equal to each other because they both equal the same thing. Then simplify.

12b+8=180-5b-2

17b=170

b=10

Knowing b is 10 degrees, we can easily plug that back into one of our original two equations. I'll choose 2a=12b+8.

2a=12(10)+8

2a=120+8

2a=128

a=64

b is 10 degrees and a is 64 degrees.

Answer:

A, C, and F

Step-by-step explanation:

You need 5/2 times the amounts given in the recipe, so you need:

Here we have the recipe for 16 crepes:

You want to make 5 crepes for person, for 8 persons, so you need:

8*5 = 40 crepes.

So you need to make the recipe N times:

16*N = 40

N = 40/16 = 10/4 = 5/2

So you need a fraction of 5/2 times each of the amounts in the recipes.

You will need:

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Answer:

1.2

Hope it helps :)

[tex]\frac{24}{25}*\frac{5}{4}\\\\\\=\frac{6}{5}[/tex]

Cohen's d (standardized effect size): approximately 0.963

Conclusion: The difference in mean solution times between the difficult instruction group and the easy instruction group is statistically significant, with a moderate effect size.

To calculate the value of the standardized effect size, also known as Cohen's d, we can use the formula:

Cohen's d = (M1 - M2) / Sp

Where:

M1: Mean solution time for the "difficult" instruction group (given as 15.8 minutes)

M2: Mean solution time for the "easy" instruction group (given as 9.0 minutes)

Sp: Pooled standard deviation (given as 7.06)

Let's calculate the value of Cohen's d:

Cohen's d = (15.8 - 9.0) / 7.06

= 6.8 / 7.06

≈ 0.963

The value of the standardized effect size (Cohen's d) is approximately 0.963.

Now, let's provide a conclusion based on this information. A standardized effect size of 0.963 indicates a moderate effect. Since the null hypothesis was rejected, it suggests that the difference in mean solution times between the two groups (difficult instruction and easy instruction) is statistically significant.

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Answer:

5) No

The actual distance between the drone and the fossil is [tex]32\dfrac{3}{4}[/tex] ft

Step-by-step explanation:

3) A. -2/9

(2/3 - 5/6)/3/4 = (-1/6)/(3/4) = (-1/6) × (4/3) = -2/9

4) d. [tex]0.\overline {90}[/tex]

10/11 = 0.9090909...

∴ 10/11 = [tex]0.\overline {90}[/tex]

5) The height of the drone is flying above the ground = [tex]25\dfrac{1}{2}[/tex] ft.

The location of the fossil below the ground = [tex]7\dfrac{1}{4}[/tex] ft.

Taking the ground level as the origin on a number line, we have;

The location of the drone relative to the ground =  + [tex]25\dfrac{1}{2}[/tex] ft. (The positive sign for a point above the origin)

The location of the fossil relative to the ground = [tex]-7\dfrac{1}{4}[/tex] ft. (The negative sign for a point below the origin)

Therefore;

The distance between the drone and the fossil = The difference between the location of the drone and the fossil

The distance between the drone and the fossil = [tex]25\dfrac{1}{2} - \left(-7\dfrac{1}{4} \right)[/tex]

[tex]25\dfrac{1}{2} - \left(-7\dfrac{1}{4} \right) = 25\dfrac{1}{2} + 7\dfrac{1}{4} = 32\dfrac{3}{4}[/tex]

The distance between the drone and the fossil = [tex]32\dfrac{3}{4}[/tex] ft.

Therefore;

The distance between the drone and the fossil > 32 ft.

Answer:

its option B : 18x3 – 12x2 + 9x – 6

Step-by-step explanation:

[tex]12( \frac{ -2 }{3}) {}^{2} +23( \frac{ - 2}{3} )+10= \frac{16}{3} − \frac{46}{3} +10=0[/tex]

12x² + 15x + 8x + 10 has a binomial factor of (3x+2).

ax²+bx+c=0, with a not equal to 0 is a quadratic equation, which is a second-order polynomial equation in a single variable. It has at least one solution because it is a second-order polynomial equation, which is guaranteed by the algebraic fundamental theorem. The answer could be simple or complicated.

We may utilize the factor theorem, which asserts that if a polynomial f(x) has a component (x - a), then f(a) = 0, to identify which polynomial has (3x + 2) as a binomial factor.

In this situation, finding a value of x that reduces 3x + 2 to zero is necessary since we are trying to discover a polynomial that contains (3x + 2) as a component. We obtain x = -2/3 by solving 3x + 2 = 0.

Let's try the polynomials one by one:

(a) 6x³ + 3x² + 4x + 2:

f(-2/3) = 6(-2/3)³ + 3(-2/3)² + 4(-2/3) + 2

= -8/3 - 4/9 - 8/3 + 2

= -32/9,

so (3x + 2) is not a factor.

(b) 12x² + 15x + 8x + 10:

f(-2/3) = 12(-2/3)₂ + 15(-2/3) + 8(-2/3) + 10

= 16/3 - 10 - 16/3 + 10

= 0,

so (3x + 2) is a factor.

(c) 18x³ - 12x² + 9x - 6:

f(-2/3) = 18(-2/3)³ - 12(-2/3)² + 9(-2/3) - 6

= -32/3 + 8/3 - 6 - 6

= -32/3,

so (3x + 2) is not a factor.

(d) 21x⁴ + 7x³ + 6x + 2:

f(-2/3) = 21(-2/3)⁴ + 7(-2/3)³ + 6(-2/3) + 2

= 64/27 - 56/27 - 4 + 2

= 2/27,

so (3x + 2) is not a factor.

Therefore, the only polynomial that has (3x + 2) as a binomial factor is 12x² + 15x + 8x + 10.

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The producer surplus at a price of $250 based on the supply curve, s(x) = 180 + 0.3·[tex]x^{\frac{3}{2} }[/tex] is about $1,326.5

The supply curve is the graphical representation of the price of a good or service and the quantity that manufacturers are willing to supply or provide.

The function for the supply curve is; s(x) = 180 + 0.3·[tex]x^{\frac{3}{2} }[/tex]

When the selling price is $250, the quantity of the product supplied can be found from the equation; s(x) = 250 = 180 + 0.3·[tex]x^{\frac{3}{2} }[/tex]

0.3·[tex]x^{\frac{3}{2} }[/tex] = 250 - 180 = 70

[tex]x^{\frac{3}{2} }[/tex] = 70/0.3 = 700/3

x = (700/3)[tex]\frac{2}{3}[/tex] ≈ 37.9

The quantity of soap supplied when the price is $250, is therefore, about 37.9

The producer surplus can be calculated from the area of a trapezoid formula as follows;

A = (b₁ + b₂) × h/2

Where the length of the bases are; b₁ ≈ 37.9,   b₂ = 0, and the height, h = (250 - 180) = 70

A = (37.9 + 0) × 70/2 = 1326.5

Therefore, at a selling price of $250, the producer surplus is about $1,326.5

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Answer:

P value = 0.23527 which is greater than 0.10

Step-by-step explanation:

Given :

Phat = proportion of rotten apple = 2/50 = 0.04

1 - phat = 0.96

p = 0.06

Tstatistic = (Phat - p) / sqrt[(Phat(1-Phat))/n]

Tstatistic = (0.04 - 0.06)/sqrt[(0.04(0.96))/50]

Tstatistic = (-0.02) / 0.0277128

Tstatistic = - 0.7216

Pvalue of Tstatistic

P(Z < - 0.7216) = 0.23527 (Pvalue calculator)

Answer:

they are the same

Step-by-step explanation:

We can conclude that the volume of cylinder 1 is 3/4 times the volume of cylinder 2.

The volume of cylinder is given by -

V = πR²h

Given is to compare the volume of a cylinder with a radius of 6 inches and a height of 8 inches compare to the volume of a cylinder with a radius of 8 inches and a height of 6 inches.

Volume of cylinder 1 will be -

V(1) = πR²h = 6 x 6 x 8π = 36 x 8π = 288π

Volume of cylinder 2 will be -

V(2) = πR²h = 8 x 8 x 6π = 64 x 6π = 384π

So, we can write that -

V(1)/V(2) = (288π)/(384π)

V(1)/V(2) = (288)/(384)

V(1)/V(2) = 3/4

Therefore, we can conclude that the volume of cylinder 1 is 3/4 times the volume of cylinder 2.

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Answer:

x=6√3

Step-by-step explanation:

In 30-60-90 triangles, if the hypotenuse is x, the longest leg is [tex]\frac{x}{2}[/tex], and the shortest leg is [tex]\frac{x\sqrt{3} }{2}[/tex].

If the longest leg is 6, then [tex]\frac{x}{2} =6[/tex]

Multiply by 2,

[tex]x=12[/tex]

If x=12,

[tex]\frac{12\sqrt{3} }{2}[/tex]

[tex]=6\sqrt{3}[/tex]

So, the shortest leg is 6√3.

Answer:

5ft^3

Step-by-step explanation:

The formula for volume is length × width × height.

so you multiply 1×2×2.5, which equals 5

Using the DINK method (Dual Income, No Kids), the total insurance need for Marianne and Roger is $172,000.

The DINK method calculates the insurance need based on the financial obligations and potential future expenses of a couple with dual incomes and no children. To determine their total insurance need, we consider their outstanding debts and potential expenses in case of death.

The calculations are as follows:

Mortgage: $125,000 (outstanding debt)

Car loans: $25,000 (outstanding debt)

Student loans: $22,000 (outstanding debt)

Funeral expenses: $12,000

The total outstanding debt and funeral expenses amount to $184,000.

However, the DINK method suggests subtracting the couple's annual incomes from the total insurance need since they have secure careers and can continue to generate income even in the event of the death of one spouse.

Both Marianne and Roger earn $45,000 annually, so we subtract $45,000 from the total, resulting in a total insurance need of $139,000.

Therefore, the correct answer is $172,000.

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Answer:

Option E

Step-by-step explanation:

The two points are (1,6) and (-3,-6) . We can find the Equation of the line using two point form , as ,

[tex]\implies y - y_1 =\dfrac{y_2-y_1}{x_2-x_1}(x - x_1) \\\\\implies y - 6 = \dfrac{-6-6}{-3-1}(x-1) \\\\\implies y-6 = \dfrac{-12}{-4}(x-1) \\\\\implies \boxed{\boxed{y -6 = 3(x-1)}} [/tex]

On looking at options we see that option E is correct .

Answer:

[tex]-8x + 6y = -180[/tex]

Step-by-step explanation:

Given

[tex]\frac{4}{5} x-\frac{3}{5}y=18[/tex]

[tex]8x + 12y = 11[/tex]

Required

Equivalent form of the first equation that eliminates x when added to the second

To do this, we simply make the coefficients of x to be opposite in both equations.

In the second equation, the coefficient of x is 8.

So, we need to make the coefficient of x -8, in the first equation.

[tex]\frac{4}{5} x-\frac{3}{5}y=18[/tex]

Multiply by -10

[tex]-10 * [\frac{4}{5} x-\frac{3}{5}y=18][/tex]

[tex]\frac{-40}{5} x+\frac{30}{5}y=-180[/tex]

[tex]-8x + 6y = -180[/tex]

When this is added to the first equation, the x terms becomes eliminated

Answer:

It is called a rectangular prism

It has 8 vertices

Answer:

its c ^u^ and the next to it is b :D

Step-by-step explanation:

edg 21

Answer:

It’s c and the next one is b

Step-by-step explanation:

Just took edge

Answer:

A

Step-by-step explanation

Answer:

C:  y = 5x + 3

Step-by-step explanation:

Note that if x changes from 1 to 3 (the "run"), y changes from 8 to 14 (the "rise").  Thus the slope of the line represented by the table is m = rise/run = 6/2, or m = 3.  Answer choice D is the only one that displays a slope of 3.

Answer:

Answer is D

Step-by-step explanation:

A. 14=8(3), 14≠24

B. 14=3+7 , 14≠10

C. 14=5(3)+3, 14≠18

D.14=3(3)+5, 14=9+5 14=14

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