Please help I need this answer immediately

B

1) To solve this question, we can write out two equations within this expression:

So we can do it with 10L of that 30% solution.

2)Let's find the other volume, plugging into that x=10, since the whole volume of this new solution is 30L we can subtract from that 30L that 10L we have just found:

3) So we found 20l of the 15% solution.

Thus the answer is B

[tex]8x + 6 + 118 = 180 \\ 8x + 124 = 180 \\ 8x = 180 - 124 \\ 8x = 56 \\ \frac{8x}{8} = \frac{56}{8} \\ x = 7[/tex]

NOTE THAT DUE TO LACK OF LABELLING OF ANGLES IN THE DIAGRAM I COULDN'T GIVE YOU BRIEF EXPLANATION BUT I HOPE YOU UNDERSTAND.

-24 ≤ 2x-10

⇒ -24 + 10 < 2x

⇒-14 < 2x

⇒ 2x < 14

⇒ x < 7

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Step-by-step explanation:

yes its important because we need to know the measurements of the side

The value of the expression is 0.125

Numerical expressions are sets of numbers that undergo mathematical operations with a pre-established order of operations. Numerical expressions are sets of numbers that undergo mathematical operations with a pre-established order of operations.

The expression is

0.3(1/4 - 1) + 0.350.3(0.25-1) + 0.35

solve by using BODMAS0.3(-0.75) + 0.35= -0.225 + 0.35= 0.125

Hence the value of the expression is 0.125

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Answer:

Is it 6-1?

Step-by-step explanation:

Answer: 6-1

Step-by-step explanation:

is simplest form

1 ÷ 3 is the scale factor that takes parallelogram H to parallelogram I.

If Parallelogram I is a scaled replica of Parallelogram H, then perhaps the figure in which every length in the initial estimate is multiplied by the exact number.

Scale factor = size of new shape ÷ size of the old shape.

The magnification ratio of a parallelogram I is significantly 3 times that of parallelogram H this ratio could be only assumed when the data is not given.

The polygon will be reduced if the magnification ratio would be between 0 and 1. The picture will be magnified if the zoom ratio is larger than one.

The scale factor refers to the ratio of the old thing's scale to the new object's scale. Although the size of these ratios varies, they are useful.

Use negative magnification to enlarge the picture. Whenever the scale factor is negative, the value diverges from the scale.

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The complete question is -

Parallelogram I is a scaled copy of parallelogram H. What scale factor takes parallelogram H to parallelogram I in the image?

The scaling factor that transforms parallelogram H into parallelogram I is 1/3.

If Parallelogram I is a scaled-down version of Parallelogram H, then it might be the result of multiplying each length in the initial estimate by a precise value.

Scale factor is equal to new shape's size minus old shape's size.

A parallelogram I's magnification ratio is noticeably three times greater than a parallelogram H's. Only in cases where no data is provided may this ratio be assumed.

If the magnification ratio is in the range between 0 and 1, the polygon will be smaller. If the zoom ratio exceeds one, the image will be enlarged. The scale factor is the ratio of the scale of the old thing to the scale of the new thing.These ratios are helpful despite the fact that their sizes differ.

Enlarge the image by applying negative magnification. The value deviates from the scale whenever the scale factor is negative.

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Answer:

ask your village people fowl

(a)

In order to find the function, let's use the ordered pair (-3, 8) in the given exponential function f(x).

So we have:

So the function is f(x) = (1/2)^x

(b)

The asymptote of this graph is y = 0, that is, the horizontal axis.

(c)

The domain is the values that x can assume, so the domain of this function is all real numbers, that is, (-infinity, infinity)

The range is the values that f(x) can assume, so the range of this function is y>0, that is, all positive numbers: (0, infinity)

Explanation

Step 1

et

w represents the cost of gift-wrapping.

then

Jessie spent a total of $14

total= 14

the cost for postage=$2.25

the cost of the gift( itself)=9.50

in words, the total is

the total cost is the cost of the gift plus the cost of the postage plus the cost of gift-wrapping

Now,replace

If the original price =$50

If we take $20 off, we have: $50-20 =$30

Next, taking 25% off of $30, we have:

Final Price = (100%-25%) of $30

=0.75 x 30

Final Price Final 0Price=$22.5

9

If we take $20 off, we have: $90-20 =$70

Next, taking 25% off of $70, we have:

Final Price = (100%-25%) of $70

=0.75 x 70

Final Price =$52.50

Remember that

csc k=1/sin k

and

sin k=55/73

therefore

csc k=1/(55/73)

Answer:

8 and 9

Step-by-step explanation:

consider perfect squares either side of 78

64 < 78 < 81 , then

[tex]\sqrt{64}[/tex] < [tex]\sqrt{78}[/tex] < [tex]\sqrt{81}[/tex] , that is

8 < [tex]\sqrt{78}[/tex] < 9

Answer: u≤29

Hope this helps! :)

The value of P(A|B) will be;

⇒ 0.6

What is mean by Probability?

The term probability refers to the likelihood of an event occurring.

Given that;

For the two events A and B;

⇒ P(A) = 0.60

⇒ P(B) = 0.40

And, P(B|A) = 0.60

Now,

Since, We know that;

⇒ P(A∪B) = P(A) + P(B) - P(A∩B)

Substitute all the values, we get;

⇒ P(A∪B) = 0.60 + 0.40 - P(A∩B)

And, P(A∩B) = P(A) P(B)

⇒  P(A∩B) = 0.60 × 0.40

⇒ P(A∩B) = 0.24

Hence,

⇒ P(A∪B) = 0.60 + 0.40 - P(A∩B)

⇒ P(A∪B) = 0.60 + 0.40 - 0.24

⇒ P(A∪B) = 0.76

Since, We know that the formula;

⇒  P(A|B) = P(A∩B) / P(B)

Substitute all the values we get;

⇒ P(A|B) = P(A∩B) / P(B)

⇒ P(A|B) = 0.24 / 0.40

⇒ P(A|B) = 0.6

Therefore,

The value of P(A|B) will be;

⇒ 0.6

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All multiplications must also be the same if to add the number over and over again.(if 9* 5 was 45, then 9+9+9+9+9 must also be 45.

Answer: Any number multiplied by zero equals zero. 4x0=0

Answer:

-10v

Step-by-step explanation:

-3v - 7v

OR

(-3v)+(-7v)

= -10v

Answer:

the answer is -3v-7v= -10

Answer:

please mark my brain list answer

Answer:

s = ut + 1/2 at²

2.4 = 4.9t²

t = 0.70

distance = speed x time

d = 24 x 0.7

d = 16.8 m

The correct option C. No extrema, is obtained for the given function.

For the given question;

The function is defined as ;

f(x) = 2/(3x-5)

First differentiate the function with respect to x using division rule.

f'(x) = -6/(3x - 5)²

Now, find the point of contraflexure for x by putting f'(x) equals to zero.

f'(x) = 0

-6/(3x - 5)² = 0

-6 = 0

But, -6 ≠ 0

As, x is getting eliminates, we don't have any point of contraflexure.

Thus,the will be no extrema for the given function.

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One angle's measurement is 11 times that of another. if the two angles supplementary one another. The measure of the angles area one is 165° and other angle is 15°.

Given that,

One angle's measurement is 11 times that of another. if the two angles supplementary one another.

We have to determine the angles' measurements.

The word "supplementary" refers to two angles coming together to form a straight angle. It indicates that when two angles sum up to 180 degrees, they are said to be supplementary angles. If two angles complement one another

It has an acute angle on one side and an obtuse angle on the other.

The angles are both right angles.

So, It follows that A + B = 180°.

Angle A is 11 times angle B means

A=11B

We get,

11B+B=180

12B=180

B=180/12

B=15°

Then angle A is

A=11×15

A=165°

Therefore, The measure of the angles area one is 165° and other angle is 15°.

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Let

[tex]\displaystyle f(x) = \sum_{n=2}^\infty \frac{x^n}{n^2(n^2-1) \binom{2n}n}[/tex]

Differentiate and multiply by [tex]x[/tex].

[tex]\displaystyle xf'(x) = \sum_{n=2}^\infty \frac{x^n}{n(n^2-1) \binom{2n}n}[/tex]

Now differentiate twice.

[tex]\displaystyle x f''(x) + f'(x) = \sum_{n=2}^\infty \frac{x^{n-1}}{(n^2-1)\binom{2n}n}[/tex]

[tex]\displaystyle xf'''(x) + 2f''(x) = \sum_{n=2}^\infty \frac{x^{n-2}}{(n+1)\binom{2n}n}[/tex]

Multiply by [tex]x^3[/tex].

[tex]\displaystyle x^4 f'''(x) + 2x^3 f''(x) = \sum_{n=2}^\infty \frac{x^{n+1}}{(n+1)\binom{2n}n}[/tex]

Differentiate one last time and multiply by [tex]\frac1x[/tex].

[tex]\displaystyle x^3 f^{(4)}(x) + 6x^2 f'''(x) + 6x f''(x) = \sum_{n=2}^\infty \frac{x^{n-1}}{\binom{2n}n}[/tex]

Now integrate with the fundamental theorem of calculus, noting that [tex]f(0)=f'(0)=0[/tex] follows from our series definition. We do this twice and make use of the recurrence

[tex]I_n = \displaystyle \int_0^x y^n f^{(n+1)}(y) \, dy = x^n f^{(n)}(x) - n I_{n-1}[/tex]

Integrating once yields

[tex]\displaystyle x^3 f'''(x) + 3x^2 f''(x) = \sum_{n=2}^\infty \frac{x^n}{n \binom{2n}n}[/tex]

Multiply by [tex]\frac1x[/tex].

[tex]\displaystyle x^2 f'''(x) + 3x f''(x) = \sum_{n=2}^\infty \frac{x^{n-1}}{n \binom{2n}n}[/tex]

Integrating once more yields the ordinary differential equation

[tex]\displaystyle x^2 f''(x) + x f'(x) - f(x) = \sum_{n=2}^\infty \frac{x^n}{n^2 \binom{2n}n}[/tex]

and we recognize the right side as the series

[tex]\displaystyle \sum_{n=2}^\infty \frac{x^n}{n^2 \binom{2n}n} = 2\arcsin^2\left(\frac{\sqrt x}2\right) - \frac x2[/tex]

Solving the differential equation is quite doable with the variation of parameters method; we ultimately find

[tex]\displaystyle f(x) = \frac12 + \frac{7x}8 - \left(\frac1x+\frac12\right) \sqrt x \sqrt{4-x} \, \arcsin\left(\frac{\sqrt x}2\right) + 2 \left(\frac1x-1\right) \arcsin^2\left(\frac{\sqrt x}2\right)[/tex]

Recover the sum we want by letting [tex]x=-1[/tex]. Recall that

[tex]\arcsin(iz) = i \,\mathrm{arsinh}(z) = i\ln(z + \sqrt{1+z^2})[/tex]

Then we have the following equivalent results involving our old friend [tex]\phi[/tex].

[tex]\displaystyle f(-1) = -\frac38 - \frac{\sqrt5}2\, \mathrm{arsinh}\left(\frac12\right) + 4 \,\mathrm{arsinh}^2\left(\frac12\right) \\\\ f(-1) = -\frac38 - \frac{\sqrt5}2 \ln\left(\frac{1+\sqrt5}2\right) + 4 \ln^2\left(\frac{1+\sqrt5}2\right) \\\\ f(-1) = \boxed{-\frac38 - \left(\frac12 - \phi\right) \ln(\phi) + 4 \ln^2(\phi)}[/tex]

Hey you man what are you doing here go to there

Answer: 55 cm

Step-by-step explanation:

a^2 + b^2 = c^2

X^2 + 48^2 = 73^2

X^2 + 2,304 = 5,329

X^2 = 3,025

X = 55

The subset's components can be listed in any order when combined.

The former two are both 15/16.

P(at least one boy) and then P(at least one Girl)

P(at least one boy and one girl)

If we assume P(girl) = P(boy) = 50%

The latter results from the 16 possible combinations.

noting only two of which are single sex.

So 14/16 = 7/8.

Therefore, the former two are both 15/16.

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The correct statements regarding sum and subtraction with negative numbers are given as follows:

When two negative numbers are added, the result is negative, as we keep the signal and then add the absolute amounts of each value, for example:

-5 + (-5) = -(5 + 5) = -10.

Hence the fourth statement is correct, while the first and the third are not.

When we subtract two negative numbers, we first transform the second number to positive, meaning that the result can be either positive or negative, as the result will take the signal of the higher value and their absolute amounts are subtracted.

Hence:

Hence the fifth and the sixth statements are correct.

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Answer:

C. the dilate with scale of 2

Step-by-step explanation:

when you dilate, a scale bigger than 1 means you enlarge the figure A

no other choices make figure a bigger to 'fit into' or be the same as figure B

so thus, the answer is C.

Answer:

C.

Step-by-step explanation:

as we can clearly see, when going from figure A to figure B every length and coordinate is doubled. that means a constant scale factor of 2 for all of that. but the angles and the general structure of the object remained the same (so, both are similar).

Answer:

y=-3/2x+4

Step-by-step explanation:

The expression 6⁻² can be written as -

6⁻² = 1/6²

6⁻² = 1/36

6⁻² = (1/6 x 1/6)

A mathematical expression is a combination of terms separated by mathematical operators. For example : 2x + 3y + 6. Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have the following expression -

6⁻²

We can write the expression 6⁻² in the following possible ways -

6⁻² = 1/6²

6⁻² = 1/36

6⁻² = (1/6 x 1/6)

Therefore, the expression 6⁻² can be written as -

6⁻² = 1/6²

6⁻² = 1/36

6⁻² = (1/6 x 1/6)

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In a single year, factories create a total of 21550 gallons.

In both imperial and US customary units, the gallon is a unit of volume.A gallon is a unit of measurement for liquids that is equal to eight pints. In Britain, it is equal to about 4.546 litres. In America, it is equal to about 3.785 litres.

We have been given that

Lemonade = 11,650 gallons

Ice tea = 4,950 fewer than lemonade

Root beer = 3,500 fewer than Ice tea.

After calculating

Ice tea = 11,650 - 4,950

Ice tea = 6700 gallons

Root beer = 6700 - 3,500

Root beer = 3200 gallons

Total  factory produced in one year

= 11,650 + 6700 + 3200

Hence , 21550 gallons are total factory produced in one year.

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Answer:

The average speed of the runner is 12.7 mph and 20.4 km/h

Step-by-step explanation: