Please help, I’m stuck........

Please Help, Im Stuck........

Answers

Answer 1

Answer:

Step-by-step explanation:

Nhgbbhhgffgh

Answer 2

(a+b)2×h = (6.5+15.1)/2× 5= 54 in²


Related Questions


Pedro solves the quadratic equation x^2+6x –14 using the quadratic formula. In which step did Pedro make an error?

Answers

9514 1404 393

Answer:

  correct choice is marked

Step-by-step explanation:

The error is in step 2. The square root cannot be distributed to a sum.

GIVING OUT BRAINLIEST PLS HELP! ALMOST DUE

Answers

Answer:

I think it's option B

What is the outlier for the data set?
19, 19, 27, 21, 77, 18, 23, 29

Answers

Answer: 77

Step-by-step explanation:

Determine the missing angle in the picture below.

Answers

Answer:

x =41.18114952

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

We know the hypotenuse and adjacent sides

cos theta = adjacent / hypotenuse

cos x  = 14.3/19

taking the inverse cos of each side

cos^-1 (cos x) = cos ^-1 ( 14.3/19)

x =41.18114952

Answer:

Step-by-step explanation:

take x degree as reference angle

using cos rule

cos x=adjacent/hypotenuse

cos x=14.3/19

cos x=0.75

x=cos 41

x= 41 degree

Find the solution of the differential equation f' (t) = t^4+91-3/t
having the boundary condition f(1) =1/4

Answers

Answer:

[tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

BracketsParenthesisExponentsMultiplicationDivisionAdditionSubtractionLeft to Right  

Equality Properties

Multiplication Property of EqualityDivision Property of EqualityAddition Property of EqualitySubtraction Property of Equality

Algebra I

FunctionsFunction Notation

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]:                                                               [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]

Integration Property [Addition/Subtraction]:                                                       [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]

Integration Property [Multiplied Constant]:                                                         [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle f'(t) = t^4 + 91 - \frac{3}{t}[/tex]

[tex]\displaystyle f(1) = \frac{1}{4}[/tex]

Step 2: Integration

Integrate the derivative to find function.

[Derivative] Integrate:                                                                                   [tex]\displaystyle \int {f'(t)} \, dt = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Simplify:                                                                                                         [tex]\displaystyle f(t) = \int {t^4 + 91 - \frac{3}{t}} \, dt[/tex]Rewrite [Integration Property - Addition/Subtraction]:                               [tex]\displaystyle f(t) = \int {t^4} \, dt + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][1st Integral] Integrate [Integral Rule - Reverse Power Rule]:                     [tex]\displaystyle f(t) = \frac{t^5}{5} + \int {91} \, dt - \int {\frac{3}{t}} \, dt[/tex][2nd Integral] Integrate [Integral Rule - Reverse Power Rule]:                   [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - \int {\frac{3}{t}} \, dt[/tex][3rd Integral] Rewrite [Integral Property - Multiplied Constant]:                 [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3\int {\frac{1}{t}} \, dt[/tex][3rd Integral] Integrate:                                                                                 [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex]

Our general solution is  [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| + C[/tex].

Step 3: Find Particular Solution

Find Integration Constant C for function using given condition.

Substitute in condition [Function]:                                                               [tex]\displaystyle f(1) = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Substitute in function value:                                                                         [tex]\displaystyle \frac{1}{4} = \frac{1^5}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate exponents:                                                                                     [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3ln|1| + C[/tex]Evaluate natural log:                                                                                     [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91(1) - 3(0) + C[/tex]Multiply:                                                                                                         [tex]\displaystyle \frac{1}{4} = \frac{1}{5} + 91 - 0 + C[/tex]Add:                                                                                                               [tex]\displaystyle \frac{1}{4} = \frac{456}{5} - 0 + C[/tex]Simplify:                                                                                                         [tex]\displaystyle \frac{1}{4} = \frac{456}{5} + C[/tex][Subtraction Property of Equality] Isolate C:                                               [tex]\displaystyle -\frac{1819}{20} = C[/tex]Rewrite:                                                                                                         [tex]\displaystyle C = -\frac{1819}{20}[/tex]Substitute in C [Function]:                                                                             [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex]

∴ Our particular solution to the differential equation is  [tex]\displaystyle f(t) = \frac{t^5}{5} + 91t - 3ln|t| - \frac{1819}{20}[/tex].

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Integration

Book: College Calculus 10e

I need help with this three problems (with procedure)

Answers

Answer:

13. [tex]x^{3} y^3[/tex] cubic units

14. 43 million; 79 million; 3.6 × [tex]10^7[/tex]

15. 2.68 × [tex]10^5[/tex]

Step-by-step explanation:

The track team has 12 more boys than girls. There are a total of 142 team members. How many boys and girls are on the team?

Answers

Answer:

77 boys, 65 girls

Step-by-step explanation:

x as the variable to represent amount of girls, and there are 12 more boys than girls (x+12). So the equation would be:

x + x + 12 = 142

2x + 12 = 142

x = 65

65 girls

then 65+ 12 = 77 boys

HELPPPP PLZZZZZzz HELLP FAST I NEED TO PASS

Answers

Answer:

m∠Q= 105°

➬➬➬➬➬➬➬➬

[tex]6x+5+(11x-5)+x=180^o[/tex]

[tex]18x=180[/tex]

[tex]x=10[/tex]

☄m∠Q=105°

❆❆❆❆❆❆❆❆❆❆❆❆

hope it helps....

have a great day!!

c and d for 20 pts
aaaaaaaaaaaaaaaaa

Answers

Answer:

C. a = 7

D. c = -3

Step-by-step explanation:

C. 7(2a + 3) + 21 = 100+ 40

   14a + 21 + 21 = 140

   14a = 140 - 21 - 21

    14a = 98

    a = 7

D. 6+ 14 - 12c = 56

    20 - 12c = 56

     -12c = 56 - 20

     -12c = 36

       c = - 3

Answer:

Step-by-step explanation:

c.7(2a+3)+21=100+40

14a+21+21=140

14a+42=140

14a=140-42

a=98/14

a=7

d.6+14-12c=56

20-12c=56

-12c=56-20

c=36/-12

c=-3

How many solutions will the following equation have? 2x - 7 = -3x + 5
a. One Solution
b. Infinite Solutions
c. No Solutions

Answers

Answer:

one solution lets see

[tex]2x - 7 = 3x + 5 \\ - x = 12 \\ x = - 12[/tex]

If you just want to check then substitute the value

[tex]2x - 7 = 3x + 5 \\ 2 \times ( - 12) - 7 = 3 \times ( - 12) + 5 \\ - 24 - 7 = - 36 + 5 \\ - 31 = - 31[/tex]

Hope it helps

What is 8.75% of 172?

Answers

Answer:

15.05 is your answer.

Step-by-step explanation:

To find our answer we will first divide 8.75 by 100 since it is a percentage.  8.75 ÷ 100 = 0.0875

Now we will take 0.0875 and multiply it by 172 and we get 15.05.  Therefore, 15.05 is our answer

Hey there!

8.75% of 172

The word “of” means multiply in mathematical terms.

8.75% * 172

8.75% = 8.75/100 = 0.0875

0.0875 * 172

= 301/20

= 15.05

Answer: 301/20 OR 15.05

(BOTH ANSWERS WORK because they are both equivalent)

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

The hypotenuse function is correct, but the main function has a problem. Explain why it may not work, and show a way to fix it. Your fix must be to the main function only; you must not change the hypotenuse function in any way.

Answers

Answer: hello your question is incomplete attached below is the missing codes

Answer : It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement was not written in the main function

Step-by-step explanation:

It may not work because; the double pointer P was not allotted a double using a new double ( I.e. Error in the main function ) also the cout statement  should be moved to the Main

The correction  is below

{

   double* p = new double;

   hypotenuse(1.5, 2.0, p);

  cout << "The hypotenuse is " << *p << endl;

}

Help will be appreciated

Answers

Answer:

48

hope this helps

have a good day :)

Step-by-step explanation:

Answer:

48

the picture 20 words or longer for the answer so this is extra text

Plz help me!!(ᗒᗣᗕ)՞
Plz!

Answers

Answer:

A) 64 cm²

Step-by-step explanation:

Trapezoid area formula:

[tex]A=\frac{a+b}{2} h[/tex]

Given:

a = 6

b = 10

h = 8

Work:

[tex]A=\frac{a+b}{2} h\\\\A=\frac{6+10}{2} *8\\\\A=\frac{16}{2} *8\\\\A=8*8\\A=64[/tex]

Last week at the business where you work , you sold 120 items. The business paid $1 per item and sold them for $3 each. What profit did the business make from selling the 120 items

Answers

Answer:

240

Step-by-step explanation:

They spent $120 buying 120 items, so they have -$120. By selling the items at 3x the price, they gained the 120 back and made a profit of 240 (120 x 2).

240

3-1=2

120 x 2=240

Student spend 5 minutes of every 60 minutes at school moving from class to class. Which fraction is equivalent to the number of minutes student spend moving from class to class?

A. 10/120
B.no answer provided
C. 2/10
D. 10/60
E. 1/15

Answers

A. 10/120 sorry if I’m wrong

jack bought a mother bike the original price was 1300 but he got a discount of 20% what was the discounted price of the bike

Answers

The discounted price of the bike is 260.

Which is the volume of a sphere with diameter
50 cm?

Answers

Answer:

V =65416.666666 cm^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The diameter is 50 so the radius is 1/2 of the diameter

r = 1/2 (50) = 25

V = 4/3 ( pi) (25)^3

V = 4/3 (pi) 15625

V =20833.3333 pi

Using 3.14 for pi

V =65416.666666 cm^3

Answer:

V =65416.666666 cm^3

Step-by-step explanation:

The volume of a sphere is given by

V = 4/3 pi r^3

The diameter is 50 so the radius is 1/2 of the diameter

r = 1/2 (50) = 25

V = 4/3 ( pi) (25)^3

V = 4/3 (pi) 15625

V =20833.3333 pi

Using 3.14 for pi

V =65416.666666 cm^3

plsss help!! is this a right triangle if no or yes please explain why??

Answers

Answer:

yes, it is a right triangle

Step-by-step explanation:

the other two angles are 35 and 55 degrees

Answer:

is NOT a right triangle

Step-by-step explanation:

is a right triangle if it checks the Pythagorean Th.

12² = 10² + 7²

144 = 100+49

144 = 149 False

What is the median of these numbers 2.4,2.8,2.3,2.9,2.9

Answers

Answer:

2.8

Step-by-step explanation:

x2.3, x2.4, 2.8, x2.9, x2.9

The value of the 2 in 43,290 is
times the value
of the 2 in 32,865.

Answers

9514 1404 393

Answer:

  1/10

Step-by-step explanation:

The value of any digit is found by setting all other digits to zero.

The value of the 2 in 43,290 is 200.

The value of the 2 in 32,865 is 2,000.

200 is 200/2000 = 1/10 times 2000

The value of 2 in 43,290 is 1/10 times the value of 2 in 32865.

The cost of producing x units of a product is $1.25 per unit plus $1,000 in flat production costs. If you spend $3,000 on production costs, how many units were produced?

3,000=1.25x+1&comma;000

Answers

Answer:

1600

Step-by-step explanation:

1.25x + 1000 = 3000

Subtract 1000 from both sides

1.25x = 2000

Divide both sides by 1.25

x = 1600

find the largest prime factor of 6108

Answers

Answer:

509

Step-by-step explanation:

There are 4 prime factors of 6108

6108 ÷ 2 = 3054

3054 ÷ 2 = 1527

1527 ÷ 3 = 509

509 ÷ 509 = 1

4d = -16

what’s the value of d

Answers

[tex]4d = - 16 \\ \\ d = \cancel \frac{ - 16}{4} \\ \\ d = - 4[/tex]

Hope This Helps You

Answer:

The value of d is -4. When you multiply 4 by -4 you get -16. If you want me to elaborate, let me know.

Step-by-step explanation:

Find the value of x.

Answers

The value of x is 26

Which is the inverse of the following statement?
If the measure of an angle is 90°, then it is a right angle.

Answers

Yes if it’s less than 90 it’s an acute but yes 90 is a right angle

Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow is a predictor of lead content. You find the 95% CI for expected lead content when traffic flow is 15, based on a sample of n= 10 observations, is (461.7, 598.1).

Required:
What parameter is this interval estimating?

Answers

Answer:

The answers is " Option B".

Step-by-step explanation:

[tex]CI=\hat{Y}\pm t_{Critical}\times S_{e}[/tex]

Where,

[tex]\hat{Y}=[/tex] predicted value of lead content when traffic flow is 15.

[tex]\to df=n-1=8-1=7[/tex]

 [tex]95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\[/tex]

     [tex]=\frac{1059.8}{2}\\\\=529.9[/tex]

Calculating thet-critical value[tex]t_{ \{\frac{\alpha}{2},\ df \}}=-2.365[/tex]

The lower predicted value [tex]=529.9-2.365(Se)[/tex]

[tex]463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076[/tex]

When [tex]99\%[/tex] of CI use as the expected lead content: [tex]\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)[/tex]

Can someone help me pls pls help with this question

Answers

Answer:

D.

Step-by-step explanation:

The mean is 11,000

Choose the best estimate for the multiplication problem below. 56 x 51
A. 2000
B. 3000
C. 4100​

Answers

Answer:

B

Step-by-step explanation:

Answer: B.

Explanation: 56 multiply 51 is 2856 and 3000 is the closest to 2856.

Also pls mark me as brianliest!!

A 15-foot ladder leans against the side of a house with its base 4 feet from the house. Use the Pythagorean Theorem to approximate how high the ladder reaches up the side of the house. Round your answer to the nearest hundredth.

Answers

Answer: The ladder reaches 14.46 feet up of the building.

Step-by-step explanation:

According to Pythagorean theorem,

In a right triangle,

(Hypotenuse)²= (Base)²+(perpendicular)^2

Using given information, we have

[tex](15)^2=(4)^2+(height)^2\\\\225=16+(height)^2\\\\(height)^2=209\\\\ (height)^2=\sqrt{209}\approx14.46\ feet[/tex]

Hence, the ladder reaches 14.46 feet up of the building.

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