Please help me answer this, I didn’t mean to click A i don’t know if it’s right or not

The domain of a function are the values for which the function is defined or in the other words, it is the set of all possile values that the function accepts.

Therefore:

Answer:

3/10 hope this helps you answer your question!

Answer: 18 mins

Step-by-step explanation

there is 3600 secs in an hour so do the same for this.

6 mins is 360 secs and times 360 by 3 is 1080 and then double it they figure out how many mins is 2160 im sorry if thats confusing.

C is the correct option

Here, we want to selct which of the plotted points in the graphs correctly represent the given points

The given points are (2,21/2) and (-1 1/2,-4)

As we can see on the graphs, there are four different marked points

We just need to select the graph that contains the points

What the point (2, 2 1/2) means is that we have point 2 on the x-axis and trace point 2 1/2 on the y-axis

This point is missing in the first two options

However, on the third option C, we can see this option

We can check if the second option is there too

(-1 1/2 , -4)

We have -1 1/2 on the x-axis and -4 on the y-axis

We can see this on the third option too

So option C is our correct answer

Answer:

He can buy 8 pounds

Step-by-step explanation:

13.75/5=2.75

22/2.75=8 or 8 pounds the to check your answer 2.75x8=22

If;

then these variables must meet the following conditions below;

In rational expressions (fractional numbers), if the denominators are equal, arithmetic operations are performed with the numerators. Therefore;

If we add both equations at the same time, we get the following result;

Now that we have found the unknown x, we can find the unknown y.

Now let's write our fraction pairs.

Answer:

[tex]\frac{5}{11}[/tex] and [tex]\frac{2}{11}[/tex]

Step-by-step explanation:

let the 2 fractions be x and y , x > y , then

x + y = [tex]\frac{7}{11}[/tex] → (1)

x - y = [tex]\frac{3}{11}[/tex] → (2)

add the 2 equations term by term to eliminate y

2x + 0 = [tex]\frac{10}{11}[/tex]

2x = [tex]\frac{10}{11}[/tex] ( divide both sides by 2 )

x = [tex]\frac{5}{11}[/tex]

substitute x = [tex]\frac{5}{11}[/tex] into (1) and solve for y

[tex]\frac{5}{11}[/tex] + y = [tex]\frac{7}{11}[/tex] ( subtract [tex]\frac{5}{11}[/tex] from both sides )

y = [tex]\frac{2}{11}[/tex]

the pair of fractions are [tex]\frac{5}{11}[/tex] and [tex]\frac{2}{11}[/tex]

Answer:

d

Step-by-step explanation: d

Yes, I do agree with Jamie.

1 is NEITHER a prime number NOR a composite number.

Reason for agreeing:-

We know that a PRIME NUMBER is any given number that has only one as a factor. I.e it is only divisible by 1 AND ITSELF.

And, a COMPOSITE NUMBER is any number that is divisible by a number other than one and itself.

Here in the case of 1, we see that it is divisible by 1 and itself, and since it cannot have any other factor we can't put in either of the two categories

There is a mistake in the first step. The correct way to add the linear expression is (−3.78b + 12) − (4.82b − 16) = -8.6b + 18

An expression is used to show the relationship between the variables.

The linear expression to add is as follows: (−3.78b + 12) − (4.82b − 16)

Firstly we open the bracket on the right side by multiplying the negative sign by the numbers in the brackets.

(−3.78b + 12) − (4.82b − 16)

−3.78b + 12 - 4.82b + 16

Combine like terms

−3.78b + 12 - 4.82b + 16

-3.78b - 4.82b + 12 + 16

Add the like terms

-3.78b - 4.82b + 12 + 16

-8.6b + 18

Therefore, she made the mistake in the first step.

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Answer: 174

Step-by-step explanation: ok so we divide 220 by 11 to get 20 and times that by two to get 20 children on this journey then see that all children paid and 70 percent of adults so 70 percent of 220 is 154 and then 154 + 20 is 174 so thats the number of fares paid

[tex]\sqrt{\cfrac{4x^2}{3y}}\implies \cfrac{\sqrt{4x^2}}{\sqrt{3y}}\implies \cfrac{\sqrt{2^2x^2}}{\sqrt{3y}}\implies \cfrac{2x}{\sqrt{3y}}[/tex]

Answer:

[tex]\frac{2x}{\sqrt{3y} }[/tex]

Step-by-step explanation:

Hope that's helps.

Answer:

Martha exercises 310 minutes more than Greg in a 31-day month!

Step-by-step explanation:

30x

40x

Where x equals the number of days.

Let's plug it in:

30(31) = 930

40(31) = 1240

Let's subtract:

1240 - 930 = 310

MEANING Marta exercises 310 minutes more than Greg in a 31-day month!

Answer:

7.25

Step-by-step explanation:

Barangay Maligaya is 28.5km

Since Ricardo traveled 12.75km by Jeep and 8.5km by tricycle and rest by hiking

Jeep = 12.75

Tricycle = 8.5

Hiking = 12.75 + 8.5

=21.25

Total= 28.5

=28.5 -21.25

= 7.25

Answer: 2200

Step-by-step explanation:

33 1/3 of 66

Dennis's curtain company needs 252 feet long fabric to make 63 curtains.

Given,

The length of a curtain = 43 inches

Number of curtains they want to make = 63

We have to find the length of fabric in foot needed to make 63 curtains.

1 foot = 1/12 inches

Now,

The total length of fabric needed in inches = Number of curtains × Length of 1 curtain = 63 × 48 = 3024 inches

Convert this into feet.

That is,

3024 × 1/12 = 252 feet.

Therefore,

Dennis's curtain company needs 252 feet long fabric to make 63 curtains.

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To determine the price per ounce walter paid to ship the package you can use cross multiplication.

If 5.5 ounces ______$2.53

Then 1 ounce______$x

He will pay $0.46 per ounce

Answer:

w = 135

Step-by-step explanation:

-27 = -w/5

multiply both sides by 5:

5(-27) = 5(-w/5)

- 135 = -w

divide both sides by -1:

- 135/-1 = -w/-1

w = 135

Approximate value of d = 4.29 cm.

The Cosine Rule states in trigonometry that the square of the length of any side of a given triangle is equal to the sum of the squares of the other sides minus twice the product of the other two sides multiplied by the cosine of angle contained between them. Cosine rule is also known as the law of cosines or the Cosine Formula.

In Δ ADR , AR = d, DR = 8 cm. AD = 5 cm. ∠D = 28°

By using cosine rule,

AR² = AD² + DR² - 2 AD ×DR CosD

AR² = 5² + 8² - 2×(5)×(8) × Cos 28°

AR² = 25 + 64 - 80 Cos 28°

AR² = 89 - 80 Cos 28°

AR² = 89 - 80 × (0.8829)

AR² = 89 - 70.6358

AR² = 18.3641

AR = 4.29 cm. = d

Thus, approximate value of d = 4.29 cm.

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Answer: Look at photo. Your y intercept is -1 and the line goes up 4 and right 1.

Step-by-step explanation: Look at your last number, the -1. That should be on the y axis. Put that number there and then take 4x which can also be read as 4/1x and from the point of -1, go up 4 and right 1.

The four functions with a local minima are:

y = x², y = |x|, y = sin x, y = cos x

A function f(x) has a local minima if its second derivative, f''(x) > 0 at the point where f'(x) = 0.

We use this to find which among the functions y = x, y = x², y = x³, y = |x|, y = 1/x, y = eˣ, y = √x, y = ln x, y = sin x, y = cos x, y = int(x), y = 1/(1+e⁻ˣ) has a local minima.

y' = 1. There is no point x such that y' = 0. So it has no local minima.

y' = 2x

y' = 0

⇒ 2x = 0

⇒ x = 0

y'' = 2 > 0

So y = x² has a local minima at x = 0

y' = 3x²

y' = 0

⇒ 3x² = 0

⇒ x = 0

y'' = 6x = 0 at x = 0

So y = x³ has no local minima.

i.e., y = x, when x ≥ 0 and y = -x , when x < 0

So y ' = 1, when x ≥ 0 and y' = -1, when x < 0

But at x = 0, y = 0 and y' = 0.

Now y'' = 0 everywhere. But the graph of y = |x| clearly shows that y = |x| has a local minimum at x = 0.

y' = -1/x²

Here, y' is nowhere zero and hence doesn't has a local minima.

y' = eˣ

 eˣ is nowhere zero and hence it does not has a local minima.

y' = 1/2√x

Here also  y' is nowhere zero and hence it does not has a local minima.

y' = 1/x

Here also y' is  nowhere zero and hence it does not has a local minima.

y' = cos x

y' = 0

⇒ cos x = 0

⇒ x = (2n+1)π/2, n = 0,1,2,....

y'' = -sin x

-sin ((2n+1)π/2)  = -1, when n = 0,2,4,... and -sin ((2n+1)π/2)  = 1, when n = 1,3,5,....

So y = sin x has local minima at x = (2n+1)π/2, where n = 1,3,5,....

y' = -sin x

y' = 0

⇒ -sin x = 0

⇒ x = nπ

y'' = -cos x

-cos(nπ) = (-1)ⁿ⁺¹

So, -cos(nπ) = 1, when n = 1,3,5,.... and -cos(nπ) = -1, when n = 0,2,4,...

Hence y = cos x has local minima at x = nπ with n = 1,3,5,....

y' = x

y' = 0

⇒ x = 0

y'' = 1 >0

So y = int (x) has local minima at x = 0

y' = e⁻ˣ/(1+e⁻ˣ)²

y' = 0

⇒ e⁻ˣ/(1+e⁻ˣ)² = 0

⇒ e⁻ˣ = 0

⇒ 1/eˣ = 0 which is not possible anywhere.

Hence y = 1/1+e⁻ˣ has no local minima.

Finally the four functions with local minima are:

y = x², y = |x|, y = sin x, y = cos x

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The values of x are x = 13 and x = 1 when we have [tex](x-7)^{2} = 36[/tex].

According to the question,

We have the following information:

[tex](x-7)^{2} = 36[/tex]

Now, we will solve the expression on the left hand side using an identity.

The identity that will be used here is [tex](a-b)^{2}= a^{2}+ b^{2} -2ab[/tex].

In this case, we have a = x and b = 7.

[tex]x^{2}+ 7^{2} -2x*7[/tex] = 36

[tex]x^{2} +49-14x = 36[/tex]

Moving 36 from the right hand side to the left hand side:

[tex]x^{2} +49-14x-36 = 0\\x^{2} -14x+13 = 0[/tex]

Now, to find the values of x, we will factorize this expression by splitting the middle term such that the sum of two terms is -14x and their multiplication is 13[tex]x^{2}[/tex].

The two terms will be -13x and -x.

[tex]x^{2} -13x-x+13 = 0\\[/tex]

Taking x common from the first two terms and -1 common from the last two terms:

x (x-13) -1(x-13) = 0

Taking (x-13) as common:

(x-13) (x-1) = 0

x-13 = 0 and x-1 = 0

x = 13 and x = 1

Hence, the values of x are 13 and 1.

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Step-by-step explanation:

x^3 =64

x^2+x=64( you can write x^3 like this .there is not problem with it )

x+x= root 64

2x= 8 ( 8×8=64)

x=8÷2

x = 4

Marilyn's capital gain is 73%.

Marilyn purchased 2,000 shares

$25.43 per share

She sold them for $44.10 per share

Solution:

Capital gain per share = 44.10 - 25.43 = $18.67

Capital gain  for  2,000 shares = 2000*18.67

= $37,340

Her capital gain is $37,340.

The price of 2000 shares she bought initially = 2,000*25.43

= $50,860

Her capital gain in percentage =  37,340/50,860*100

= 73.41

That is,

73%

Her capital gain is 73%.

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Step-by-step explanation:

Another music store rents trombones for $30 per month plus a yearly fee of $48. Which deal is better? Should Maria change her rental plan?

Part A: Maria needs a trombone for only 12 months. Renting the trombone costs $34 per month. She can buy the trombone for $495. Should she buy or rent the trombone? Explain.

Option 1, SHOP 1: [at $30 a month] When Maria rents for a year, or x = 12 months

This can be described by the equation:

30x + 48

where x = number of months rented

30(12) + 48

= $408

___________

Option 2, SHOP 2:  [at $34 a month] When Maria rents for a year, or x = 12 months

This can be described by the equation:

34x + 48

where x = number of months rented

34(12) + 48

= $456

___________

Option 2, buy: for $495

ANALYSIS:

Because Maria only needs the instrument for a year (12 months), Maria would do best to rent her instrument from option 1, shop 1 (renting at $30 a month + $48 yearly fee). Purchasing the instrument is the most costly.

Should Maria need the instrument longer than a year, then the option preference would change.

the dimensions of the box that minimize the amount of material used is 4.641cm by 4.641cm by 2.32cm

Let the side of the square base be x

h be the height of the box

Volume V = x²h

50 = x²h

h = 50/x² ..... 1

Surface area =  x² + 2xh + 2xh

Surface area S =  x² + 4xh  ...... 2

Substitute 1 into 2;

From 2; S =  x² + 4xh

S = x² + 4x(50/x²)

S = x² + 200/x

To minimize the amount of material used; dS/dx = 0

dS/dx = 2x - 200/x²

0 = 2x - 200/x²

0 = 2x³ - 200

2x³ = 200

x³ = 100

x = ∛100

x = 4.6416cm

Since V = x²h

50 = 4.642²h

h = 50/21.548

h = 2.32cm

Hence the dimensions of the box that minimize the amount of material used is 4.641cm by 4.641cm by 2.32cm

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Answer:

  27. 48°, 132°

  28. The expressions resolve to both angles being 0°, a contradiction to the lines being distinct.

Step-by-step explanation:

Given a figure showing parallel lines crossed by a transversal with marked angles, you want to know (27) the measures of consecutive interior angles that have a ratio of 4:11, and (28) the contradiction in corresponding angles being marked (60-2x)° and (2x-60)°.

The two marked angles are consecutive interior angles, so are supplementary. Using x for the smaller angle value, we can write the equation ...

  x/(180-x) = 4/11 . . . . . the given ratio of the two angles

Multiplying by 11(180-x) gives ...

  11x = 4(180-x)

  15x = 4(180) . . . . add 4x and simplify

  x = 48 . . . . . . . . divide by 15

Then the obtuse angle is ...

  180 -48 = 132

The measures of the angles are ∠1 = 48°, ∠2 = 132°.

The two marked corresponding angles are congruent, so ...

  (60 -2x)° = (2x -60)°

  4x = 120 . . . . . . . . . . . divide by °, add 2x+60

  x = 30 . . . . . . . . . . divide by 4

  60 -2x = 60 -2(30) = 0

  2x -60 = 2(30) -60 = 0

The marked values require the angles to be 0°, which means the transversal is coincident with each of the "parallel" lines.

The given angle values require the lines not to be distinct, as the diagram shows they are.

The train should travel at a speed of 30√5 miles/hour on a 300​-mile trip to minimize the total cost for the​ trip?

Given the cost per hour for fuel to run is v^2/15 dollars:

Labor cost=$300 per hour

Calculate the velocity to travel on a 300-miles trip:

Total time t=Distance/speed

                  =300/v

                 t=300/v

Total cost=(fixed cost*time)+(variable cost*time), where fixed cost is $300 per hour and variable cost is v^2/15 dollars , and time t=300/v

Total cost=(300*300/v)+((v^2/15)*(300/v))

               =(90000/v)+(300v/15)

Now, to minimize the total cost on a 300-mile trip, we differentiate the total cost with respect to the velocity:

Let the d/dv of total cost be C(v):

C(v) =(-90000/v^2+300/15=0

(-90000/v^2+300/15)=0

90000/v^2=300/15

90000/v^2=20

v^2=90000/20

v^2=4500

v=√4500

v=30√5 miles/hour

Hence, the speed is 30√5 miles/hour

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