please help me i need to reconcile but it is hard, thank you

Answer:

13/52

Step-by-step explanation:

According to the given data,

By adding the probabilities, we get

→ [tex]P (D \leq = 2) = 0.301+0.176[/tex]

                     [tex]= 0.477[/tex]

Thus the response above is appropriate.

Learn more about probability here:

https://brainly.com/question/16790640

Answer:

0.097

Step-by-step explanation:

1) "First digit greater than 7" means that the first digit is 8 or 9.

2) P(first digit greater than 7)=0.051+0.046=0.097

3) 0.097

Answer:

150°

Step-by-step explanation:

We know each angle in a equilateral triangle is 60° and that of a rectangle is 90° . So ,

[tex]\implies \angle ABC = \angle DBC + \angle ABD \\\\\implies \angle ABC = 90^o + 60^o \\\\\implies \boxed{\boxed{ \angle ABC = 150^o }}[/tex]

Answer:

[tex]\frac{225}{30}[/tex] or [tex]7\frac{1}{2}[/tex]

Step-by-step explanation:

[tex]\frac{25*9}{3*10} = \frac{225}{30}[/tex]

hope this helped

sorry if im too late lol

Answer:

Theatre A has the greatest percent

Answer:

8 lakhs = 8,00,000

Step-by-step explanation:

770000

=> 7,70,000

=> 7.7 lakhs

7.7 lakh rounded to the nearest lakh = 8 lakhs and it is Rounded Up

Hope it helps :)

Answer:

My answer is 20ft I'm not really sure but hope this helps

Answer:

the answer is b

Step-by-step explanation:

Answer:

Last Choice

Step-by-step explanation:

No time to explain I am 100 % sure its correct i had same problem

Answer:

10ft · (8ft) = 80 [tex]f^ {2} t^{2}[/tex]

3.14 = 80 [tex]f^{2} t^{2}[/tex]

Step-by-step explanation:

Answer:

1/3 * 84 = 28 were under 25

2/7 * 84 = 24 were at least 50

28 + 24 = 52

84-52 = 32 were between 25 and 50

Step-by-step explanation:

Answer:

Do you see the lines and how they are named? I am going to try and explain this in less words than I can. Where it says XS you have to match it up with the lines. But if it says that you have to find XSU (which it does not) you would have to go up all the way but you stop where it says the S so you wont go all  the way up to the U. I hope this helps!

Answer: Hewo, there! your answer is Below

There are 60 mins In 11 a.m And every hour

Step-by-step explanation:

You can easily convert 1 hour into minutes using each unit definition:

Hour

hour = 60 min = 3600 s

Minutes

minute = 60 s = 60 s

Hope this helps you!!

Have a great day!!

Answer:

their are 60 minutes in 11 am

Step-by-step explanation:

Seven lakh and seventy thousand.

This is your answer.

Answer:

My dude the groul that shows that tiny bit of smiling must be the beatles or backstreet boys

Answer:

right: 11.15

left: 17.15

Step-by-step explanation:

right formula: [tex]\int _a^bf\left(x\right)dx\:\approx \Delta \:x\left(f\left(x_1\right)+f\left(x_2\right)+...+f\left(x_n\right)\right)[/tex]

left formula: [tex]\int _a^bf\left(x\right)dx\:\approx \Delta \:x\left(f\left(x_0\right)+f\left(x_1\right)+...+f\left(x_{n-1}\right)\right),[/tex]

[tex]\Delta \:x\:=\:\frac{b-a}{n}[/tex]

estimating : [tex]\int _1^7\left(\frac{7}{x}\right)dx[/tex] , with n = 6 (number of sub-intervals in Riemann sum)

right: 1 [tex]\left(f\left(x_1\right)+f\left(x_2\right)+f\left(x_3\right)+f\left(x_4\right)+f\left(x_5\right)+f\left(x_6\right)\right)[/tex] =[tex]1\cdot \left(\frac{7}{2}+\frac{7}{3}+\frac{7}{4}+\frac{7}{5}+\frac{7}{6}+1\right)[/tex] = 11.5

left: [tex]1\cdot \left(f\left(x_0\right)+f\left(x_1\right)+f\left(x_2\right)+f\left(x_3\right)+f\left(x_4\right)+f\left(x_5\right)\right)[/tex] =

[tex]1\cdot \left(7+\frac{7}{2}+\frac{7}{3}+\frac{7}{4}+\frac{7}{5}+\frac{7}{6}\right)[/tex] = 17.15

Answer:

a) The total engine volume is 30.3265 in³

b) the mass of air contained in the engine is 0.00129 lbm

c) The efficiency of the engine is 55.6%

Step-by-step explanation:

Given the data in the question;

The configuration is in line with four-stroke, four-cylinder engine.

Bore ( d ) = 3.17 in

Stroke ( L ) = 3.48 in

compression ratio ( r ) = 10.6 : 1

First, we calculate the swept Volume V₁ = π/4 × d²L

we substitute

V₁ = π/4 × (3.17 )² × (3.48) = 27.4655 in³

Now, Compression Ration; r = Vs + Vc / Vc

r = (V₁ + V₂) / V₂

we substitute

10.6 = (27.4655 + V₂) / V₂

10.6V₂ = 27.4655 + V₂

10.6V₂ - V₂ = 27.4655

9.6V₂ = 27.4655

V₂ = 2.861 in³

So

a) total engine volume

[tex]V_{BDC[/tex] = V₁ + V₂

we substitute

[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³

[tex]V_{BDC[/tex] = 27.4655 in³ + 2.861 in³

[tex]V_{BDC[/tex] = 30.3265 in³

Therefore, The total engine volume is 30.3265 in³

b) The mass of air

given that; T = 540°R, P = 14.7 psia

we know that; PV = mRT   { R is constant }

we solve for m

m = PV / RT

we substitute

m = (14.7 × 30.3265)  / ( 0.3704 × 1728 )540

m = 445.79955 / 345627.648

m = 0.00129 lbm

Therefore, the mass of air contained in the engine is 0.00129 lbm

c) The efficiency

from table { properties of air}

At 540°R; u₁ = 92.04 BTu/lbm, u[tex]_r[/tex]₁ = 144.32

Now process 1 - 2 ( Isentropic )   u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂  = V₁/V₁ = r

so,  u[tex]_r[/tex]₁ / u[tex]_r[/tex]₂ = r

144.32  / u[tex]_r[/tex]₂ = 10.6

u[tex]_r[/tex]₂ = 144.32/10.6

u[tex]_r[/tex]₂ = 13.61

Thus, at u[tex]_r[/tex]₂ = 13.61, u₂ = 235 BTU/lbm, T₂ = 1340°R

Now, we know that;

P₁V₁/T₁ = P₂V₂/T₂  ⇒ (P₁/V₁)r = P₂/T₂

⇒ ( 14.7 / 540 )10.6 = P₂/1340

P₂ = 386.664 psia  

process 2 - 3; constant volume heat addition;

Now, At T₃ = 3600°R, u₃ = 721.44 BTU/lbm, u[tex]_r[/tex]₃ = 0.6449

so, [tex]q_{in[/tex] =  u₃ -  u₂

we substitute

so, [tex]q_{in[/tex] =  721.44  -  235  = 486.44 BTU/lbm

Next, process 3 - 4; Isentropic  

u[tex]_r[/tex]₄/u[tex]_r[/tex]₃ = V₄/V₃ = r

u[tex]_r[/tex]₄ / 0.6449  = 10.6

u[tex]_r[/tex]₄ = 6.8359

At u[tex]_r[/tex]₄ = 6.8359; u₄ = 308 BTU/lbm

∴

Heat Rejection [tex]q_{out[/tex] = u₄ - u₁ = 308 - 92.04 = 215.96 BTU/lbm

so, [tex]W_{net[/tex] = [tex]q_{in[/tex] - [tex]q_{out[/tex]

[tex]W_{net[/tex] = 486.44 - 215.96

[tex]W_{net[/tex] = 270.48 BTU/lbm

so the efficiency; η[tex]_{thermal[/tex] = ([tex]W_{net[/tex] / [tex]q_{in[/tex] ) × 100%

η[tex]_{thermal[/tex] = ( 270.48 / 486.44  ) × 100%

η[tex]_{thermal[/tex] = ( 0.55604  ) × 100%    

η[tex]_{thermal[/tex] = 55.6%

Therefore, The efficiency of the engine is 55.6%

Answer:

hi

Step-by-step explanation:

i think it is A

because

[tex] \frac{x}{3} + 10 = \frac{15}{3} + 10 = 5 + 10 = 15[/tex]

hope it helps

have a nice day

Answer:

answer is A and C

hope it helps

Answer:

wait nvm I did the wrong answer lemme re check

Ok sorry I reviewed it and i think its D i looked to fast and got confused sorry

Answer:

Its C Translation,reflection

Step-by-step explanation:

I took the test and this was the right answer!!

Answer:

C) (9,15)

Step-by-step explanation:

1) For each dot you go right 3 up 5 to get to the next dot.

2) right 3 up 5 from (6, 10) would be (9,15)

Answer:

Step-by-step explanation:

For x- coordinate we have:

For y-coordinate we have:

Missing point is (9, 15)

Correct choice is C

Answer:

H) 7x² + 8x - 2

Step-by-step explanation:

Answer:

34 I am pretty sure

Step-by-step explanation:

34+55 well is 89 so yeah d=34

Step-by-step explanation:

If we think over it, we could recognise that this question is like

How many 3's are in 6?

Probably the answer is

2

, as

6

÷

3

=

2

So, we divide

1

by

5

6

→

1

÷

5

6

→

1

⋅

6

5

→

6

5

⇒

1

1

5

=

1.2

So, there are

1

1

5

number of

5

6

's in

1

Answer:

3/(5/6)

Step-by-step explanation:

multiply the numerator and denominator by 6

18/5

Answer:

there are 35 bananas in B

Step-by-step explanation:

There are 16 bana

Answer:

if you help me ill help you

Step-by-step explanation:

Carmen's father is 28 years older than her and 3 years ago he was 5 times her age. What are their ages?

Answer:

y = 100x + 200

Step-by-step explanation:

Answer:

spotted male

Step-by-step explanation:

if you look at the numbers then you will see that this one has the biggest number

Answer:

a) 9/7

Step-by-step explanation:

[tex] \dfrac{x^2 + x - 20}{x^2 - x - 12} = [/tex]

[tex] = \dfrac{(x + 5)(x - 4)}{(x + 3)(x - 4)} [/tex]

[tex] = \dfrac{x + 5}{x + 3} [/tex]

x = 4

[tex] = \dfrac{4 + 5}{4 + 3} [/tex]

[tex] = \dfrac{9}{7} [/tex]