Mathematics College

please help me quick!

Answers

Answer 1

Answer:

transition 1 would be 5 to the right

transition 2 would be 1 down

Step-by-step explanation:

Related Questions

What is the volume of the rectangular prism?
Type the answer in the boxes below.

Answers

Answer:

3.75 cubic centimeters

Step-by-step explanation:

1.5*2.5*1 cubic centimeters

Answer:

3/20

Step-by-step explanation:

1/2 x 3/5 x 1/2

L x W x H is the formula

Length x Width x Height

count the squares, they're each 1/2 so multiply the number of squares with 1/2.

For example, the rectangular prism is 3 squares high, which means it's 3/6, and that simplifies to 1/2. Now you have your height. You do the same for the width and length.

Hope this helps <3

30% tip on a bill of $150.47

Answers

Answer:

45.141 or if you round 45.14

Step-by-step explanation:

150.47 x 0.30 = 45.141

2.* Use the slope (m) and y-intercept (b)
to describe the system.
(1) x + y = -1
(2) -x - y=-1
F. Intersecting lines
G. Same lines, m > 0
H. Same lines, m < 0
J. Parallel lines, m > 0
K. Parallel lines, m < 0

Answers

Answer:

the answer is for this particular problem is F

10 POINTS PLEASE HELP

Answers

Answer:

m∠A = 49°

Step-by-step explanation:

According to Angle Sum Property,

angles of the Δ add up to 180°∠A + ∠B + ∠D = 180°5x - 6 + 7x - 24 + 78 = 18012x + 48 = 180x + 4 = 15x = 11

m∠A

5x - 65(11) - 655 - 649°

a number minus 4 is less than thirteen

Answers

I would think that for it to be less then thirteen it would either be 12 or 11

Use the box plots comparing the number of boy dogs and number of girl dogs attending doggy daycare each day for a month to answer the questions.

Answers

The boxplots 1 and 2 represent the distribution of data using a five number summary for the male and the female attendance

(a) The IQR of the male's data

The first box plot represents the male's boxplot.

So, we have:

Upper quartile (Q3) = 14Lower quartile (Q1) = 2

The IQR is the difference between the above values

IQR = Q3 - Q1

So, we have:

IQR = 14 - 2 = 12

So: the IQR for the males' data is 12

(b) The difference in the median values

From the first and second boxplots, we have:

Median male = 10Median female = 18

The difference (d) between these values is

d = 18 - 10

d = 8

So: the difference between the median values of each data set is 8

This is dependent on whether the dataset has an outlier or not.

From the figure, we have:

Male's data: presence of an outlier - use medianFemale's data: absence of an outlier - use mean

So: the male dataset is measured by median, while the mean is a better measure of center for the female's data

(d) Reason for outliers

A possible reason for outliers is sampling problems

Answers

[tex]y= x^2 -5~~~~~~...(i)\\\\y = -2x +3~~~~...(ii)\\\\\text{From (i) and (ii):}\\\\~~~~~~~~x^2 -5 = -2x+3\\\\\implies x^2 -5 +2x -3 = 0\\\\\implies x^2 +2x -8 = 0 \\\\\implies x^2 +4x -2x -8 = 0\\\\\implies x(x+4) -2(x+4) = 0\\\\\implies ( x+4)(x-2) = 0\\ \\\implies x = -4,~ x = 2\\\\\text{Substitute x = 2 in eq (ii)}:\\\\y = -2(2) +3 = -4 +3 = -1\\\\\text{Substitute}~ x = -4 ~\text{in eq (ii)}:\\\\y = -2(-4) +3 = 8 +3 = 11\\\\\text{So,} ~(x, y)=\{(2,-1), (-4,11) \}\\\\\text{Hence the answer is option B.}[/tex]

i need help with 7th grade math please need help ASAP + brainleist

Answers

Answer:

Area : π mm²

Circumference : 2π mm

Step-by-step explanation:

Finding area :

πr²π x 1²π mm²

Finding circumference :

2πr2 x π x 12π mm

A lion can run at a speed of 1.43 kilometers per minute. How fast can the lion run in miles per hour

Answers

The loin's speed in miles per hour will be 53.31 miles per hour.

What is velocity?

Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.

It is given that:-

lion can run at a speed of 1.43 kilometres per minute.How fast can the lion run in miles per hour

Now to find the speed of a lion in miles per hour we have the following relationship.

[tex]1\ \ \ \dfrac{KM}{min} \ = \ 37.28\ \ \ \ \dfrac{Miles }{hour}[/tex]

[tex]1\ \ \ \dfrac{KM}{min} \ \times 1.43\ = \ 37.28 \times 1.43\ \ \ \dfrac{Miles }{hour}[/tex]

[tex]1.43\ \ \ \dfrac{KM}{min} \ = \ 53.3\ \ \dfrac{Miles }{hour}[/tex]

Therefore the loin's speed in miles per hour will be 53.31 miles per hour.

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Yellow Bird launches from point (10,0). His flight path reaches a maximum height of 22 yards and lands at point (42, 0).

Answers

The Equation for the launch of the yellow bird is y = -0.1( x - 26 )² + 20

what will be the equation?

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values

Given:

Starting position of the bird = ( 10 , 0 )

Final position of the bird = ( 42 , 0 )

Maximum Height of the bird = 20 yards

To find: Equation that represent this condition.

Clearly, Birds flight path is not a straight line. It has a curved path.

So, the path bird follow is a PARABOLA.

Standard Equation of the parabola in vertex form, y = a( x - h )² + k

where ( h , k ) is the vertex of the parabola.

In our Question , vertex is the point at the highest position.

Vertex will be 20 yard above the mid point of the starting and final position.

Using Mid-Point Formula,

Mid-Point of ( 10 , 0 ) & ( 42 , 0 ) =

Now, the vertex = ( 26 , 0 + 20 ) = ( 26 , 20 )

⇒ Equation, y = a( x - 26 )² + 20

Now, we find value of by substituting value of (10 , 0) in the equation,

⇒ 0 = a( 10 - 26 )² + 20

a( -16 )² = -20

a(256) = -20

a = -20/256

a = −0.078125

a ≈ -0.1

Therefore, The Equation is y = -0.1( x - 26 )² + 20

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rewrite! Write an new and equivalent equation that is easier to solve

Answers

[tex]{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}[/tex]

[tex] \sf 7( \sqrt{m + 1} - 3) = 21[/tex]

we will multiply 7 with bracket

[tex] \sf 7 \sqrt{m + 1} - 21 = 21[/tex]

Now we will take (-21) on LHS to RHS

[tex] \sf 7 \sqrt{m + 1} = 21 + 21 \\ \\ \sf7 \sqrt{m + 1 } = 42 \\ \\ \sf \sqrt{m + 1} = \frac{42}{7} \\ \\ \sf \sqrt{m + 1} = 6[/tex]

Now we will do squaring both sides

[tex] \sf {( \sqrt{m + 1}) }^{2} = {(6)}^{2} \\ \\ \sf \red {m + 1 = 36}[/tex]

[tex]\sf{ 7( \sqrt{m+1} - 3)=21}[/tex]