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If two vectors are represented both in magnitude and direction by the two adjacent sides of a triangle taken in an order, then their resultant is given by the third side taken in the reverse order.

Resultant vector :

                         R = sqrt of A^2 + B^2 + 2ABcosθ

given :

          A = 200 units

          B = 300 units

          θ = 30 degrees

∴ R = sqrt of 200^2 + 300^2 + 2(200)(300)cos35

the answer is 477.805656

Answer:

Work is ability if application of energy.

Such as pushing a wheel barrow through a distance ( Newton's third law )

Work is the ability to do something.

Answer:

4. the feather experiences more fluid friction than the ball

Answer:

5m/sec^2

Explanation:

Distance=1200m

Time=4 min

1=60sec

4=4 x 60

=240sec

Velocity=Distance/Time

Velocity=1200/240

Velocity=5m/sec^2

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Answer:

[tex]k.e = \frac{1}{2} m {v}^{2} \\ {v}^{2} = {u}^{2} + 2gs \\ {v}^{2} = 0 + (2 \times 9.8 \times 15) \\ v = 17.1 \: m {s}^{ - 1} \\ k.e = \frac{1}{2} \times m \times {17.1}^{2} \\ = 147m \: joules \\ m \: is \: mass[/tex]

Kinetic energy of the rock just before hitting the water is 147m joules where m is the mass of the object.

The kinetic energy of an object is defined as the energy it possesses due to its motion. It is the work required to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains the kinetic energy as long as its momentum does not change.

It is directly proportional to the mass of the object and the square of its velocity:[tex]K.E. = 1/2 mv^2[/tex].

Where, m= mass of the object

v= velocity

So if the units of mass are in kilograms and the units of velocity are meters per second, then kinetic energy has units of kilogram-meter squared per second squared.

For above given information,

[tex]K.E= 1/2 mv^2\\v^2= u^2 + 2gs\\ \\v^2= 0+ (2* 9.8*15)\\v^2= 294 m/s\\So, K.E. = 1/2 m* 294 m/s\\K.E.= 147m joules[/tex]

Thus, Kinetic energy of the rock just before hitting the water is 147m joules where m is the mass of the object.

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Answer:

The speed she must have at point 3 is approximately 21.72 m/s

Explanation:

The given parameters are;

The radius of the track, r = 3.25 m

The speed with which the driver goes past point 1, v₁ = 20.2 m/s

Let, 'm', represent the mass of the driver and the car, and let v₃ represent the velocity at point 3, based on the diagram and solution method from a similar question online, we have;

At point 1, The net force, [tex]F_{NET} = F_N - F_g[/tex]

The net force, [tex]F_{NET}[/tex], is the centrifugal force, therefore;

[tex]F_{NET} = \dfrac{m \cdot v_1^2}{r}[/tex]

[tex]F_g[/tex] = The force of gravity on the car (the weight of the car) = m·g

[tex]F_N_1[/tex] = The normal reaction at point 1

Therefore, we have;

[tex]F_{NET} = \dfrac{m \cdot v_1^2}{r} = F_N_1 - F_g = F_N_1 - m \cdot g[/tex]

[tex]F_N_1= \dfrac{m \cdot v_1^2}{r} + m \cdot g = m\cdot \left(\dfrac{ v_1^2}{r} + g \right)[/tex]

[tex]F_N_1 = m\cdot \left(\dfrac{ v_1^2}{r} + g \right)[/tex]

At point 3, The net force, [tex]F_{NET} = F_N_3 + F_g[/tex]

Where;

[tex]F_{N3}[/tex] = The normal reaction at point 3

Therefore;

[tex]F_N_3= F_{NET} - F_g = \dfrac{m \cdot v_3^2}{r} - m \cdot g = m\cdot \left(\dfrac{ v_3^2}{r} - g \right)[/tex]

For the normal force to be the same, we get;

[tex]F_{N1} = F_{N3}[/tex]

Therefore;

[tex]m\cdot \left(\dfrac{ v_1^2}{r} + g \right) = m\cdot \left(\dfrac{ v_3^2}{r} - g \right)[/tex]

[tex]\left(\dfrac{ v_1^2}{r} + g \right) = \left(\dfrac{ v_3^2}{r} - g \right)[/tex]

[tex]v_3^2 = r \times \left(\dfrac{ v_1^2}{r} + g + g \right) = v_1^2 + 2\cdot g \cdot r[/tex]

[tex]v_3 = \sqrt{v_1^2 + 2\cdot g \cdot r}[/tex]

Where;

g = The acceleration due to gravity ≈ 9.81 m/s²

Therefore;

v₃ = √(20.2² + 2 × 9.81 × 3.25) ≈ 21.72 m/s

The speed she must have at point 3, so that the normal force at the top has the same magnitude as it did at the bottom, v₃ ≈ 21.72 m/s

Answer:

The pressure at the depth is 201775 Pa.

Explanation:

Depth, h = 10 m

density, d = 1025 kg/m3

atmospheric pressure, Po = 101325 Pa

The total pressure at the depth is

P = Po + h d g

P = 101325 + 10 x 1025 x 9.8

P = 101325 + 100450

P = 201775 Pa

Answer:

The acceleration is - 3 m/s2.

Explanation:

initial speed, u = 54 km/h = 15 m/s

final speed, v = 0

time, t = 5 s

Let the acceleration is a.

use first equation of motion

v = u + at

0 = 15 + a x 5

a = - 3 m/s2

Answer:

Wavelength of AM radio wave = 0.125 meter

Explanation:

Given:

Frequency of AM radio wave = 24 Hz

Velocity of AM radio wave = 3 m/s

Find:

Wavelength of AM radio wave

Computation:

Wavelength = Velocity / Frequency

Wavelength of AM radio wave = Velocity of AM radio wave / Frequency of AM radio wave

Wavelength of AM radio wave = 3 / 24

Wavelength of AM radio wave = 0.125 meter

Answer:

Displacement

Explanation:

The distance between an object and a certain reference point is called displacement. This is not to be confused with distance, which represents the total distance the object has travelled to get a certain point, regardless of how long it is. Displacement always represents the shortest distance (a straight line) between the initial and final points.

Answer:

Displacement is the distance and direction of an object's change in position from a reference point. Suppose a runner jogs to the 50-m mark and then turns around and runs back to the 20-m mark.

Answer:

a. V_y = 50m/s and V_x = 86.6m/s

b. d_x = 173.2m

c. d_y = 80.38m

Explanation:

V_x = 100m/s*cos(30°)

V_x = 86.6m/s

V_y = 100m/s*sin(30°)

V_y = 50m/s

D_x = v_x*t

d_x = 86.6m/s*2s

d_x = 173.2m

v_f = 50m/s+(-9.81m/s²)*2s

v_f = 30.38m/s

d_y = .5*(30.38m/s+50m/s)*2s

d_y = 80.38m

Answer:

Explanation:

V = I * R

V = 4 * 12.1 = 48.4 v

Answer

Velocity, Mass, and Radius

Explanation:

radius is what the size of the thing moving and the mass and velocity is both part of momentum because of speed and direction, BUT acceleration is both the change in speed and direction, not speed for direction themselves, so it is Velocity, Mass, and Radius

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Answer:

10 N

Explanation:

From the diagram,

Applying the principle of moment,

Sum of clockwise moment = sum of anti clockwise moment.

Assuming: the 10 N is placed on the 5 cm mark, F is placed on the 40 cm mark, The 25 N is placed on the 10 cm mark, the 30 N is placed on the 75 cm mark, and the 40 N is placed on the 80 cm mark.

Therefore,

10(50-5)+F(50-40)+40(80-50) = 30(75-50)+25(50-10)

450+10F+1200 = 750+1000

10F+1650 = 1750

10F = 1750-1650

10F = 100

F = 100/10

F = 10 N

c- temperature

The speed of sound increases with increasing temperature .

The voltage from one side of the battery all the way around to the other side of the battery is 12v .

If 4 of those volts show up across the circle-thing, then the rest of the 12v ... 8v ... Must show up across the set of parallel rectangles.

To get that answer, I subtracted the 4 from the 12.

Just like it says in choice-C.

Answer:

1200000 J

Explanation:

Applying,

W = Fdcos∅....................... Equation 1

Where W = Workdone, F = Force applied to pull the wagon, d = distance, ∅ = angle with the horizontal.

From the question,

Given: F = 2000 N, d = 0.75 miles = (0.75×1600) = 1200 m, ∅ = 60°

Substitute these values into equation 1

W = 2000×1200×cos60°

W = 2000×1200×0.5

W = 1200000 J

Hence the work done in pulling the wagon is 1200000 J

Explanation:

we know that

v = m/d

or; v=1kg/800kgm^3

or; v=0. 00125m

Answer:

1)  ΔE = -800 J, 2) ΔE = 200 J, 3)  ΔE = -200 J, 4) ΔE = 800 J

Explanation:

For this exercise let's use the first law of thermodynamics

          ΔE = Q + W

Where we will apply this expression to several cases

1) output Q = 500 J and does work of W = 300 J.

The two processes involve an energy output

         ΔE = - 500 - 300

         ΔE = -800 J

Therefore, the internal energy of the gas decreases by this amount,

2) enter Q = 500J and do work of W = 300 J

         Positive heat is added and does negative work

         ΔE = 500 - 300

         ΔE = 200 J

3) they leave Q = 500 J and do (work on the gas) W = 300J

negative heat and positive work come out

          ΔE = -500 + 300

          ΔE = -200 J

4) heat enters Q = 500 J, work on gas W = 300 J

both positive

         ΔE = 500 + 300

         ΔE = 800 J

Answer:

When an object falls, gravity pulls the object towards the ground and causes the object to accelerate by 9.8m/s each second. Regardless of mass, every object accelerates at the same rate (9.8m/s) when dropped unless there´s air resistance.  

Answer:

i need this 2

Explanation:

Answer:

Materials Science

Explanation:

Materials Science: "The study of the characteristics of materials such as glass, plastics, and metals."

Ceramics is a glass so they are studying materials science.

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Pressure is defined as the perpendicular force acting per unit area.

Its SI unit is pascal.

Explanation:

Formula to calculate pressure is,

P=F/A

Where as,

P = Pressure

F = Force

A = Area

Its SI unit is pascal(pa).

Answer:

4 amp

Explanation:

From ohm's law,

V=IR

so,

I=V/R

I=120/30

I=4amp ans..

Answer:

Equal to the frictional force

Explanation:

Question; The options given with regards to a similar question posted online are;

A. Equal (equivalent) to the frictional force

B. Larger than the frictional force

C. Equal to the object's weight

D. More than the object's weight

Explanation

According to Newton's first law of motion, every object shall remain at rest or continue moving with uniform (constant speed) motion unless there is a net force acting on the object

Given that the velocity of the massive block, lying on the surface that has friction, being pulled by the rope = Constant

Therefore;

The net force acting on the moving block while being pulled by the rope = 0

From which we have;

The pulling force = The resistive force

Where;

The pulling force = The (pulling) force (applied) on the rope

The resistive force = The frictional force of the surface which tends to prevent the motion of the block

Therefore, given that the net force acting on the block = 0

The force on the rope = The frictional force (of the surface)

The correct option is option A. Equal to the frictional force.

Substance:-

Answer:

2.4 secs.

Explanation:

Current (A) = Charge (coulomb)/Time(sec)

We are looking for time. So:

Time (sec) = Charge (coulomb)/Current (A)

↓

12coulombs/5.0A = 2.4 secs

The statement which describes the possible interaction(s) between two objects caused by the electric, magnetic, or gravitational force between them is:

Gravitational forces only cause objects to be attracted to each other, and magnetic and electric forces can cause objects to

Force can be defined as the push or pull on an object with mass that causes it to change its velocity

So therefore, the statement which describes the possible interaction(s) between two objects caused by the electric, magnetic, or gravitational force between them is:

Gravitational forces only cause objects to be attracted to each

other, and magnetic and electric forces can cause objects to

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Answer: [tex]0.2464\ W[/tex]

Explanation:

Given

Charge [tex]Q=200\ mC[/tex]

Resistance [tex]R=50\ k\Omega[/tex]

Time [tex]t=90\ s[/tex]

Charge is the amount of current flown in a particular time

[tex]Q=It\\\Rightarrow 200\times 10^{-3}=I\times 90\\\\\Rightarrow I=\dfrac{200\times 10^{-3}}{90}\\\\\Rightarrow I=2.22\times 10^{-3}\ A[/tex]

Power is the given by [tex]P=I^2R[/tex]

Insert values

[tex]\Rightarrow P=\left(2.22\times 10^{-3}\right)^2\times 50\times 10^3\\\\\Rightarrow P=246.42\times 10^{-3}\ W\\\\\Rightarrow P=0.2464\ W[/tex]

The power is in the circuit is [tex]0.2464\ W[/tex].

Answer:

[tex]h=3.18\times 10^{-9}\ m[/tex]

Explanation:

Given that,

The volume of a drop, [tex]V=10^{-10}\ m^3[/tex]

The radius of the circular film, [tex]r=10^{-1}\ m[/tex]

We need to find the thickness of the film.

We know that,

Volume, [tex]V=\pi r^2 h[/tex]

So,

[tex]h=\dfrac{V}{\pi r^2}\\\\h=\dfrac{10^{-10}}{\pi \times (10^{-1})^2}\\\\h=3.18\times 10^{-9}\ m[/tex]

So, the thickness of the file is equal to[tex]3.18\times 10^{-9}\ m[/tex].