Please help me !!!!!!!

Answer:

h = 47 m

Explanation:

First, we will calculate the force on the cord due to the weight:

[tex]Force = F = Weight\\F = mg\\F = (79\ kg)(9.81\ m/s^2)\\F = 775\ N[/tex]

Now, we will calculate the elongation by using Hooke's Law:

[tex]F = k \Delta x[/tex]

where,

k = spring constant = 43 N/m

Δx = elongation = ?

Therefore,

[tex]775\ N = (43\ N/m)\Delta x\\\\\Delta x = \frac{775\ N}{43\ N/m}\\\\\Delta x = 18\ m\\[/tex]

So, the final length of the cord will be:

[tex]Final\ Length = Initial\ Length + \Delta x\\Final\ Length = 35\ m + 18\ m\\Final\ Length = 53\ m\\[/tex]

Hence, the height from water (h) can be found using the following formula:

[tex]h = Height\ of\ Bridge - Final\ Length\ of\ cord\\h = 100\ m - 53\ m\\[/tex]

h = 47 m

Answer:

the power of the two light bulbs is 23.4 W

Explanation:

Given;

the resistance of the two identical light bulbs in series, R₁ and R₂ = 6.77 ohms and 6.77 ohms respectively

battery voltage , V = 17.8 V

The equivalent resistance of the two light bulbs, R = R₁ + R₂

R = 6.77 + 6.77

R = 13.54 ohms

The power of the two light bulbs is calculated as follows;

[tex]P = IV = (\frac{V}{R} )V = \frac{V^2}{R} = \frac{17.8^2}{13.54} = 23.4 \ W[/tex]

Therefore, the power of the two light bulbs is 23.4 W

Answer:

(A)   She needs to move the decimal point by 3 places

Answer:

m = 2.4

Explanation:

Given that,

Input force, [tex]F_i=5\ N[/tex]

Output force, [tex]F_o=12\ N[/tex]

We need to find the mechanical advantage of the ramp. The ratio of output force to the input force is equal to mechanical advantage. So,

[tex]m=\dfrac{12}{5}\\\\m=2.4[/tex]

So, the mechanical advantage of his ramp is 2.4.

Answer:

Polishing the rough surface.

Oiling or lubricating with graphite or grease the moving parts of a machine.

Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.

Explanation:

Answer:

A I hope its not wrong I hope u do good

Answer:

is that youuuuuuu? fine.

Answer:

B.will increase the maximum static friction between the box and the floor

Explanation:

Because static friction is the force that keeps an object at rest

Answer:

E₀ = 2.0*10⁻¹¹ J = 0.2 pJ

Ef = 3.0*10⁻¹¹ J = 0.3 pJ

Explanation:

      [tex]E = \frac{1}{2} * C * V^{2} (1)[/tex]

       [tex]C = \frac{\epsilon_{o}*A}{d} (2)[/tex]

       [tex]E_{o} = \frac{1}{2} * C_{o} * V_{o} ^{2} = \frac{1}{2} * 1.77*10^{-13}F*(1.5V)^{2} = 0.2 pJ (6)[/tex]

       [tex]E_{f} = \frac{1}{2} * C_{f} * V_{f} ^{2} = \frac{1}{2} * 1.18*10^{-13}F*(2.25V)^{2} = 0.3 pJ (9)[/tex]

Answer:

comparing the beam waist for both lasers ( ratio of the beam waists )

4.536 μm / 2.117 μm = 2.14

Explanation:

Nd-YAG laser system : emits at 532 nm , beam diameter = 8 mm

Ti-sapphire laser system : emits at 855 nm , Beam diameter = 6mm

Comparing the beam waist for both lase systems using a focusing lens

Focal length = 10 mm

assumption : light fills lenses in each laser system

Beam waist radius ( W ) =  [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex]

β = wavelength , D = diameter illuminated  , F = focal length

For

Nd-YAG laser system

β = 532 mm , D = 8 mm

hence ( Wn ) =   [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex] =  ( 2*532 / π ) ( 10 / 8 )   = 2.117 μm

For

Ti-sapphire laser

β = 855 nm ,  D = 6 mm

hence ( Wt )  [tex](\frac{2\beta }{\pi } )(\frac{F}{D} )[/tex] =  ( 2* 855 ) / π ) ( 50 / 6 ) = 4.536 μm

comparing the beam waist for both lasers ( ratio of the beam waists )

4.536 μm / 2.117 μm = 2.14

Answer:

I dont understand what you are trying to ask

Explanation:

Answer:

the canoe moved 1.2234 m in the water

Explanation:

Given that;

A man whose mass = 69 kg

A woman whose mass = 52 kg

at opposite ends of a canoe 5 m long, whose mass is 20 kg

now let;

x1 = position of the man

x2 = position of canoe

x3 = position of the woman

Now,

Centre of mass = [m1x1 + m2x2 + m3x3] / m1 + m2 + m3

= ( 69×0 ) + ( 52×5) + ( 20× 5/2) / 69 + 52 + 20

= (0 + 260 + 50 ) / ( 141 )

= 310 / 141

= 2.19858 m

Centre of mass is 2.19858 m

Now, New center of mass will be;

52 × 2.5 / ( 69 + 52 + 20 )

= 130 / 141

= 0.9219858 m  { away from the man }

To get how far, the canoe moved;

⇒ 2.5 + 0.9219858 - 2.19858

= 1.2234 m

Therefore, the canoe moved 1.2234 m in the water

The canoe move in the water will be 1.2234 m. The canoe move depending on the center of mass of the bodies.

The center of mass of an item or set of objects is a place specified relative to it. It's the average location of all the system's components, weighted by their mass.

The centroid is the location of the center of mass for simple rigid objects with homogeneous density. The center of mass of a uniform disc shape, for example, would be at its center.

The given data in the problem is;

m₁ is the mass of man = 69 kg

m₂ is the mass of woman whose= 52 kg

m₃ is the mass  of  canoe =  20 kg

L is the length of canoe = 5 m

x₁ is the position of the man

x₂ is the position of the canoe

x₃ is the position of the woman

The center of mass will be;

[tex]\rm COM= \frac{[m_1x_1 + m_2x_2 + m_3x_3]}{ m1 + m2 + m3} \\\\ \rm COM= \frac{[69 \times 0 +52 \times 5 + 20 \times 2.5]}{ 69+ 52 + 20} \\\\ \rm COM= (0 + 260 + 50 ) / ( 141 )\\\\ \rm COM = 310 / 141 \\\\ \rm COM = 2.19858 m[/tex]

The new center of mass is;

[tex]\rm COM= \frac{52 \times 2.5 }{69+52+20} \\\\ \rm COM=\frac{130}{141} \\\\ \rm COM= 0.9219 m[/tex]

The distance to find how the canoe moved will be found by;

[tex]\rm x= 2.5+0.9219-2.1985 = 1.2234[/tex]

Hence the canoe move in the water will be 1.2234 m.

To learn more about the center of mass refer to the link;

https://brainly.com/question/8662931

Answer:

Explanatation

1 is just walking

2 spinging

3 roatating

4 rolling

5 stomping there feet

Those should be right but if im wrong then just someone eles the brainly

Answer:F = kq2/d2 ⇒

q = √(Fd2/k)

q = d √(F/k)

d = 3.8 x 10-10 m

F = 6.4 x 10-9 N

Look up k in your physics book in appropriate units, and plug in the numbers. You should get q in coulombs.

Explanation:

The value of each charge will be 1.64 ×10⁻⁴. The concept of the columb force is used.

When the matter is put in an electromagnetic field, it has an electric charge, which causes it to experience a force. A positive or negative electric charge can exist.

Charges that are similar repel each other, whereas charges that are dissimilar attract each other. The term "neutral" refers to an item that has no net charge.

[tex]\rm F =K \frac{q_1Q_2}{d^2} \\\\ F = K\frac{q^2}{d^2} \\\\ q = \sqrt{\frac{dF}{k} } \\\\ q = \sqrt{\frac{3.8 \times 10^{10}\times 6.4 \times 10^{-9}}{9 \times 10^9} } \\\\ q=1.64 \times 10-4[/tex]

Hence the value of each charge will be 1.64 ×10⁻⁴. The concept of the columb force is used.

To learn more about the charge refer to the link;

https://brainly.com/question/24391667

Answer:

1)

a) in the state of rest with respect to surroundings of the compartment,

2)

b) periodic motion

3)

a) moving car in a straight line

4)

d) velocity

5)

b) velocity decrease

6)

b) increases

7)

d) acceleration

8)

10 m/s

9)

b) average velocity

10)

b) instantaneous velocity

11)

a) 439.6 m

Explanation:

1)

With respect to the inside surrounding the person will be at rest. Because the person is not moving inside the compartment.

2)

The vibration motion follows periodic motion.

3)

The car moving in a straight line is an example of rectilinear motion and its wheels are in rotational motion. They are not in periodic motion.

4)

Definition of velocity.

5)

Acceleration is the rate of change of velocity. So negative acceleration means a decrease in velocity.

6)

Acceleration is the rate of change of velocity. So an increase in velocity means an increase in acceleration.

7)

Definition of acceleration.

8)

[tex]velocity = \frac{Distance}{Time}\\\\velocty = \frac{600\ m}{1\ min}\frac{1\ min}{60\ s}\\\\velocity = 10\ m/s[/tex]

Hence, none of the options is correct. The correct answer is 10 m/s.

9)

Definition of average velocity.

10)

Definition of instantaneous velocity.

11)

[tex]Displacement = Circumference = \pi d\\Displacement = \pi(140\ m)\\Displacement = 439.6\ m[/tex]

Answer:

2) a_y= -g  3) vₓ=constant v_y = v_{oy} - g t, 4)  vₓ = v₀ₓ - ax t

5)  changes the horizontal speed, should change range

7) changes the vertical speed change the maximum height

Explanation:

1) After reading your long writing, we are going to solve the exercise, in the attachment you can see the different vectors.

2) The acceleration vectors are vertical and directed downwards due to the attraction of the Earth (gravity force) this force is constant, on the x axis there is no acceleration

3) the velocity vectors on the x-axis are constant because there are no relationships and the y-axis changes value according to the expression

           v_y = v_{oy} - gt

at the point of maximum height, vy = 0 is equal to the maximum height

4) For someone to change the horizontal acceleration we must assume a friction with the air, in this case they relate it would be in the opposite direction to the horizontal speed

In the graph it would be directed to the left, therefore the velocity would be

           vₓ = v₀ₓ - ax t

5 and 6) If someone changes the horizontal speed, they should change the range of the shot for greater horizontal speed, the rock goes further.

the equations of motion are

           x = v₀ₓ t

           y = v_{oy} t - ½ g t²

7) If someone changes the vertical speed change the maximum height, but not the scope of the shot, for higher speed higher maximum height,

the equations of motion are the same.

Answer:

Mass of Exoplanet =  0.58 kg

Explanation:

First, we will calculate the speed of the forest moon:

[tex]speed = v = \frac{Circumference}{time}\\[/tex]

circumference = 2πr = 2π(14441566 m) = 90739035.3 m

time = 6 days 10 hr = (6 days)(24 h/1 day)(3600 s/1 h) + (10 h)(3600 s/1 h)

time = 554400 s

Therefore,

[tex]v = \frac{90739035.3\ m}{554400\ s}\\\\v = 163.67\ m/s[/tex]

We know that the centripetal force on forest moon will be equal to the gravitational force given by Newton's Gravitational Law, as follows:

[tex]Centripetal\ Force = Gravitational\ Force\\\frac{m_{moon}v^2}{r} = \frac{Gm_{moon}m_{exoplanet}}{r^2}\\\\m_{exoplanet} = \frac{v^2r}{G}\\\\m_{exoplanet} = \frac{(163.67\ m/s)^2(14441566)}{6.67\ x\ 10^{-11}\ N.m^2/kg^2}[/tex]

Mass of Exoplanet =  0.58 kg

Answer:

3m/s up

Explanation:

Answer:

[tex]1796.65\ \text{N}[/tex]

Explanation:

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

w = Weight of spracecraft at the surface = [tex]7.2\times10^3\ \text{N}[/tex]

m = Mass of spracecraft

R = Radius of Earth = [tex]6.38\times10^3\ \text{km}[/tex]

h = Elevation = [tex]6.38\times10^3\ \text{km}[/tex]

G = Gravitational constant = [tex]6.674\times 10^{-11}\ \text{Nm}^2/\text{kg}^2[/tex]

M = Mass of Earth = [tex]5.972\times 10^{24}\ \text{kg}[/tex]

[tex]w=mg\\\Rightarrow m=\dfrac{w}{g}\\\Rightarrow m=\dfrac{7.2\times 10^3}{9.81}\\\Rightarrow m=733.94\ \text{kg}[/tex]

From the gravitational law we have

[tex]w'=\dfrac{GMm}{(r+h)^2}\\\Rightarrow w'=\dfrac{6.674\times10^{-11}\times 5.972\times 10^{24}\times 733.94}{(6.38\times10^6+6.38\times10^6)^2}\\\Rightarrow w'=1796.65\ \text{N}[/tex]

The weight of the spacecraft at the given height is [tex]1796.65\ \text{N}[/tex]

Answer:

sandy loam

Explanation:

The best soil for most plants to ensure optimum growth is a rich, sandy loam. This soil is an even mixture of all three main types of soil. In most cases, you'll need to amend the soil with compost. Depending on how compact the soil is, you may need to add peat moss and sand.

The work-energy theorem states that the net work done by the forces on an object equals the change in its kinetic energy.

Answer:

a kinetic energy

Explanation:

Answer:

mars, reason why is because they both are diff from the size

Explanation:

Answer:

The velocity would decrease

Explanation:

Let

[tex]m_1[/tex] = Mass of car

[tex]m_2[/tex] = Mass of trash can

[tex]u_1[/tex] = Initial velocity of car = 10 m/s

[tex]u_2[/tex] = Initial velocity of trash can = 0

v = Velocity of combined mass

From the question the momentum balance of the system will be

[tex]m_1u_1+m_2u_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1u_1+m_2u_2}{m_1+m_2}\\\Rightarrow v=\dfrac{10m_1}{m_1+m_2}[/tex]

The velocity would decrease as now the mass of the car and trash will both be moving as one. The mass would increase resulting in a lower velocity of the combined mass.

La erosión costera es la pérdida o desplazamiento de tierra, o la remoción a largo plazo de sedimentos y rocas a lo largo de la costa debido a la acción de olas, corrientes, mareas, agua impulsada por el viento, hielo transportado por el agua u otros impactos de marejadas ciclónicas.

Answer: yes

Explanation:

Un teléfono móvil o teléfono celular es un dispositivo portátil que puede hacer o recibir llamadas a través de una portadora de radiofrecuencia, mientras el usuario se está moviendo dentro de un área de servicio telefónco.​ El enlace de radiofrecuencia establece una conexión con los sistemas de conmutación de un operador de telefonía móvil, que proporciona acceso a la red telefónica pública conmutada (PSTN). La mayoría de los servicios de telefonía móvil modernos utilizan una arquitectura de red celular, y por lo tanto los teléfonos móviles son, con frecuencia, llamados celulares, especialmente en Hispanoamérica. En España, se utiliza más el término móvil.