Please help! Precalco

Answer:

  A = 2r²

Step-by-step explanation:

A square is a rhombus with equal-length diagonals. A square inscribed in a circle has diagonals equal to the diameter of the circle: 2r.

The area of a rhombus is half the product of the lengths of its diagonals. Hence the area of our square is ...

  A = (1/2)(2r)(2r)

  A = 2r²

Answer:

2

Step-by-step explanation:

r=1/2s[tex]\sqrt{2}[/tex]

2r=s[tex]\sqrt{2}[/tex]

2r/[tex]\sqrt{2}[/tex]=s remove [tex]\sqrt{2}[/tex] denominator by multiplying with [tex]\sqrt{2}[/tex]/[tex]\sqrt{2}[/tex]

2[tex]\sqrt{2}[/tex]r/2  -- simplify , 2 cancels

s=r[tex]\sqrt{2}[/tex]

so area = (r[tex]\sqrt{2}[/tex])^2

A(r)= 2r²

(6-i\sqrt(2))/(6+i\sqrt(2))

x - 7 < -20 inequalify

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Me ayudan a responder este asientos de contabilidad

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