Please Help!

5|x + 9| < 10

Please Help!5|x + 9| &lt; 10

Answers

Answer 1

Answer: -7, -11

Step-by-step explanation:

[tex]5|x+9| \leq 10\\\\|x+9| \leq 2\\\\-2 \leq x+9 \leq 2\\\\-11 \leq x \leq -7[/tex]

Answer 2

Answer:

x∈(−11,−7)

Step-by-step explanation:


Related Questions

The remainder when the expression x^3+6x^2+x+c is divided by x-2 is twice the remainder when the expression is divided by x-1.
show that c=24

Answers

Answer:

c = 18

Step-by-step explanation:

According to the remainder theorem, the remainder when f(x) is divided by (x - n) is f(n).

As per question we are given:

f(2) = 2f(1)

Substitute and solve for c:

2³ + 6*2² + 2 + c = 2(1³ + 6*1² + 1 + c)8 + 24 + 2 + c = 2(1 + 6 + 1 + c)34 + c = 2(8 + c)34 + c = 16 + 2c2c - c = 34 - 16c = 18

Note: I got a different value of c. This may be a result of a typo in the given expression. I provided a guide to solve such problems. Let me know is anything is unclear.

Find the slope of the line that passes through (1, 6) and (3, 7)

Answers

[tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{7 - 6}{3 - 1} \\ m = \frac{1}{2} [/tex]

I ALSO PROVIDED YOU WITH THE FORMULA OF FINDING THE GRADIENT/SLOPE FOR FUTURE USE

HOPE THIS HELPS.

Answer: Y= 1/2x + 5.5

i’ll mark brainliest!

Answers

1.  (a)The  vertex of the  function [tex]y=x^{2} +5x-7[/tex]  is [tex](-\frac{5}{2} ,-\frac{53}{4} )[/tex]

How is the vertex calculated?

In function [tex]y=x^{2} +5x-7[/tex],

a= 1 ,b= 5, c= -7

For a function   [tex]y=ax^{2} +bx+c[/tex]  , where (a≠0),

The vertex is [tex](-\frac{b}{2a} ,\frac{4ac-b^{2} }{4a} )[/tex]

[tex]x_v=-\frac{b}{2a}\\\\ =-\frac{5}{2*1} \\\\=-\frac{5}{2} \\\\\\y_v=\frac{4ac-b^{2} }{4a} \\\\=\frac{4*1*(-7)-(5^{2} )}{4*1}\\\\ =-\frac{53}{4}[/tex]

So, vertex  [tex](-\frac{5}{2} ,-\frac{53}{4} )[/tex] is minimum because a>0

(b)The solutions are [tex](\frac{\sqrt{53} -5}{2},0) (\frac{-5-\sqrt{53} }{2},0)[/tex]

How is the solution calculated?

When a function [tex]y=ax^{2} +bx+c =0[/tex]  where (a≠0),

[tex]x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a} \\\\x=\frac{-5\pm\sqrt{5^{2} -4(1)(-7)} }{2(1)} \\\\x=\frac{-5\pm\sqrt{53} }{2} \\\\x=\frac{\sqrt{53} -5}{2} , x=\frac{-5-\sqrt{53} }{2} \\\\\text{The solutions are } (\frac{\sqrt{53} -5}{2},0) (\frac{-5-\sqrt{53} }{2},0)[/tex]

2. (a)The  vertex of the  function [tex]y=-x^{2} +3x+8[/tex]  is [tex](\frac{3}{2} ,\frac{41}{4} )[/tex]

How is the vertex calculated?

In function [tex]y=-x^{2} +3x +8[/tex]

a= -1 ,b= 3, c= 8

For a function   [tex]y=ax^{2} +bx+c[/tex]  , where (a≠0),

The vertex is [tex](-\frac{b}{2a} ,\frac{4ac-b^{2} }{4a} )[/tex]

[tex]x_v=-\frac{b}{2a}\\\\ =-\frac{3}{2*(-1)} \\\\=\frac{3}{2} \\\\\\y_v=\frac{4ac-b^{2} }{4a} \\\\=\frac{4*(-1)*(8)-(3^{2} )}{4*(-1)}\\\\ =\frac{41}{4}[/tex]

So, vertex  [tex](\frac{3}{2} ,\frac{41}{4} )[/tex] is maximum because a<0

(b)The solutions are [tex](\frac{3+\sqrt{41} }{2},0) (\frac{3-\sqrt{41} }{2},0)[/tex]

How is the solution calculated?

When a function [tex]y=ax^{2} +bx+c =0[/tex]  where (a≠0),

[tex]x=\frac{-b\pm\sqrt{b^{2} -4ac} }{2a} \\\\x=\frac{-3\pm\sqrt{3^{2} -4(-1)(8)} }{2(-1)} \\\\x=\frac{-3\pm\sqrt{41} }{-2} \\\\x=\frac{3\pm\sqrt{41} }{2}\\\\x=\frac{3-\sqrt{41}}{2} , x=\frac{3+\sqrt{41} }{2} \\\\\text{The solutions are } (\frac{3+\sqrt{41} }{2},0) (\frac{3-\sqrt{41} }{2},0)[/tex]

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3. a person is watching the space shuttle launch. the person is 3000 ft from the launch pad. how fast is the distance between the person and the shuttle changing when the shuttle is 4,000 ft high and rising at a rate of 800 ft/sec?

Answers

The distance between the person and the shuttle is changing at a rate of 640 feet/sec when the shuttle is 4000 ft high and is rising at a rate of 800 ft/sec.

Considering x to be the height of the triangle and y to be the hypotenuse of the triangle, a right-angled triangle will be formed according to the given information having a base of 3000 feet which is the distance of the person from the launch pad.

In this right-angle triangle x will be the height of the shuttle and y will be the distance between the person and the shuttle.

Now we apply the Pythagorean theorem to the triangle;

y² = x²+(3000)²

Now differentiating this equation with respect to time,t :

2y (dy/dt) = 2x(dx/dt) + 0

dy/dt = x(dx/dt)/y

As the shuttle is rising at a speed of 800 ft/sec, (dx/dt)=800

Substitute 4000 for x into the equation, y²=x²+(3000)², to find y;

y² = (4000)²+(3000)²

y = 5000

Now we substitute 4000 for x, 5000 for y, and 800 for dx/dt in the equation, dy/dt = x(dx/dt)/y

dy/dt = 4000(800) / 5000

dy/dt = 640

Therefore, the distance between the person and the shuttle is increasing at a rate of 640 feet/sec.

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The next two problems show the attempts of two different students to provide a proof of the same statement. Each proof has something about it that is not quite correct. Explain how you would improve the argument.

Answers

We will improve the argument by stating that two intersecting lines have vertically opposite angles equal in magnitude.

We are given a diagram in which we have two lines, namely "m" and "n".The intersection point of the two lines is P.We need to prove that ∠1≅∠3.We know that line "m" is a straight line, so it makes a total angle of 180° on either of its sides.∠1+∠2 = 180°We know that line "n" is a straight line, so it makes a total angle of 180° on either of its sides.∠3+∠2 = 180°From the above two equations, we find that :∠1+∠2 = 180° = ∠3+∠2∠1+∠2 = ∠3+∠2∠1 = ∠3Thus, ∠1≅∠3.

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PLEASE HELP ASAP!!!!!!!

Answers

Rotate R and reflect 90

Step-by-step explanation:

Denasia and Kenya are training to run a half marathon. In the first week of training, Denasia runs 11 miles and Kenya runs 14 miles.
Each week, Denasia increases her weekly total by 2 miles, and Kenya increases her weekly total by 1.5 miles. Write and solve an
equation to find how many weeks after the first week of training Denasia and Kenya will be running the same number of miles.
A. 2w + 14 = 1.5w+11; w=-6 weeks
B. 2w + 11 = 1.5w+14; w=6 weeks
C. 11w+2= 14w +1.5; w=0, 167 weeks

Answers

Option B. 2w + 11 = 1.5w + 14, w = 6 weeks is the correct answer

Miles run by Denasia = 11 miles

Miles run by Kenya = 14 miles

Let w represent the number of weeks after which both Kenya and Denasia will be running the same number of miles

Formulating the equation we get:

Miles run by Denasia + Increase in miles each week*Number of weeks = Miles run by Kenya + Increase in miles each week*Number of weeks

11 + 2w = 14 + 1.5w

0.5w = 3

w = 6

Hence, option B is the correct answer according to the given contraints and both Denasia and Kenya will run the same distance in the 6th week

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Can someone please help me! I have no idea what I am doing and have no book to look from!

Answers

Answer:

Step-by-step explanation:

1) Find DGE

Bisecting an angle makes it half. A straight line is 180

180/2 = DGE

90 = DGE

2) Find FGE

Bisecting an angle makes it half. A straight line is 180

180/2 = FGE

90 =  FGE

So, angle DGF=180
Clearly since GB bisects this angle,
Angle DGE = angle FGE = x (say)
Then 2x = 180
=> x=90
Clearly both are right angles (90 each)

Which functions are equivalent to f (x) = RootIndex 4 StartRoot 162 EndRoot Superscript x? Check all that apply.

Answers

The functions that are equivalent are

f (x) = 162 Superscript StartFraction x Over 4f (x) = (3 RootIndex 4 StartRoot 2 EndRoot) Superscript xf (x) = left-bracket 3 (2 Superscript one-fourth Baseline) right-bracket Superscript x

What are roots of a number?

The root of a number is the inverse of the exponents. for instance

a squared has an inverse of square root of a.  

mathematically:

a^2 = (a)^1/2  has an inverse of √a

How to find the equivalents of the given data

The data given:

[tex]\sqrt[4]{162^{x} }[/tex]

Solving the given data for the equivalence

[tex]\sqrt[4]{162^{x} }=162^{x/4}[/tex]

The above proves option A correct

[tex]\sqrt[4]{(3*3*3*3*2)^{x} }[/tex]

[tex]\sqrt[4]{(3^{4} *2)^{x} }[/tex]

[tex](3\sqrt[4]{(2) })^{x}[/tex]

The above solution makes option B correct

[tex](3\sqrt[4]{(2) })^{x}=(3{(2)^{1/4} })^{x}[/tex]

The above proves Option D correct

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complete question

Which functions are equivalent to f (x) = RootIndex 4 StartRoot 162 EndRoot Superscript x? Check all that apply.

f (x) = 162 Superscript StartFraction x Over 4

f (x) = (3 RootIndex 4 StartRoot 2 EndRoot) Superscript x

f (x) = 9 RootIndex 4 StartRoot 2 EndRoot Superscript x

f (x) = 126 Superscript StartFraction 4 Over x

f (x) = left-bracket 3 (2 Superscript one-fourth Baseline) right-bracket Superscript x

42
X
40
Find the unknown side length, x. Write your answer in simplest radical form.
A. 241
B. 4 29
C. 48
D. 58

Answers

The unknown side length of the right triangle is 58 units.

What is pythagoras theorem for a right triangle?
In essence, the Pythagorean theorem is used to determine a triangle's angle and length of an unknown side. In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side. When the positive integer sides of a right triangle (let's say sides a, b, and c) are squared, the result is an equation known as a Pythagorean triple.
Mathematically, Hypotenuse² = Base² + Perpendicular²

Given, the length of the perpendicular of the right triangle = 42 units
Also, the length of the base of the right triangle = 40 units
Let the length of the hypotenuse of the right triangle = 'x' units
Following the statement of the pythagoras theorem as established in literature, we have: Hypotenuse² = Base² + Perpendicular²
Substituting the values from the question given, we get:
x² = 42² + 40² = 3364 ⇒ x = √3364 ⇒ x = √58² ⇒ x = 58
Therefore, the unknown side length of the right triangle is 58 units.

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4x + 10 =-26 solve for x

Answers

Answer:

x=-9

Step-by-step explanation:

To solve for x, isolate this equation from left to right.

4x+10=-26

First, subtract by 10 from both sides.

4x+10-10=-26-10

Solve.

-26-10=-36

4x=-36

Then, you divide by 4 from both sides.

4x/4=-36/4

Solve.

-36/4=-9

[tex]\Rightarrow \boxed{\sf{x=-9}}[/tex]

As a result, the solution is x=-9, which is the correct answer.

I hope this helps, let me know if you have any questions.

Answer:

-9

Step-by-step explanation:

First you subtract 10 from each side

4x + 10 = -26

-10 -10

then you divide by your x

4x = -36

4 4

the 4s cancel out leaving you with x only

x = -36/4

x = -9

work out the value of 6 2 plus 3 3

Answers

Answer:95

Step-by-step explanation:

This can simply be answered by adding the first digit of both numbers which would be 9 then add the secound number of both  numbers and that would be 5

The answer is 95

Answer:

if its 6^2 + 3^3 then its 63

Step-by-step explanation:

6^2 simplified is 36 and 3^3

6 x 6 = 36 + 27 = 63

                             

                                        3 x 3 x 3 =27

                                        3 x 3= 9

                               

                                        9 x 3= 27

14/3 = 7y solve for y and simplify your answer as much as possible

Answers

Answer:

2/3 = y

Step-by-step explanation:

to solve you got to cancel out the 7
so 7y/7.
whatever you do to one side, you do to the other.
14/3 ÷ 7 = 7y/7
14/3 ÷ 7 = 0.6666... = 2/3 = y

What percentage of the number 1 to 20 contain the digit 2????

Answers

So first the numbers that contain 2 is 2,12, and 20.
It’s out of 20 numbers so 3/20

The amount as a percentage is 15% which represents the number 1 to 20 containing the digit 2.

What is the percentage?

The percentage is defined as a ratio expressed as a fraction of 100.

We know that the numbers 1 to 20 that contain the digit 2 are 2,12, and 20.

So, the quantity of the numbers is 3

It’s out of 20 numbers, this means 3/20

Calculating percentages indicated above can be readily computed using the formula below:

Percentage = (Value/Total Value) × 100

The amount as a percent = (Value/Total Value) × 100

The amount as a percent = (3/20) × 100

The amount as a percent = 15%

Thus, the amount as a percentage is 15% which represents the number 1 to 20 containing the digit 2.

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Tanya sells cars. Her yearly salary is $35,000 plus 8% of her sales. Type and solve an inequality to determine her necessary sales to earn over $50,000.

Answers

Tanya yearly salary is

$35000 + 8% of her sales

Let her sales be x

Since, her sales is x

35000 + 0.08x > salary

To determine her necessary sales to earn over $50, 000

Let $50, 000 be her benchmark salary

35,000 + 0.08 * x > 50000

35000 + 0.08x > 50000

0.08x > 50000 - 350000

0.08x > 15000

Divide both sides by 0.08

0.08x/0.08 > 15000/0.08

x > 15000 / 0.08

x > 187,500

Therefore, she will need a sales of 188,000 and above to earn above $50,000

-7 -6 -5 -4 -3 -2 ONO MN ++ HA -6-5-4-3-2-1 + 11 2 3 4 5 6 7 8 9 -2 -3 F-4 -5 -6 -7 -A + jo voo Alcon ixth If this is the graph of f(-x) = a +k, then : A. 0 < a < 1 B. a < 0 O c. a> 1 O D. K> 1

Answers

The function is

[tex]f(x)=a^{(x+h)}+k[/tex]

The limit when x->+/- infinite are (analitically)

[tex]\begin{gathered} \lim _{x\to\infty}f(x)=a^{(\infty+h)}+k=a^{\infty}+k \\ \text{and} \\ \lim _{x\to-\infty}f(x)=a^{(-\infty+h)}+k=\frac{1}{a^{\infty}}+k \\ \end{gathered}[/tex]

And, from the figure,

[tex]\begin{gathered} \lim _{x\to\infty}f(x)=\infty \\ \text{and} \\ \lim _{x\to-\infty}f(x)=-4 \end{gathered}[/tex]

Therefore,

[tex]\begin{gathered} \Rightarrow a^{\infty}+k=\infty \\ \Rightarrow a>1 \\ \text{and} \\ \Rightarrow-4=\frac{1}{a^{\infty}}+k,a>1 \\ \Rightarrow-4=k \end{gathered}[/tex]

Therefore, the answer is option C, a>1.

3(5y-7)-2(9y-11)=4(8y-13)-17

Answers

Answer:[tex]3(5y - 7) - 2(9y - 11) = 4(8y - 13) - 17 \\➪ 15y - 21 - 18y + 22 = 32y - 52 - 17 \\ ➪15y - 18y - 32y = - 52 - 17 + 21 - 22\\➪-35y = - 70 \\➪35y = 70 \\ \: (cancel \: \: out \: "-" \: from \: both \: sides) \\ ➪y = \frac{ 70}{35} = 2 \\ \\ [/tex]

Tʜᴀɴᴋs| (• ◡•)|Hᴏᴘᴇ ɪᴛ ʜᴇʟᴘs

Which exponential equation is equivalent to this logarithmic equation? \log _(5)x - \log _(5)25=7

Answers

The exponential equation [tex]14=5^x[/tex] is equivalent to the  given logarithmic equation.

Which is the Exponential function?

The exponential function that is represented as y=[tex]m^x[/tex], where:

m=base, m>0

x= exponent

Logarithm Properties

Knowing some of the main logarithm rules.

Product Rule with the same base: you should repeat the base  add  the logarithms of the factors.

example: [tex]log(a*b)= log a + log b[/tex]

Quotient Rule:  you should subtract the logarithm of the numerator with the logarithm of the denominator.

example: [tex]log\frac{a}{b} = log a - log b[/tex]

 

Power Rule:  you should multiply the exponent by the logarithm of the base

example: [tex]log\frac{a^b} = b*log a[/tex]

For solving this question, you should apply the logarithm rules and  rewrite the function as an exponential equation.

[tex]log_5(x)}-{log_5(25)=7[/tex]

[tex]\frac{log_5(x)}{log_5(25)} =7[/tex]

[tex]{log_5(x)}=7{log_5(25)}[/tex]

[tex]{log_5(x)}=7{log_5(5^2)}[/tex]

[tex]{log_5(x)}=7*2[/tex]

[tex]{log_5(x)}=14[/tex]

[tex]x=5^{14^}[/tex]

Therefore, the  exponential function is [tex]14=5^x[/tex]

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Compare these two fractions: 3/10 and 4/5*03/10 > 4154/5>3/10О4/5 = 3/10

Answers

[tex]\begin{gathered} \text{Change the given fraction into decimal,so} \\ \frac{3}{10}\Rightarrow0.3 \\ \frac{4}{5}\Rightarrow0.8 \\ So,\text{ the }\frac{4}{5}>\frac{3}{10} \end{gathered}[/tex]

i'm still confused. helpppppppppppppppppppppppppppppppppppppppppppppppppppppp meeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

Answers

Answer:

I believe you forgot to add the attachment

Step-by-step explanation:

There is no math problem I can see to help you

Identify the factors of x2 − 5x − 24. (1 point) (x + 8)(x − 3) (x − 8)(x + 3) (x + 4)(x − 6) (x − 4)(x + 6)

Answers

Answer:

(x+3)(x–8)

Step-by-step explanation:

Normally you will always write factors in this form: (variable + smallest number)(variable – largest number)

Correct form: (x+2)(x–8)

Incorrect form: (x–2)(x+8)

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Learn with an example
or Watch a video D
Two cars leave the same parking lot, with one heading north and the other heading east.
After several minutes, the northbound car has traveled 3 kilometers, and the eastbound car
has traveled 4 kilometers. Measured in a straight line, how far apart are the two cars?
kilometers.

Answers

The two cars are 5 kilometers far apart from each other.

What is Pythagoras theorem?

The Pythagoras theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the square of the other two sides.

Given that;

Two cars leave the same parking lot, with one heading north and the other heading east.

After several minutes, the northbound car has traveled 3 kilometers, and the eastbound car has traveled 4 kilometers.

Now,

The straight path is find by using the Pythagoras theorem as;

Straight path = √3² + 4²

                    = √9 + 16

                    = √25

                    = 5 km

Therefore,

The two cars are 5 kilometers far apart from each other.

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0.194805194805...

Convert the decimal into a fraction.

Answers

Answer:

The fraction is 15/77

Step-by-step explanation:

The repeated part is 194805, six digits. Let the fraction be x.

Convert as follows:

1000000x - x = 194805.194805 ... - 0.194805 ... 999999x = 194805x = 194805/999999

Find prime factors of both numerator and denominator and simplify by cancelling common factors:

194805 = 3⁴*5*13*37,999999 = 3³*7*11*13*37.

The common factors are:

3³*13*37

When they cancel we are left with:

x = (3*5)/(7*11) x = 15/77

8.
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Please help
HELP PLEASE

Answers

Answer:

[tex]\begin{aligned}&\phantom{=.} \dfrac{1}{8}x \cdot \dfrac{-4}{5}x\\\\&=\dfrac{1}{2} \cdot \dfrac{\boxed{-1}}{5} \cdot x \cdot \boxed{x}\\\\& = \dfrac{\boxed{-1}}{\boxed{10}} \;x\;^\boxed{2}\end{aligned}[/tex]

Step-by-step explanation:

According to the Commutative Property Law of Multiplication, changing the order or position of the numbers does not change the end result.

Therefore, collect like terms by moving the fractions to the left and the variables to the right.

As the denominator of the first fraction has been divided by 4, the numerator of the second fraction should also be divided by 4.

Therefore:

[tex]=\dfrac{1}{2} \cdot \dfrac{\boxed{-1}}{5} \cdot x \cdot \boxed{x}\\[/tex]

[tex]\textsf{Apply\;the\;fraction\;rule} \quad \dfrac{a}{c}\cdot \dfrac{b}{d}=\dfrac{ab}{cd}.[/tex]

[tex]\textsf{Apply\;the\;exponent\;rule}\quad \:aa=a^2.[/tex]

Therefore:

[tex]=\dfrac{\boxed{-1}}{\boxed{10}} \;x\;\boxed{^2}[/tex]

Is this relation a function? Justify your answer. 10 9 8 7 5 3 2 1 1 2 3 4 5 6 7 8 9 10 11 A. Yes, because the number of x-values is the same as the number c y-values. B. No, because two points with the same x-value have different y- values. C. Yes, because every x- and y-value is positive. f se two points with the same vevalue have different x-​

Answers

The correct answer is option B that is No, because two points with the same x-value have different y values.

A relation in mathematics may be defined as the term which describes the relationship between the input and output variables. A function may be defined as the expression in which for one value of input variable x there is only one output variable y. The input variable is called independent variable and output variable is called dependent variable. From the graph given in question it can be seen that at point x = 2 there are two points on the y axis that are y = 2 and y = 11. So, this violates the basic definition of function as for input x there are two outputs y and hence it cannot be regarded as function.

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When going out for dinner, Sally left an 18% tip. The tip was 9.50. How much was the dinner bill before the tip?

Answers

The dinner bill of Sally before the tip is $53.

Given that, Sally left an 18% tip. The tip was 9.50.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the dinner bill of Sally be x.

Now, 18% of x = 9.50

⇒ 18/100 × x = 9.50

⇒ 0.18x = 9.50

⇒ x = 9.50/0.18

⇒ x = 52.77

≈ 53

Therefore, the dinner bill of Sally before the tip is $53.

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identify the paragraph proof for the two-column proof. Given: m∠d=125° and m∠r=125° Prove: ∠d≅∠r Two-Column Proof 1. m∠d=125° (Given) 2. m∠r=125° (Given) 3. m∠d=m∠r (Trans. Prop. of = ) 4. ∠d≅∠r (Def. of ≅∠s)

Answers

The two column proof is written as follows

Statement                                                    Reason

1. m ∠ d = 125°                                                 Given

2. m ∠ r = 125°                                                 Given  

3. m ∠ d = m ∠ r                                       Definition of equality

4. ∠ d ≅ ∠ r                                              Definition of congruent angles

What is two column proof?

This is a method of proof used in geometry. It helps to show how the required proof came to be possible. The major items in two column proof is:

StatementReason

what is equality?

The term equality as used in mathematics is defined to mean that the terms in comparison can be replace by the other

Using the given question as an instance:

m ∠ d = 125° and m ∠ r = 125°

This means that the two angles have same value and they can replace each other.

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At the beginning of spring, Anand planted a small sunflower in his
backyard. The sunflower's height in inches, h, after w weeks, is given by the equation h = 3.75w+18. What
could the number 3.75 represent in the equation?
Hint: this equation is in slope-intercept form: y=mx+b
The rate of change in the sunflower's height
The sunflower's height after one week
The sunflower's height when it is planted

Answers

Answer:

3.75 represents how much the flower grows every week.

Step-by-step explanation:

Which number is the smallest?
pls answer fast
Responses

A 4.68 x 10−44.68 x , 10 -4

B 5.48 x 10−85.48 x , 10 -8

C 2.85 x 10−62.85 x , 10 -6,

D 3.24 x 10−53.24 x , 10 -5,

E 1.28 x 10−4

Answers

The smallest number from the given options is

[tex]5.48 × {10}^{ - 8} [/tex]

The correct answer option is option d

How to find the smallest number?

A.

[tex]1.28 × {10}^{ - 4} [/tex]

= 1.28 × 0.0001

= 0.000128

B.

[tex]2.85 × {10}^{ - 6} [/tex]

= 2.85 × 0.000001

= 0.00000285

C.

[tex]3.24 × {10}^{ - 5} [/tex]

= 3.24 × 0.00001

= 0.0000324

D.

[tex]5.48 × {10}^{ - 8} [/tex]

= 5 48 × 0.00000001

= 0.0000000548

Therefore, the smallest number is

[tex]5.48 × {10}^{ - 8} [/tex]

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how many of these figures have atleast one vertex

Answers

Is there a picture involved?
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