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Hi there!

We can begin by converting "spinning once per second" to angular velocity:

[tex]\frac{1rev}{1s} * \frac{2\pi rad}{1rev} = 2\pi rad/sec[/tex]

(a)

As we are given the angular acceleration, we can calculate the time using the following equation:

ωf = ωi + αt

There is an initial angular velocity of 0 rad/sec, so:

ωf = αt

2π/1.2 = t

t = 5.236 sec

(b)

We can use the following rotational kinematic equation to first solve for the angular displacement:

θ = ωit + 1/2αt²

The initial velocity is 0 rad/sec, so plug in values:

θ = 1/2(1.2)(5.236²)

θ = 16.449 rad

Convert to linear distance using the following:

d = θr

d = 1.5m, so r = 1.5/2 = 0.75m

d = 16.449(0.75) = 12.337m

(c)

Find the amount of revolutions by converting radians to revolutions:

[tex]16.449 rad * \frac{1rev}{2\pi rad} = \large\boxed{2.618 rev}[/tex]

OR, 2.618 times.

Answer:

a) Gradient = rise/run = mass/volume

since the graph is mass against volume we know mass is on the y-axis and volume is on the x-axis

in physics it’s best to use a larger part of the graph to find the gradient, so imma use the biggest values.

90/4.5 = 20

(additional note: sometimes you may get a different gradient. For example, when using 30 and 1.4 you get ≈21 this is an anomalous result since ita gradient differs; a mass against volume graph is supposed to be linear)

b) gradient represents density (p) since gradient is = mass/volume. And density also = mass/volume

For c and d just plot the points and you’ll be able to read from the graph to get the values.

I got this graph (the image)

but you’ll be able to interpret better when ‘you’ draw it (so try plotting it)

Answer:

Explanation:

BMI= weight/(height × height)          ; weight in kilogram and height in metter

     = 58kg / (1.61m  × 1.61m )

     = (58/ 2.5921) kg/[tex]m^{2}[/tex]

     = 22.375  kg/[tex]m^{2}[/tex]

     ≈ 22.4 kg/[tex]m^{2}[/tex]

Hi there!

We know that:

Momentum (p) = mass (kg) × velocity (m/s)

Or:

P = mv

We can rearrange the equation to solve for speed:

P/m = v

Plug in the given values:

(3.75 × 10⁸)/75000 = 5000 m/s

The models of the universe allow finding the result for how serious the universe in the distant future is:

The Big Bang model shows that the universe was created at a certain point and time where from which all matter is separating at a speed from these objects.

Based on these models and the measurements that the galaxies are moving away, in the distant future the galaxies must be very far from each other so that the universe would be composed of isolated entities without the possibility of interaction between them.

Within each galaxy the bodies are not separated because in each one there is a black body whose gravity holds the stars within its galaxy together.

In conclusion of the models of the universe we can find the result for how serious the universe in the distant future is:

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The required torque at the axle, is given by the difference between the

moments of the applied forces.

The torque required is 19.62 N·m counterclockwise

Reasons:

The given parameters are;

Mass of the disk, m = 5.0 kg

Location of the axle = Half the radius of the disk

Diameter of the disk, D = 40 cm = 0.4 m

Applied mass, 0.1 m from the axle = 15 kg

Applied mass, 0.3 m from the axle = 10 kg

Required:

Magnitude of torque at the axle that prevent the disk from rotating

Solution:

Torque needed = Clockwise moment - Counterclockwise moment

Clockwise moment = (10 kg × 0.3 m + 5 kg × 0.1 m) × 9.81 m/s² = 34.335 N·m

Counterclockwise moment = 15 kg × 0.1 m  × 9.81 m/s² = 14.715 N·m

τ + Counterclockwise moment = Clockwise moment

τ + 14.715 N·m = 34.335 N·m

Torque required, τ = 34.335 N·m - 14.715 N·m = 19.62 N·m

Torque required, τ = 19.62 N·m counterclockwise

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The probable question drawing obtained from a similar question online is attached

The galaxy is known to contain stars of different ages. The indicated features as it points  from left to right are;

Bottom row

The Milky Way Milky exist because  our Sun (a star) and all the planets close to it are part of a galaxy called the Milky Way Galaxy.

A galaxy is known to be a large group of stars, gas, and dust bound together by the force of gravity.

Our galaxy is called by the name the Milky Way because it is usually seen or it appears as a milky band of light in the sky when you view it in a really dark area.

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Answer:

https://gml.noaa.gov/education/info_activities/pdfs/LA_radiation.pdf

Explanation:

Answer:

The variation of the wheel and axle is the pulley. In a pulley, a cord wraps around a wheel. It is a simple machine that is used to change the direction of the force. When the wheel rotates, the cord can move in either of the directions.

Explanation:

Answer: Varies

Explanation:

Because moving his legs require force.

Answer:

He is also a low-level telekinetic

Explanation:

He is a telepath and doesn’t have telekinesis btw.

Answer:

A. longer days and more direst sunlight

Explanation:

In the Northern Hemisphere, June 21 has longer days and more direct sunlight than December 21, so option A is correct.

Essentially, it alludes to a person's half-divisions. The Earth can be split up into many equal divisions. Latitudinal or longitudinal divisions may be used. Based on a hypothetical equator line, it can be either the northern or Southern Hemisphere, and based on the prime meridian, it can be either the eastern or western hemisphere. When viewed from a latitudinal perspective, the Northern and Southern Hemispheres are essentially hemispheres of the Earth.

The Northern Hemisphere is the region of the Earth that lies above the equator, which is an imaginary line. This hemisphere includes anything that is above this 0° line. It is the half of the planet that has the most people on the planet and more land than water.

The summer solstice falls on June 21 in the Northern Hemisphere and the winter solstice falls on June 21 in the Southern Hemisphere. The solstices are reversed around December 21 and winter officially starts in the Northern Hemisphere.

Therefore, in the Northern Hemisphere, June 21 has longer days and more direct sunlight than December 21.

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Answer:

Current

Explanation:

Answer:

Answer:

0.8 A

Explanation:

Given: Q = 240 C

t = 300 s

Required: I

Equation: I = Q / t

Solution: I = 240 C / 300 s

Answer: I = 0.8 A

Answer and Explanation: The geosphere interacts with the cryosphere when glaciers and sheets of ice from the cryosphere erode the rocks located on the geosphere. This happens as ice passes over the land and carries eroded rocks to new locations. The cryosphere can also cause soil to become icy and take hold of greenhouse gases from the atmosphere. The geosphere is the part of the Earth that has rocks, minerals, sand, and lava. The cryosphere has frozen water, ice, and glaciers. The cryosphere also interacts frequently with the hydrosphere because it draws water from the hydrosphere and freezes it during cold temperatures. Warmer temperatures cause the cryosphere to melt and release water back to the hydrosphere.

Answer:

It is defined as an astronomical phenomenon which occurs when one spatial object comes within the shadow of another spatial object.

The speed of light and the propagation of errors allows to find the results on the questions of the radiation emitted by the laser are:

    a) The frequency is: f = 3.7 10¹⁴ Hz

    b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

a) The speed of a wave is related to its wavelength and frequency.

           c = λ f

           [tex]f = \frac{c}{\lambda}[/tex]

Where c is the speed of light, λ the wavelength and f the frequency.

They indicate that the wavelength is λ = 800 nm = 800 10⁻⁹ m, the speed of light is a constant c = 2.99 10⁸ m/s.

         f = [tex]\frac{2.99 \ 10^8}{800 \ 10^{-9}}[/tex]  

         F = 3.7 10¹⁴ Hz

b) Planck's equation states that the energy is proportional to the frequency of the radiation.

         E = h f

Where E is the energy, h the Planck constant and f the frequency.

         E = 6.63 10⁻³⁴  3.7 10¹⁴

         E = 2.46467 10⁻¹⁹ J

The uncertainty or error is the fluctuation that a magnitude may have due to the precision in the measurements, when the magnitude is calculated by some formula, the propagation of these uncertainties must be carried out.

        Δm = ∑   [tex]\sum \frac{dm}{dx_i} | \Delta x_I|[/tex]  

the expression for energy is:

        E = [tex]\frac{hc}{\lambda }[/tex]  

        [tex]\Delta E = \frac{dE}{d \lambda} |D\lambda |[/tex]  

        [tex]\Delta E = \frac{h c }{\lambda^2 } |\Delta \lambda |[/tex]

When the error in the measured magnitude is not explicitly indicated, we assume that the error is in the last digit written, therefore

         Δλ = ± 1 nm = ± 1 10⁻⁹ m

We calculate.

        [tex]\Delta E = \frac{6.63 \ 10^{-34} \ 2.99 \ 10^8 }{(800 \ 10^{-9})^2} 1 \ 10^{-9}[/tex]  

        ΔE = 3.1 10⁻²² J

the error is given with a significant figure.

        ΔE = 3 10⁻²² J = 0.004 10⁻¹⁹ J

The result of the energy is:

        E = (2.465 ± 0.004) 10⁻¹⁹ J

In conclusion, using the speed of light and the propagation of errors, we can find the results on the questions of the radiation emitted by the laser are:

    a) The frequency is; f = 3.7 1014 Hz

    b) The energy with its uncertainty is: E = (2.465 ± 0.004) 10⁻¹⁹ J

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Answer: Relative to the bus, you are stationary. Relative to a point on the ground, you are walking forward with velocity  equal to the velocity of the bus.

As a person walks toward the back of a bus, they are walking towards a stationary object according to their own perspective. However, from an outside perspective, the bus is moving forward with a constant velocity and so relative to that point in motion, you are actually walking backwards with respect to it. This difference in motion means you would not be able have the same experience as the person on the bus when getting off because when you get off you would stop while they continue going forward. The last sentence could be considered a footnote because it only applies if this was an actual situation rather than just an analogy question in a physics test.

Relative to the bus, you move at walking speed. The motion relative to the ground is in the direction same as the bus and equal to the difference between the speed of the bus and walking speed.

When an object has a certain velocity, then this velocity is w.r.t. some frame that is called the reference frame. When we measure the velocity of an object, the ground or the earth is taken as the reference frame.

The motion of an object observed by the observer depends on the frame of the observer and this type of motion is known as relative motion.

For example, if you are traveling in a train and the train is moving at a speed of 80 km/hr, then your speed according to another passenger sitting on the same train is equal to zero.

Similarly, if you are walking toward the back of a bus, then your motion relative to the bus is walking speed. Relative to the ground, it is the difference between the speed of the bus and walking speed.

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Answer:

heat transfer? sorry if I'm wrong!

Answer:

the vertical velocity is constant.

Explanation:

The horizontal velocity of a projectile is constant (a never changing in value), There is a vertical acceleration caused by gravity; thus, the vertical velocity of a projectile changes. and the horizontal motion of a projectile is independent of its vertical motion.

Answer:

Explanation:

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass in kg

v is the velocity of the object in m/s

From the question

m = 100 kg

v = 10 m/s

We have

[tex]k = \frac{1}{2} \times 100 \times {10}^{2} \\ = 50 \times 100 \\ = 5000 \: \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer:Work is a measurement of energy.

Power is a measurement of energy per time.

So, power measures how fast work is done.

If we raise 1kg up to a height of 1 meter it takes a certain amount of work. It doesn't matter if it takes us 1 second or 1 hour to raise it. It takes more power, energy per second, to raise it in 1 second than to raise it in one hour.

An engines power rating is in horsepower. A higher horsepower car engine will get a certain car up a hill more quickly than if it had a lower horsepower engine. Even though both engines did the same amount of work in getting the car up the hill

Answer:

work is a measurement of energy, but power is how much energy it takes. Two people could do the same amount of work. Sally and James. James may finish his work in 2 days due to the amount of power he puts in, but it may take Sally a week.

Answer:

having a secure firewall

Explanation:

A firewall validates access by assessing this incoming traffic for any price malicious like hackers and malware that would infect your computer.

Answer:

C

Explanation:

fuses of same kind can be used for different things, and of different kinds could be used for different things as well.

Answer:

5.66 m/s

Explanation:

p=mv

255 = 45v

v = 255/45

v = 5.66 m/s

If you want to verify your answer, just insert your value to the equation.

Hi there!

(A) The force that the ball exerts on Earth is equal in magnitude to the force that Earth exerts on the ball.

Gravitational force is an example of an action-reaction pair:

[tex]F_{1,2} = -F_{2,1}[/tex]

Gravitational force is given by the equation:

[tex]F_g = \frac{Gm_1m_2}{r^2}[/tex]

Plugging in the masses of the Earth and ball, gravitational constant, and radius will result in the SAME GRAVITATIONAL FORCE exerted by both objects on each other.

Answer:

6 newtons

Explanation:

If it's an equal force exerted on the student's hands, the object will not move.

If a student pushes on an object with a force of 6 newtons and the object does not move then the force exerted by the object on the student’s hands would be 6 Newtons because the applied force is equal to the static frictional force until the object does not move.

Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact

As given in the problem If a student pushes on an object with a force of 6 newtons and the object does not move then we have to find out the force exerted by the object on the student’s hands,

Force applied by the student of the object = 6 Newtons

The force exerted by the object on the student's hand = 6 Newtons

Thus, the force exerted by the object on the student’s hands would be 6 Newtons

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