Answer:
For Ryan:
[tex]at \: highest \: point : v = 0 \\ velocity = 0 \: {ms}^{ - 1} [/tex]
For the football kicked:
[tex]s = ut - \frac{1}{2} g {t}^{2} \\ for \: range : s = 0 \\ u \sin( \theta) = \frac{gt}{2} \\ t = \frac{2u \sin(\theta) }{g} \\ range(x) = ut \\ x = \frac{ {2u {}^{2} \sin(\theta) }^{} }{g} \\ \frac{50 \times 9.8}{ {2318.9}^{} } = \sin(\theta) \\ \\but \: 0 = u \sin(25) - 2 \times 9.8 \times 50 \\ u = 2318.9 \: {ms}^{ - 1} \\ \theta = 12.2 \degree[/tex]
Answer:
the highest point for the first question is 0 meters per second
the answer for question 2 is 45 degrees
3) A bird flies toward a tree limb at a 45-degree angle to the ground along a path that is 50 m long landing on the limb. Determine, in m, how high above the ground the bird is perched.
Answer:
35 m
Explanation:
Given :
The distance of the path from the ground to the tree limb = 50 m
The angle between the path of flight of the bird towards the tree limb and the ground = 45 degrees
Therefore we can determine the height above which the bird perched above the ground by using the rules of the trigonometric ratios as;
We know that ,
[tex]$\sin 45^\circ =\frac{\text{perpendicular}}{\text{hypothenus}}$[/tex]
[tex]$\sin 45^\circ =\frac{\text{BC}}{\text{AC}}$[/tex]
[tex]$0.7 =\frac{\text{BC}}{\text{50}}$[/tex]
[tex]\text{BC }= 0.7 \times 50[/tex]
= 35
Therefore, the bird perched on the tree limb at a height of 35 m.
If two students push a box with a force of 3N in the same direction, and there is no other unbalanced force on the box, what is the magnitude of the net force on the box? *
0N
3N
6N
9N
Answer:
SILEM B
Explanation:
ERILAQNQJJQKIQKQJNDJKIDJKS
A 1,000 kg car is travelling at 6.5 m/s to the North. A 3,500 kg truck is travelling South at the same velocity. What is the total momentum of the two vehicles (don’t forget to assign a NEGATIVE velocity to one of the vehicles, because they are travelling in opposite directions
please help asap
Answer:
Total momentum of both is 16250 kgm/s
A 15.0 kg crate, initially at rest, slides down a ramp 2.0 m long and inclined at an angle of 20.0° with the horizontal. Using the work-kinetic energy theorem and disregarding friction, find the
velocity of the crate at the bottom of the ramp. (g = 9.81 m/s?)
The component of the crate's weight that is parallel to the ramp is the only force that acts in the direction of the crate's displacement. This component has a magnitude of
F = mg sin(20.0°) = (15.0 kg) (9.81 m/s^2) sin(20.0°) ≈ 50.3 N
Then the work done by this force on the crate as it slides down the ramp is
W = F d = (50.3 N) (2.0 m) ≈ 101 J
The work-energy theorem says that the total work done on the crate is equal to the change in its kinetic energy. Since it starts at rest, its initial kinetic energy is 0, so
W = K = 1/2 mv ^2
Solve for v :
v = √(2W/m) = √(2 (101 J) / (2.0 m)) ≈ 10.0 m/s
Determine the force exerted by two particles that have a charge of +0.35 Coulombs each and are 1 meter apart
The electric force between two charges is:
F = (9 x 10⁹) Q₁ Q₂ / D²
F is the force, in Newtons
Q₁ and Q₂ are the two charges, in Coulombs
D is the distance between them, in meters
For these two particles:
F = (9 x 10⁹) (0.35) (0.35) / (1)²
F = (9 x 0.35 x 0.35 x 10⁹) / (1)
F = 1.10 x 10⁹ Newtons
Thatsa lotta force . . . like 124 thousand tons !
The reason it's so big is because the charges in this question are so big ... 0.35 Coulombs each. 1 Coulomb is a huge amount of charge.
Each of the particles feels the same force, pushing it away from the other particle. (The electric force between two charges is always the same in both directions, just like the gravitational force between two masses.)
Acc. to columb's law;
F = k × Q1Q2/r²Clearly, from the question you have:
Charge on both particles = +0.35 columbsDistance between them = 1 meter = 1 × 10-¹⁰ ÅNow just put them up in the formula:
F = k × Q1Q2/r²
F = 9 × 10⁹ × 0.35 × 0.35/1 × 10-¹⁰
F = 9 × 10⁹ × 35 × 35/ 10-¹⁰ × 100 × 100
F = 9 × 10⁹ × 35 × 35/ 10-¹⁰ × 10⁴
F = 9 × 10⁹ × 35 × 35/ 10-⁶
F = 9 × 10⁹+⁶ × 1225
F = 11025 × 10¹⁵
Which statement best describes science?
Answer:
Science is a collection of knowledge about the natural world, but it is also the process of discovering how the natural world works. It is supported by evidence.
Answer: The correct answer is C). Science is a collection of knowledge about the natural world, but it is also the process of discovering how the natural world works.
Explanation:
Una grúa está subiendo una caja de 1000 kg atada a una cadena. La caja, que inicialmente está en reposo, incrementa su velocidad 4 m/s cada segundo
Answer:
40 metros en 10 segundos.
Explicación:
Una grúa está levantando una caja de 1000 kg atada a una cadena y la caja, que inicialmente está en reposo, aumenta su velocidad en 4 m / s por segundo, por lo que si la región de colocación está a 40 metros de distancia, la grúa tarda 10 segundos en completar el proceso. tarea de movimiento y colocación de la caja. La grúa se utiliza para levantar y mover cargas pesadas, máquinas, materiales y mercancías para diferentes propósitos. Entonces el trabajo realizado por la grúa depende de la velocidad y la distancia de colocación.
PLEASE HELP WITH THIS QUESTION
What is one benefit of a seatbelt?
A. It decreases the passenger's inertia. B. It allows you to share the same motion as the vehicle
C. It makes you fly out of the car when stopping.
D. It prevents gravity from affecting the passenger
Answer:
D
Explanation:
why is so you don't go flying out of the car
46. Nuclear generating plants use the potential
energy stored in
to generate electrical
energy. (12.5)
Answer:
nuclear battery to generate energy
A small hole is made at the bottom of a plastic cup. If it is filled with water and allowed to fall freely, will waterfall down from the hole?
Answer:
It depends on how big the hole is.
Explanation:
If the hole is too big, the water will fall freely out of the cup. However, if it is just a small opening (from a needle, pencil/pen tip, etc.) the water pressure will be able to hold in the water.
A 27 kg disk with a radius of 1.3m is spinning at an angular speed of 15 rad/s. What is the rotational kinetic energy of the disk?
Answer:
the rotational kinetic energy of the disk is 5,133.375 J
Explanation:
Given;
mass of the disk, m = 27 kg
radius of the disk, r = 1.3 m
angular speed, ω = 15 rad/s
The rotational kinetic energy of the disk is calculated as;
[tex]K.E_{rot} = \frac{1}{2}I \omega^2\\\\ where;\\I \ is \ moment \ of \ inertia\\\\K.E_{rot} = \frac{1}{2} \times (mr^2) \times \omega ^2\\\\ K.E_{rot} = \frac{1}{2} \times (27\times 1.3^2) \times \ 15^2\\\\K.E_{rot} = 5,133.375 \ J[/tex]
Therefore, the rotational kinetic energy of the disk is 5,133.375 J
How long does it take you to create 200 Watts of power if you use 1000 J of
work?
Answer:200,000
Explanation:
p=w/t
200=1000/t
t=200*1000
time=200,000
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What are the chemicals that react with one another in a chemical reaction?
Answer:
reactants react with eachother
Explanation:
yep
What is the amount of change in an object's momentum equal to?
A.
The amount of mass applied to the object over a certain amount of time
B.
The amount of force applied to the object over a certain amount of time
C.
The amount of acceleration applied to the object over a certain amount of time
D.
The amount of energy applied to the object over a certain amount of time
answer:
Explanation:
the impulse-momentum theorem states that the change in momentum of an object equals the impulse applied to it. The impulse-momentum theorem is logically equivalent to Newton's second law of motion (the force law).
According to the impulse-momentum theorem, the amount of change in an object's momentum equal to the amount of force applied to the object over a certain amount of time. So, option B.
According to the impulse-momentum theorem, the impulse that is applied to an item is equal to the change in momentum.
It shows how an object's change in momentum depends on both the strength and duration of the applied forces.
Impulse is defined as the force acting for a short interval of time.
Impulse = F x t
The momentum of the object,
P = mv
So, the rate of change of momentum,
dP/dt = d(mv)/dt
dP/dt = mdv/t
dP/dt = ma = Force
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A force of 120N acts on 200g of an object. Calculate the acceleration of the object
Answer:
Explanation:
This is very straightforward, except that we need the mass in kg and it's in g. So we have to convert first, using the fact that there are 1000g in 1 kg:
[tex]200g*\frac{1kg}{1000g}=.200kg[/tex] and now we're ready to solve your problem.
F = ma and
120 = .200a so
a = 6.0 × 10² (which is 600 m/s/s)
Some people can roll the tongue into a tube shape, while others cannot. Practicing is not likely to help because tongue-rolling is an inherited trait. The allele for rolling the tongue (R) is dominant to the allele for not being able to roll the tongue (r). Look at the Punnett square. It shows a cross between two parents with at least one R allele. Drag each option to its spot to correctly finish the Punnett square.
Hope this helps you.
A 75kg hockey player is skating across the ice at a speed of 6.0m/s. What is the magnitude of the average force required to stop the player in 0.65s?
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
A block slides down a smooth inclined surface and the gap between the block and the surface contains viscous fluid. Assume the velocity distribution in the gap is linear, and the area of the block in contact with the vicious fluid remains constant. If you increase the inclined angle, the terminal velocity will Group of answer choices
Answer:
The velocity increases as the inclination increases.
Explanation:
hen a block moves downwards along the inclined plane, the viscous property of the fluid between the block and the inclined acts and thus there is a friction between the block and surface.
When gravitational force acting along the plane provides the acceleration of the block.
When the angle of inclination increases, the acceleration along the plane increases and thus the velocity increases.
Many scientific discoveries are made by chance. While studying one phenomenon, a scientist may discover a different one. Such was the case when William Herschel discovered the planet Uranus in 1781. Herschel was charting faint stars in the sky, when he discovered something that was not a star. How can astronomers tell the difference between a star and a planet
Answer:
One simple explanation is that planets move, while stars remained fixed in the sky. You can observe a planet's orbit, but a star will stay in the same position.
Explanation:
Stars emit their own light due to thermonuclear fusion while planets have fixed orbits and they do not have their own light.
What are the differences between a planet and a star?A star can be described as an astronomical body that possesses a light that causes it to reflect the light. A planet can be described as a fixed celestial body with a fixed path that spins on its own axis and reflects the light from an external source. Planets do not have an internal light source and receive light from external sources such as the Sun.
Stars have incredibly hot high temperatures while planets have relatively low temperatures. Stars produce their own light but planets are incapable of producing their own light.
Stars exhibit the unique effect of twinkling in the sky while planets do not exhibit the twinkling effect. The position of stars changes but can be seen only after a long time while planets in orbits change their positions constantly.
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what is electricity?write any two defects of a simple cell.
Answer:
Electricity is the set of physical phenomena associated with the presence and motion of matter that has a property of electric charge. Electricity is related to magnetism, both being part of the phenomenon of electromagnetism, as described by Maxwell's equations.
A 14300 kg airplane is flying at an altitude of 147 m at a speed of 214 m/s. determine the airplane's total mechanical energy.
Answer:
Mechanical energy in Joules:
348,041,980
The total mechanical energy of the airplane is equal to 348,041,980 Joules.
Given the following data:
Mass = 14300 kgHeight = 147 meters.Velocity = 214 m/s.Scientific data:
Acceleration due to gravity on Earth = 9.8 [tex]m/s^2[/tex]To calculate the total mechanical energy of the airplane:
How to calculate total mechanical energy.The total mechanical energy possessed by this airplane is equal to the sum of both the potential energy and kinetic energy at the given altitude.
Mathematically, the total mechanical energy is given by this formula:
[tex]E = \frac{1}{2}mv^2 + mgh[/tex]
Substituting the given parameters into the formula, we have;
[tex]E = \frac{1}{2}\times 14300 \times 214^2 + 14300 \times 9.8 \times 147\\\\E=7150 \times 45796 + 20600580\\\\E= 327441400 + 20600580[/tex]
E = 348,041,980 Joules.
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Types of energy transformation
Answer:
This is the types of energy transformation
Explanation:
hope it helps
Sandy wants to know whether an item dropped into a fluid will sink or float. What is true for any item that floats?
A.
The force of gravity is equal to the force of mass.
B.
The force of gravity is stronger than the buoyant force.
C.
The buoyant force is stronger than the force of gravity.
D.
The object has no density.
Answer:
A, I think but I'm sureExplanation:
ur welcomeee ♥️♥️
Answer: C.
The buoyant force is stronger than the force of gravity.
Explanation:because I did it
Accuracy of physical balance is dash
Answer:
the answer for this is my.
A car lows down at -5.00m/s^2 until it comes to a stop after traveling 15.0m. How much time did it take to stop
Answer:time taken is 6 seconds
Explanation:
Answer: 2.45 seconds
Explanation: Acceleration a = -5, distance s = 15, time = ?.
Final velocity = v = 0.
We need to use the equations of motion under constant acceleration.
v^2 = u^2 + 2as where u is the initial velocity
0 = u^2 + 2*-5*15
u^2 = 150
so u = √150
Now we use v = u + at:
0 = √150 - 5t
t = √150/5
t = 2.45 seconds.
what should be done to make simple machine more efficient
Answer:
Friction is the main factor which reduces the efficiency of a simple machine. Efficiency of a simple machine can be increased by reducing the friction. But oiling and greasing the machine is a useful way to increase the efficiency of a machine.
Explanation:
Because all machines lose input work to friction, one way to improve the efficiency of a machine is by reducing friction. Oil is used to reduce friction between the moving parts of car engines. The use of oil makes engines more efficient. Another machine that loses input work is a bicycle.
Un campo eléctrico es creado por una carga eléctrica de 5 microcoulomb, a 35 cm se coloca una carga de prueba la cual es atraída por una fuerza de 1,5 N. Determinar:
Answer:
Supongo que queremos determinar la carga de la carga de prueba.
Sabemos que la fuerza culombiana entre dos cargas q₁ y q₂, separadas por una distancia R, está dada por:
[tex]F = k_c*\frac{|q_1*q_2|}{R^2}[/tex]
Aislandolo para una de las cargas, obtenemos:
[tex]\frac{F*R^2}{kc*|q_1|} =|q_2|[/tex]
En este caso sabemos:
fuerza atractiva, por lo que los signos de las cargas son opuestos.
q₁ = 5 mC
R = 35cm
F = 1.5 N
Kc = 9*10^9 N*m^2/C^2
Un primer paso, seria reescribir todos los valores en las mismas unidades.
Sabiendo que:
100cm = 1m
R = 35cm = (35/100) m = 0.35m
Y sabiendo que:
1mc = 1*10^(-6) C
Entonces:
q₁ = 5 mC = 5*1*10^(-6) C = 5*10^(-6) C
Ahora podemos reemplazar esos valores en la ecuación de la fuerza, para obtener el valor de la otra carga:
[tex]\frac{15N*(0.35m)^2}{(9*10^9 N*m^2/C^2)*5*10^{-6}C} =|q_2| = 4.08*10^{-5} C[/tex]
Y recordar que las cargas tienen signo opuesto, entonces la carga de la carga de prueba es:
q₂ = -4.08*10^-5 C
Myra kicked the stone with an initial speed of 8.15 m/s at an angle of 30° above the horizontal.
a. Determine the horizontal and vertical components of the velocity of the projectile.
b. How far has the object traveled in 2.1 s?
c. How high has the object reached in 2.1 s?
Grade 9 Science (Serious Answers Please)
Answer:Its B
Explanation:Trust Me i done This Before
Your friends sit in a sled in the snow. If you apply a force of 95N to them they have an acceleration of 0.8 m/s2. What is their mass