PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answer:

x=2

Step-by-step explanation:

The axis of symmetry goes through the vertex and is the line that makes the image the same on one side as the other

Since this is a vertical parabola, the axis is symmetry is  of the form x=

The vertex is at x=2  so the axis of symmetry is x=2

The solution to the equation (log510 - log52) (log61296) = log₂(x - 5)² is x = 9. To solve the given equation, let's break it down step by step.

First, we simplify the left side of the equation using logarithmic properties. Using the property log(a) - log(b) = log(a/b), we can rewrite (log510 - log52) as log5(10/2), which simplifies to log5(5) or 1.

Next, we simplify the right side of the equation. Using the property logₐ(b²) = 2logₐ(b), we can rewrite log₂(x - 5)² as 2log₂(x - 5).

Now our equation becomes 1 * log61296 = 2log₂(x - 5).

Since log61296 is the logarithm base 6 of 1296, which is 4, we can simplify the equation further to 4 = 2log₂(x - 5).

Dividing both sides by 2, we have 2 = log₂(x - 5).

Now we can rewrite this equation in exponential form: 2² = x - 5.

Simplifying, we get 4 = x - 5.

Adding 5 to both sides, we find x = 9.

Therefore, the solution to the equation (log510 - log52) (log61296) = log₂(x - 5)² is x = 9.

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Answer:

A. Third period

Step-by-step explanation:

- hope this helped!

Answer:

3rd

Step-by-step explanation:

(a) All the elements of S are : S = {RR, RB, BR, BB},

(b) Elements in event A are {RB and BR},

(c) The probability of "event-A", which is the person drawing one "red-ball" and one "black-ball", is 1/2.

Part (a) : The "sample-space" (S) consists of all possible outcomes when drawing two balls with replacement. In this case, there are four possible outcomes : S = {RR, RB, BR, BB},

Part (b) : The "event-A" represents the person drawing one red-ball and one black-ball. The elements in event A are {RB and BR},

Part (c) : To calculate the probability P(A), we need to determine the ratio of favorable outcomes (elements in A) to the total number of possible outcomes (elements in S).

P(A) can be written as : (Number of favorable outcomes)/(Total number of possible outcomes),

Substituting the values from part(a) and part(b),

We get,

P(A) = 2/4

P(A) = 1/2

Therefore, the required probability is 1/2.

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Answer:

An impossible event has a probability of 0. A certain event has a probability of 1.

The given trigonometric equation is sin x + 2 = 0.

It is important to note that sine values range from -1 to 1 and never exceed those bounds. Thus, it can be determined that sin x + 2 will never equal zero.This is because the lowest possible value of sine is -1, which is not equal to zero. When 2 is added to that value, the sum is still negative. Therefore, the equation sin x + 2 = 0 has no solutions.

A trigonometric equation is one that has a variable and a trigonometric function. For instance, sin x + 2 = 1 is an illustration of a mathematical condition. The equations can be as straightforward as this or more complicated than that, such as sin2 x – 2 cos x – 2 = 0.

The six mathematical capabilities are sine, secant, cosine, cosecant, digression, and cotangent. The trigonometric functions and identities are derived by referencing a right-angled triangle as a reference: Sin is the opposite side or the hypotenuse.

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Answer:

960

Step-by-step explanation:

it says use 3 for pi, so you plug the values into given equation

V = 3·(4)²·20

r is 4 because it is half of 8.

Then multiply

3·16·20 = 48·20 = 960

Answer:

960 cm

Step-by-step explanation:

8/2 = 4 (radius)

3 (since we're using 3 for pi) * 4^2 * 20

3 * 16 * 20

48 * 20

= 960 cm

I hope this helps heh :)

The values of N and p that define the random graph ensemble G(N, p) with an average degree (k) of 40 and a variance of the degree distribution (σ²) of 50 are N = 201 and p = 0.2.

The values of N and p that define a random graph ensemble G(N, p) with an average degree (k) of 40 and a variance of the degree distribution (σ²) of 50, we can use the following formulas:

k = (N-1) × p

σ² = (N-1) × p × (1-p)

Plugging in the given values:

k = 40

σ² = 50

We can solve these equations to find the values of N and p:

From the first equation:

40 = (N-1) × p

From the second equation:

50 = (N-1) × p × (1-p)

By substituting the value of (N-1) × p from the first equation into the second equation, we can solve for p.

40 = 50 × (1-p)

1-p = 40/50

1-p = 0.8

p = 1 - 0.8

p = 0.2

Now, we can substitute the value of p back into the first equation to solve for N:

40 = (N-1) × 0.2

200 = N-1

N = 200 + 1

N = 201

Therefore, the correct values of N and p that define the random graph ensemble G(N, p) with an average degree (k) of 40 and a variance of the degree distribution (σ²) of 50 are N = 201 and p = 0.2.

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The 99.9% confidence interval for a sample of size 176 with 118 successes is (0.558, 0.778).

The formula for finding the confidence interval for a sample proportion is given as follows:

Confidence interval = sample proportion ± zα/2 * √(sample proportion * (1 - sample proportion) / n)

Where,

zα/2 is the z-value for the level of confidence α/2,
n is the sample size,
sample proportion = successes / n

Here, level of confidence, α = 99.9%, so α/2 = 0.4995. The value of zα/2 for 0.4995 can be found from the z-table or calculator and it comes out to be 3.291.

Putting all the values in the formula, we get:

Confidence interval = 0.670 ± 3.291 * √(0.670 * 0.330 / 176)

                   = (0.558, 0.778) (rounded to three decimal places and put in parentheses)

Thus, the 99.9% confidence interval for a sample of size 176 with 118 successes is (0.558, 0.778).

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Given the expression |x - 4|, condition on |x - 4| that will assure that:(a)|x - 2| < 2/1(b)|x - 2| < 0.01

Given expression |x - 4|, the two possible values are: x - 4 if x > 4 -(x - 4) if x < 4Let us solve each part of the question separately:

(a)Part (a) can be expressed as follows:|x - 2| < 2/1Subtracting 2 from both sides of the in equality |x - 2| - 2 < 0Adding 4 to both sides of the inequality. |x - 2| - 2 + 4 < 0|x - 2| - 2 + 4 = |x - 4| < 0Since it is impossible to have an absolute value less than 0, therefore there is no solution.

(b)Part (b) can be expressed as follows:|x - 2| < 0.01 Subtracting 2 from both sides of the inequality |x - 2| - 2 < -0.01Adding 4 to both sides of the inequality. |x - 2| - 2 + 4 < -0.01|x - 2| - 2 + 4 = |x - 4| < -0.01Since it is impossible to have an absolute value less than 0, therefore there is no solution.

Thus, there are no solutions for the given conditions.

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In multilevel signaling over an Additive White Gaussian Noise (AWGN) channel, the received signal can be represented as:

Y = X + N

where Y is the received signal, X is the transmitted signal, and N is the AWGN with zero mean and variance σ^2.

In this case, M = 4, which means we have 4 symbols: -2v, -v, +2v, +v. The pulse values assigned to these symbols are: -2v, -v, +2v, +v.

To find the optimum threshold values, we need to consider the decision regions between adjacent symbols. Let's denote the threshold values as T1, T2, and T3, corresponding to the decision boundaries between -2v and -v, -v and +2v, and +2v and +v, respectively.

For correct transmission of the symbol -2v, the received signal Y should be greater than T1 and less than or equal to T2. Mathematically, this can be expressed as:

T1 < Y ≤ T2

The probability of correct transmission for the symbol -2v can be obtained by integrating the probability density function (PDF) of the received signal Y over the region T1 < Y ≤ T2.

Now, let's find the expression for the total probability of error. The total probability of error (P_e) can be obtained by summing the probabilities of error for each symbol. In this case, we have four symbols, so the expression for P_e is:

[tex]P_e = P_error(-2v) + P_error(-v) + P_error(+2v) + P_error(+v)[/tex]

where P_error(-2v) is the probability of error for symbol -2v, P_error(-v) is the probability of error for symbol -v, and so on.

Finally, to evaluate the total probability of error when σ^2 = 0.40 and v = 0, we need more information. Specifically, we need the signal-to-noise ratio (SNR) or the value of σ^2 in order to proceed with the calculation.

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The probability that the girls would randomly choose their two favorite movies to watch is 0.0034.

The number of favorable outcomes is 2 (since Rhonda has two favorite movies).

Using the combination formula:

C(n, r) = n! / (r! * (n - r)!)

In this case, n = 35 (total number of movies) and r = 2 (number of movies to be chosen).

C(35, 2) = 35! / (2! x (35 - 2)!)

C(35, 2) = 35! / (2! x 33!)

= (35 x 34 x 33!) / (2! x 33!)

= (35 x 34) / 2

= 595

Therefore, there are 595 possible outcomes when choosing any two movies from Laura's collection.

Now, Probability = Favorable Outcomes / Total Outcomes

Probability = 2 / 595

Therefore, the probability that the girls would randomly choose their two favorite movies to watch is 0.0034.

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Answer:

36 cubic feet

Step-by-step explanation:

Answer:

To find volume use the solution of l x w x h

Length x Width x Height

Step-by-step explanation:

16. 2 x 3 x 6 = 36 cubic feet

???. 5/8 x 3/4 x 2  = 15/16

???. 2 x 1 1/4 x 1 1/2 = 3 3/4 cubic inches

25.

1 = 4.89 / 3 = 1.63

3 = $4.89

9 = 4.89 + 4.89 + 4.89 = 14.67

10 = 14.67 + 1.63 = $16.30

???. Interquartile Range = Q3 - Q1

65 - 62 = 3

If i remember correctly

The alternate form of the polar decomposition of `A` is given by `A = PW`, where `W` is a positive semidefinite Hermitian matrix and `P` is a positive semidefinite Hermitian matrix.

Let `A` be a square matrix. Prove an alternate form of the polar decomposition for `A`.For a given square matrix `A`, the polar decomposition of `A` is a factorization of `A` into the product of a unitary matrix `U` and a positive semi-definite Hermitian matrix `P`. This polar decomposition of `A` can be given by `A = UP` or `A = PU*`, where `U` is the unitary matrix and `P` is a positive semidefinite matrix such that `P = (AA*)^(1/2)` or `P = (A*A)^(1/2)`.

The alternate form of the polar decomposition of `A` is given by `A = PW`, where `W = P^(1/2)U P^(1/2)` and `P` is a positive semidefinite matrix.Let `A = UP` be the polar decomposition of `A`, where `U` is unitary and `P` is positive semi-definite Hermitian. Then `P = A(A*)^(1/2)` and `U = P^(-1)A`. Let `W = P^(1/2)U P^(1/2)` and `W* = P^(1/2)U* P^(1/2)`. Since `U` is unitary, we have `U* = U^(-1)`. Hence `W* = P^(1/2)U^(-1) P^(1/2)`.Multiplying `UP` by `P^(1/2)`, we get `UP^(1/2) = P^(1/2)U P`. Multiplying both sides of the equation by `P^(1/2)` on the right, we get `UP^(1/2)P^(1/2) = P^(1/2)U P P^(1/2)` or `UP = P^(1/2)U P^(1/2)P^(1/2)` or `UP = P^(1/2)U P^(1/2)` or `U = P^(-1/2)W P^(1/2)`.

Substituting the value of `U` in `A = UP`, we get `A = P^(-1/2)W P^(1/2)P`. Since `P` is positive semi-definite, `P = (P^(1/2))^2` is a Hermitian matrix. Therefore, `W = P^(1/2)U P^(1/2)` is a Hermitian matrix and is positive semi-definite. Thus, we have `A = PW` where `W = P^(1/2)U P^(1/2)` is a positive semidefinite Hermitian matrix. Hence, the alternate form of the polar decomposition of `A` is given by `A = PW`, where `W` is a positive semidefinite Hermitian matrix and `P` is a positive semidefinite Hermitian matrix.

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There are many possible solutions, but one example in the case of three functions f, g, and h would be: f(0) = 0, f(1) = 1g(0) = 1, g(1) = 0h(0) = 0, h(1) = 1

We have the set J2 = {0,1} and we need to estimate three functions f, g, and h such that f:

J2→ J2, g: J2→ J2, and h:

J2→ J2, and f = g = h.

To do this, we can simply assign values to each element of the set J2 for each of the three functions. For example, we can let f(0) = 0 and f(1) = 1, which means that the function f maps 0 to 0 and 1 to 1. We can also let g(0) = 1 and g(1) = 0, which means that the function g maps 0 to 1 and 1 to 0.

Finally, we can let h(0) = 0 and h(1) = 1, which means that the function h maps 0 to 0 and 1 to 1. Note that all three functions have the same values for each element in J2, so we can say that f = g = h.

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The volume of the cuboid as a function of x is V(x) = x * 3x * y.

the volume of the cuboid as a function of x is V(x) = 675/4 - (9/4)x^2.

The surface area of the cuboid is given as 450 cm, which can be expressed as:

2(x * 3x) + 2(x * y) + 2(3x * y) = 450.

Simplifying this equation, we get:

6x^2 + 2xy + 6xy = 450,

6x^2 + 8xy = 450,

3x^2 + 4xy = 225.

Now, we need to express y in terms of x. From the given dimensions, we know that the surface area is formed by six rectangular faces of the cuboid. Therefore, the length of one face is x, the width is 3x, and the remaining face (height) is y.

To find y, we can use the equation for the surface area. Rearranging the equation above, we have:

3x^2 + 4xy = 225,

y(4x) = 225 - 3x^2,

y = (225 - 3x^2) / (4x).

Now we can substitute the value of y into the expression for the volume:

V(x) = x * 3x * [(225 - 3x^2) / (4x)].

Simplifying further:

V(x) = (3/4) * (225 - 3x^2),

V(x) = 675/4 - (9/4)x^2.

Therefore, the volume of the cuboid as a function of x is V(x) = 675/4 - (9/4)x^2.

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(a) The number of football boots XYZ Clothing needs to sell to break even can be found by solving the quadratic equation.

(b) To maximize profit, XYZ Clothing needs to sell 1120 football boots.

(c) Plotting relevant points on a graph, we can sketch XYZ Clothing's profit function, indicating important points.

(a) To find the number of football boots XYZ Clothing needs to sell to break even, we set the profit function equal to zero:

Profit = Revenue - Cost

Since the revenue is given as $120 per football boot and the cost function is provided as C(x) = 3,000 + 8x + 0.1x^2, the profit function is:

Profit = 120x - (3,000 + 8x + 0.1x^2)

Setting the profit function equal to zero, we have:

0 = 120x - (3,000 + 8x + 0.1x^2)

Simplifying the equation, we get:

0 = 112x - 0.1x^2 - 3,000

To find the number of football boots needed to break even, we solve the quadratic equation:

0.1x^2 - 112x + 3,000 = 0

Solving this equation will give us the value of x, which represents the number of football boots XYZ Clothing needs to sell to break even.

(b) To find the number of football boots XYZ Clothing needs to sell to maximize profit, we need to determine the vertex of the profit function. The profit function is the same as in part (a):

Profit = 120x - (3,000 + 8x + 0.1x^2)

To find the vertex, we can use the formula x = -b/2a, where a = 0.1 and b = 112.

x = -(-112) / (2 * 0.1)

x = 1120

So, XYZ Clothing needs to sell 1120 football boots to maximize profit.

(c) To sketch the profit function on a pair of axes, we can plot the points that are relevant to the problem. We know that the profit function is given by:

Profit = 120x - (3,000 + 8x + 0.1x^2)

We can plot the following points:

Breakeven point: (x, 0) where x is the number of football boots needed to break even.

Maximum profit point: (1120, Profit(1120)) where Profit(1120) is the maximum profit obtained when 1120 football boots are sold.

Additionally, we can plot a few more points to get an idea of the shape of the profit function.

By connecting these points, we can sketch the profit function on the axes, indicating the relevant points and labeling them accordingly.

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Quarter 1: $300,000Quarter 2: $300,013Quarter 3: $250,000Quarter 4: $500,000 the adjusted chart representing the Sales .

The given chart to represent the sales each quarter, we need to find out the sales of each quarter first and then represent them in the chart. Let's calculate the sales of each quarter one by one:

Sales of Quarter 1Let the sales of Quarter 1 be xSales of Quarter 2As per the given data, Quarter 2 produced 13 more sales than Quarter 1Therefore, sales of Quarter 2 = x + 13Sales of Quarter 3Let the sales of Quarter 3 be sales of Quarter 4As per the given data, Quarter 4 produced 17% of total sales for the year

therefore, 17% of $1,254,000 = (17/100) x 1,254,000= 213,180Sales of Quarter 4 = 213,180Sales increased 100% over the previous quarter

Therefore, sales of Quarter 4 = 2 x sales of Quarter 3= 2yNow, we can form the equation as follows: Total Sales = Sales of Quarter 1 + Sales of Quarter 2 + Sales of Quarter 3 + Sales of Quarter 4$1,254,000 = x + (x + 13) + y + 2y + 213,180$1,254,000 = 4x + 3y + 213,193or 4x + 3y = $1,040,807

Now, we can assume some values of x and y and then calculate the values of other variables. Let's assume x = $300,000 and y = $250,000Therefore, sales of Quarter 1 = $300,000Sales of Quarter 2 = $300,000 + $13 = $300,013Sales of Quarter 3 = $250,000Sales of Quarter 4 = 2 x $250,000 = $500,000Now, we can represent these sales in the chart as follows:

Quarter 1: $300,000Quarter 2: $300,013Quarter 3: $250,000Quarter 4: $500,000

Therefore, the adjusted chart representing the sales each quarter is shown above.

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Answer

6.

Steps

30/100×30

=6

Answer:

6

Step-by-step explanation:

There are 30 students

So,

20÷100×30=6

Answer:

14

Step-by-step explanation:

42:?

3:1

42/3=14

42:14

3:1

Answer:

[tex]Range = 3.169m[/tex]

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the difference between the shortest and the longest

This question implies that we calculate the range.

[tex]Range = Longest - Shortest[/tex]

From the table, we have:

[tex]Longest = 8.7m[/tex]

[tex]Shortest = 5.531m[/tex]

So, we have:

[tex]Range = 8.7m- 5.531m[/tex]

[tex]Range = 3.169m[/tex]

1/5 cups of sugar.

have a nice day

Answer:

x = 43

Step-by-step explanation:

x = 98 - 55

x = 43

Answer:

x=43

Step-by-step explanation:

have a nice day and stay safe:)

Answer:

B

Step-by-step explanation:

A or constant is the answer

Both the given statements are true

1. Two equilateral triangles are always similar: True.

An equilateral triangle is a triangle in which all three sides are equal. Since two equilateral triangles have the same shape and size, they are always similar. Similarity means that the corresponding angles are equal, and the corresponding sides are in proportion.

2. The diagonals of a rhombus are perpendicular to each other: True.

In a rhombus, opposite sides are parallel, and all sides have equal length. The diagonals of a rhombus bisect each other at right angles, which means they are perpendicular to each other. This property holds true for all rhombuses, regardless of their size or orientation.

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Given question is incomplete, the complete question is below

State true or false

1. Two equilateral triangles are always similar.

2. The diagonals of a rhombus are perpendicular to each other.

Answer:

44

Step-by-step explanation:

because it a millon and not a bilolon

Answer:

Each box weighs 6.906 pounds.

Step-by-step explanation:

We know the total weight of the boxes. We also know how many boxes we have. To find the weight of one box, we want to divide the total weight by the total number of boxes.

34.53 / 5

= 6.906

Each box weighs 6.906 pounds.

Hope this helps!

Answer:

12

..................................................

Step-by-step explanation:

2 + 2 + 1 + 2 + 1 + 4 = 12

Answer:

12 centimeters

Step-by-step explanation:

The double dashes are both the same number. Since the base is 4cm and they have to be two of the same number, the double dashes are each 2cm long. Meanwhile, the height is 2cm, and the single dashes are two of the same numbers (but not 2cm, because that's what the double dashes are). So, each dash must be 1cm long. When you add them up: [tex]4+2+2+2+1+1=12[/tex]