Pls help fractions pls and sm else

There are 34 ways by which  pairs of potential clients can be randomly chosen from pool or eight candidates.

We can be able to talk about the combination when the order of the selection is not seen as important as in the case that we have in the question here. We have been told that the pairs are to be chosen randomly.

As such we would have the use of the formula for combination as follows;

C = n!/r!( n - r)!

C = 8!/2!(8 - 2)!

C = 8 * 7 * 6!/2! 61

C = 8 * 7/ 2 * 1

C = 28

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Answer:

Step-by-step explanation:

Triangle JKL is a 51-51-78 triangle, since the angles in a triangle must add up to 180°. Since triangle PQR is similar to triangle JKL, it must also be a 51-51-78 triangle. Since corresponding sides in similar figures are in proportion, we can set up a proportion to find the length of PR:

(PR)/(JK) = (PQ)/(JL) = (36)/(18)

Cross multiplying and solving for PR, we find:

PR = (JK) * (PQ)/(JL) = 18 * 36/18 = 36

Answer:

There is a root between x=3 and x=5.

Step-by-step explanation:

Not entirely sure what this question wants, but from this you can tell that the function crossed the x-axis in the interval (3, 5). When x is 3, y is 5, and then when x is 5, y is -2.

Answer:

which one is correct about HRM?

The cost of the order can be expressed as 7x + 5, where x is the number of t-shirts ordered.

In this expression, "7x" represents the cost of the t-shirts, where each shirt is $7 and the number of shirts is represented by "x". The "$5" represents the flat shipping fee for the entire order, which does not change regardless of the number of shirts being ordered.

By adding the cost of the shirts and the shipping fee, we can find the total cost of the order. It's important to understand that the value of "x" must be specified to evaluate the expression.

For example, if 3 shirts are ordered, then x = 3 and the expression becomes:

So the total cost of the order would be $26.

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Answer:

It is in its simplest form

Step-by-step explanation:

Answer:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For:

x

=

0

(

3

⋅

0

)

+

2

y

=

6

0

+

2

y

=

6

2

y

=

6

2

y

2

=

6

2

y

=

3

or

(

0

,

3

)

For:

y

=

0

3

x

+

(

2

⋅

0

)

=

6

3

x

+

0

=

6

3

x

=

6

3

x

3

=

6

e

d

)

(

3

)

x

=

2

or

(

2

,

0

)

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y-3)^2-0.125)((x-2)^2+ y^2-0.125)(3x+2y-6)=0 [-20, 20, -10, 10]}

Now, we can shade the left side of the line. And we need to make the boundary line a dashed line because the inequality operator does not contain an "or equal to" clause.

graph{(3x+2y-6) < 0 [-20, 20, -10, 10]}

Step-by-step explanation:

Attributes of a parallelogram leads to, Due to the equal length of each side and the 90° angles that they create at their corners, a square is a parallelogram.

The complete question is,

Which of the following attributes of a parallelogram leads to the conclusion that every square can be categorized as a parallelogram? Choose each option that applies.

four equal sides

two pairs of diametrically opposed equal angles

diagonals are cut in half.

two sets of parallel, opposed sides.

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Using place value along with division facts in a division equation, helps in dividing larger numbers easily. Place value counters and tape diagrams are often used to represent division using place value.

What is division?

With the arithmetic operation of division, we can divide a collection of items into equal pieces. Typically, it is represented by the symbol "÷".

The bigger amount that is divided into equal halves is called the dividend.

The number of groups that divide the payout is known as the divisor. Following division, the result is the quotient.

The value of a digit in a number is determined by its place in the number, or place value.

Divide larger numbers simply by applying place value and division facts in a division equation. Place value division is frequently shown using tape diagrams and place value counters.

Example - 4 ÷ 2 = 2

In the first equation, the digits are 4 and 2. We can write it as 4 ones ÷ 2 ones = 2 ones (using the division fact).

Example - 40 ÷ 20 = 2

For the second equation, the digits are the same, but a zero has been added after 4, and the quotient thus has one zero at the end. So, we can write it as 4 tens ÷ 2 ones = 2 tens (using place value and the division fact).

Example - 400 ÷ 200 = 2

Similarly, for the third division equation, the same digits are present, but the number of zeros has increased. We are dividing 4 hundreds ÷ 2 ones = 2 hundreds (using place value and the division fact).

Therefore, place value blocks help in division for making it simpler.

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Answer:

9 = 1st number

21 = 2nd number

Step-by-step explanation:

given that :

1st number = x __eq_i

2nd number (in terms of the first number) = 2x + 3 __eq_ii

1st number + 2nd number = 30 __eq_iii

input eq_i and eq_ii in eq_iii

x + 2x + 3 = 30

3x + 3 = 30

3x = 30 - 3

x = 27 ÷ 3

x = 9

9 = 1st number

input the value of x in eq_ii

2x + 3

2(9) + 3

18 + 3

21 = 2nd number

hope that helps.

Answer:

No, it is not a proportion

Step-by-step explanation:

10/12 and 40/64 is not a proportion since although the numerator is constant because when multiplied by 4, it gives us 40, however, when you multiply 4 by 12, you get 48, therefore, it is not a proportion since the changes in the value of a proportion must be constant in both the numerator and denominator.

Hope this helped!  :D

The measurement of the hypotenuse is obtained as 9 units using the Pythagoras theorem.

What is Pythagoras Theorem?

In a right-angled triangle, the square of the hypotenuse side is equal to the sum of the squares of the other two sides, according to Pythagoras's Theorem. These triangle's three sides are known as the Perpendicular, Base, and Hypotenuse. Due to its position opposite the 90° angle, the hypotenuse in this case is the longest side.

According to the graph -

The perpendicular measures 4 units.

The base measures 3 units.

To find the hypotenuse g apply the Pythagoras theorem -

(hypotenuse)^2=(base)^2+(perpendicular)^2

(g)^2=(3)^2+(4)^2

(g)^2=9+16

(g)^2=25

g=[tex]\sqrt{25}[/tex]

g=5

Therefore, line segment g measures 5 units.

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The equations that are true for x = –2 and x = 2 are:

x^2-4=0 and 4x^2 = 16

We can determine the equations that are true for x = –2 and x = 2 by testing the given options:

After testing the options option  1 ; x^2-4=0 putting x = 2 or -2 into the equation will give zero.  

(2^)2-4=0

(-2)^2-4=0

Then option 4: 4x^2 = 16

4(2)^2 = 16

4(-2)^2 = 16

Therefore, option 1st and 4th are correct.

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The length of segments TA and TB are both 4 cm.

To solve this problem, we can use the properties of circles and the relationship between the radius and the diameter.

Since the radius of the circle with center T is 4 cm, the diameter of this circle is 2 * 4 = 8 cm.

Since the length of segment ST is 9 cm, the diameter of the second circle is also 9 cm.

Since the radius of the circle with center T is 4 cm, the radius of the second circle is also 4 cm.

Since the two circles intersect at points A and B, the segments TA and TB are equal in length.The length of segment TA and TB is the radius of the second circle, which is 4 cm.

Therefore, the length of segments TA and TB are both 4 cm.

The figure is attached

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Answer:

The answer is C

Step-by-step explanation:

You have to divide both numerators then the denominater.

So, it would look like:  160 over 90 x 100 over 290

160x100=16   90x290=25     16/25

Answer:

510 miles

Step-by-step explanation:

                                       A                     B

Rate                               80                  120

Time                                 x                     x - 2

Distance        

Distance = rate x time

A's distance

d = 80x

B's distance

d = 120(x -2)          

The distances equal each other when B catches up to A.  Set the equations equal to each other and solve for the time

80x = 120(x -2)  Distribute the 120

80x = 120x - 240  Subtract 120x from both sides

-40x = -240    Divide both sides by -40

x = 6

After 6 hours, B caught up with A.  Substitute 6 for t and find the distance. You can use A or B.    

d= 80x

d = 80(6)

d = 480

We need to add another 30 miles to get to the next town.

480 + 30 = 510

Answer: 130

Step-by-step explanation:

The original price of the sweater is $303.

A discount is the reduction of either the monetary amount or a percentage of the normal selling price of a product or service.

Given that, June is buying a sweater using a coupon offering a 30% discount on items over $99.

The discounted price is $91

Let the original price of the sweater be x.

So, 30% of x=91

30/100 ×x=91

0.3x=91

x=91/0.3

x=$303

Therefore, the original price of the sweater is $303.

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Answer:

both are right

Step-by-step explanation:

2/5x = 14

multiply both sides by 5/2:

(5/2)(2/5)x = 14(5/2)

x = 70/2 = 35

However, dividing by 2/5 is the same as multiplying by 5/2, so you are BOTH right.  Dividing by a fraction is the same as multiplying by the reciprocal of the fraction.

a) The longest time a borrower can take to pay off the new car loan of 2 - 6 years is 6 years.

b) Based on the above, the best interest rate the borrower could get is 8%.

Many factors are considered in determining the interest rate for a loan.

Some of the factors include:

We know that the longer the term of a loan, the higher the interest rate charged.  This higher rate is meant to compensate the lender for the time value of money, made variable by inflation and credit risks.

Thus, if a loan term varies between two and six years, the longest time to pay off the loan is 6 years while the best interest rate the borrower can be granted is 8%.

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The blank spaces of the statement coefficient: The number in BLANK of the variable within the BLANK BLANK are, front, addition, subtraction.

A quantity or number that is combined with a variable is known as a coefficient. The variable is often multiplied by an integer, which is then printed next to it.

Terms that have the same variables raised to the same power are referred to as like terms. The only difference is in the numerical coefficients.

We know a coefficient is a constant value combined with a variable.

For example, In 7x the coefficient of x is 7.

Given, A fill-in-the-blank statement,

coefficient: The number in BLANK of the variable within the BLANK BLANK.

Therefore,

coefficient: The number in front of the variable within the addition subtraction.

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The total number of employees that this company would be said to have is given as 122424

How to solve for the number of employees in the company

We know that the number of employees in one country is 22400, and that this represents 18.3% of the company's employees in total.

We can use this information to set up a proportion to find the total number of employees in the company.

Employees in one country / Total employees = 18.3 / 100

22400 / X = 18.3/100

To find the total number of employees, we can cross-multiply and divide:

X = (22400 * 100) / 18.3

X = 122424

So the company has a total of 122424 employees.

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From the exponential function, the average rate of change from year 1 to year 4 is 62.43, the average rate of change from year 5 to year 8 is 67.57 and the rate of change per year is 65

An exponential function is a type of function that involves a variable in an exponent. It is of the form f(x) = a⋅b^x where a and b are constants and b > 0, b ≠ 1. The input to the function, x, is the exponent that the base, b, is raised to. The output, f(x), is the result of raising the base to the exponent.

In this problem, we have to calculate the rate of increase per year.

Data;

rate = 2%

P = 3000

The exponential growth can be calculated by;

A = P(1 + r)ⁿ

In year 1

A = 3000(1 + 0.02)¹

A = 3060

In year 4

A = 3000(1 + 0.02)⁴

A = 3247.3

a)

The average rate of change from year 1 to year 4 will be

A = [3000(1 + 0.02)⁴ - 3000(1 + 0.02)¹] / 4 - 1

A = 62.43

The average rate of change from year 1 to year 4 is 62.43

b)

The average rate of change from year 5 to year 8 is calculated as

A = [3000(1 + 0.02)⁸ - 3000(1 + 0.02)⁵] / 8 - 5

A = 67.57

C)

The rate of change increase can be calculated as;

A = [3000(1 + 0.02)⁸ - 3000(1 + 0.02)¹] / 8 - 1

A =65

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Answer:

Step-by-step explanation:

According to question, we know that

His Sister has "1/5*$25 which is equal to $5, and his father has "40%*$25 which is equal to 0.4 * $25 = $10". So, the money Hafiz, his sister and his father have in total

= $25+$5+$10 = $40

Hafiz = $25

Sister = [tex]\frac{1}{5}[/tex]

Father = 40%

Total money of Hafiz, Sister, and Father altogether.

[tex]\frac{1}{5} X[/tex] $25

= $5

40% (0.4) x $25

= $ 10

$ 25 + $ 5 + $ 10

laucs ori nisiquiera estoy en universidad estoy en eseyo pe

The coordinate of the point C is (0, a)

From the question, we have the following parameters that can be used in our computation:

A = (0, a)

B = (b, 0)

As a general rule, the orthocenter of a triangle is a point located at the intersection of the lines containing the altitudes of the triangle.

This means that we start by calculating the equation of the altitude from B to line AC.

A linear equation is represented as

y = mx + c

Where

slope = m

y-intercept = c

Using the above as a guide, we have the following:

slope = (y₂ - y₁)/(x₂ - x₁)

This gives

m(BC) = (0 - 0)/(b - 0) = 0

y-intercept (c) = a

So the equation of the line BC is

y = 0 * x + a

y = a

For line AC, we have

m(AC) = (a - 0)/(0 - 0) = a/0 = undefined.

This means that the equation of the line AC is

x = 0

The equation x = 0 implies that the x-coordinate is always 0, irrespective of the y-coordinate e.g. (0, a)

At this stage, we have the coordinates of the points from lines AC and BC to be

(0, a) and (0, a)

Next, we calculate the C as follows

C = Midpoints of (0, a) and (0, a)

This gives

C = 1/2 * (0 + 0, a + a)

Evaluate

C = (0, a)

Hence, the coordinate of C is (0, a)

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[tex]~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] ~\dotfill[/tex]

[tex](-6x^3 y^5 + 11x^3 y^2) \div (-2x^2 y^3)\implies \cfrac{-6x^3 y^5 + 11x^3 y^2}{-2x^2 y^3} \\\\\\ \cfrac{-6x^3 y^5}{-2x^2 y^3}+\cfrac{11x^3 y^2}{-2x^2 y^3}\implies \cfrac{-6}{-2}\cdot \cfrac{x^3 y^5}{x^2 y^3}+\cfrac{11}{-2}\cdot \cfrac{x^3 y^2}{x^2 y^3} \\\\\\ 3\cdot x^3 x^{-2}y^5 y^{-3}+\cfrac{11}{-2}\cdot \cfrac{x^3 x^{-2}}{y^3 y^{-2}}\implies 3x^{3-2}y^{5-3}-\cfrac{11}{2}\cdot \cfrac{x^{3-2}}{y^{3-2}} \\\\\\ ~\hfill {\Large \begin{array}{llll} 3x y^2 -\cfrac{11x}{2y} \end{array}}~\hfill[/tex]

Check the picture below.