Pls help!! I need help

Answer: Brainlest would be much appreciated

(A= amount P=principal r= interest rate n= number of times interest is compounded per unit 't' nt=time)

n=4. I'm not sure tho!!

Answer:

3.94

Step-by-step explanation:

i think it is correct and i hope this helps but it may be wrong

Answer:

24 [tex]in^{3}[/tex]

Step-by-step explanation:

volume formula= l x w x h

Box A:

4 x 3  x 4 = 48

Box B: 48/2 = 24

Answer:

Step-by-step explanation:

1 and 7 is Corresponding

2 and 8 is Alternate exterior

this is what I know but I am not sure

Answer:

25/7

Step-by-step explanation:

mixed number to improper fraction greater than 1

-multiply the denominator by the whole number then add that number to the top number and put the original denominator under that number.

Answer:

Given, 3x−2<2x+1

⇒3x−2x<1+2

⇒x<3orx∈(−∞,3)

The lines y=3x−2 and y=2x+1 both will intersect at x=3 

Clearly, the dark line shows the solution of 3x−2<2x+1.

Answer:

No

Step-by-step explanation:

If you input g = 4 into the inequality, you have

8 - 4 > 4

4 > 4

4 is NOT greater than 4

To be correct, the inequality would have to read:

8 - g ≥ 4

This would be correct because now it reads

4 ≥ 4

4 is greater than OR equal to four

Answer:

308

Step-by-step explanation:

Answer:

So the answer would be no, because the length of the rope is needs to be 46 and 35 is not long enough

Step-by-step explanation:

A flagpole, rope and the length of secure point from the flagpole are forming the right triangle, where the rope is a hypotenuse. Let a = 45 and b = 10ft. Use Pythagorean Formula to find length of the rope c

a² + b² = c²

Since we are going to solve for c, we set up the equation like this:

c² = 45² + 10²  (Substitute into formula)

c² = 2,025 + 100 (Add)

c² = 2,125 (Simplify)

√c² = √2,125 (Take the square root from both sides)

c = 46.09772228646444 (Round to the nearest whole number)

c = 46

So the answer would be no, since the length of the rope needs to be 46ft long and a 35 foot piece of rope is not long enough.

Answer:

6, 12, 24, 48, 96.

All the terms are multiples of 6.

Step-by-step explanation:

The given rule is to multiply by 2.

To find the next 4 numbers, we need to multiply 6, and the products that we've obtained after.

First number:

[tex]6 \times 2 = 12[/tex]

12 is our first number.

Second Number:

[tex]12 \times 2 = 24[/tex]

24 is our second number.

Third Number:

[tex]24 \times 2 = 48[/tex]

48 is our third number.

Last Number:

[tex]48 \times 2 = 96[/tex]

96 is our last number.

All the terms are multiples of 6.

Proof:

Answer:

the answer is 60

Step-by-step explanation:

you multiply what's on top 5*12=60

Answer:

I believe its C sorry if im wrong

Step-by-step explanation:

Answer:

Make an eqaution from here.
Let’s make evening 2 “x”

So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).

X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x

And when solved, it has to equal 105.

So solve from here.
Combine like terms.

6x-9=105
Isolate

6x=114
x= 19

First evening is 9 less then 19, so 10.

The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76

1st night = 10

2nd night= 19 calls
Thrid night= 76 calls

Notice that

y² - 20y + 100 = y² - 2•10y + 10² = (y - 10)²

Then

√(y² - 20y + 100) = y - 10

is equivalent to

√((y - 10)²) = y - 10

|y - 10| = y - 10

If y ≥ 10, then |y - 10| = y - 10, and

y - 10 = y - 10   ⇒   0 = 0

so there are infinitely many solutions, y ≥ 10.

Otherwise, if y < 10, then |y - 10| = -(y - 10), and

-(y - 10) = y - 10   ⇒   10 = -10

which is false, so there are no solutions in this case.

[tex]\\ \tt\hookrightarrow \sqrt{y^2-20y+100}=y-10[/tex]

[tex]\\ \tt\hookrightarrow y^2-20y+100=(y-10)^2[/tex]

[tex]\\ \tt\hookrightarrow y^2-20y+100=y^2-20y+100[/tex]

Both sides are equal

Hence

Answer:

the area is 20 in

Step-by-step explanation:

3 times 4 is 12. since we used 3 inches out of the 11, we can only multiply the 8 inches with 1. 8 times 1 is 8. 12+8=20.

Answer:

1) x = 3 and y = -2

2) x = 2 and y = 1

3) x = -2 and y = -1

4) x = 3 and y = 2

5) x = 2

6) x = 2 and y = -3

7) x = 4 and y = 3

8) x = -3 and y = -6

Step-by-step explanation:

1. Answer :

y = -2

4x - 3y = 18 ----(1)

Substitute y = -2 in (1).

4x - 3(-2) = 18

4x + 6 = 18

Subtract 6 from both sides.

4x = 12

Divide both sides by 4.

x = 3

So,

x = 3 and y = -2

2. Answer :

y = 6x - 11 ----(1)

2x + 3y = 7 ----(2)

Substitute y = 6x - 11 in (2).

2x + 3(6x - 11) = 7

2x + 18x - 33 = 7

20x - 33 = 7

Add 33 to both sides.

20x = 40

Divide both sides by 20.

x = 2

Substitute x = 2 in (1).

y = 6(2) - 11

= 12 - 11

= 1

So,

x = 2 and y = 1

3. Answer :

x = -3y - 5 ----(1)

4x - 5y = -3 ----(2)

Substitute x = -3y + 5 in (2).

4(-3y - 5) - 5y = -3

-12y - 20 - 5y = -3

-17y - 20 = -3

Add 20 to both sides.

17y = -17

Divide both sides by 17.

y = -1

Substitute y = -1 in (1).

x = -3(-1) - 5

= 3 - 5

= -2

So,

x = -2 and y = -1

4. Answer :

x = 5y - 7 ----(1)

-2x - 3y = -12 ----(2)

Substitute x = 5y - 7 in (2).

-2(5y - 7) - 3y = -12

-10y + 14 - 3y = -12

-13y + 14 = -12

Subtract 14 from both sides.

-13y = -26

Divide both sides by -13.

y = 2

Substitute y = 2 in (1).

x = 5(2) - 7

= 10 - 7

= 3

So,

x = 3 and y = 2

5. Answer :

5x + 3y - 8 = 0 ----(1)

2x - 3y - 6 = 0 ----(2)

Solve for 3y in (1).

5x + 3y - 8 = 0

Subtract 5x from both sides.

3y - 8 = -5x

Add 8 to both sides.

3y = -5x + 8

Substitute 3y = -5x + 8 in (2).

2x - (-5x + 8) - 6 = 0

2x + 5x - 8 - 6 = 0

7x - 14 = 0

Add 14 to both sides.

7x = 14

Divide both sides by 7.

x = 2

6. Answer :

x - 3y - 11 = 0 ----(1)

5x + y - 7 = 0 ----(2)

Solve for x in (1).

x - 3y - 11 = 0

Subtract 3y and 11 to both sides.

x = 3y + 11 ----(3)

Substitute x = 3y + 11 in (2).

5(3y + 11) + y - 7 = 0

15y + 55 + y - 7 = 0

16y + 48 = 0

Subtract 48 from both sides.

16y = -48

Divide both sides by 16.

y = -3

Substitute y = -3 in (3).

x = 3(-3) + 11

= -9 + 11

= 2

So,

x = 2 and y = -3

7. Answer :

2x - 3y = -1 ----(1)

y = x - 1 ----(2)

Substitute y = x - 1 in (1).

2x - 3(x - 1) = -1

2x - 3x + 3 = -1

-x + 3 = -1

Subtract 3 from both sides.

-x = -4

Multiply both sides by -1.

x = 4

Substitute x = x in (3).

y = 4 - 1

= 3

So,

x = 4 and y = 3

8. Answer :

-4x + y = 6 ----(1)

-5x - y = 21 ----(2)

Solve for y in (1).

-4x + y = 6

Add 4x to both sides.

y = 4x + 6 ----(3)

Substitute y = 4x + 6 in (2).

-5x - (4x + 6) = 21

-5x - 4x - 6 = 21

-9x - 6 = 21

Add 6 to both sides.

-9x = 27

Divide both sides by -9.

x = -3

Substitute x = -3 in (3).

y = 4(-3) + 6

= -12 + 6

= -6

So,

x = -3 and y = -6

Learn more:

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Divisibility - Math

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Mathematics

Thank You!

Answered by: ms115

Answer:

See below for all answers and explanations

Step-by-step explanation:

Problem 1

4x - 3y = 18

4x - 3(-2) = 18 <-- Substituting y = -2

4x + 6 = 18

4x = 12

x = 3

Problem 2

2x + 3y = 7

2x + 3(6x-11) = 7 <-- Substituting y = 6x - 11

2x + 18x - 33 = 7

20x - 33 = 7

20x = 40

x = 2

y = 6x - 11 <-- Substituting x=2 to solve for y

y = 6(2) - 11

y = 12 - 11

y = 1

Problem 3

4x - 5y = -3

4(-3y-5) - 5y = -3 <-- Substituting x = -3y - 5

-12y - 20 - 5y = -3

-17y - 20 = -3

-17y = 17

y = -1

x = -3y - 5 <-- Substituting y = -1 to solve for x

x = -3(-1) - 5

x = 3 - 5

x = -2

Problem 4

-2x - 3y = -12

-2(5y-7) - 3y = -12 <-- Substituting x = 5y - 7

-10y + 14 - 3y = -12

-13y + 14 = -12

-13y = -26

y = 2

x = 5y - 7 <-- Substituting y=2 to solve for x

x = 5(2) - 7

x = 10 - 7

x = 3

Problem 5

5x - 3y - 8 = 2x - 3y - 6 <-- Setting equations equal to each other

5x - 8 = 2x - 6 <-- Eliminating y-variable to solve for x

3x - 8 = -6

3x = 2

x = 2/3

5x - 3y - 8 = 0 <-- Substituting x = 2/3 into first equation

5(2/3) - 3y - 8 = 0

10/3 - 3y - 8 = 0

10/3 - 3y - 24/3 = 0

-14/3 - 3y = 0

-3y = 14/3

y = -14/9

Problem 6

x - 3y - 11 = 0 <-- Solve for x

x - 3y = 11

x = 11 + 3y

5x + y - 7 = 0

5(11+3y) + y - 7 = 0 <-- Substituting x = 11 + 3y

55 + 15y + y - 7 = 0

55 + 16y - 7 = 0

48 + 16y = 0

16y = -48

y = -3

x = 11 + 3y <-- Substitute y=-3 into first equation to solve for x

x = 11 + 3(-3)

x = 11 - 9

x = 2

Problem 7

2x - 3y = - 1

2x - 3(x-1) = -1 <-- Substituting y = x - 1

2x - 3x + 3 = -1

-x + 3 = -1

-x = -4

x = 4

y = x - 1 <-- Substitute x=4 to solve for y

y = 4 - 1

y = 3

Problem 8

-4x + y = 6 <-- Solve for y in first equation

y = 6 + 4x

-5x - y = 21

-5x - (6+4x) = 21 <-- Substituting y = 6 + 4x

-5x - 6 - 4x = 21

-9x - 6 = 21

-9x = 27

x = -3

y = 6 + 4x <-- Substitute x = -3 to solve for y

y = 6 + 4(-3)

y = 6 - 12

y = -6

Answer:

5 sec

Step-by-step explanation:

Hit the water, means h = 0

Solve -16t^2 + 68t +60 =0

4t^2 - 17t - 15 = 0

(4t + 3)(t - 5) = 0

so t = 5 sec

Answer:

[tex]x ^ { 4 } - 3 x ^ { 2 } - 10 = 0\\Let, t = x^{2} \\\rightarrow \: t^{2}-3t-10=0 \\\\\\t=\frac{-\left(-3\right)(+/-)\sqrt{\left(-3\right)^{2}-4\times 1\left(-10\right)}}{2} \\t=\frac{3(+/-)7}{2} \\\\So,\\t = 5 \: and \: -2\\\\Then,\\x = \sqrt{5} \: and \: -\sqrt{5}[/tex]

Hope it helps ⚜

[tex]\huge\boxed{\boxed{Hello!}}[/tex]

How to Find the Area of a Rectangle:

A=LW, where L stands for Length and W stands for Width.

In this case, L is 4 cm more than the width, and the width is 10 cm.

Thus, the length is 14 cm.

Multiply 14 by 10:

A=140 cm²

[tex]\huge\boxed{\boxed{\pmb{Answer:{\boxed{\sf{A=140cm^{2} }}}}}}[/tex]

Hope it helps!

Enjoy your day!

Please feel free to ask if you have any doubts.

✷[tex]\mathfrak{MistySparkles}[/tex]✷

Answer:

142.24$

Step-by-step explanation:

112 = 100% 9x112

/ 100100. = 10.08$

? = 9%

112 = 100% 18x112 /100 =. 20.16$

? = 18%

so.......

112$ + 20.16$ + 10.08$

= 142.24$

Answer:

c

Step-by-step explanation:

Refer to the attachment

Answer and Step-by-step explanation:

Alright, so when creating any type of math problem, it is important to identify the parts of the problem and where they go. First, we need to start by putting the problem together. We will use one of the most common forms of equations of math, also known as the linear equation of y=mx+b.

So we have: S(w)=__x + __. S(w) is also equal to f(x), which is also equal to y. So: y= __x + __.

Let's start filling this equation in. So, because it says that she will add 25 dollars each week, The problem is addition. Also, the 25 dollars each week will represent the mx in this situation. Here's why:

The x in this can stand for the amount of week she added this 25 dollars to her account. So:

y= 25x + __.

Now, we can add the 150 to the problem because that is what she started with for this one-time deal. So now we have:

y= 25x + 150.

You can now where everything is represented, but we are not done. Let's change y and x back into S(w) and w like the question asks us to have. So:

S(w)= 25w + 150.

If you want to solve this question, just replace the number of weeks in place of all w's in the equation, like this: S(2)= 25(2) + 150.

I hope that this helps.

Answer:

False

Step-by-step explanation:

Your answer is false because the 3 in 157.83 is in the hundereths place not the tenths place.

I hope it helps! Have a great day!

Lilac~

Answer:There would be 1 chocolate bar left over

Step-by-step explanation: 2 people can eat 1 bar.

Answer:

1 chocolate bar

Step-by-step explanation:

Since they want to eat 1/2 a bar, 2 people can eat 1 bar. 6 total children / 2 that eat 1 bar = 3 chocolate bars eaten

4 original chocolate bars - 3 already eaten = 1 remaining chocolate bar

[tex]2p - 3 > p + 6 \\ 2p - p > 6 + 3 \\ p > 9[/tex]

Answer:

28.26

Step-by-step explanation:

a=3.14159...(pi)r^2

If a figure is dilated by a factor of 6, the perimeter of the figure will change by a factor of 6.

Step-by-step explanation:

The objects that have the same shape are known as similar figures. Since they are similar in shape it doesn't necessary for those objects to have the same size.

Dilation is the process that enlarges or shrinks the size of an object to its similar figure without changing its size. The Dilation is based on a factor that makes the object to enlarge or shrink.

Since its size has changed so as the perimeter will be changed for both of the figures. The perimeter of an object remains same as the scale factor used to dilate the object.

Consider a square with its side as 2 cm initially and dilated with factor 3.

Perimeter of the square = 4 a. where a is the side.

Then the perimeter of the square will be 8 cm initially.

After dilation the side of the square will be changed as 6.

Then the perimeter will change as 24 cm.

Thus the perimeter of the square initially has increased 3 times after dilation.