Pls help LOL I WILL MARK U BRAINLIEST‼️‼️‼️‼️

Answer:

3179cm^3

Step-by-step explanation:

[tex]volum = height × width × length \\ = 17cm \times 17cm \times 11cm \\ = {3179cm}^{3} [/tex]

Answer:

-2

Step-by-step explanation:

range is y values

Answer:

-2

Step-by-step explanation:

That's the minimum range, which is basically the lowest point on the y-axis that the line touches

Answer:

4/3

Step-by-step explanation:

Out of the six sides 3 are odd and there's 5 numbers greater than 1. Basically these turn to the fractions 3/6 and 5/6 (these fractions stand for the probability they get rolled on this die).

Since the question says OR and not AND you add these fractions!

3/6 + 5/6 = 4/3

Answer:

A

Step-by-step explanation:

It's only slightly bigger than 90 degrees, so 110 is the only plausible conclusion

Answer:

110

Step-by-step explanation:

Answer:

total of the data points = 1200

Step-by-step explanation:

The 'average' of a data set is the total of the data points divided by the number of data points.

Here:

total of the data points

---------------------------------- = 48

                 25

Multiplying both sides of this equation by 25 yields:

total of the data points = 1200

Answer:

[tex]m {}^{2} - 100 = - 99[/tex]

Step-by-step explanation:

Set up the binomial.

[tex](m - 10)[/tex]

[tex](m + 10)[/tex]

Multiply the binomial.

[tex](m - 10)(m + 10) = - 99[/tex]

Apply difference of squares rule

[tex](p + q)(p - q) = p {}^{2} - q {}^{2} [/tex]

[tex]m {}^{2} - 100 = - 99[/tex]

Answer: m^2-100=-99

Step-by-step explanation:

Set up the binomial.

(m-10)

(m+10)

Multiply the binomial.

(m-10)(m+10)=-99

Apply difference of squares rule

(p+q)(p-q) = p2-q2

Answer: m^2-100=-99

Answer:

The colder it is, the more cups of hot chocolate will be sold.

Step-by-step explanation:

When it was 15 degrees Fahrenheit, 80 cups of hot chocolate were sold. When it was a 90 degree summer day, only 4 cups of hot chocolate were sold.

Answer:

Step-by-step explanation:

( x - 1 )2 + ( y + 3 )2 = 90

The value of x is 7.

A triangle is a three-sided polygon that consists of three edges and three vertices.

The two triangles PQR and P'Q'R' are similar triangles

Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .

Firstly let us find the P'Q' by using pythagoras theorem

R'Q'²=PR'²+P'Q'²

12²=10²+P'Q'²

144-100=P'Q'²

44=P'Q'²

P'Q'=6.6

The value of PR is x

The value of x is 7. as R it is a midpoint of P'Q'R'

Hence the value of x is 7

To learn more on Triangles click:

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Answer:

2821.51

73425.64

28124.24

4124.24

Step-by-step explanation:

Effective rate: .058/2 = .029

This question is kind of ambigous and I'll make the assumption that there is no payment at time 0

[tex]175000=x\frac{(1+.029)^{2*18}-1}{.029}\\x=2821.511[/tex]

interested earned:

175000-2821.51*36= 73425.64

2.)

Same assumption as question 1 (there is no payment at time 0)

effective rate: .063/12= .00525

[tex]400(\frac{(1+.00525)^{60}-1}{.00525})=28124.24[/tex]

Interest earned: 28124-400*60=4124.24

Answer:

First problem: monthly payment $2741.99; interest earned $76,288.36

Second problem: amount in account $28,271.90; interest earned $4271.90

Step-by-step explanation:

First problem:

You open an account with a deposit. The deposit is the first monthly payment. This means that this is an annuity in which you pay at the beginning of the pay period. That makes it into an "annuity due."

[tex] A = \dfrac{F}{\frac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

where A = periodic payment,

F = future value

i = interest rate per compounding period, n = number of compounding periods

[tex]A = \dfrac{175000}{\frac{(1 + \frac{0.058}{2})^{2 \times 18} - 1}{\frac{0.058}{2}} \times (1 + \frac{0.058}{2})}[/tex]

[tex] A = 2741.99 [/tex]

Interest earned:

[tex] 2 \times 18 \times 2741.99 - 175000 = 76288.36 [/tex]

Second problem:

Once again, the account starts with a deposit of the monthly payment, so this is also an annuity due, meaning the payments occur at the beginning of each compounding period. Here, we are given the monthly payment, an d we need to find the future value.

[tex] F = A \times \dfrac{(1 + i)^n - 1}{i} \times (1 + i)} [/tex]

[tex] F = 400 \times \dfrac{(1 + \frac{0.063}{12})^{5 \times 12} - 1}{\frac{0.063}{12}} \times (1 + \frac{0.063}{12})} [/tex]

[tex] F = 28271.90 [/tex]

The interest earned is:

[tex] 28271.90 - 12 \times 5 \times 400 = 4271.90 [/tex]

Answer:

D (The square root property should have been applied to both complete sides of the equation instead of to select variables)

Step-by-step explanation:

On edge 2021

Answer:

bugo.ka pag answer bobo ka bah ha wag kanang umasa dito piste ka

Answer:

the correct answer is option D. 7

Answer:

see Image below:)

Step-by-step explanation:

Go here for steps

Answer: 106 seconds. (1 minute and 46 seconds.

Step-by-step explanation: If it takes 53 seconds to get through 3 floors and there are six, that means you have to multiply 53 by 2, because there are 2 sets of 3 floors.

Hope this helps! :)

Answer:

2400 ways

Step-by-step explanation:

Combination has to do with the idea of selection. Here we need to select a president, a secretary, and a treasurer.

This means to select three out of twenty five persons.

From;

nCr = n! / ((n – r)! r!)

n = the number of items.

r = how many items are taken at a time.

Thus we have;

25C3 = 25!/(25 - 3)! 3!

=

1.6× 10^25/1.1×10^21 × 6

= 2400 ways

Answer:

C

Step-by-step explanation:

I've completed the test before. :)

answer:

1393.84

Step-by-step explanation:

since the formula for a square base pyramid is a^2×h/3

we can find out the height for the pyramid by dividing the a^2×h/3 by a^2 =h/3

1568/7^2=32 since 32 = h/3 we multiply by 3 to find the height which = 96

now that we have the height we usee the pathagorean Therom to find the height of one of the face triangles

so 96^2+3.5^2=L^2 so L =96.06

so now that we have all we need

the surface area of the square at the bottom of the pyramid is 7×7

the surface area of the triangles are 96.06 ×7/2 since the area of a triangle is h×b/2

since there are 4 triangles and on square 49+4(96.06×7/2)= 1393.84

Answer:

Root         Multiplicity

 -4                    2

 -1                     2

  2                     1

   5                    3

---------------------------

y = a(x + 4)²(x + 1)²(x - 2)(x - 5)³

find "a" using point (0, 20000)

20000 = a(0 + 4)²(0 + 1)² (0 - 2)(0 - 5)³

20000 = a(16)(1)(-2)(-125)

20000 = a (4000)

a = 20000/4000

a = 5

y = 5(x + 4)²(x + 1)²(x - 2)(x - 5)³

Answer:

128° because it is corresponding with <4

[tex] < 5 = \: < 3 \\ = \: < 4 \\ < 5 = 128 \degree[/tex]

Answer:

option 3

Step-by-step explanation:

ORIGINAL                REFLECTED

A = ( 2, 0)                    A' = (-2, 0)

B = (5 , 0)                    B' = (-5, 0)

C = (5, -2)                    C' = (-5, -2)

D = (2, -2)                    D' = (-2, -2)

Answer:

Solution given:

a.

tn=12-n

1 st term =12-1=11

2nd term =12-2=10

3rd term=12-3=9

4th term=12-4=8

10th term=12-10=2

b.

tn=5-2n

1st term=5-2*1=3

2nd term=5-2*2=1

3rd term=5-2*3=-1

4th term=5-2*4=-3

10th term=5-2*10=-15

(a) Solution

T(n) = 12 - n

T(1) = 12 - 1 = 11

T(2) = 12 - 2 = 10

T(3) = 12 - 3 = 9

T(4) = 12 - 4 = 8

T(10) = 12 - 10 = 2

(b) Solution

T(n) = 5 - 2n

T(1) = 5 - 2 = 3

T(2) = 5 - 4 = 1

T(3) = 5 - 6 = -1

T(4) = 5 - 8 = -3

T(10) = 5 - 20 = -15

Answer:

c. As sample size increases, standard error decreases.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

Thus:

The standard error is inversely proportional to the square root of the sample size, that is, as the sample size increases, the standard error decreases, and the correct answer is given by option c.

Answer:

1/3

Step-by-step explanation:

Hope this is useful even though there isn't any working

Answer:wpeleoe

Step-by-step explanation:

Use the formula below:

[tex] \large \boxed{h = - \frac{b}{2a} }[/tex]

From the given equation:

[tex] \large{y = 2 {x}^{2} - 6x + 2}[/tex]

Substitute a = 2 and b = -6 in the formula.

[tex] \large{h = - \frac{ - 6}{2(2)} } \\ \large{h = - \frac{ - 6}{4} } \\ \large{h = - \frac{ - 3}{2} \longrightarrow \boxed{h = \frac{3}{2} }}[/tex]

Since h is from (h,k). From an ordered pair, h = x and k = y. When answering the axis of symmetry, you should answer in term of x.

Answer

Answer:

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

Step-by-step explanation:

Given the data in the question;

Hypothesis;

Null hypothesis             : H₀ : Car accidents are equally distributed throughout the year

Alternative hypothesis : Hₐ : Car accidents are NOT equally distributed throughout the year

significance level ∝ = 0.05

x ;

Spring = 27

Summer = 39

Fall = 31

Winter = 53

Test Statistics;

Chi Square = ∑[ (O – E)²/E ]

                         O               E                   (O – E)²/E

Spring               27            37.4                2.94

Summer            39            37.4                0.06

Fall                    31             37.4                1.1267

Winter               53            37.4                6.4067

Total                 150           150                 10.5334

so; z = ∑[ (O – E)²/E ] = 10.5334

{from table}

p-value = 0.0145

Hence, Since p-value ( 0.0145 ) is less than significance level ( 0.05 )

we reject null hypothesis.

Therefore, there is sufficient evidence to conclude that Car accidents are NOT equally distributed throughout the year

In this exercise we have to use probability knowledge to calculate the distribution during the year, so we find that:

There is sufficient evidence to conclude that car accidents are not equally distributed throughout the year.

Given the data in the question;

Now the values ​​given in the statement can be exemplified below as:

In this way, we can assemble a table of values ​​with the statistical data previously informed and using the formula given below:

[tex]Z=\sum[\frac{(O-E)^2}{E}][/tex]

[tex]Z = 10.5334[/tex]

So:

[tex]\ \ \ \ \ \ \ \ \ \ \ O \ \ \ \ \ E \ \ \ \ (O - E)^2/E\\Spring \ \ 27 \ \ 37.4 \ \ \ \ 2.94\\Summer \ 39 \ 37.4 \ \ \ \ 0.06\\Fall \ \ \ \ \ \ 31 \ 37.4 \ \ \ \ 1.1267\\Winter \ \ \ 53 \ 37.4 \ \ \ 6.4067\\Total \ 150 150 \ 10.5334[/tex]

Hence, Since pvalue ( 0.0145 ) is less than significance level ( 0.05 ), so we reject null hypothesis.

See more about probability at brainly.com/question/795909