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[tex]\text{The base and height have to be factors of 60, since}\\\\~~~~~~~~\text{Area}= \dfrac{1}{2} \times \text{Base} \times \text{Height}\\\\\implies 30 = \dfrac 12 \times \text{Base} \times \text{Height}\\\\\implies \text{Base} \times \text{Height}= 60[/tex]

[tex]\textbf{Example 1:}\\\\\text{Height} = 6~ cm \\\\\text{Base} = 10~ cm\\\\\text{Area} = \dfrac 12 \times 6 \times 10 = 30~ cm^2\\\\\textbf{Example 2:}\\\\\text{Height} = 5~ cm\\\\\text{Base} = 12~ cm\\\\\text{Area} = \dfrac 12 \times 12 \times 5 = 30~ cm^2\\\\\textbf{Example 3:}\\\\\text{Height} =4~ cm\\\\\text{Base} = ~15 ~cm\\\\\text{Area} = \dfrac 12 \times 15 \times 4 = 30~ cm^2[/tex]

Let's see

Base be B

Height be H

So

The ppossible values are

Answer:

i believe the answer is A

Step-by-step explanation:

Answer:

the center is (5,-1) and the radius is 3

Step-by-step explanation:

Answer:

(10, 14)

Step-by-step explanation:

Hello there!

Given such a problem, we have been told to use substitution method to solve it.

To cut it short, substitution refers to replacing a variable with a value.

Here is a way to solve this problem even in future:

Back to our problem,

y = 2x - 6, x = 10

Substitute x into equation y = 2x - 6

y = 2(10) - 6

= 20 - 6

= 14

. ° . x = 10, y = 14

Variables in terms of x and y

(x, y) = (10,14) ✓

This is our answer.

I hope this helps.

Have a nice studies.

Answer:

31°

Step-by-step explanation:

As the opposing side and adjacent side of the angle x are given, we need to take the tan ratio of the angle.

=============================================================

Solving :

⇒ tan x° = 9/15

⇒ tan x° = 3/5

⇒ x = tan⁻¹ (0.6)

⇒ x = 31°

The size of the unknown angle "x"

We'll have to check which is the appropriate one from SOHCAHTOA.

In this question we'll have to use tan because opposite and adjacent is given.

[tex]\large\boxed{Formula: tan(A)= \frac{opp}{adj}}[/tex]

Substitute according to the formula.

[tex]tan \: x= \frac{9}{15}[/tex]

We'll have to use tan inverse.

[tex]x={tan}^{-1}(\frac{9}{15})[/tex]

[tex]x=30.96375653[/tex]

[tex]\large\boxed{x=31° }[/tex]

Hence, the size of the unknown angle "x" is 31°

Answer:

1. Reflection

2. G` will coincide with A, because having a reflection along with BC would mean G` directly goes on A.

3. GBC is congruent to triangle ABC because triangle GBC and triangle ABC have the same exact line measurements, and angles, and share a line.

Step-by-step explanation:

I don't know your notes on 6/3 so number 3 might not be 100% correct.

Answer:

Step-by-step explanation:

We want to identify a rigid transformation that maps congruent triangles to one-another, to explain the coincidence of corresponding parts, and to identify the theorems that show congruence.

__

Triangles GBC and ABC share side BC. Whatever rigid transformation we use will leave segment BC invariant. Translation and rotation do not do that. The only possible transformation that will leave BC invariant is reflection across line BC.

__

In part 3, we show ∆GBC ≅ ∆ABC. That means vertices A and G are corresponding vertices. When we map the congruent figures onto each other, corresponding parts are coincident. That is, vertex G' (the image of vertex G) will coincide with vertex A.

__

The markings on the figure show the corresponding parts to be ...

And the reflexive property of congruence tells us BC corresponds to itself:

There are four available congruence theorems applicable to triangles that are not right triangles

We don't know which of these are in your notes, but we do know that all of them can be used. AAS can be used with two different sides. SAS can be used with two different angles.

SSS

  Corresponding sides are listed above. Here, we list them again:

  AB and GB; AC and GC; BC and BC

SAS

  One use is with AB, BC, and angle ABC corresponding to GB, BC, and angle GBC.

  Another use is with BA, AC, and angle BAC corresponding to BG, GC, and angle BGC.

ASA

  Angles CAB and CBA, side AB corresponding to angles CGB and CBG, side GB.

AAS

  One use is with angles CBA and CAB, side CB corresponding to angles CBG and CGB, side CB.

  Another use is with angles CBA and CAB, side CA corresponding to angles CBG and CGB, side CG.

Answer:

D. 2x-30

Step-by-step explanation:

7x-5(x+6)

7x-5x-30

2x-30

Answer:

49 ÷ 66 × 100= x

Step-by-step explanation:

Answer:

61

Step-by-step explanation:

aₙ = a₁ + (n - 1)d

aₙ = 4 + (20 - 1)3

aₙ = 4 + (19)3

aₙ = 4 + 57

aₙ = 61

Answer:

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Step-by-step explanation:

an acute angle is an angle less than 90 degrees

an obtuse angle is an angle more than 90 degrees

a right angle is an angle equivalent to 90 degrees (looks like two straight lines perpendicular)

a straight angle is an angle equivalent to 180 degrees (looks like a straight line)

a reflex angle is an angle greater than 180 degrees

so, ...

i = right angle

ii = obtuse angle

iii = straight angle

iv = obtuse angle

v = acute angle

Answer:

[tex] \frac{4}{9} [/tex]

Step-by-step explanation:

[tex]( \frac{16 {}^{ \frac{1}{2} } }{81 { }^{ \frac{1}{2} } }) \\ ( \frac{ {4}^{2 \times \frac{1}{2} } }{9^{2 \times \frac{1}{2} } }) \\ ( \frac{4^{1} }{9 ^{1} } ) \\ \frac{4}{9} [/tex]

[tex]: \: \implies \: \sf{ \bigg( \dfrac{4 {}^{2} }{9 {}^{2} } \bigg) } {}^{ \frac{1}{2} } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: 2 \times \frac{1}{2} } }{9 {}^{ \: 2 \times \frac{1}{2} } } \bigg) } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: \cancel2 \times \frac{1}{ \cancel2} } }{9 {}^{ \: \cancel2 \times \frac{1}{ \cancel2} } } \bigg) } \\ \\ : \: \implies \: \sf{ \bigg( \dfrac{4 {}^{ \: 1 }}{9 {}^{ \: 1 } } \bigg) } \\ \\ : \: \implies \: \red{\bf{ \bigg( \dfrac{4 }{9 } \bigg) } }[/tex]

Answer:

8:9

Step-by-step explanation: Add 88+11 to get his weight before=99 Pounds. Then you put together the ratio. 88:99.

The GCF for those numbers would be 11, so divide them both by 11, to get a final answer of 8:9

126 Grams Per Box

Step-by-step explanation:

15 grams of fiber / 5 ounces = 3 grams

3g X 7oz = 21g

21g X 6b = 126g

G - Grams

Oz - Ounces

B - Bars

Answer:

ok so i think its a becuase thats wgat i got

Step-by-step explanation:

Answer: [tex]125^{\circ}[/tex]

Step-by-step explanation:

Angles that form a straight angle are supplementary, so:

[tex]m\angle 1+m\angle 2=180^{\circ}\\ \\ 55^{\circ}+m\angle 2=180^{\circ}\\ \\ m\angle 2=\boxed{125^{\circ}}[/tex]

Answer: it suggests that this equation has no remainder and that the value of x is the factor.

Answer:

10 and 4; and -8 and -5.

Answer:

help me to find Xian pleaseee:( i miss him so much:(

sorry for answering Non sense po i hope u understand me ty po!

Answer:

50.13

Step-by-step explanation:

We can easily find the area of our square, so to get that over with, 6*6=36. Now, for our circle, a full circle would be A=pi*r^2, but we only have half a circle. That means our equation will be A= 1/2(pi*r^2). We have our diameter, but we need our radius. Radius is just half the diameter, so 6/2=3. Now, we multiply. 3^3 is 9, and 9*3.14 is 28.26. All we have to do now is divide that by 2. If we do that, we get 14.13. The area of the semi-circle is 14.13. But we still have to add it to the area of the square, which will be our final step. 36+14.13=50.13, which is your area.

Hope this helps!

The graph which shows the function h(x) according to the task content is; Choice B.

It follows from the task content that the function h(x) = f(x)/4.

On this note, it follows that the values of h(x) in each case is one-fourth of the value of f(x).

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Step-by-step explanation:

it is not important that the triangle is right-angled.

but the distance between each pair of points is calculated via Pythagoras

c² = a² + b²

with c being the Hypotenuse (baseline opposite of the 90° angle) = distance between the end points, and a and b are the legs (= the x and y coordinate differences of the 2 end points) of the virtual right-angled triangles between each pair of points.

so,

AB² = (6 - -3)² + (-4 - -4)² = 9² + 0² = 81

AB = 9 ft

BC² = (6 - 6)² + (8 - -4)² = 0² + 12² = 144

BC = 12 ft

and now for AC, which is because of the special case of how the main triangle is placed and oriented, the same calculation as with Pythagoras for the main right-angled triangle. but I keep showing you the point distance calculation, because this is what you will need in the future for more general triangle or other shapes calculations :

AC² = (6 - -3)² + (8 - - 4)² = 9² + 12² = 81 + 144 = 225

AC = 15 ft

so, Nasir will need

9 + 12 + 15 = 36 ft

of fencing.

x/7 >= -6

x×1/7 >= -6

x>= -6 ÷ 1/7

x>= -6× 7/1

x>= -6×7/1

x>= -42

The legs of the triangle are 6.91 feet, 7.9 feet, and 10.5 feet.

The Pythagoras theorem states that the sum of two squares equals the squared of the longest side.

The Pythagoras theorem formula is given as

H² = P² + B²

The ratio of the one leg of the right triangle to the other leg of the right triangle must be 8:7.

Let x be one leg and y be another leg. Then we have

x/y = 8/7

   y = 7x/8

Then the greatest length of one leg of the right triangle given the other leg of the right triangle is 10.5 feet will be

 10.5² = x² + (7x/8)²

110.25 = x² + 49x²/64

110.25 = 113x²/64

      x² = 62.44

        x = 7.902

        x ≅ 7.9 feet

Then the other leg will be

y = 7.9 x 7 / 8

y = 6.91

More about the Pythagoras theorem link is given below.

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The metaphor and its purpose from the excerpt from "On Beholding the Mountain" is "The heart's flame illustrates the intensity of the writer's emotion".

A metaphor is a figure of speech which is used to compare two things without using "like" or "as", by making the object of the metaphor take on the characteristic of the other thing.

It is also the use of a word or phrase to refer to something that it is not, invoking a direct similarity between the word or phrase used and the thing described but without the words like or as, which would imply a simile.

Therefore, the correct answer is option D; The heart's flame illustrates the intensity of the writer's emotion.

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Answer:

5

Step-by-step explanation:

Spanish: 46

Chinese: 51

Both languages: 46 - 41 = 5

Hope this helps

Answer:

  C, A, E, B, D

Step-by-step explanation:

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

__

Using the expression for x, this is ...

  r·cos(θ) = 2

  r = 2/cos(θ) . . . . divide by cos(θ)

  r = 2·sec(θ) . . . . use the trig identity

__

From above, this becomes ...

  r² = 36

  r = 6 . . . . . . take the square root

__

From above, this becomes ...

  r² = 2·r·sin(θ)

  r = 2·sin(θ) . . . . . . divide by r

__

Using the above relations, this is ...

  r·cos(θ) = √3·r·sin(θ)

  1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

  tan(θ) = 1/√3   ⇒   θ = arctan(1/√3)

  θ = π/6

__

From above, this is ...

  r·cos(θ) = r·sin(θ)

  1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

  θ = arctan(1)

  θ = π/4

_____

Additional comment

An equation of the form y = kx defines a line through the origin and through opposite quadrants of the Cartesian plane. Above, we found the equivalent polar equation to be θ = arctan(k). Using the principal branch of the arctangent function, this is the equation of a ray.

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also an equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

The correct answer for the polar coordinates will be C, A, E, B, D

The polar coordinate system is a two-dimensional coordinate system in which a distance from a reference point and an angle from a reference direction identify each point on a plane. The pole is the reference point, and the polar axis is the ray from the pole in the reference direction.

The conversion relations between rectangular and polar coordinates can be used to find the polar coordinate equivalents. Those relations are ...

x = r·cos(θ)

y = r·sin(θ)

x² +y² = r²

x = 2

Using the expression for x, this is ...

r·cos(θ) = 2

r = 2/cos(θ) . . . . divide by cos(θ)

r = 2·sec(θ) . . . . use the trig identity

x²+y²=36

From above, this becomes ...

r² = 36

r = 6 . . . . . . take the square root

x²+y²=2y

From above, this becomes ...

r² = 2·r·sin(θ)

r = 2·sin(θ) . . . . . . divide by r

x=√3y

Using the above relations, this is ...

r·cos(θ) = √3·r·sin(θ)

1/√3 = sin(θ)/cos(θ) . . . . . . divide by √3·r·cos(θ)

tan(θ) = 1/√3   ⇒   θ = arctan(1/√3)

θ = π/6

x=y

From above, this is ...

r·cos(θ) = r·sin(θ)

1 = sin(θ)/cos(θ) = tan(θ) . . . . divide by r·cos(θ)

θ = arctan(1)

θ = π/4

However, the tangent function is periodic with period π, so θ = arctan(k)+π is also equivalent to the rectangular equation. It is the opposite ray, so forms the complete line when joined with the first ray.

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Answer:

P = 20

Step-by-step explanation:

Hello!

We can solve this by substituting -4 for t.

Remember that any negative number squared is the absolute value of that number squared.

The final evaluation is 20.

Answer:

-3k^3+8k

Step-by-step explanation:

-2k^3-k^3+8k

Combine like terms

-3k^3+8k

Answer: Standard Form: [tex]-3k^3+8k[/tex]

Step-by-step explanation:

[tex]-k*(3k^2-8)=-3k^3+8k[/tex]

Step 1:

[tex]((0 - 2k^3) - k^3) + 8k[/tex]

Pull out like factors, Pulling out like terms:  [tex]8k - 3k^3 = -k[/tex] • [tex](3k^2 - 8)[/tex]

Factoring: [tex]3k^2 - 8[/tex]

Final result:

[tex]-3k^3+8k[/tex]

A total of 720 tickets were sold for the school play. They were either adult tickets or student tickets is mathematically given as

Generally, the equation for a sold tickets is mathematically given as

S=x+72

Therefore

x+x+72=772

2x+72=772

2x=772-72

x=350

In conclusion, tickets sold was

x=350

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Answer:

This is the i-ready test, you have to try your best because if someone were to give you the answer, that will be cheating. The test provides teachers with a complete picture of student performance relating to their grade level and national norms. So, just try your best so you can get the lessons that are right for you.

(Im just saying but you don't have to listen to me ^^)