Pretty simple physics :) will give brainliest
pls dont just use me for points

Answer:

(1) R n = ( 1 − α ) R si − L ↑ + L ↓ where Rn is the net radiation (W m−2), Rsi is the solar radiation (W m−2), α is the soil surface albedo (α = 0–1

Explanation:

Answer:

[tex]V = IR[/tex]

Explanation:

Required

Which equation represents ohm's law?

Literally, ohm's law implies that current (I) is directly proportional to voltage (V) and inversely proportional to resistance (R).

Mathematically, this can be represented as:

[tex]I\ \alpha\ \frac{V}{R}[/tex]

Convert the expression to an equation

[tex]I\ =\ \frac{V}{R}[/tex]

Multiply both sides by R to make V the subject

[tex]I\ * R\ =\ \frac{V}{R} * R[/tex]

[tex]I\ * R\ =V[/tex]

Reorder

[tex]V = I\ * R[/tex]

[tex]V = IR[/tex]

Option (a) is correct; Others are not

Answer:

V=ir

Explanation:

Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. The correct answers from the choices are:

v = ir

Answer:

organ

Explanation:

Answer:

an organ

Explanation:

cell -> tissue -> organ -> organ system -> organism

Answer: Plant A

Explanation: The control group is participants who do not receive the experimental treatment.

Answer:

HOPE IT HELPS.....

Explanation:

The legal standard for drunkenness across the United States ranges from 0.10 to 0.08. If a person's BAC measures 0.08, it means that there are 0.08 grams (i.e., 80 mg) of alcohol per 100 ml of blood. The American Medical Association says that a person can become impaired when the blood alcohol level hits 0.05.

Answer: 0.08

Driving While Intoxicated or Impaired is Illegal

Under Michigan law, it is illegal to drive: While intoxicated, or impaired, by alcohol, controlled substance, or other intoxicating substance. With a bodily alcohol content of 0.08 or more. (This crime is one of the driving while intoxicated offenses.)

Hope this helps... Stay safe and have a Merry Christmas!!!!!!!! :D

Answer:

[tex]\boxed {\boxed {\sf B. \ 23}}[/tex]

Explanation:

The mass number is found by adding up the nucleons in an atom.

The nucleons are the subatomic particles found in the nucleus, so just protons and neutrons.

There are 11 protons and 12 neutrons.

Add them together.

[tex]mass \ number = protons + neutrons[/tex]

[tex]mass \ number= 11+12[/tex]

[tex]mass \ number= 23[/tex]

The mass number for this atom is 23.

Answer:

diverging lens

Explanation:

Since the nature of the problem of nearsightedness is that the light is focused in front of the retina, a diverging lens will serve to diverge light before it reaches the eye. This light will then be converged by the cornea and lens to produce an image on the retina.

Answer:

The minimum work done by the heart is 1.911 J

Explanation:

Given;

mass of the blood, m = 130 g = 0.13 kg

height the blood is pumped, h = 1.5 m

Apply work energy theorem, the gravitational potential energy of the height in which the blood is pumped to, is equal to the work done in pumping the blood form the foot to the heart.

E = mgh = W

where;

g is acceleration due to gravity = 9.8 m/s²

W = (0.13)(9.8)(1.5)

W = 1.911 J

Thus, the minimum work done by the heart is 1.911 J

Answer:

v_maria > 4.5 m/s

v_samantha > 3.8 m/s

Explanation:

Formula for centripetal acceleration is;

a_c = v²/r

Where;

v is speed

r is radius

For Maria;

r = 12 m

v = 4.5 m/s

Thus;

a_c = 4.5²/12

a_c = 1.6875 m/s²

For Samantha;

r = 6

v = 3.8 m/s

Thus;

a_c = 3.8²/6

a_c = 2.41 m/s²

We want to find how could each skater increase her centripetal acceleration without changing the size of her path.

From the centripetal acceleration formula, since the size of path can't be changed it means the radius can't be changed and so the only thing that can now increase the centripetal acceleration is when the speed increases.

Thus;

For Maria, she has to move with a faster speed. Thus: v_maria > 4.5 m/s

For Samantha, she also has to move with a faster speed. Thus; v_samantha > 3.8 m/s

Answer:

Since there is no air resistance on the Moon, all objects would be in free fall at 1.6 m/s2. This means that they would all hit the ground at the same time if released simultaneously from the same height, but at a slower speed compared to objects free falling in a vacuum on Earth.

Explanation:

Answer:

The end temperature is 174 °C

Explanation:

Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

So, being:

and replacing:

2 atm*V= 2 moles* 0.082 [tex]\frac{atm*L}{mol*K}[/tex] *298 K

you get:

[tex]V=\frac{2 moles* 0.082\frac{atm*L}{mol*K} *298 K}{2 atm}[/tex]

V= 24.436 L

Now, two moles of neon gas is expanded to 3 times the original volume while the pressure is reduced to 1.0 atm. Then you know:

Replacing:

1 atm*73.308 L= 2 moles* 0.082 [tex]\frac{atm*L}{mol*K}[/tex] *T

Solving:

[tex]T=\frac{1 atm*73.308 L}{2 moles* 0.082\frac{atm*L}{mol*K}}[/tex]

T= 447 °K= 174 °C (being 0°C=273 °K)

The end temperature is 174 °C

Answer:

200rad/s

Explanation:

The angular frequency of oscillation of the pendulum is 44.3 rad/s.

Angular frequency is defined as the rate of change of angular displacement in a simple harmonic motion.

Here,

Angular displacement of the pendulum, θ = 0.32 rad

Angular acceleration, α = -630 rad/s²

We know that the equation for angular acceleration is given by,

α = -ω²θ

where ω is the angular frequency

ω² = -α/θ

ω² = 630/0.32

ω² = 1968.8

Therefore,

Angular frequency, ω = √1968.8

ω = 44.3 rad/s

Hence,

The angular frequency of oscillation of the pendulum is 44.3 rad/s.

To learn more about angular frequency, click:

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Answer:

The displacement is 6.4m

Explanation:

Step one:

given

we are told that Lucy runs 4 meters to the east,

then 5 meters south.

let the distance east be the displacement in the x-direction, and south be the y-direction

Step two:

The resultant of the x and y displacement is the magnitude of the total displacement z

applying Pythagoras theorem we have

z=√x^2+y^2

z=√4^2+5^2

z=√16+25

z=√41

z=6.4m

Absolute zero, technically known as zero kelvins, equals −273.15 degrees Celsius, or -459.67 Fahrenheit, and marks the spot on the thermometer where a system reaches its lowest possible energy, or thermal motion.

Explanation:

Given parameters:

Mass of Jogger  = 60kg

Time  = 4s

Vertical height  = 4.5m

Unknown:

Jogger's power output  = ?

Energy required  = ?

Solution:

The power output of the jogger is defined as the rate at which work is done.

 Power  = [tex]\frac{force x distance}{time}[/tex]  

Now insert the parameters and solve;

  Work done = Force x distance = mgh

   m is the mass

   g is the acceleration due to gravity = 9.8m/s²

    h is the height

  Work done  = 60 x 9.8 x 4.5  = 2646J

 Power = [tex]\frac{2646}{4}[/tex]   = 661.5W

Energy required;

 The work done here is also the energy required;

 Energy required  = 2646J

The energy required is 2646 J and the jogger's power output 661.5 W.

Given here,

Mass of Jogger  = 60 kg

Time  = 4s

Vertical height  = 4.5 m

The power output of the jogger is defined as the rate of energy tranfer  work is done.

Power  =  W/t

Where,

W- work = mgh = 60 kg  x  9.8 m/s² x 4.5 m = 2646 J

t - time - 4 s

Put the values, we get

Power = 661.5W

To know more about power,

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Answer:

The answer is 493.05kJ

Explanation:

given

mass m= 3kg

t1=  10°C

t2= 60°C

Specific heat capacity of ham =3287 cal/kgºC

Required,

The quantity of heat, Q

Step two:

the formula is

Q= mcΔT

substitute

Q= 3*3287(60-10)

Q=9861*50

Q=493050 J

Q= 493.05kJ

Answer:

Cannot move off with high speed

Explanation:

Just did it

Answer:

Pt 1: [tex]W=39J[/tex]

Pt 2: θ = [tex]19.7[/tex]

Explanation:

Part 1:

[tex]W=FS[/tex]

[tex]W=F_{_xs_x}+F{_ys_y}[/tex]

imagine the "i"and the "j" with the hat

[tex]W=(10i-1j)(4i+3j)[/tex]

[tex]W=(10*4)-(1*1)[/tex]

[tex]W=40-1[/tex]

[tex]W=39J[/tex]

Part 2:

[tex]|F|=\sqrt{10^2+(-1)^2}[/tex]

[tex]|F|=\sqrt{101}[/tex]

[tex]|S|=\sqrt{4^2+1^2}[/tex]

[tex]|S|=\sqrt{17}[/tex]

[tex]W=|F||S|cos[/tex]θ

[tex]39=(\sqrt{101})(\sqrt{17} )cos[/tex]θ

θ = [tex]19.7[/tex]

Hope it helps

Answer:

[tex]W_F=127.64283 J[/tex]

Explanation:

Information Given:

[tex]m = 5kg[/tex]  [tex]v=constant[/tex]

Key: μ = Kinetic Friction (Kf)   θ = Theta α = 180° N = Normal Force

[tex]W_F=F_ydcos[/tex]θ

[tex]W_F=Fdsin[/tex]θ

[tex]_{net}F_y = sin[/tex]θ-μ[tex]N-mg=0[/tex]

[tex]_{net}F_x = 0[/tex]

[tex]N=Fcos[/tex]θ

[tex]Fsin[/tex]θ-μ[tex]N=mg[/tex]

[tex]Fsin[/tex]θ-μ[tex]Fcos[/tex]θ[tex]=mg[/tex]

[tex]F=\frac{mgdsin(theta)}{sin(theta)-(Kf)cos(theta)}[/tex] →[tex]W_F=\frac{mgdsin(theta)}{sin(theta)-(Kf)cos(theta)}[/tex]

[tex]W_F=\frac{(2)(9.81)(2)sin(30)}{sin(30)-(0.40)cos(30)}[/tex]

[tex]W_F=127.64283 J[/tex]

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Answer:

False

Explanation:

Answer:

False because cells depend on the others and absolutely positively CANNOT work alone.

Explanation:

Answer:

the object's weight changes but its mass stays the same

Answer:

the object's weight changes but its mass stays the same

Explanation:

100% correct

Answer:

every 4 years

Explanation:

Answer:

Every four years

Explanation:

Answer:

W = 6642 J

Explanation:

Given that,

Mass of a crate, m = 67 kg

Force with which the crate is pulled, F = 738 N

It is moved 9 m across a frictionless floor

We need to find the work done in moving the crate. Let the work done is W. It is given by :

W = F d

W = 738 N × 9 m

= 6642 J

So, the work done is 6642 J.

Answer:

Component

Explanation:

All circuits have some basic parts, called components. One component is the power source, also called a voltage source. The power source is what pushes the electricity through the circuit.

Answer:

Waxing Gibbous

Explanation:

New Moon Rises at sunrise, transits meridian at noon, sets at sunset

Explanation:

Answer:

D i think

Explanation:

Heavier objects (objects with more mass) are more difficult to move and stop.

Answer:

Increasing the mass of the object (option D in the list of answers)

Explanation:

Recall that F = m x a

therefore, if the mass increases, the force increases

Answer:

a.75cm

Explanation: