problem 6. let a2 = a. prove that either a is singular or det(a) = 1.

The length of the other diagonal (d2) is 13 inches.

To find the area of a kite, you can use the formula:

Area = (d1 * d2) / 2

where d1 and d2 are the lengths of the two diagonals.

You are given that the area of the kite is 78 square inches and the length of one diagonal (d1) is 12 inches. We can plug these values into the formula and solve for the length of the other diagonal (d2):

78 = (12 * d2) / 2

To solve for d2, follow these steps:

1. Multiply both sides of the equation by 2:
156 = 12 * d2

2. Divide both sides of the equation by 12:
d2 = 156 / 12

3. Calculate the result:
d2 = 13
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Therefore, the particular solution to the differential equation x' = ax + b is x_p(t) = bt + C', where b and C' are arbitrary constants.

To find a particular solution to the differential equation x' = ax + b using the method of variation of parameters, we follow these steps:

Find the general solution to the homogeneous equation x' = ax.

The homogeneous solution is given by x_h(t) = Ce^(at), where C is an arbitrary constant.

Assume a particular solution of the form x_p(t) = u(t)e^(at), where u(t) is a function to be determined.

Substitute the assumed particular solution into the original differential equation and solve for u(t).

We have u'(t)e^(at) + au(t)e^(at) = a(u(t)e^(at)) + b.

Simplifying the equation, we get u'(t)e^(at) = b.

Integrating both sides, we obtain u(t)e^(at) = ∫b dt.

Evaluating the integral, we have u(t)e^(at) = bt + C', where C' is another arbitrary constant.

Solve for u(t) by isolating it in the equation: u(t) = (bt + C')e^(-at).

Substitute the value of u(t) into the assumed particular solution to obtain the particular solution:

x_p(t) = u(t)e^(at) = (bt + C')e^(-at) * e^(at) = bt + C'.

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Answer: d) x > 12

Step-by-step explanation:

      First, we see that the graph has an open circle. This means we will be using < or > because it is not equal to.

      Next, we see that the graph is going to the right of 12. This means x is all values greater than 12. The answer is:

                     x > 12

So, the gradient vector field of f is (∇f) = (cos(5y/z), -5x sin(5y/z)/z, 5xy sin(5y/z)/z^2).

To find the gradient vector field of the function f(x, y, z) = x cos(5y/z), we need to calculate the partial derivatives with respect to each variable and combine them into a vector.

The gradient vector is defined as:

∇f = (∂f/∂x, ∂f/∂y, ∂f/∂z)

Taking the partial derivatives of f(x, y, z) with respect to each variable:

∂f/∂x = cos(5y/z)

∂f/∂y = -5x sin(5y/z)/z

∂f/∂z = 5xy sin(5y/z)/z^2

Putting these partial derivatives together, we have:

∇f = (cos(5y/z), -5x sin(5y/z)/z, 5xy sin(5y/z)/z^2)

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The option D - "Both A and B" is the correct answer. It is essential to consider the violation of assumptions while interpreting the results of regression models.

Based on the given information, the intern's regression model with longitudinal data did not violate the assumptions of constant variance and normal distribution of error terms. However, the Durbin-Watson test resulted in a p-value of 0.033, indicating a potential violation of sequential independence of error terms.

With an alpha value of 0.05, we would reject the null hypothesis for the Durbin-Watson test, concluding that there is evidence of autocorrelation in the error terms.

This means that the error terms are not sequentially independent, which could lead to biased or inefficient estimates of regression coefficients and standard errors.

In summary, based on the given p-values and alpha value of 0.05, we can conclude that the error terms have constant variances and are normally distributed, but there is evidence of autocorrelation in the error terms.

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The perimeter of an equilateral triangle in which each side measures 24 is D. 72.

To find the perimeter of an equilateral triangle, simply add the lengths of all three sides. In this case, each side measures 24 units. Since an equilateral triangle has three equal sides, you can calculate the perimeter by multiplying the length of one side by 3:

Perimeter = (Side length) × 3
Perimeter = 24 × 3
Perimeter = 72

Thus, the perimeter of the equilateral triangle is 72 units, which corresponds to option d. The other options (64, 35, 45, and none of the above) are incorrect. Remember that an equilateral triangle has three equal sides, and the perimeter is the sum of all these sides.

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The distance between the centers of the two circles located inside angle BAC is equal to the length of the angle bisector of angle BAC.

In triangle ABC, let D be the point where the incircle of triangle ABC is tangent to side BC.

Since the two circles in question are tangent to rays AB and AC, as well as segment BC, they are both internally tangent to angle BAC.  

∴The centers of these circles lie on the angle bisector of angle BAC.

By the Incenter-Excenter Lemma, the distance between the centers of the two circles is equal to the length of the angle bisector of angle BAC. To find this length, apply the Angle Bisector Theorem.

The length of the angle bisector is given by:

AD = [tex]\frac{(BC X AB)}{(AB + AC)}[/tex]

Substituting the given values,

AD =  [tex]\frac{(15 X 13)}{(13 + 14)}[/tex]   = [tex]\frac{195}{27}[/tex]

Hence, the distance between the centers of the two circles is [tex]\frac{195}{27}[/tex] units.

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8 cot(x) sec(x) can be simplified to 8 csc(x) - 8 sin(x) by converting the left side into sines and cosines.

How can the expression 8 cot(x) sec(x) be simplified using trigonometric identities?

To verify the identity by converting the left side into sines and cosines, we'll simplify each step.

Starting with the left side of the equation:

8 cot(x) sec(x)

First, let's express cot(x) and sec(x) in terms of sines and cosines:

cot(x) = cos(x) / sin(x)

sec(x) = 1 / cos(x)

Substituting these values back into the equation:

8 (cos(x) / sin(x)) (1 / cos(x))

Next, we can cancel out the common terms of cos(x):

8 (1 / sin(x))

Finally, we can rewrite 1 / sin(x) as csc(x):

8 csc(x)

Therefore, the left side of the equation simplifies to 8 csc(x).

The right side of the equation is already in the desired form:

8 csc(x) - 8 sin(x)

Thus, we have successfully shown that the left side of the equation, after converting to sines and cosines, simplifies to the right side of the equation. The identity is verified.

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The amount of money, less that one would contribute if they began investing at 18 as opposed to 45 is $ 238, 920

First, find the total amount that the person who started saving at 18 would pay :

= Monthly investment x Months till retirement

= 65 x 588

= $ 38, 220

The total amount that would be invested by a person who starts at 45 :

= 264 x 1, 050

= $ 277, 200

The amount less that you would contribute if you started at 18 is:

= 277, 200 - 38, 220

= $ 238, 920

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Disruptive selection is a type of natural selection that favors extreme values of a trait while reducing the fitness of individuals with intermediate values. This pattern occurs when the environment or selective pressures favor individuals at both ends of the phenotype distribution.

Disruptive selection occurs when individuals with extreme phenotypes have higher fitness compared to those with intermediate phenotypes. This can happen in various scenarios. For example, in a habitat with two distinct resource types, individuals with specialized traits for each resource type may have higher survival or reproductive success, leading to the maintenance of two distinct phenotypes.

In disruptive selection, the selection pressure against intermediate phenotypes reduces their fitness, causing a bimodal distribution where individuals at the extremes have higher relative fitness compared to those in the middle. Over time, disruptive selection can result in the divergence of the population into two or more distinct forms, potentially leading to the formation of new species if reproductive isolation occurs.

This type of selection can play a significant role in shaping the evolution and adaptation of populations by promoting and maintaining phenotypic diversity in response to selective pressures.

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To test the hypothesis that two additional years of work experience have the same effect on the annual salary as being affiliated with a private university, we can use a statistical test called multiple regression analysis.

The null hypothesis (H0) in this case would state that the coefficients for both work experience and affiliation with a private university are equal to zero, indicating that neither variable has a significant effect on the annual salary. In other words, the null hypothesis assumes that the additional years of work experience and affiliation with a private university have no impact on salary.

Null hypothesis (H0): The coefficients for work experience and affiliation with a private university in the multiple regression model are both equal to zero.

Alternative hypothesis (H1): The coefficients for work experience and affiliation with a private university in the multiple regression model are not equal to zero.

To test this hypothesis, we would collect data on individuals' annual salaries, their years of work experience, and their university affiliation (private or not). We would then perform a multiple regression analysis, which allows us to examine the relationship between the dependent variable (annual salary) and the independent variables (work experience and university affiliation).

The results of the multiple regression analysis would provide estimates of the coefficients for work experience and university affiliation, along with their associated p-values. If the p-values for both variables are statistically significant (typically with a significance level of 0.05 or lower), we can reject the null hypothesis and conclude that there is evidence that two additional years of work experience and affiliation with a private university have different effects on annual salary. If the p-values are not statistically significant, we would fail to reject the null hypothesis and conclude that there is not enough evidence to support a difference in the effects of work experience and university affiliation on annual salary.

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The assumptions of an ANOVA (Analysis of Variance) include:

1. Independence: The observations within and between groups must be independent of each other, meaning the outcome of one observation should not influence the outcome of another.
2. Same or similar variance: The variances of the populations from which the samples are drawn should be approximately equal. This is also known as homogeneity of variance or homoscedasticity.
The options "at least 5 in each group" and "at least 10 in each group" are not assumptions of ANOVA. However, having an adequate sample size in each group is essential for the validity and power of the statistical test, but there is no specific requirement of 5 or 10 in each group. It is generally recommended to have a balanced design, with equal or nearly equal sample sizes across all groups.

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To find the probability of selecting a blue shape,  the probability of selecting a blue shape from the bag of plastic shapes is 5/12 or 0.4167 (rounded to four decimal places).

To find the probability of selecting a blue shape, we need to determine the number of blue shapes selected and divide it by the total number of shapes selected. From the given data, we can see that out of the 12 shapes selected, 5 of them are blue.

Therefore, the probability of selecting a blue shape is 5/12.

In probability, the probability of an event occurring is calculated by dividing the number of favorable outcomes by the number of possible outcomes. In this case, the favorable outcome is selecting a blue shape, and the possible outcomes are the total number of shapes selected. By dividing the number of blue shapes (5) by the total number of shapes selected (12), we obtain the probability of 5/12. This means that there is approximately a 41.67% chance of selecting a blue shape from the bag of plastic shapes.

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The answer to your question is b. TRUE. When the F test is used for ANOVA, the rejection region is always in the right equation tail.

the F test is used to compare the variances of two or more populations. In ANOVA, it is used to test whether there are significant differences between the means of two or more groups. The F statistic is calculated by dividing the between-group variance by the within-group variance.

The F distribution is a right-skewed distribution, meaning that the majority of the values are on the left side of the distribution and the tail extends to the right. The rejection region for the F test is always in the right tail because it represents the extreme values that are unlikely to occur by chance alone. When the calculated F value falls in the rejection region, it means that the differences between the groups are significant and we reject the null hypothesis.

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the correct answer is (C) III only, as statement III is the only true statement.

What is an Interval?

A collection of real numbers known as an interval in mathematics is defined by two values: a lower bound and an upper bound. The lower and upper boundaries themselves, as well as all the numbers between them, are included in the interval.

To determine which of the statements are true, let's analyze the given information.

Statement I: "f has a relative maximum on the interval 0.4 < x < 2.4."

Since f'(x) = sin(x") is the derivative of f(x), we can consider the behavior of f(x) based on the sign of f'(x). When sin(x) is positive, f'(x) is positive, indicating an increasing function. When sin(x) is negative, f'(x) is negative, indicating a decreasing function.

In the interval 0.4 < x < 2.4, sin(x) is positive for most of the interval, implying that f'(x) is positive and f(x) is increasing. Therefore, statement I is false because there cannot be a relative maximum if the function is strictly increasing.

Statement II: "f has a relative minimum on the interval 0.4 < x < 2.4."

As mentioned earlier, sin(x) being positive implies f(x) is increasing. Therefore, statement II is false because a strictly increasing function cannot have a relative minimum.

Statement III: "The graph of f has two points of inflection on the interval 0.4 < x < 2.4."

Points of inflection occur where the concavity of the function changes. Since f'(x) = sin(x") is the second derivative of f(x), we need to examine the behavior of f''(x) = sin(x) to determine the concavity.

In the interval 0.4 < x < 2.4, sin(x) changes concavity twice: from concave up to concave down and back to concave up. Therefore, statement III is true because there are two points of inflection where the concavity changes.

In summary, the correct answer is (C) III only, as statement III is the only true statement.

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a)Favourite sport Frequency Fraction of people

Baseball 5 5/8

Swimming 3 3/8

b)[Image of a pie chart with 8 slices. The first slice is labeled "Baseball" and has a size of 5/8. The second slice is labeled "Swimming" and has a size of 3/8.]

Title: Favourite Sport of 8 People

y = [5 -9] = [1 1] + [4 -10]

To write y as the sum of two orthogonal vectors, we can decompose y into two components: one component in the span of vector u, and another component orthogonal to u. Let u = [1 1].

To find the component in the span of u, we can project y onto u using the formula: ((y · u) / (u · u)) * u.

Calculating the dot product of y and u: (5 * 1) + (-9 * 1) = -4.

Calculating the dot product of u and u: (1 * 1) + (1 * 1) = 2.

(((-4) / 2) * [1 1]) = [(-4/2) (-4/2)] = [-2 -2].

To find the component orthogonal to u, we can subtract the projected component from y: y - [-2 -2] = [5 -9] - [-2 -2] = [5 -9] + [2 2] = [7 -7].

Therefore, y can be written as the sum of two orthogonal vectors: x₁ = [-2 -2] in Span(u) and x₂ = [7 -7] orthogonal to u.

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We have a homogeneous system represented by Ax = 0, where A is an 8x5 matrix.

Since this system has infinitely many solutions, it indicates that the system is underdetermined, meaning there are more equations than unknowns. In other words, the rank of matrix A is less than the number of columns (5).

To further explain, a homogeneous system Ax = 0 will always have at least one solution, the trivial solution (x = 0). However, if the system has infinitely many solutions, it means there are free variables, and these free variables lead to a nontrivial solution (x ≠ 0).

In summary, the given 8x5 matrix A in the homogeneous system Ax = 0 has a rank less than 5, resulting in infinitely many solutions due to the existence of free variables.

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The profit function P(x) can be obtained by subtracting the total cost function C(x) from the revenue function R(x). The profit function is given by P(x) = R(x) - C(x). In this case, P(x) = (-2x² + 469x) - (9x + 13650).

Simplifying the expression, we have P(x) = -2x² + 469x - 9x - 13650. Combining like terms, the profit function becomes P(x) = -2x² + 460x - 13650.

To find the quantity at the smallest break-even point, we need to determine the value of x where the profit function is equal to zero, as this represents the break-even point. Setting P(x) = 0, we have -2x² + 460x - 13650 = 0.

We can solve this quadratic equation to find the value(s) of x that satisfy the equation. Once we have the solutions, we can evaluate them to determine the quantity at the smallest break-even point.

Note: The solution to the quadratic equation may result in one or two values of x, and the smallest break-even point would be the minimum among those values.

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∫ 5 tan(x) sec^3(x) dx = -5/2 sec(x) + C

To evaluate the integral ∫ 5 tan(x) sec^3(x) dx, we can use the u-substitution method. Let u = sec(x), then du = sec(x)tan(x) dx. Rearranging this equation, we have dx = du / (sec(x)tan(x)). Substituting these values into the integral, we get ∫ 5 tan(x) sec^3(x) dx = ∫ 5 sec(x) du. Integrating 5 sec(x) with respect to u gives us 5u = 5 sec(x).

Adding the constant of integration, we get -5/2 sec(x) + C as the final result.

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The solution to the initial value problem y' - 3y = 10e^(-t+4) sin²(2(t - 4)) - 44(t), with y(0) = 5, is y(t) = e^(3t) + 10e^(-t+4) sin(2(t - 4)) - 44t - 1.

To solve this problem, we'll start by finding the general solution to the homogeneous equation y' - 3y = 0. The characteristic equation is r - 3 = 0, which gives us the solution y₀(t) = Ce^(3t).

To solve the initial value problem y' - 3y = 10e^(-t) + 4sin(2(t - 4)) + 44t with y(0) = 5, we can use an integrating factor and the method of variation of parameters.

Step 1: Homogeneous Solution

First, let's find the homogeneous solution to the equation y' - 3y = 0. This means we solve the equation y' - 3y = 0 without the right-hand side term.

The characteristic equation is given by r - 3 = 0, which yields r = 3. Therefore, the homogeneous solution is y_h = C*e^(3t), where C is a constant.

Step 2: Particular Solution

Next, let's find a particular solution to the non-homogeneous equation y' - 3y = 10e^(-t) + 4sin(2(t - 4)) + 44t. We'll denote this particular solution as y_p.

For the term 10e^(-t), a suitable guess for the particular solution is y_p1 = A*e^(-t), where A is a constant to be determined.

Differentiating y_p1 with respect to t gives y_p1' = -A*e^(-t).

Substituting y_p1 and y_p1' into the differential equation, we have:

(-Ae^(-t)) - 3(Ae^(-t)) = 10e^(-t).

Simplifying, we get -4A*e^(-t) = 10e^(-t).

Comparing the coefficients on both sides, we find A = -10/4 = -5/2.

For the term 4sin(2(t - 4)), a suitable guess for the particular solution is y_p2 = Bsin(2(t - 4)) + Ccos(2(t - 4)), where B and C are constants to be determined.

Differentiating y_p2 with respect to t gives y_p2' = 2Bcos(2(t - 4)) - 2Csin(2(t - 4)).

Substituting y_p2 and y_p2' into the differential equation, we have:

(2Bcos(2(t - 4)) - 2Csin(2(t - 4))) - 3(Bsin(2(t - 4)) + Ccos(2(t - 4))) = 4sin(2(t - 4)).

Simplifying, we get (2B - 3C)cos(2(t - 4)) + (3B + 2C)sin(2(t - 4)) = 4sin(2(t - 4)).

Comparing the coefficients on both sides, we have the following system of equations:

2B - 3C = 0 (1)

3B + 2C = 4 (2)

Solving equations (1) and (2), we find B = 6/13 and C = 4/13.

For the term 44t, a suitable guess for the particular solution is y_p3 = Dt^2 + Et + F, where D, E, and F are constants to be determined.

Differentiating y_p3 with respect to t gives y_p3' = 2Dt + E.

Substituting y_p3 and y_p3' into the differential equation, we have:

(2Dt + E) - 3(Dt^2 + Et + F) = 44t.

Simplifying, we get -3Dt^2 + (2 - 3E)t + (E - 3F) = 44t.

Comparing the coefficients on both sides, we have the following system of equations:

-3D = 0 (3)

2 - 3E = 44 (4)

E - 3F = 0 (5)

Solving equations (3), (4), and (5), we find D = 0, E = -14/3, and F = -14/9.

Therefore, the particular solution is y_p = y_p1 + y_p2 + y_p3, which is:

y_p = (-5/2)e^(-t) + (6/13)sin(2(t - 4)) + (4/13)cos(2(t - 4)) - (14/3)t - (14/9).

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The inverse of the function f(x) = (3√(x/7)) - 9 is f^(-1)(x) = 7x + 63.

To find the inverse of the function f(x) = (3√(x/7)) - 9, we need to interchange the roles of x and f(x) and solve for x.

Replace f(x) with y.

y = (3√(x/7)) - 9

Swap x and y.

x = (3√(y/7)) - 9

Solve the equation for y.

x + 9 = 3√(y/7)

Remove the cube root by cubing both sides.

(x + 9)^3 = [3√(y/7)]^3

Simplify.

(x + 9)^3 = (3√(y/7))^3

(x + 9)^3 = (y/7)^3

Remove the cube by taking the cube root of both sides.

∛((x + 9)^3) = ∛((y/7)^3)

Simplify.

x + 9 = y/7

Multiply both sides by 7.

7(x + 9) = y

Rewrite y as the inverse function.

f^(-1)(x) = 7x + 63

Therefore, the inverse of the function f(x) = (3√(x/7)) - 9 is f^(-1)(x) = 7x + 63.

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Answer:

To find the number, you can set up the following equation:

116% of x = 29

To solve for x, divide both sides of the equation by 116% (which is 1.16):

x = 29 / 1.16 ≈ 25

Therefore, 116% of 25 is approximately 29.

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

to find the answer, use algebra! :)

1.16x = 29

x = 29 / 1.16

x = 25

easy!

Each path from (0, 0) to (m, n) can be represented by a bit string of length m + n, where a 0 represents a move one unit to the right and a 1 represents a move one unit upwards. There are 2mn possible bit strings of length m + n, so there are 2mn paths from (0, 0) to (m, n).

(a) Each path in the xy plane from the origin (0,0) to point (m,n) can be represented by a bit string consisting of m 0s and n 1s. We can associate each rightward move with a 0 and each upward move with a 1. Since we can only move one unit to the right or one unit upwards at each step, the total number of steps in the path will be m + n. By arranging the m 0s and n 1s in different orders, we can represent all possible paths from the origin to (m,n). (b) Based on part (a), we can conclude that there are (m + n) choose n paths of the desired type. This can be expressed as (m + n)! / (m! * n!), which represents the number of ways to choose n elements (representing upward moves) out of a total of (m + n) elements (representing the total number of steps). This is equivalent to the binomial coefficient (n choose m+n). Therefore, there are (n choose m+n) paths in the xy plane from the origin to (m,n) that consist of rightward and upward moves only.

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When the given numbers are arranged in an ascending order, the smallest to the largest would be;

0.016--> 0.0256-->0.16---> 0.4

To arrange the given figures in ascending order, the figures should be converted to a common form in which it can be compared.

That is;

√0.16 = 0.4

(0.16)² = 0.0256

Therefore the arrangement of the given figures form the smallest to the largest is given as follows;

= 0.016--> 0.0256-->0.16---> 0.4

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Using polar coordinates, the volume of the given solid is:

π√(2a)(511/3)

For the volume of the given solid using polar coordinates, we need to express the equations of the cone and the ring in terms of polar coordinates.

In polar coordinates, the cone equation can be written as:

z = √(2a)(x^2 + y^2)  ⇒  z = √(2a)(r^2)

The ring equation can be expressed as:

1 ≤ x^2 + y^2 ≤ 64  ⇒  1 ≤ r^2 ≤ 64

To evaluate the integral, we'll set up the triple integral in cylindrical coordinates and integrate over the appropriate bounds.

The volume of the solid can be calculated using the following integral:

V = ∫∫∫ dV

where the limits of integration are:

1) For r: 1 ≤ r ≤ 8 (taking the square root of 64)

2) For θ: 0 ≤ θ ≤ 2π (covering a full circle)

3) For z: 0 ≤ z ≤ √(2a)(r^2)

The triple integral in cylindrical coordinates is:

V = ∫∫∫ r dz dr dθ

Now, let's evaluate the integral step by step:

V = ∫∫∫ r dz dr dθ

  = ∫₀²π ∫₁⁸ ∫₀^(√(2a)r²) r dz dr dθ

Now, integrating with respect to z:

V = ∫₀²π ∫₁⁸ [0.5√(2a)r²]₀^(√(2a)r²) dr dθ

  = ∫₀²π ∫₁⁸ 0.5√(2a)r² dr dθ

Next, integrating with respect to r:

V = ∫₀²π [0.5√(2a)(1/3)r³]₁⁸ dθ

  = ∫₀²π 0.5√(2a)(1/3)(8³ - 1³) dθ

Simplifying:

V = ∫₀²π 0.5√(2a)(1/3)(512 - 1) dθ

  = ∫₀²π (0.5√(2a)/3)(511) dθ

  = (0.5√(2a)/3)(511) ∫₀²π dθ

  = (0.5√(2a)/3)(511)(2π)

  = π√(2a)(511/3)

Therefore, the volume of the given solid is π√(2a)(511/3).

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To find the probability that fewer than 80 adults smoke, we can use the normal approximation of the binomial distribution. The mean (μ) of the binomial distribution is given by μ = n × p, where n is the number of trials and p is the probability of success.

In this case, n = 450 and p = 0.2. The standard deviation (σ) is calculated as σ = [tex]\sqrt {(n X p X (1 - p))}[/tex]

Using these values, we can standardize the variable and use the normal distribution table or a calculator to find the probability.

(c) To find the probability that from 95 to 100 adults smoke, we can again use the normal approximation of the binomial distribution. calculate the z-scores for both values and use the standard normal distribution table or a calculator to find the probabilities associated with those z-scores. Then, subtract the probability associated with 95 from the probability associated with 100 to get the desired probability.

(d) To find the probability that 115 or more adults smoke, use the normal approximation of the binomial distribution. calculate the z-score for 115 and use the standard normal distribution table or a calculator to find the probability associated with that z-score. Then, subtract that probability from 1 to get the probability of 115 or more adults smoking.

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Therefore, the value of d for the given function is 144x^2 + 100.

To evaluate the expression d = f_xxf_yy - [fxy]^2 for the given function f(x, y) = 2x^4 + 3y^2 - 10xy - 3, we need to calculate the second-order partial derivatives and substitute them into the formula.

First, let's find the first-order partial derivatives:

f_x = 8x^3 - 10y

f_y = 6y - 10x

Now, let's find the second-order partial derivatives:

f_xx = d/dx (f_x) = d/dx (8x^3 - 10y) = 24x^2

f_yy = d/dy (f_y) = d/dy (6y - 10x) = 6

f_xy = d/dx (f_y) = d/dx (6y - 10x) = -10

f_yx = d/dy (f_x) = d/dy (8x^3 - 10y) = -10

Substituting these values into the expression:

d = f_xxf_yy - [fxy]^2

= (24x^2)(6) - (-10)^2

= 144x^2 + 100

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