Q2. You push a crate up a ramp with a force of 10 N. Despite your pushing, the crate slides down the ramp 4 m. How much work did you do

Answers

Answer 1

Answer:

40 J

Explanation:

From the question given above, the following data were obtained:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Work done is simply defined as the product of force and distance moved in the direction of the force. Mathematically, we can express the Workdone as:

Workdone = force × distance

Wd = F × s

With the above formula, we can obtain the workdone as follow:

Force (F) = 10 N

Distance (s) = 4 m

Workdone (Wd) =?

Wd = F × s

Wd = 10 × 4

Wd = 40 J

Thus, 40 J of work was done.


Related Questions

Why do astronomers use spectroscopes to analyze light from distant objects?

Answers

Spectroscopy — the use of light from a distant object to work out the object is made of — could be the single-most powerful tool astronomers use, says Professor Fred Watson from the Australian Astronomical Observatory. ... "It lets you see the chemicals being absorbed or emitted by the light source.

true or false

Almost all of Earth's atmosphere is created through the process of photosynthesis.

Answers

Answer:

true

Explanation:

I believe the answer i chose because the earths atmosphere is mostly made up of different things that causes the earth to interact with human life and also interacts with what's in the atmosphere like energy oxygen carbon dioxide and all the stuff like that i hope its right.

A block of mass m is hung from the ceiling by the system of massless springs consisting of two layers. The upper layer consists of 3 strings in paralle, and the lower layer consists of 2 strings in parallel. The horizontal bar between the two layers has negligible mass. The force constants of all springs are k. Calculate the period of the vertical oscillations of the block.

Answers

Answer:

  T₀ = 2π [tex]\sqrt{\frac{m}{k} }[/tex]           T = [tex]\sqrt{\frac{5}{6} }[/tex] T₀

Explanation:

When the block is oscillating it forms a simple harmonic motion, which in the case of a spring and a mass has an angular velocity

        w = [tex]\sqrt{k/m}[/tex]

To apply this formula to our case, let's look for the equivalent constant of the springs.

Let's start with the springs in parallels.

* the three springs in the upper part, when stretched, lengthen the same distance, therefore the total force is

       F_total = F₁ + F₂ + F₃

the springs fulfill Hooke's law and indicate that the spring constant is the same for all three,

       F_total = - k x - k x - kx = -3k x

         

therefore the equivalent constant for the combination of the springs at the top is

      k₁ = 3 k

* the two springs at the bottom

following the same reasoning the force at the bottom is

        F_total2 = - 2 k x

the equivalent constant at the bottom is

         k₂ = 2 k

now let's work the two springs are equivalent that are in series

the top spring is stretched by an amount x₁ and the bottom spring is stretched x₂

            x₂ = x -x₁

            x₂ + x₁ = x

if we consider that the springs have no masses we can use Hooke's law

            [tex]-\frac{F_{1} }{k_{1} } - \frac{F_{2}}{k_{2} } = \frac{F}{k_{eq} }[/tex]

therefore the equivalent constant is the series combination is

             [tex]\frac{1}{k_{eq} } = \frac{1}{k_{1} } + \frac{1}{k_{2} }[/tex]

we substitute the values

             \frac{1}{k_{eq} }  = \frac{1}{3k } + \frac{1}{2k }  

             \frac{1}{k_{eq} }  = \frac{5}{6k} }  

              k_eq = [tex]\frac{6k}{5}[/tex]  

therefore the angular velocity is

             w = [tex]\sqrt{\frac{6k}{5m} }[/tex]  

           

angular velocity, frequency, and period are related

           w = 2π f = 2π / T

           T = 2π / w

            T = 2π [tex]\sqrt{\frac{5m}{6k} }[/tex]

           T₀ = 2π [tex]\sqrt{\frac{m}{k} }[/tex]

           T = [tex]\sqrt{\frac{5}{6} }[/tex] T₀

True or False: Jumping off a diving board and into a pool is an example of a contact force.

Answers

Answer:

False

Explanation:

A contact force is any force that requires contact to occur. Contact forces are ubiquitous and are responsible for most visible interactions between macroscopic collections of matter. Pushing a car up a hill or kicking a ball across a room are some of the everyday examples where contact forces are at work. 

Answer:

false

Explanation:

Determine the absolute pressure on the bottom of a swimming pool 30.0 mm by 8.4 mm whose uniform depth is 1.9 mm .

Answers

Answer:

=101343.62N/m^2

Explanation:

absolute pressure on the bottom of a swimming pool= atmospheric pressure +( 2 ×ρ ×g)

( 2 ×ρ ×g)= guage pressure

atmospheric pressure= 101325pa

h= height= 1.9 mm = 1.9×10^-3m

ρ = density of water

= 1000kg/m^3

g= acceleration due to gravity= 9.8m/s^2

Then substitute, we have

absolute pressure on the bottom of a swimming pool= 101325+ [0.0019 ×1000 × 9.8)]

=101343.62N/m^2

Hence, the absolute pressure on the bottom of a swimming pool is =101343.62N/m^2

Essential Questions: What does the particle theory tell us about the nature of matter? How does
each state of matter behave?

Answers

sowwie :( i need points

Explanation:

Economics these two PLEASE

Answers

Answer:

7. d. England during the Age of Enlightenment

8. a. State governments do not usually act together

Explanation:

The Age of Enlightenment occurred in the 18th century and at this time England was a Constitutional monarchy with a monarch and parliament ruling the country with different powers.

The third and fourth methods of amending the Constitution will be much harder to use because state governments simply do not usually act together as they most times have ideological differences. The sheer number of states it would take to unite for these methods to be used makes this impractical.

What does Newton's first law describes​

Answers

The idea that objects only change their velocity due to a force is encapsulated in Newton's first law. Newton's first law: An object at rest remains at rest, or if in motion, remains in motion at a constant velocity unless acted on by a net external force.

You use 35 J of energy to move a 7.0N object.How far did it move

Answers

Answer:

5 metres

Explanation:

Work Done = Force x Distance

So Distance = Work done ÷ Force

= 35 ÷ 7.0

= 5 metres

Need help y’all ASAP please...physics

Answers

Answer:

t = 3/8 seconds

Explanation:

h=-16t^2 - 10t+6

h= 0 when it hits the ground

0=-16t^2 - 10t+6

factor out a -2

0= -2(8t^2 +5t -3)

divide by -2

0 = (8t^2 +5t -3)

factor

0=(8t-3) (t+1)

using the zero product property

8t-3 = 0    t+1 =0

8t = 3         t= -1

t = 3/8     t= -1

t cannot be negative  ( no negative time)

t = 3/8 seconds

Determine the speed, wavelength, and frequency of light from a helium-neon laser as it travels through flourite. The wavelength of the light from the laser is 632.8 nm in air and the index of refraction of flourite is 1.434.

Answers

Answer and Explanation:

The computation is shown below:

As we know that

Frequency = Speed ÷ wavelength

= (3 × 10^8 )÷ (632.8 × 10^-9)

= 4.74 × 10^14 Hz

Speed in flourite is

= Vaccum speed ÷ refraction index

= 3 × 10^8 ÷ 1.434

= 2.092 × 10^8 m/s

wavelength is

= Speed in flourite ÷ frequency

= (3 × 10^8 × 632.8 × 10^-9) ÷ (1.434 × 3 × 10^8)

= 441.28nm

What happens at the end of most cold currents?​

Answers

Answer:

Ocean currents act as conveyer belts of warm and cold water, sending heat toward the polar regions and helping tropical areas cool off, thus influencing both weather and climate.

Explanation:


If ocean currents were to stop, climate could change quite significantly, particularly in Europe and countries in the North Atlantic. In these countries, temperatures would drop, affecting humans as well as plants and animals. In turn, economies could also be affected, particularly those that involve agriculture.

A sled with a mass of 20 kg is sliding along the snow with a velocity of 5 m/s. What is the momentum of the sled?

Question 7 options:

100 kg/ms

4 kg/ms

15 kg/ms

25 kg/ms

Answers

Answer:

100kgms⁻¹

Explanation:

Given parameters:

Mass of the sled  = 20kg

Velocity of the sled  = 5m/s

Unknown:

Momentum of the sled = ?

Solution:

The momentum of a body is the quantity of motion such a body possesses. Due to this;

    Momentum  = mass x velocity

Now insert the parameters and solve;

      Momentum  = 20 x 5  = 100kgms⁻¹

in 1-2 complete sentences define "opportunity cost " in your own words ​

Answers

Answer:

Here you go, hope this helps! :)

Explanation:

Opportunity cost is the value of the next best thing you give up whenever you make a decision. It is "the loss of potential gain from other alternatives when one alternative is chosen". ... For example, opportunity cost is how much leisure time we give up to work.

If two cars A and B are moving with velocity 60 km/hr and 80 km/hr
respectively in thesamedirection. What willbethe relative velocity of B with
respect to A? (20 kmhr)​

Answers

Answer:

VAB = 20km/hr

Explanation:

Given the following data;

Velocity of car A, VA = 60km/hr

Velocity of car B, VB = 80km/hr

To find the relative velocity of B w.r.t A, VAB;

Since the two cars are moving in the same direction, we have;

VAB = VB - VA

Substituting into the equation, we have;

VAB = 80 - 60

VAB = 20km/hr

Therefore, the relative velocity of car B with respect to car A is 20 kilometers per hour.

Caca box like fish no earnings play like caca
400 points in arena youa have none thats Why I wonder

Answers

Answer:

I actually have 20000 arena points thank you very much

Answer: Caca means in French lol.

A circular space station of radius 100 m rotates twice each minute.

a. Find the acceleration of an astronaut standing at the outer edge of the space

station. How many g's does she feel? (1g=9.8ms2)

b. What must the period of rotation of the space station be in order for astronauts

at the outer edge to experience the same acceleration as on earth?​

Answers

The space station completes 2 revolutions each minute, so that it traverses a distance of 2π (100 m) = 200π m each minute, giving it a linear/tangential speed of

v = (200π m) / (60 s) ≈ 10.472 m/s

(a) The astronaut would experience an acceleration of

a = v ² / (100 m) ≈ 1.09662 m/s² ≈ 0.1119g0.11g

(b) Now you want to find the period T such that a = g. This would mean the astronaut has a tangential speed of

v = (200π m) / T

so that her centripetal/radial acceleration would match g :

a = g = ((200π m) / T )² / (100 m)

Solve for T :

(100 m) g = (400π ² m²) / T ²

T ² = (400π ² m²) / ((100 m) g) = (4π ² m)/g

T = √((4π ² m) / (9.8 m/s²)) ≈ 2π √(0.102 s²) ≈ 2.007 s ≈ 2.0 s

A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?

Answers

Answer:

[tex]\huge\boxed{\sf P.E. = 39.2\ Joules}[/tex]

Explanation:

Given Data:

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

Required:

Potential Energy = P.E. = ?

Formula:

P.E. = mgh

Solution:

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807

PLEASE ANSWER QUESTION 7!!!! PLEASE

Answers

Answer:

Explanation:

The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects

so a option is correct

Your answer is correct because it’s 2 object distance them self it will decrease because there being apart.
And for the gravity it will pull it close together like for example in space the sun is in the middle and we circle around the earth gravity is pulling us close to the sun but in which we are not so close. That’s because the sun is the gravity force it just puts in in line for use to circle around it.

The two plates are now to be pushed together to a separation of d/2. The pushing together can be done either with the battery connected or with it disconnected. Which way would result in the greater electric field magnitude, and by what factor

Answers

Answer:

Electric field will be greater when the battery is connected by the factor of 2.

Explanation:

Solution:

I will be doing some algebraic calculations to answer this question:

As we know that,

Q = CV

and

C = [tex]\frac{AE_{0} }{d}[/tex]

So, when separation = d/2, then,

[tex]C^{'}[/tex] = [tex]\frac{AE_{0} }{d/2}[/tex] by rearranging we get

So,

[tex]C^{'}[/tex]  = 2C

We further know that, Voltage will remain same if the battery is  connected.

This further implies that,

Q = CV

So,

[tex]Q^{'}[/tex] = [tex]C^{'}[/tex]V

[tex]Q^{'}[/tex]  = 2CV

[tex]Q^{'}[/tex] = 2Q

and we also know that,

Electric field E = [tex]\frac{Q}{AE_{0} }[/tex]

So, the new E or [tex]E^{'}[/tex] = [tex]\frac{Q^{'} }{AE_{0} }[/tex]

Hence,

[tex]E^{'}[/tex] = [tex]\frac{2Q}{AE_{0} }[/tex] = 2E

[tex]E^{'}[/tex] = 2E

when battery is disconnected, Q remain the same.

So,

When disconnected

E = E

E = [tex]\frac{Q}{AE_{0} }[/tex]  = Same

Hence, we can see that the magnitude of the electric does not depend upon the distance of separation. Instead it does depend upon the magnitude of charge.

So, when battery is disconnected, Q is same, so the Electric field.

But when it is connected, [tex]Q^{'}[/tex] = 2Q and the [tex]E^{'}[/tex] = 2E

So,

[tex]\frac{E connected}{E disconnected} = \frac{E^{'} }{E}[/tex] = [tex]\frac{2E}{E}[/tex] = 2

Electric field will be greater when the battery is connected by the factor of 2.

If the angle between the net force and the displacement of an
object is greater than 90 degrees, then which option holds
true?
aThe object stops
b Kinetic energy decreases
C Kinetic energy increases
d Kinetic energy remains the same

Answers

Answer: kinetic energy decreases

Explanation:

When the angle between the net force and the displacement of an

object is greater than 90 degree, the Kinetic energy decreases.

The work done by a net force in moving an object over a given distance is given as;

[tex]W = F \times d \ cos(\theta)[/tex]

where;

θ is the angle between the net force and the displacement

The value of cos(θ) decreases from 0 to 180, consequently, the value of work-done will decrease as well.

Based on work-energy theorem, the work done on the object is equal to kinetic energy of the object.

[tex]W = K.E[/tex]

Thus, we can conclude that when the angle increases, the Kinetic energy decreases.

Learn more about kinetic energy here:https://brainly.com/question/10063455

Hey Motors and lamps both use...
electricity that isn't moving
electric current
Both a and b

Answers

Answer:

both

Explanation:

Both! I hope that’s right!

The area of the foundation of a square house is 840 ft. Find
the side length of the foundation of the house to nearest whole
number

Answers

Answer:

210 ft.

Explanation:

Since a square has 4 sides and all sides are equal, just do 210 divided by 4.

Diffusion and osmosis are forms of passive transport.

True
False

Answers

Answer:

True. Diffusion and osmosis are forms of passive transport.

Explanation:

In diffusion, particles move from an area of higher concentration to one of lower concentration until equilibrium is reached.

In osmosis, a semipermeable membrane is present, so only the solvent molecules are free to move to equalize concentration.

Answer:

100% true

Explanation:

Simple diffusion and osmosis are both forms of passive transport and require none of the cell's ATP energy. Example of diffusion: Gas Exchange A biological example of diffusion is the gas exchange that occurs during respiration within the human body.

A certain planet has a radius of 4990 km. If, on the surface of that planet, a 95.0 kg object has a weight of 591 N, then what is the mass of the planet?

Answers

Answer:

3743.489 kg

Explanation:

F_g = 591 N

G = 6.674x10^-11 constant of gravity

m_1 = 95 kg

m_2 = unknown

r = 4990*1000 =

F_g = G[(m_1*m_2)/r^2]

591 N = 6.674x10^-11[(95*m_2)/4990^2]

8.855 = [(95*m_2)/4990^2]

355631.472 = 95*m_2

m_2 = 3743.489 kg

The  mass of the planet, which has a radius of 4990 km, is  1.81×10²³kg.

What is Newton's law of universal gravitation ?

Newton's law of universal gravitation states that

The force of attraction between any two bodies is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

Given parameters:

Mass of the object: m = 95 kg

Radius of the planet: r = 4990 km = 4990 × 1000 m.

Weight f the object: F= 591 N

We know that: universal gravitational constant: G = 6.674x10^-11 SI unit.

We have to find: mass of the planet: M = ?

Now, F= GMm/r^2

591 N = 6.674x10^-11[(95×M)/(4990×1000)^2]

⇒ M =1.81×10²³kg

Hence, mass of the planet is  1.81×10²³kg.

Learn more about gravitational force here:

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The heat vaporization for methyl alcohol is 1100 kj/kg. It is 2257 KJ/Kg for water. Thus means that______________.

A) these are the amounts of energy to change temperature 1 degree C. required for these substances

B) Methyl alcohol requires less than half as much energy per kg to evaporate than water doe

C) water will get twice as ot as methyl alcohol during vaporization.

d) when alcohol and water evaporate they release 2,2 kj and 2257 kj of energy for every kg respectivly



Please hurry! I'm being timed!

Answers

Answer: B) Methyl alcohol requires less than half as much energy per kg to evaporate than water does

Explanation:

Latent heat of vaporization is the amount of heat required to convert 1 kilo gram of liquid into its vapor state without change in its temperature.

Heat of vaporization is more for water than for methyl alcohol which means more heat is required to convert from liquid to vapour form.

As the Heat of vaporization for methyl alcohol  (1100) is almost half as that of Heat of vaporization for water (2257) , it means  Methyl alcohol requires less than half as much energy per kg to evaporate than water does.

the force of an electric field is proportional to to electric charge? True or False

Answers

Answer:True

Explanation:

Answer:

I am going to say true not too sure

1. A low frequency will have a wavelength?​

Answers

Answer:

There are many kinds of waves all around us. There are waves in the ocean and in lakes. Did you also know that there are also waves in the air? Sound travels through the air in waves and light is made up of waves of electromagnetic energy.

The wavelength of a wave describes how long the wave is. The distance from the "crest" (top) of one wave to the crest of the next wave is the wavelength. Alternately, we can measure from the "trough" (bottom) of one wave to the trough of the next wave and get the same value for the wavelength.

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength.

Light waves have very, very short wavelengths. Red light waves have wavelengths around 700 nanometers (nm), while blue and purple light have even shorter waves with wavelengths around 400 or 500 nm. Some radio waves, another type of electromagnetic radiation, have much longer waves than light, with wavelengths ranging from millimeters to kilometers.

Sound waves traveling through air have wavelengths from millimeters to meters. Low-pitch bass notes that humans can barely hear have huge wavelengths around 17 meters and frequencies around 20 hertz (Hz). Extremely high-pitched sounds that are on the other edge of the range that humans can hear have smaller wavelengths around 17 mm and frequencies around 20 kHz (kilohertz, or thousands of Hertz).

Explanation:

Explanation:

Hope This Helped U

Brqinliest

A different bullet has a mass of 0.09 kg. Starting from rest, after its gun's trigger is pulled, a constant force acts on the bullet for the next 0.025 seconds until the bullet leaves the barrel of the gun with a speed of 1,346 m/s.

What force acts on this bullet?

Answers

The force acts on this bullet : 4.8456 N

Further explanation

Given

m=0.09 kg

Δt=0.025 s

vo=0(from rest)

vt=1.346 m/s

Required

Force

Solution

Impulse is a change in momentum

I=ΔP

F.Δt=m(vt-vo)

Input the value

F x 0.025 = 0.09(1.346-0)

F=4.8456 N

(b)
The total power input to the leaf blower is 750 W.
The useful power output of the leaf blower is 360 W.
Calculate the efficiency of the leat blower.

Answers

% Eff = (Eout/Ein) x 100
% Eff = (360/750)x 100
% Eff = 48
The efficiency is 48%

The efficiency of the leaf blow is 48%.

How can we find the efficiency of the leaf blower?E = m×c×Ф

         Here, E = Energy transferred

                   m = Mass

                   Ф = Temperature change

efficiency = (Useful energy out / Total energy in ) × 100efficiency =  (Useful power out / Total power in ) × 100E = P × t

            Here, E = Energy transferred

                      P = Power

                      t = time

v = f ×∧

        Here, v = speed

                   f = frequency

                  ∧ = wavelength

Substitute into the time equation,

       Efficiency =  (Useful power out / Total power in ) = 360/750 = 0.48

Convert it to percentage = 0.48 × 100 = 48%

So, the efficiency of the leaf blower is 48%.

To learn more about efficiency, refer to: https://brainly.com/question/21305967

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