¿Qué proporción deberían guardar los platos de una prensa hidráulica para que, aplicando 40N de fuerza en el plato menor, podamos levantar un objeto de 40Kg en el plato mayor?

Answers

Answer 1

Answer:

El área de la placa más grande es aproximadamente 9,81 veces el tamaño del área de la placa más pequeña

Explanation:

Los parámetros dados son;

La fuerza aplicada sobre la placa más pequeña, F = 40 N

El culo del objeto levantado en la placa más grande, m = 40 kg

El peso del objeto, W = 40 kg × 9,81 m / s² = 392,4 N

Tenemos la presión en el plato pequeño = La presión en el plato más grande

Por lo tanto;

F / A₁ = W / A₂

Dónde;

A₁ = El área del plato pequeño

A₂ = El área de la placa más grande

Por lo tanto, obtenemos;

40 N / (A₁) = 392,4 N / (A₂)

A₂ / A₁ = 392,4 N / (40 N) = 9,81

∴ A₂ = A₁ × 9,81

El área de la placa más grande, A₂ = 9,81 (9,81 m / s² ≈ g) multiplicado por el área de la placa más pequeña A₁.


Related Questions

Can someone help me with this please

Answers

Carbon: C, 12.011, 6, 12
Oxygen: O, 8, 8, 8, 16
Boron: B, 10.811, 5, 5, 11

Whats a recent new discovery made in physics ? please add a link to the study if you can !

Answers

Answer:

Heres the link!

Explanation:

https://www.bbc.co.uk/news/science-environment-56491033

Answer:

here's the link you asked for: https://www.nyas.org/ebriefings/the-physics-of-everything/ and here's the info inside the link: During the second quarter of 2016, the Academy hosted a series of evening panel discussions boldly titled "." With grant support from The John Templeton Foundation, the six panels addressed how physics is addressing grand questions and the potential limitations on what we may be able to learn using physics to address those questions.

The first session posed the question "" Three physicists explored the frontiers of cosmology and quantum physics. There may always be limits to our understanding in areas such as string theory, dark matter, and multiverses. But the panelists agreed that it is best to proceed as if explanations based in physics can be found.

The second session asked "" The panelists argued that philosophy has much to offer physics, in contrast to the assertions of some prominent physicists. In such areas as the role of observations in quantum mechanics and the experimental validation of theory, the panelists illustrated the power of a critical, interdisciplinary approach to understanding not only the facts but the significance of physics ideas.

Physics has achieved its success in part by selecting problems that can be addressed by reducing them to simple parts following simple laws. Less amenable subjects were discussed in the third session, "" Biology, ecology, and social phenomena such as cities are all not easily described with simple equations, but still show amazing regularities. The panelists, including two physicists, a philosopher, and a computer scientist, sketched their hopes for unifying principles that explain these regularities.

One complex phenomenon that has so far evaded physical analysis was the topic of the fourth session, "." Two of the panelists, a neuroscientist and a roboticist, did not even regard consciousness as a distinct phenomenon but rather as a byproduct of systems that model themselves. In contrast, a philosopher and a physicist felt that this behavioral description misses something essential about what consciousness "feels like." Both groups expressed hope for experimental tests of their views.

The fifth session addressed the question, "" Recent experimental observations of thousands of planets orbiting other stars bolster the expectation that ours is not the first civilization. The panelists explored how we might look for others and why we have not encountered any yet. One troubling possibility is that civilizations that achieve global scale inevitably encounter challenges such as climate change that they fail to overcome.

The sixth session was entitled "." Two physicists and a computer scientist discussed amazing developments at the intersection of quantum gravity (as manifested in black holes) and quantum information. Trying to reconcile these disparate observations has overturned the traditional view of black holes, with no clear resolution so far. At the same time, an abstract connection between gravitational models and quantum models in one fewer dimension is providing insight into both fields, including new methods for error correction in quantum computing as well as benchtop tests of black hole physics.

The wide ranging discussions of the six panels illustrate the power of physics to explain the universe as well as the vast frontiers of that universe that still remain to be explored.

Explanation:

hope this helped plz give brainliest and rating ^_^

where would a car traveling on a roller coaster have the most kinetic energy ? and why?

Answers

Answer:

As the car travels up the coaster it is gaining potential energy.

Explanation:

Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.

Most potential energy at the top of a hill/loop and the most kinetic energy at the bottom of a hill/loop

how do we calculate the value of work?

Answers

The percent complete is calculated by dividing the quantity of material progressed at a point in time by the total quantity required for the project. The resulting percent is multiplied by the current agreed committed value of the material item to obtain the VOWD for that item.

Answer:

Work = Force × Distance

Explanation:

Work = Force × Distance

The SI unit of work is Joule

-TheUnknownScientist

Which of the following actions will decrease the gravitational force between two objects?

Increasing the mass of the objects
Increasing the density of the objects
Increasing the distance between the objects
Increasing the temperature of the objects

Answers

Answer:

option 3 increasing the distance between the objects

Newton’s second law of motion is also known as law of _____

Answers

Newton’s second law of motion can also be knows as the law of acceleration

Explain why the weather changes with the season's temperate climate zones.

Answers

Environments that have moderate rainfall spread year to year with sporadic droughts. Mild and warm- leads to summer(hot) cool and cold leads the winter

A 0.500 kg mass is oscillating on a spring with k = 330 N/m. The total energy of its oscillation is 3.24 J. What is the amplitude of the oscillation? (Unit = m)​

Answers

Answer:

0.140

Explanation:

may i be marked brainliest

I need help with this

Answers

Answer:

1) distance walked = 210 m

2) not sure

3) avg speed = total d/ total t = 210/52 = 4 m/s approx

4) For avg vel, use the formula - displacement/time

Explanation:

im not fully sure but i studied this last year

What is physic?............​

Answers

Physics is the study of nature and law

Answer:

Physics is the science of matter and how matter interacts. Matter is any physical material in the universe. Everything is made of matter. Physics is used to describe the physical universe around us, and to predict how it will behave.

An electron and a proton are held on an x axis, with the electron at x = + 1.000 m

and the proton at x = - 1.000 m . If a second electron is initially at x = + 20.00 m on the x axis and is given an initial velocity of 450 m/s towards the origin, will it reach and origin? And how close will it get to the origin if it doesn't?

Answers

Answer:

  r2 = 1 m

therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m

Explanation:

For this exercise we must use conservation of energy

the electric potential energy is

          U = [tex]k \frac{q_1q_2}{r_{12}}[/tex]

for the proton at x = -1 m

          U₁ =[tex]- k \frac{e^2 }{r+1}[/tex]

for the electron at x = 1 m

          U₂ = [tex]k \frac{e^2 }{r-1}[/tex]

starting point.

        Em₀ = K + U₁ + U₂

        Em₀ = [tex]\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}[/tex]

final point

         Em_f = [tex]k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})[/tex]

   

energy is conserved

        Em₀ = Em_f

        \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})              

       

        \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²(  [tex]\frac{2}{(r_2+1)(r_2-1)}[/tex] )

we substitute the values

½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ [tex]- \frac{1}{20+1} + \frac{1}{20-1}[/tex] ) = 9 109 (1.6 10-19) ²( [tex]\frac{2}{r_2^2 -1}[/tex] )

          2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( [tex]\frac{1}{r_2^2 -1}[/tex] )

          2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷     [tex]\frac{1}{r_2^2 -1}[/tex]

          [tex]\frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}[/tex]

          r₂² -1 = (4.443 10⁸)⁻¹

           

          r2 = [tex]\sqrt{1 + 2.25 10^{-9}}[/tex]

          r2 = 1 m

therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m

Why do electric fish need to force electric charges to move?

Answers

The electric eel generates large electric currents by way of a highly specialized nervous system that has the capacity to synchronize the activity of disc-shaped, electricity-producing cells packed into a specialized electric organ. Hope this helps!! Good luck

Convertir 0.3 Hm en cm.

Answers

Answer:

3000 cm

Explanation:

If the distance between us and a star is doubled, with everything else remaining the same, the luminosity If the distance between us and a star is doubled, with everything else remaining the same, the luminosity remains the same, but the apparent brightness is decreased by a factor of two. is decreased by a factor of four, but the apparent brightness remains the same. is decreased by a factor of two, and the apparent brightness is decreased by a factor of two. remains the same, but the apparent brightness is decreased by a factor of four. is decreased by a factor of four, and the apparent brightness is decreased by a factor of four.

Answers

Answer:

The luminosity remains the same, but the apparent brightness is decreased by a factor of four.

Explanation:

The apparent brightness, F = L/4πr² where L = luminosity and r = distance between us and the star.

Since L is independent of the distance between us and the star, it is constant, then

F ∝ 1/r²

So, F₁/F₂ = r₂²/r₁² where F₁ = apparent brightness at r₁ and F₂ = apparent brightness at r₂

If the distance is doubled, that is r₂ = 2r₁, then

F₁/F₂ = r₂²/r₁²

F₁/F₂ = (2r₁)²/r₁²

F₁/F₂ = 4r₁²/r₁²

F₁/F₂ = 4

F₂ = F₁/4

So, since the luminosity is constant, the luminosity remains the same, but the apparent brightness is decreased by a factor of four.

What was your hypothesis? According to your data, do you think your hypothesis was correct? (Be sure to refer to your data and graph in answering this question.)
Summarize any difficulties or problems you had in performing this experiment that might have affected the results. Describe how you might change the procedure to avoid these problems.
Explain how a graphical analysis can be used to explore the relationship between any two scientific variables.

Answers

Answer:

Present Your Findings Write a summary paragraph discussing this experiment and the results. Use the following questions and topics to help guide the content ...

The downward force acting on an object in free fall is the force of ___________​

Answers

it’s gravitational force

Help me with this Bell Ringer / Answer Only / Ez 30 Points /

identifying the forces among the four particles in the Helium nucleus atom and explain why the nucleus stays together.
(Write a paragraph)

Answers

Explanation:

the forces among the four particles in the helium nucleus atom are strong, weak, electromagnetic and gravity

Which injury stimulates muscle growth? critical injury microtrauma broken bone overuse injury

Answers

Answer: Microtrauma stimulates muscle growth!

Explanation - I hope that helped!

In which of the following situations is the Doppler effect absent?

Answers

The source and the observer are moving towards each other. The observer is moving toward the source. The source is moving away from the observer

Shown below is a 10 kg block being pushed by a horizontal force F of magnitude 200N. The coefficient of kinetic friction between the two surface is 0.50. Find the acceleration of the block.

Answers

Answer:

15.1 m/s²

Explanation:

Step 1: Calculate the force exerted by the friction

Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.

Ff = μ × m × g

where,

μ: coefficient of kinetic friction

m: mass of the block

g: gravity

Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N

Step 2: Calculate the resulting force

The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.

R = F - Ff = R = 200 N - 49 N = 151 N

Step 3: Calculate the acceleration of the block

We will use Newton's second law of motion.

R = m × a

a = R/m

a = 151 N/10 kg = 15.1 m/s²

If the frequency of a sound wave increases, the wavelength of the wave in air
a. Increases
b. Decreases
c. Remains the same

Answers

A it will increase (adding extra letters so I can send answer: ansushshsudhsbsbehe)

I’m think 3 or 1.. am I right?

Answers

Answer:

C-3 I beleive it is three!!!!

Explanation:

Hope this helps!

Have a grreat day!

-Hailey

Answer:

it is n2+3

Explanation:

100 points!!! Please help!!!
In the system shown above, the pulley is a uniform disk with a mass of .75 kg and a radius of 6.5 cm. The coefficient of friction between the 5.8 kg mass and the horizontal surface is .25, and the ropes does not slip on the pulley. They system is released from rest. Use work-energy principles to determine the kinetic energy of the (a) 2.8 kg mass and (b) the pulley after the 5.8 kg mass has moved 2.2 meters.

Answers

Answer:

please find the answer in the attached image, divided in 2 parts.

A specified volume of space contains an electric field for which the magnitude is given by E=E0cos(ωt). Suppose that E0 = 20 V/m and ω = 1.0 × 107 s−1. What is the maximum displacement current through a 0.40 m2 cross-sectional area of this volume?

Answers

Answer: [tex]0.708\ mA[/tex]

Explanation:

Given

[tex]E_o=20\ V/m[/tex]

[tex]\omega =10^7\ s^{-1}[/tex]

Cross-sectional area [tex]A=0.40\ m^2[/tex]

Current density is given by

[tex]J=\epsilon_o \dfrac{dE}{dt}[/tex]

Displacement current

[tex]\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A[/tex]

The required value of the maximum displacement current of the given space is  [tex]7.08 \times 10^{-4} \;\rm A[/tex].

Given data:

The intensity of electric field is, [tex]E_{0}=20 \;\rm V/m[/tex].

The angular frequency of electric field is, [tex]\omega=1.0 \times 10^{7} \;\rm s^{-1}[/tex].

The cross-sectional area of space is, [tex]A =0.40 \;\rm m^{2}[/tex].

In the given problem, the instantaneous electric field is given by [tex]E = E_{0} \times cos(\omega t)[/tex]

So, the expression for the current density is,

[tex]J= \epsilon_{0} \times \dfrac{dE}{dt}[/tex]

Here, [tex]\epsilon_{0}[/tex]  is the permittivity of free space. Solving as,

[tex]J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)[/tex]

And the expression for the maximum displacement current is,

[tex]I = J \times A[/tex]

And the maximum displacement current is possible only when, J is positive and J will be positive for  [tex]sin(\omega t)=-1[/tex].

Then solving as,

[tex]I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A[/tex]

Thus, we can conclude that the required value of the maximum displacement current of the given space is  [tex]7.08 \times 10^{-4} \;\rm A[/tex].

Learn more about the displacement current here:

https://brainly.com/question/20344850

a vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west​

Answers

Answer:

5 m/s

Explanation:

Given that,

A vehicle is moving with 20m/s towards the east and another is moving 15m/s towards the west​.

It is assumed to find the resultant velocity of the vehicle. Let east side is positive and west is negative. So,

[tex]v=v_1+v_2\\\\=20+(-15)\\\\=5\ m/s[/tex]

Hence, the resultant velocity of the vehicle is equal to 5 m/s.

What different forms of energy are present when an egg crashes into the egg catcher?

Answers

Answer:

An egg raised above the ground has potential energy due to the force of gravity. When dropped, the egg's potential energy is converted into the kinetic energy of motion. :)

Explanation:

While traveling along a highway a driver slows from 31 m/s to 15 m/s in 8 seconds. What is the automobile’s acceleration? (Remember that a negative value indicates a slowing down or deceleration.)​

Answers

Answer:

The automobile's acceleration in that time interval is -2 m/s^2

Explanation:

The acceleration is defined as the rate of change of the velocity.

The average acceleration in a given lapse of time is calculated as:

A = (final velocity - initial velocity)/time.

In this case, we have:

initial velocity = 31 m/s

final velocity = 15 m/s

time = 8 seconds.

Then the average acceleration is:

A = (15m/s - 31m/s)/8s = -2 m/s^2

Cuales podrian ser las causas y consecuencias del aumento de problemas de salud mental en la población chilena

Answers

Explanation:

CAUSAS:

-El gobierno de chile ha destinado el 2% de sus recursos de salud pública para tratar los problemas de salud mental,lo cual es insuficiente debido a la alta demanda de pacientes que requieren atención especializada. Según la OMS (organización mundial de la salud) , cada gobierno debería destinar al menos el 5% de sus recursos para tratar este tipo de patologías o enfermedades mentales como la depresión,la ansiedad u otros trastornos bipolares

- El personal capacitado para tratar este tipo de enfermedades es muy escaso.

- Muchos de los chilenos que padecen este tipo de enfermedades no buscan ayuda inmediata, algunos recurren al alcohol o a los vicios como el cigarrillo o la marihuana , pensando que lograrán calmar la ansiedad o sus preocupaciones pero en realidad sucede lo contrario, aumentan   la depresión y la ansiedad.

-Los problemas sociales, la crisis económica y el aumento de la pobreza así como el limitado acceso que tiene la población pobre chilena a un buen sistema de salud integrado,genera un significativo aumento de problemas de salud mental  en especial en la población pobre o más desfavorecida del país.

CONSECUENCIAS:

Debido a los problemas de salud mental las incapacidades laborales han aumentado, afectando  la economía  del país.

Debido a la falta de tratamiento ,el suicidio y otras enfermedades como la esquizofrenia han aumentado. De igual manera la violencia intrafamiliar se ha incrementado e inclusive hasta los niños están empezando a sufrir este tipo de trastornos o enfermedades mentales,lo cual está afectando su desempeño escolar.

Horticulture 120 pts (HURRY)

Auto-steer technology is dependent on the use of

tracking relayed from satellites to receivers and transmitters in the farm equipment.

Answers

Answer: GPS

Explanation:

I took the test 2021

Answer:

okkkkkkkkkkkkkkkkkkkk

How is heat transmitted?​

Answers

Like for example metal if u hold it in heat long enough it will start to burn ur hand on the other end
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