When the Sun passes through the nodal eclipse zones, the eclipses would last approximately 6 hours, with there being a chance of two solar eclipses every 34.5 days.
How far apart are eclipses?Each year, there are two to five solar eclipses, with a total eclipse occurring roughly every 18 months. You might be able to see that eclipse, depending on where you are in the world. The view of the eclipse and the Moon's shadow on Earth move from west to east as the Earth rotates.
Why are eclipses 6 months apart?This is due to the fact that there are roughly 15 days (or a fortnight) between a full moon and a new moon, and vice versa. There are enough days (30 days) for two more eclipses if one occurs at the start of the season.
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b. When a certain amount of violet light and yellow light shine on a metal surface, only violet light
produces an electric current. Write 3-4 sentences describing how an increase in the intensity of
each type of light will affect the amount of current produced. How does quantization help to explain
these observations? (6 points)
Answer:when a certain amount of violet light and yellow light shine on a metal surface only violet light produces an electric current describe how an increase in the intensity of each type of light will affect the amount of current produced, how does quantization help to explain these observations? Question thumb_up 100%
Explanation:
An increase in the intensity of violet light will lead to a proportional increase in the amount of electric current produced, as more violet photons will have enough energy to liberate electrons through the photoelectric effect.
However, an increase in the intensity of yellow light will not affect the electric current, as even with higher intensity, yellow photons do not possess sufficient energy to release electrons from the metal surface. This observation can be explained by quantization, which states that light energy is quantized into discrete packets called photons.
Each photon must possess a minimum energy threshold (the work function) to cause electron emission. Violet light photons have higher energy and can overcome the work function, while yellow light photons do not have enough energy and thus cannot produce a current, regardless of their intensity.
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With the aid pf sketch explain uniform speed and uniform velocity
If a body covers equal distances in equal intervals of time it has uniform speed. If a body covers equal displacement in equal intervals of time it has uniform velocity.
Speed is the rate of change of an object's position with respect to time in any direction. An object will have uniform speed, if the speed of the object remains constant and not varying.
Velocity is the rate of change of an object's position with respect to time in a particular direction. Uniform velocity is a condition in which a body covers equal displacements in equal intervals of time.
Therefore, if a body covers equal distances in equal intervals of time it is said to have uniform speed and if it covers equal displacement in equal intervals of time it is said to have uniform velocity.
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a force of 5.0 n is applied to a point object at 30o with the horizontal. another force of 10.0 n is applied at 120o . a) determine the net force (the magnitude and angle)
The net force calculated is 5 N. The total of all forces exerted on an object is known as the net force. A mass can accelerate due to net force. A body is subject to another force whether it is at rest or in motion.
The combined effect (the sum) of all pushing and pulling forces that are really operating on an object is known as the net force. An object will accelerate in the direction of the net force if the pushing and pulling forces acting on it are not equal (a net force acts).When there are a lot of forces acting on a system, the term "net force" is employed.
We now have a 30° - 60° /90° right triangle because this force does produce a 30° angle with the y-axis.
The force of 10N (hyp.) or sin 30 = x/10N
x = 10N sin 30
x = 5 N is used to find the magnitude of x.
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Tarzan (m = 80 kg) is on a quest to save Jane. He runs towards a rope with a velocity of 12 m·s-1 . He grabs onto the rope. To what height will Tarzan swing?
The height to which Tarzan swings with a mass 80 kg and a velocity of 12 m / s is 7.2 m
K = 1 / 2 m v²
U = m g h
E = K + U
E = Total mechanical energy
K = Kinetic energy
U = Potential energy
m = Mass
g = Acceleration due to gravity
h = Vertical height
v = Velocity
Since Tarzan swings, it represents half the motion of pendulum. Therefore total mechanical energy is constant.
[tex]E_{i}[/tex] = [tex]E_{f}[/tex]
m = 80 kg
[tex]v_{i}[/tex] = 12 m / s
[tex]v_{f}[/tex] = 0
[tex]h_{i}[/tex] = 0
g = 10 m / s²
According to Law of conservation of Energy,
[tex]K_{i}[/tex] + [tex]U_{i}[/tex] = [tex]K_{f}[/tex] + [tex]U_{f}[/tex]
( 1 / 2 * m * [tex]v_{i}[/tex]² ) + ( m g [tex]h_{i}[/tex] ) = ( 1 / 2 * m * [tex]v_{f}[/tex]² ) + ( m g [tex]h_{f}[/tex] )
( 1 / 2 * 80 * 12² ) + 0 = 0 + ( 80 * 10 * [tex]h_{f}[/tex] )
[tex]h_{f}[/tex] = 5760 / 800
[tex]h_{f}[/tex] = 7.2 m
Therefore, Tarzan will swing to a height of 7.2 m
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spike claims that dimensional analysis shows that the correct expression for change in velocity, , is , where m is mass, t is time, and f is the magnitude of force. carla says that can't be true because the dimensions of force are . which one, if either, is correct? group of answer choices
Carla says that can't be true because the dimensions of force are Carla because [tex]$[\overrightarrow{\mathrm{v}}]=\left[\frac{\mathrm{L}}{\mathrm{T}}\right]$[/tex].
The correct option is C.
What do dimensions mean?In physics, a mathematical space's dimension is formally defined as the smallest set of coordinates required to specify any given point. As a result, a line has a dimension of one since a point on it may be specified by a single coordinate, such as the point at 5 on a number line.
Describe the dimension formula:The definition of the dimensional formula is the correct statement of the physical quantity in terms of its fundamental unit. Dimensional force is one example. F = [M L T-2] It's because Netwon, or kg*m/s2, is the unit of force.
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The complete question is-
Spike claims that dimensional analysis shows that the_ correct expression for change in velocity, is , where m is mass, t is time, and f is the magnitude of force. Carla says that can't be true because the dimensions of force are ML/T2. which one, if either, is correct? group of answer choices
A-Spike because [tex]$[\overrightarrow{\mathrm{V}}]=\left[\frac{\mathrm{ML}}{\mathrm{T}}\right]$[/tex]
B- Spike because[tex]$[\overrightarrow{\mathrm{v}}]=\left[\frac{\mathrm{T}^2}{\mathrm{~L}}\right]$[/tex]
C- Carla because [tex]$[\overrightarrow{\mathrm{v}}]=\left[\frac{\mathrm{L}}{\mathrm{T}}\right]$[/tex]
D- Carla because [tex]$[\overrightarrow{\mathrm{v}}]=\left[\frac{\mathrm{L}}{\mathrm{MT}}\right]$[/tex]
E- Spike because the dimension of force are [tex]$[\overrightarrow{\mathrm{F}}]=\left[\frac{\mathrm{T}^2}{\mathrm{ML}}\right]$[/tex]
A company is creating a new mosquito repellent, and needs to figure out how much is needed to stop mosquito bites. They find volunteers from the nearby college. Each person is given either 1mL, 2mL, or 3mL of the repellent to rub on their arm. Some volunteers are given no repellent. Each person is then put in a room with mosquitoes for 10 minutes. Numbers of bites are measured for each volunteer.
In Experiment 1 above, what is the independent variable?
The independent variable is the different amount of repellent each person is given. This is because it does not depend on any variable. The dependent variable is what they are measuring, which would be the number of bites on each volunteer.
I hope this helps! :)
A scientist decides to replicate an experiment completed by another scientist. Which statement describes something that would not affect the results of the replicated experiment?
A) The two experiments were completed by two different people.
B) The variables were not kept the same in both experiments.
C) The two scientists did not use the same equipment.
D) There were some measurements that were different in the two experiments.
The statement describes something that would not affect the results of the replicated experiment is option A. (The two experiments were completed by two different people)
What is an experiment?An experiment can be defined as a procedure carried out to support or refute a hypothesis, or determine the efficacy or likelihood of something previously untried.
Experiments helps in the provision of insight into the cause-and-effect by demonstrating what outcome occurs when a particular factor is manipulated.
If two experiments were completed by two different people, it would not affect the results if the experiment is replicated.
The purpose of any experiment is to test or verify a hypothesis
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A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110.0 m.
Determine the acceleration of the car.
Answer: a = 8.10 m/s^2
Explanation:
The car starts at rest, so:
V0= 0m/s
t= 5.21m/s
S = 110.0 m
Using one of the five uniformly accelerated motion formulas
S= V0t + 1/2 at^2
but V0 = 0 m/s
S = 1/2 at^2
a= 2S/ t^2
a = 2(110m)/ (5.21 s)^2
a = 8.10 m/s^2
An engine of a train has to apply a force of 4000 newton to overcome friction. To run at a uniform rate of 60km/hr, What is the power developed by the engine?
Answer:
Power = 4000×60× 5/18
Explanation:
The reason for this result is because:
power=force × velocity.
This means that power = 400 × 60 × 5/18
A toy plane is displaced 12m to the right and then 16m upward.
What is the magnitude of the resultant displacement?
a person stands at the base of a hill that is a straight incline making an angle with the horizontal (fig. 3-48). for a given initial speed vq, at what angle 0 (to the hori- zontal) should objects be thrown so that the distance d they land up the hill is as large as possible?
θ = sin⁻¹√2gd
V2 = u2 + 2as is derived from one of the equations of motion, which is equation 1.
The initial velocity u would change to V0 sin because the item is moving at an angle of to the horizontal and the acceleration a would change to -g since the object is going against gravity.
Equation 1 would yield the following results if we entered all these parameters:
(u sin )2 - 2gd = v2
(u sin )2 equals 2gd
(u sin )2/2g = d
sin² θ = 2gd
sin θ = √2gd
θ = sin⁻¹ √2gd
The rate at which the velocity of an object changes in relation to time is known as acceleration. They are accelerations and vector quantities. The object's acceleration is determined by the direction of the net force acting on it.
All objects with mass or energy are attracted to one another by gravity, which is a fundamental interaction.
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if you walk 6.0 km in a straight line in a direction north of east and you end up 2.0 km north and several kilometers east. how many degrees north of east have you walked?
According to the given statement 19e degrees north of east have you walked.
The correct option is A
What is called straight line?A straight line is, to put it simply, a line without bends. An uncurved line that extends to infinity on both sides is said to be straight.
What are some straight line examples?Even though they have no start or finish, straight lines are represented in everyday life by things like train tracks and freeways.
What four varieties of straight lines are there?Focuses on four basic types of straight lines: vertical, horizontal, diagonal from left to right, and diagonal from right to left, as well as potential groupings of each.
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The complete question is -
If you walk 6.0 km in a straight line in a direction north of east and you end up 2.0 km north and several kilometers east. How many degrees north of east have you walked?
A) 19e
B) 45e
C) 60e
D) 71e
a school bus slows to a stop with an average acceleration of -2m/s. the bus had an initial speed of 10m/s how long will it take the bus to come to a stop
It will take 2.5 seconds for the school bus to come to stop.
The initial velocity U of the School bus is 10m/s. As the bus has to come to stop, the final velocity V of the school bus will be 0 m/s.
The Acceleration a is -2m/s² and constant.
Because the Acceleration is constant. We can use the equations of motion,
Let say the School bus stopes after Reaching a distance D.
So, applying the equation of motion,
V = U + at
0 = 10 - 4t
-10 = -4t
t = 2.5 seconds.
So the school bus will come to stop after 2.5 seconds.
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1) [30 points] find the rotation matrix after a clockwise rotation of 240 o about an axis that describes equal angles with respect to the original coordinate axes. 2) [30 points] at a given time two point charges q1
Since, ABCDEF is a regular hexagon,
The measure of the central angle of a regular polygon = [tex]\frac{360}{n}[/tex]
where n = number of sides of the polygon
The measure of the central angle of a regular hexagon =[tex]\frac{360}{6}[/tex] = 60°
That means when we rotate a regular hexagon by an angle in the multiple of 60°, the hexagon overlaps itself.
Therefore, by the rotation of 240° clockwise, point C will replace the position of point A.
The image of hexagon ABCDEF will become CDEFAB.
A rotation matrix is a transformation matrix in linear algebra that is used to make a rotation in Euclidean space. Rotation matrices depict rotations about the origin since matrix multiplication has no effect on the zero vector (the coordinates of the origin). Rotation matrices provide an algebraic description of such rotations and are widely utilized in geometry, physics, and computer graphics computations. In some publications, the term rotation is broadened to cover improper rotations, which are defined by orthogonal matrices with determinants of 1 (rather than +1). These incorporate appropriate rotations and reflections (which invert orientation). In other circumstances, where reflections are not taken into account, the label proper may be omitted. This article adheres to the later convention.
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How much thermal energy does a 2 kg steel block (c = 450 J/kg°C) lose when it cools from 300°C to
20°C?
Answer:
see below
Explanation:
x J / (2 kg * (300-20 C) = 450 J / (kgC)
x = 450 * 2(280) = 252000 J = 252 kJ
Answer:
Thermal energy lost = 252,000 J
Explanation:
change in thermal energy = mass x specific heat capacity x change in temperature
ΔE = mcΔθ
ΔE = change in thermal energy (J)
m = mass (kg)
c = specific heat capacity (J/kg℃)
Δθ = change in temperature (℃)
ΔE = 2 x 450 x (300-20)
ΔE = 252,000 J
Thermal energy lost = 252,000 J
a small button placed on a horizontal rotating platform with diameter 0.530 m will revolve with the platform when it is brought up to a speed of 39.0 rev/min , provided the button is no more than 0.230 m from the axis.
To begin, change the rotational speed () to rev/sec: 13/20 revs per second is equal to 39 revs per minute multiplied by 1 minute and 60 seconds.
The equation is then updated with all the values: = rw^2/g\s
=(0.230*13/20)/9.8
=0.015255
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compare the magnitude of the acceleration of the object that you calculate from your measurements to the ""centripetal acceleration"" that you can calculate from the speed and the radius of the object.
The magnitude of the acceleration of the object that can be calculated from the measurements is compared to the "centripetal acceleration" that can be calculated from the speed and the radius is [tex]a_{c}[/tex] = r ( α t )²
The magnitude of the acceleration of the object that can be calculated the measurements is Angular acceleration. If angular velocity and time are given,
α = ω / t
α = Angular acceleration
ω = Angular velocity
t = Time.
[tex]a_{c}[/tex] = v² / r
[tex]a_{c}[/tex] = Centripetal acceleration
v = Tangential velocity
r = Radius
Rearranging angular acceleration formula as,
ω = α t
v = r ω
[tex]a_{c}[/tex] = v² / r
[tex]a_{c}[/tex] = ( r ω )² / r
[tex]a_{c}[/tex] = r² α² t² / r
[tex]a_{c}[/tex] = r ( α t )²
This is the relation between angular acceleration and centripetal acceleration.
Therefore, the comparison is [tex]a_{c}[/tex] = r ( α t )²
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a box weighing 500n is at rest on the floor. a person pushes against it and it starts moving when 100n force is applied to it. what can be said about the coefficient of kinetic friction between the box and the floor?
The coefficient of kinetic friction between the box and the floor is 0.2.
The direction of the kinetic friction force between the box and the floor is the opposite of the velocity, as depicted in the free body diagram on the attached picture.
The second Newton's law of motion:
∑ F = m. a
Let F1 be the person force and f be the kinetic friction force.
Since the box is just about to move, it means a = 0.
F1 - f = 0
f = F1 = 100 Newton
Let N be the normal force and w be the weight of the box.
In the vertical direction:
N - w = 0
N = w = 500 Newton.
It is known that:
f = μ . N
Where: μ = coefficient of kinetic friction.
Hence,
μ . N = 100
μ = 100/N = 100/500 = 0.2
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20 points!! Pls help
An object has a mass of 40 kilograms. What is its weight on the Moon? (The acceleration due to
gravity on the moon is 1.8 m/s².)
Select one:
a. 72 newtons
B. 97 newtons
c. 108 newtons
d. 235 newtons
Answer: [tex]w=72N[/tex]
Explanation:
[tex]m=40\ kg\\g=1.8\ m/s^2\\w=mg\\w=40*1.8\\w=72N[/tex]
mrs. hogan has given you a box of materials and challenged you to use the materials to determine what effect increasing the current in a wire has on the magnetic field generated around the wire. describe how you can use some, or all, of the materials to determine what effect increasing the current in a wire has on the magnetic field generated around the wire. In your description, be sure to include the following:
Describe how you would use each of the materials you choose to use
Identify your independent and dependent variables, and at least two controlled variables
Create a data table that can be used to record your data
Materials in the Box
4 batteries
wire
directional compass
10 iron nails
a strong permanent magnet
a weak permanent magnet
a voltmeter
a box of paper clips
The magnetic field is the area around a magnet in which there is magnetic force. Moving electric charges can make magnetic fields.
we are able to make this magnetic field more potent by using growing the quantity of electrical cutting-edge going thru the twine or we are able to grow the variety
A magnetic area is a vector field that describes the magnetic affect on shifting electric costs, electric-powered currents, and magnetic materials. A shifting charge in a magnetic area reviews a force perpendicular to its very own velocity and to the magnetic field.
The force is perpendicular to each the velocity v of the price q and the magnetic field B. 2. The significance of the force is F = qvB sinθ where θ is the angle < a hundred and eighty levels among the rate and the magnetic field.
Examples of magnetic force is a compass, a motor, the magnets that maintain stuff at the fridge, teach tracks, and new roller coasters. All transferring expenses supply upward thrust to a magnetic subject and the charges that flow through its regions, revel in a force
This discipline is shaped via the magnetic strains of pressure which run from the north pole to the south pole. these traces can be located to be most crowded at the 2 ends of the magnet which might be the poles i.e the north pole and the south pole.
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suppose a boat moves at 16.4 m/s relative to the water. if the boat is in a river with the current directed east at 2.30 m/s, what is the boat's speed relative to the ground when it is heading east, with the current, and west, against the current? (enter your answers in m/s.)
The boat's speed relative to the ground when it is heading east with the current is 18.7 m/s and west against the current is -14.1 m/s.
In the first case,
The velocity of the boat concerning water= 16.4 m/s
The velocity of the water concerning ground= 2.3 m/s
By using the formula of relative velocity:
V(b, g)= V(b, w) + V(w, g)
V(b, g)= 16.4i + 2.3i m/s
V(b, g)= 18.7i m/s
Hence, the magnitude of the velocity of the boat concerning the ground is 18.7 m/s along the current.
In the second case,
The velocity of the boat concerning water is -16.4 m/s
The velocity of the water concerning the ground is 2.3 m/s
By using the formula for relative velocity:
V(b, g)= V(b, w) + V(w, g)
V(b, g)= -16.4i + 2.3i
V(b, g)= -14.1i m/s
Hence, the magnitude of the velocity of the boat concerning the ground is -14.1 m/s against the current.
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Physics Suppose that, while in a squatting position, you stand on your hands, and then you pull up on your feet with a great deal of force. You are applying a large force to the bottoms of your feet, but no matter how strong you are, you will never be able to lift yourself off the ground. Use your understanding of force and motion to explain why this is not possible.
Explanation:
can you show me the answer of science
Which of the following correctly completes box #2 in the chart above?
City - A city is defined as a group of people living in one place within a county sharing many common characteristics, especially the system of government. Cities are part of counties and counties are part of states.
A 2D column chart shows the evolution of a data series over time or compares multiple items. Element types are arranged horizontally and data values are displayed vertically to emphasize changes over time. Scatter charts have two value axes. It displays one set of numerical data along the horizontal axis and another set along the vertical axis.
Combine these values into individual data points and display them in irregular intervals or clusters. The main function of charts is to display data and explore topics in more detail. Charts are used when a simple table cannot adequately represent important relationships or patterns between data points.
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What causes the build up of static electricity in clouds?
a
The negative charge of Earth
b
Magnets
c
Friction
d
Conservation of charge
c or d
Explanation:
friction or conservation
I will gib brainlyest or whatever.
A cannonball is launched from the top of a 35m cliff at an angle of 11.2 degrees above the horizontal with a velocity of 153m/s. Find:
a. How far it goes
b. How high it goes
c. How long it's in the air
d. Its final velocity
Answer:
Range of the projectile: approximately [tex]1.06 \times 10^{3}\; {\rm m}[/tex].
Maximum height of the projectile: approximately [tex]80\; {\rm m}[/tex] (approximately [tex]45.0\; {\rm m}[/tex] above the top of the cliff.)
The projectile was in the air for approximately [tex]7.07\; {\rm s}[/tex].
The speed of the projectile would be approximately [tex]155\; {\rm m \cdot s^{-1}}[/tex] right before landing.
(Assumptions: drag is negligible, and that [tex]g = 9.81\; {\rm m\cdot s^{-1}}[/tex].)
Explanation:
If drag is negligible, the vertical acceleration of this projectile will be constantly [tex]a_{y} = (-g) = (-9.81)\; {\rm m\cdot s^{-2}}[/tex]. The SUVAT equations will apply.
Let [tex]\theta[/tex] denote the initial angle of elevation of this projectile.
Initial velocity of the projectile:
vertical component: [tex]u_{y} = u\, \sin(\theta) = 153\, \sin(11.2^{\circ}) \approx 29.71786\; {\rm m\cdot s^{-1}}[/tex]horizontal component: [tex]u_{x} = u\, \cos(\theta) = 153\, \cos(11.2^{\circ}) \approx 150.086\; {\rm m\cdot s^{-1}}[/tex].Final vertical displacement of the projectile: [tex]x_{y} = (-35)\; {\rm m}[/tex] (the projectile landed [tex]35\: {\rm m}[/tex] below the top of the cliff.)
Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find the final vertical velocity [tex]v_{y}[/tex] of this projectile:
[tex]{v_{y}}^{2} - {u_{y}}^{2} = 2\, a_{y}\, x_{y}[/tex].
[tex]\begin{aligned} v_{y} &= -\sqrt{{u_{y}}^{2} + 2\, a_{y} \, x_{y}} \\ &= -\sqrt{(29.71786)^{2} + 2\, (-9.81)\, (-35)} \\ &\approx (-39.621)\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
(Negative since the projectile will be travelling downward towards the ground.)
Since drag is negligible, the horizontal velocity of this projectile will be a constant value. Thus, the final horizontal velocity of this projectile will be equal to the initial horizontal velocity: [tex]v_{x} = u_{x}[/tex].
The overall final velocity of this projectile will be:
[tex]\begin{aligned}v &= \sqrt{(v_{x})^{2} + (v_{y})^{2}} \\ &= \sqrt{(150.086)^{2} + (-39.621)^{2}} \\ &\approx 155\; {\rm m\cdot s^{-1}} \end{aligned}[/tex].
Change in the vertical component of the velocity of this projectile:
[tex]\begin{aligned} \Delta v_{y} &= v_{y} - u_{y} \\ &\approx (-39.621) - 29.71786 \\ &\approx 69.3386 \end{aligned}[/tex].
Divide the change in velocity by acceleration (rate of change in velocity) to find the time required to achieve such change:
[tex]\begin{aligned}t &= \frac{\Delta v_{y}}{a_{y}} \\ &\approx \frac{69.3386}{(-9.81)} \\ &\approx 7.0682\; {\rm s}\end{aligned}[/tex].
Hence, the projectile would be in the air for approximately [tex]7.07\; {\rm s}[/tex].
Also the horizontal velocity of this projectile is [tex]u_{x} \approx 150.086\; {\rm m\cdot s^{-1}}[/tex] throughout the flight, the range of this projectile will be:
[tex]\begin{aligned}x_{x} &= u_{x}\, t \\ &\approx (150.086)\, (7.0682) \\ &\approx 1.06 \times 10^{3}\; {\rm m} \end{aligned}[/tex].
When this projectile is at maximum height, its vertical velocity will be [tex]0[/tex]. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find the maximum height of the projectile (relative to the top of the [tex]35\; {\rm m}[/tex] cliff.)
[tex]\begin{aligned}x &= \frac{{v_{y}}^{2} - {u_{y}}^{2}}{2\, a} \\ &\approx \frac{0^{2} - 29.71786^{2}}{2\, (-9.81)} \\ &\approx 45.0\; {\rm m}\end{aligned}[/tex].
Thus, the maximum height of the projectile relative to the ground will be approximately [tex]45.0\; {\rm m} + 35\; {\rm m} = 80\; {\rm m}[/tex].
derive an expression for the speed v of the object just before it strikes the ground for general α0 . express your answer in terms of some or all of the variables v0 , α0, h, and the acceleration due to gravity g.
The speed of the object just before it hits the ground will be equal to,
v = √ ( v₀² + 2 g H )
What are newton's equations of motion?Equations of motion describe the concept of the motion of an object such as the position, velocity, or acceleration at various times. Three equations of motion are derived for the motion of an object in 1D, 2D, and 3D.
To derive components are displacement(s), velocity, time(t), and acceleration(a). :
The 1st equation of motion is : v = u + at
The 2nd equation of motion is : S = ut + (1/2)at²
The 3rd equation of motion is : v² = u² + 2 g S
Given, the initial velocity of an object u = v₀ in an upward direction so it will be negative, u = - v₀
The displacement of an object is the height of the object from the ground S = H and It is downward so it will be positive.
The acceleration = g as the object moving towards the ground ( positive in downwards ). The final velocity of the object is V before it hits the ground.
Using the 3rd equation of motion to find the velocity of the object,
v² = u² + 2 g S
v² = (- v₀ )² + 2 g h
v = v₀² + 2 g H .
v = √ ( v₀² + 2 g H )
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A race car travels on a racetrack at 44 m/s and slows at a constant rate to a velocity of 22 m/s over 5.5 seconds. How far does it move during this time?
The distance traveled by the race car would be 181.5 meters,
What are the 3 equations of motion?First equation of motion: v = u + at.Second equation of motion: s = ut + 12 at2Third equation of motion: v2 = u2 + 2as.Equations of motion are used to describe how a physical system behaves in terms of how its motion changes over time. The behavior of a physical system is described in more detail by the equations of motion as a collection of mathematical functions expressed in terms of dynamic variables. These variables typically consist of space, time, and sometimes elements of momentum. Generalized coordinates, which can be any useful variable a part of the physical system, are the most versatile option. In classical mechanics, the functions are defined in a Euclidean space; in relativity, curved spaces are used instead. The equations are the answers to the differential equations describing the motion of the dynamics if the dynamics of a system are known.To learn more about : Equations of motion
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Two vehicles have a head-on collision. The vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. You are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash. Can you determine the momentum of both vehicles before the collision?
The answer is yes because of conservation of momentum. That is, the momentum before collision is equal to the momentum after collision.
What is Momentum ?Momentum is the product of mass and velocity. It is a vector quantity. And it is measured in Kgm/s
If two vehicles have a head-on collision, the vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. The final velocity for both vehicles immediately after the crash can be obtain by using the formula
v = u - at
Where
v = final velocityu = initial velocitya = accelerationt = timeIf you are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash, then you can determine the momentum of both vehicles before the collision by calculating the momentum of both after the collision because momentum is always conserved.
Or by first calculating the initial velocity for vehicle B by using the formula below
[tex]M_{1}U_{1} - M_{2}U_{2} = (M_{1} + M_{2} )V[/tex]
where
M1 = mass of the first objectU1 = initial velocity of the first objectM2 = mass of the second objectU2 = initial velocity of the second objectV = common final velocityAfter we obtain initial velocity for vehicle B, we can calculate the momentum of both vehicles before the collision
Therefore, the momentum of both vehicles before the collision can be determined.
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Antonio has been told that he needs to work on his self- awareness. What might he do to most improve this skill
For Antonio to improve his self-awareness skills he should be able to recognise hie strengths and his weaknesses.
What is self awareness?Self awareness is the act of being able to recognise your feelings and keep your character under control.
To be a self awareness leader, one should be able to have the following qualities:
They should be able to recognize their strengths and challenges.They should be able to recognise other people's needs and feelings,They should be able to notice how their behaviour affects the people around them.Therefore, it can be said for Antonio to improve his self awareness skills, he should be able to recognise his strength and weaknesses and observe how his character affects the people around him.
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You are on a hike in the mountains. You have 3.23 km left to go before your next camp-site. The sun will set in 5.34 h.
What average speed must you walk to get to camp at sunset
Average speed corresponds to the total distance traveled in a specific time interval. Given distance and time information just divide it.
Average speed = 3.23KM/5.34h = 0.604km/h
Hence, you should not have a speed of less than 0.604km/h if you want to catch the sunset.
Average speed is calculated by dividing the total distance something has traveled by the total time it took to travel that distance. Velocity is how fast something is going at a given moment. Average speed measures the average speed while moving. Average speed is calculated by dividing the total distance traveled by the time interval. For example, the average speed of a person who takes him 40 minutes to travel 20 miles north and then 20 miles south (to reach the same place) is 40 miles divided by his 40 minutes.
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