Question 7 (5 points)
(08.02 mc)
what is the mass of naci required to make 140 grams of a 12% solution of nach in water? (5 points)
12 grams

14 grams
oc
12 grams
od
18 grams

The structures of the aldol addition and condensation products of pentanal are attached as an Image with this answer.

What is Aldol Addition ?

An aldol addition is a reaction that occurs between the enolate of an aldehyde or ketone and the alpha-carbon of another aldehyde or ketone to form a beta-hydroxy aldehyde or ketone.

The term aldol condensation has to do with a reaction in which a nucleophile attacks the carbonyl group of an aldehyde or a ketone to convert it to the enolate from which attacks another aldehyde or ketone at the carbonyl carbon to form the required product.

The product obtained in the process is shown in the image attached with the answer.

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The product of the reaction is given by the changes in the chemical and physical properties of the reactants. The product produced is aluminum sulfide precipitate.

A precipitate is an insoluble complex formed when the solute and the solvent reacts to produce and solid complex material that does not get completely dissolved in the solution.

When ammonium sulfide is added to a solution containing aluminum ions then precipitate of aluminum sulfide is formed as:

3(NH₄)₂S + 2Al³⁺ → Al₂S₃ + 3NH₄⁺

Therefore, aluminum sulfide is the precipitate that gets formed.

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Answer:

i don't know send on my insta I'd its_arsh_pb27

Explanation:

Pathology is the main branch of forensics in order to solve a criminal justice case, although other branches may also be important.

Forensic sciences refer to the scientific fields aimed at solving justice cases such as DNA sample forensics.

Other fields in forensics science include:

In conclusion, pathology is the main branch of forensics in order to solve a criminal justice case, although other branches may also be important.

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An Arrhenius acid is a substance that dissociates in water to form hydrogen ions or protons.

An Arrhenius acid increases the number of[tex]H^+[/tex] ions in the water.

According to the Arrhenius theory, a substance which has hydrogen atom and can easily give hydrogen ion or proton in its aqueous solution is called as Arrhenius acid.

For example, when hydrochloric acid is dissolved in water, it forms chloride ion ([tex]Cl^-[/tex]) and hydronium ion ([tex]H_3O^+[/tex]).

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Answer:

l think gasoline and electric

Practical work refers to the art of conducting experiments in order to answer certain research questions.

In science, practical work refers to the art of conducting experiments in order to answer certain research questions. This could occur in a laboratory under controlled conditions or in the field.

In the physical sciences, most of the practical work is conducted in the laboratory under controlled conditions. However, some experiments in the biological sciences and most experiments in the social sciences are conducted outside the laboratory.

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The ionization constant from the reaction as shown in the calculation is 5.8.

The term ionization constant refers to the extent to which the acid is ionized in solution. It is calculated from;

Ka = [H3O^+] [Cl]/[HCl]

Thus when we substitute the values;

Ka = 13.3 * 7.4/ 16.9

Ka = 5.8

The ionization constant from the reaction as shown in the calculation is 5.8.

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Answer:

v = 4.62 L

Explanation:

Necessary Conversion:

1000 g = 1 kg

Density of Oil in kg/mL:

0.78g/ml * (1 kg/1000 mL) = 0.00078 kg/mL

Density Equation (Heart with an arrow through it):

d = m/v

Rewrite to Find Volume (Multiply Both Sides by v/d):

v = m/d

Substitue m and d to Find v:

v = (3.6 kg)/(0.00078 kg/mL)

v = 4615.38 mL

Convert to More Suitable Units (Liters) by Dividing by 1000:

v = 4.62 L

:D

1.0 m [tex]HNO_3[/tex] is added to 100 ml of water, the result is a solution with a concentration of 0.001 m [tex]HNO_3[/tex] and the ph of 0.001 M [tex]HNO_3[/tex] is 3

pH historically denoting "potential of hydrogen" (or "power of hydrogen") is a scale used to specify the acidity or basicity of an aqueous solution

GIven ,

[tex]H^{+}[/tex] = [tex]10^{-3}[/tex] M

we have the formula for

[tex]_PH[/tex] = - log [[tex]H^{+}[/tex]]

[tex]_PH[/tex] = - log [ [tex]10^{-3}[/tex] ]

       = 3 log 10

  [tex]_PH[/tex] = 3

Hence, [tex]_PH[/tex] of water is 7 but after adding 1 drop (0.001 m [tex]HNO_3[/tex] ), It changes to 3.

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Answer:

Supersaturated solution

Explanation:

Weren't there any options?

Anyways, the best I can think of right now is a supersaturated solution.

Different isotopes of the same element emit light at slightly different wavelengths, the minimum number of slits  is mathematically given as

N=1820slits

Generally, the equation for the wave is mathematically given as

[tex]d\ sin\ (\theta\ m) \ = \ m\ \lambda[/tex]

Where the chromatic resolving power (R) is defined by

[tex]R\ =\ \lambda\ / \ d \ \lambda[/tex]

R = nN,

Therefore

[tex]\lambda_1 \ = \ (656.45)(1 \ * \ 10^{-9})/1mm[/tex]

[tex]\lambda_1= 656.45*10^{-9}[/tex]

and

[tex]\lambda_2= (656.27)(1*10^{-9})/1mm[/tex]

[tex]\\\\\lambda_2= 656.27*10^{-9}m[/tex]

In conclusion, the minimum number of slits is required to resolve these two wavelengths in second-order

[tex]N\ =\ \dfrac{\lambda}{m\ d\ T\ }\\\\[/tex]

Therefore

[tex]N\ =\ \dfrac{656.45 \ * \ 10^{-9}}{2\ * \ (0.18*10^{-9})}[/tex]

N=1820slits

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When the same amount of heat is added to cold sand and cold water, the temperature change of sand will be higher because of its lower specific heat capacity.

Specific heat capacity is the quantity of heat required to raise a unit mass of a substance by 1 kelvin.

Water, c = 4,200 J/kg⁰C

Sand, c = 830 J/kg⁰C

Q = mcΔθ

where;

Δθ = Q/mc

Thus, for an equal mass of water and sand, when the same amount of heat is added to cold sand and cold water, the temperature change of sand will be higher because of its lower specific heat capacity.

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Answer:t

Explanation:

The age of the cat and presumably the village is approximately 13657 years. .

Half-Life is the time taken for half the amount of a substance to disappear.

To determine the age of the cat fossil, the following should be noted:

Mass of carbon in the sample = 0.194 × 10 lb = 1.94 lb

Ratio of carbon-12 to carbon-14 = 1 : 1.35 × 10^-12

Mass of carbon-14 initially present = 1.94 × 1/1.35 × 10^-12 = 2.619 × 10^-12

Ratio of present and original mass of carbon-14 = (5 × 10-13)/2.619 × 10^-12 =

The half-life of carbon-14 = 5700 years

The ratio of the mass of carbon-14 at present and initially = 0.191

Using the half-life formula, to calculate time elapsed:

[tex]t = \frac{t_{\frac{1}{2}}ln\frac{N_t}{N_o}}{-0.693}[/tex]

Substituting the values to solve for time, t, in years

[tex]t = \frac{5700 \times \: ln(0.191) }{-0.693} = 13656.8[/tex]

Time elapsed, t = 13656.8 years.

Therefore, the age of the cat and presumably the village is approximately 13657 years.

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Answer:

2.11×10^24

Explanation:

You times the Avogadro number by 3.5

6.023 times 10^23.

then times it by 3.5.

I got 2.11 times 10 ^24.

I hope this helps. Have a lovely day.

Let's see

Answer:

35.4 % left

Explanation:

6.75  / 4.5   = 1.5  half lives

1/2 ^(1.5) = .354      or   35 .4 %

Energy enters into the ecosystem via sunlight and leaves as heat from metabolism.

The term energy refers to the ability to do work. Energy enters the ecosystem from the sun and is transformed into chemical energy in food which is now passed along the food chain.

Animals eat plants and part of this energy is used for metabolic activities which releases some of this energy as heat energy.

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Answer:

Is Fahrenheit and Celsius the answers you are looking for?

Explanation:

I hope this could help you! :)

Answer:

Temperature Scales. There are three temperature scales in use today

Explanation:

Given the remaining quantity after the given time and the half-life, the initial quantity or original mass of the sample is 32g.

Option A) is the correct answer.

Half-life is simply the amount of time it takes a given quantity to decrease to half of its initial value.

Using the expression:

[tex]N_{(t)} = N_{0}\frac{1}{2}^{\frac{t}{t_{\frac{1}{2} }} }[/tex]

Given the data in the question;

[tex]N_{(t)} = N_{0}\frac{1}{2}^{\frac{t}{t_{\frac{1}{2} }} }[/tex]

[tex]1.0g = N_{0} * (0.5)^{40days/8.07days}\\\\1.0g = N_{0} * (0.5)^{4.95662949}\\\\1.0g = N_{0} * 0.0322037055\\\\N_{0} = \frac{1.0g}{0.0322037055} \\\\N_{0} = 31.05g = 32g[/tex]

Therefore, given the remaining quantity after the given time and the half-life, the initial quantity or original mass of the sample is 32g.

Option A) is the correct answer.

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Heat transfer is the phenomenon that occurs when the two objects are in the vicinity of each other and by increasing the area of their contact. Thus, option B is correct.

Heat transfer is a process that flows the heat from one system to another, and is because of the difference in the temperature of the two objects that are part of the system.

The methods like conduction, convection, and radiation transfer the heat from the surface area to the other object. The heat gets transferred from the area of high to the low temperature.

Therefore, option B. by increasing the surface area the heat transfer increases.

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Answer:

Less

Explanation:

The hydronium from the HCl is used to neutralize the bicarbonate in the baking soda. The hydronium is the acid and the bicarbonate ion is the base while the sodium and chloride ions are pH-neutral. Since theres a 1:1 mole ratio of hydronium to HCl and bicarbonate to sodium bicarbonate, it would require less HCl to neutralize a less concentration baking soda solution.

Gamma decay is a radioactive decay in which there is no measurable change in mass and the element remains the same.

In gamma decay, the number of protons and neutrons in the nucleus does not change, so the product of decay remain the same element..

Note that mass number is equal to the sum of the protons and neutrons and so if there is no change, the mass of the element remains the same.

Thus, gamma decay is a radioactive decay in which there is no measurable change in mass and the element remains the same.

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Answer:

B - The energy of reactants is conserved.

D - the nuclei of atoms changes completely ( if that's the option)

The energy carried by the waves depends on the amplitude of the wave. If the amplitude is doubled then the energy gets increased by four times.

The amplitude of a wave is the distance from the center line to the trough or the crest of the wave. The energy of the wave is directly proportional to the square of the amplitude.

E  ∝ A²

So if the amplitude is doubled then E = 4. Hence, the energy gets increased quadruples times. The energy is related to the frequency and the wavelength of the wave that travels.

Therefore, the energy gets increased by four times if the amplitude is doubled.

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Answer:

No, assuming that the salt/sugar is already dissolved

Explanation:

As long as the particle size is too big, it won't filter through. Therefore, if it is dissolved, it will pass through the filter.

If you were to throw rocks in there or something, and they are non-dissolvable, then yes.

Answer: [tex]2168 ^{\circ} \text{C}[/tex]

Explanation:

For this question, we can use the formula [tex]Q=mc \triangle T[/tex], where [tex]Q[/tex] is the amount of heat absorbed, [tex]m[/tex] is the mass of the sample, [tex]c[/tex] is the specific heat constant, and [tex]\triangle T[/tex] is the change in temperature (final temperature minus initial temperature as stated in the question).

From the question, we know that [tex]m=175, Q=1.57 \times 10^{6}[/tex]. Furthermore, we know that [tex]c=4.18[/tex] (this is just a fact).

So, we get that [tex]1.57 \times 10^{6}=175(4.18)(\triangle T)[/tex], meaning [tex]\triangle T=2146[/tex].

Thus, [tex]t_{f}-22.0=2146 \longrightarrow t_{f}=\boxed{2168 ^{\circ} \text{C}}[/tex]

The flying dinosaurs becoming extinct was the reason they were not found in rocks that are younger than those formed during the Mesozoic era.

This is defined as preserved remains of plants and animals found on earth crust.

The flying dinosaurs became extinct which was why the fossils found during the Mesozoic era were not younger and makes option C correct.

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