Since impulse is defined as a change in momentum, we may conclude that since all autos are based on magnitude, their initial momentum and ultimate momentum are the same. Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5
What is magnitude?Magnitude is a term used in physics to describe an object's maximal size and direction. Magnitude is a factor that is shared by both scalar and vector quantities. We are aware that by definition, scalar quantities are those with only magnitude. It displays an object's size, direction, or motion in absolute or relative terms. It is used to describe something's size or scope. Magnitude in physics typically refers to a size or quantity.
How much is a magnitude?One is roughly 10 times greater than the other if two integers are separated by one order of magnitude. They differ by a factor of around 100 if they are separated by two orders of magnitude. The greater value is less than 10 times the smaller value when two numbers are of the same order of magnitude.
Briefing:Automobile-1 Mass= 2000kg = 5m/s
Automobile-2 Mass= 1000kg = 10m/s
Automobile-3 Mass= 500kg = 20m/s
Automobile-4 Mass= 4000kg = 5m/s
Automobile-5 Mass= 500kg = 10m/s
Automobile-6 Mass= 1000kg = 20m/s
Since we now understand that each car's momentum is the result of its mass and velocity, we will have
Automobile-1
P₁ = m × v
P₁ = (2000)(5)
P₁ = 2 × 10⁴kgm/s
Automobile-2
P₂ = m × v
P₂ = (1000)(10)
P₂ = 10⁴kgm/s
Automobile-3
P₃ = m × v
P₃ = (500)(20)
P₃ = 10⁴kgm/s
Automobile-4
P₄ = m × v
P₄ = (4000)(5)
P₄ = 2 × 10⁵kgm/s
Automobile-5
P₅ = m × v
P₅ = (500)(10)
P₅ = 10³kgm/s
Automobile-6
P₆ = m × v
P₆ = (1000)(20)
P₆ = 2 × 10⁵kgm/s
Then the momentum is:
Automobile 6 = Automobile 4>(Automobile 2 = Automobile 3>Automobile 1> Automobile 5
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establish the relation among energy, density, strain and stress
Strain energy is defined as the energy stored in a body due to deformation. The strain energy per unit volume is known as strain energy density and the area under the stress-strain curve towards the point of deformation.
Two physical science classes are playing tug of war. Mrs. Hankinson’s class pulls left with a force of 100 N, while Mrs. Wade’s class pulls with a force of 105 N in the opposite direction.
What is the net force, and which class won?
A. 205 N, Mrs. Wade's class
B. 5 N, Mrs. Wade's class
C. 205 N, it was a tie
D. 5 N, Mrs. Hankinson's class
The net force is 5 N and the class that won is Mrs. Wade's class (Option B)
How do I determine the net force?We can obtain the net force by using the following formula:
Net force = Opposite force - force of pull
Now, we shall determine the net force as illustrated below:
Force by Mrs. Hankinson’s class = 100 NForce by Mrs. Wade’s class = 105 NNet force =?Net force = Opposite force - force of pull
Net force = Mrs. Wade’s class - Mrs. Hankinson’s class
Net force = 105 - 100
Net force = 5 N
From the above calculation, we can say that the net force is 5 N and the class that won given the above data is Mrs. Wade’s class
Therefore, the correct answer to the question is:
5 N, Mrs. Wade's class (Option B)
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