Resting body temperatures are normally distributed with an average of 98.25 degrees
Fahrenheit and a standard deviation of 0.73 degrees Fahrenheit. A nurse examines 40 patients in one hour. What is the probability the average temperature of the 40 patients is between 98.0 degrees Fahrenheit and 98.50 degrees Fahrenheit? (Round to the hundredths)
A)0.97
B)0.11542313
C)0.99
D)Sample size is not larger than 40 so we cannot compute probability
step 1
Find the z-scores
For x=98.0 degrees
z=(98-98.25)/0.73 --------> z=-0.3425
For x=98.50
z=(98.50-98.25)/0.73 ------> z=0.3425
using a Z-score Calculator
we have that
P=0.26803
step 2
we have that
helppppppppppppppppppypyppyoyoyoyoy
We are to solve using completing the square:
1/4x² + x + 1/4 = 0
Let's collect like terms:
1/4x² + x = -1/4
Divide both sides by the coefficient of x-squared:
x² + 4x = -1
Take half of the coefficient of x, square it, then add to both sides:
x² + 4x + 4 = -1 + 4
factor the left side of the equation:
(x + 2)² = 3
Take the root of both sides;
x + 2 = ±√3
Add 2 to both sides:
x = ±√(3) - 2
x = -2 + √3 or x = -2 - √3
herefore, the correct option is B, which is x = -2 + √3 or x = -2 - √3
What is the quotient of 2.538\times 10^92.538×10
9
and 2.7 \times 10^22.7×10
2
expressed in scientific notation?
IF U DON"T KNOW THE ANSWER DON"T ANSWER & work it out plss
The quotient of 2.538 ×10^9 and 2.7×10^2 expressed in scientific notation is : 0.94 × 10^6.
Scientific notationGiven:
2.538 × 10^ 9 and 2.7 × 10^ 2
We have to first of all formulate before determining the scientific notation
(2.538 × 10^ 9) ÷ (2.7 × 10^2)
Rewrite as fraction
2.538 × 10^9 ÷ 2.7 × 10^2
simplify
2.538 ÷ 2.7 × 10^ 9-2
= 2.538 ÷ 2.7 × 10^7
Convert the fraction to decimal
0.94 × 10^7
Now let express it in scientific notation
Scientific notation = 94 × 10^6
Therefore the scientific notation is 94 × 10^6.
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The correct question is:
What is the quotient of 2.538 ×10^9 and 2.7×10^2 expressed in scientific notation
Give an example of each survey question type below that would relate to an organic produce farmer.
a) Dichotomous
b) Multiple choice
c) Rating scale
d) Completion
e) Open-ended
Examples of each survey question that relates to organic farm produce are as follows;
a) Dichotomous
Do you prefer organic farm produce?
Yes/No
b) Multiple choice
How many of your colleagues make use of organic farm produce
OneTwoThreeFourFivec) Rating scale
On a scale of 1 to 5, with 10 being happiest, how happy are you about our customer service?
1, 2, 3, 4, 5
d) Completion
Eating organic produce _______ improve my health
Will
Will not
e) Open-ended
Tell us why you prefer organic farm produce ___________
What is a statistical survey?A survey involves the administration of questions or the examination of a process that is aimed at obtaining data with regards to a service, process or product.
a) Dichotomous questions are questions that can have only two possible responses. Such questions are used in a survey in which the two possible responses are stated such as Agree/Disagree, Yes/No, Fair/Unfair, True/False, or Cold/Hot. Based on the definition of the responses, the opinion of the responder is made clear
An example of a dichotomous question asked with respect to organic farm produce is 'Do you prefer organic farm produce?'
The possible responses are; Yes/No
b) Multiple choice survey question
Multiple choice questions provide the opportunity for a respondent to have more options to choose a response from. The multiple choice questions also allow researcher to obtain detailed information on the subject.
An example of multiple choice question is as follows;
How many of your colleagues make use of organic farm produce
OneTwoThreeFourFivec) Rating Scale
In rating scale survey questions the respondents are asked to select a rating of their experience in a response that offers a rating such as 1 to 10 or 1 to 100
An example of a rating scale question in a survey is as follows;
On a scale of 1 to 5, with 10 being happiest, how happy are you about our customer service?
1, 2, 3, 4, 5
d) Completion
Completion type question assesses the level of cognition on a subject matter
Example;
Eating organic produce _______ improve my health
WillWill note) Open–ended
Open–ended questions gives respondents the latitude to express themselves with regards to the question in written text in a detailed or in a brief response.
Example;
Tell us why you prefer organic farm produce ___________
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a wood cutter has 1/4 + 2/4 + 3/4 of wood And goes to the store and buys 1/4 + 2/4 + 3/4 And adds all of his wood up.
Answer: I believe the answer is 3.
Step-by-step explanation:
a wood cutter has 1/4 + 2/4 + 3/4 So we add those up to get 6/4.
Then he buys the same amount again which would make 12/4.
We are not done probably, so we MUST simplify.
how many times can 4 fit into 12? 3! so we have whole number 3 and since 4 fit into 12 3 times perfectly all we have is 3
find all the zeros of the[tex]y = x^2 - x - 20[/tex] quadratic function
TO find the zeros of a quadratic function we should factorize the function
[tex]x^2-x-20=(x-)(x+)[/tex]So we have to find numbers that multiplied are -20 and added are -1. So we get -5 and 4
[tex]x^2-x-20=(x-5)(x+4)[/tex]
so the zeros of the function are 5 and -4
3.656 X 10^-5 written in standard form
To write 3.656 X 10^-5 in standard form 0.00003656
What is Standard Form ?
A mathematical item's canonical, normal, or standard form refers to how the object is typically expressed mathematically in both mathematics and computer science. It is frequently the one that offers the most straightforward illustration of the thing while yet enabling distinctive identification.
Move the decimal in the number that many spaces to the right when multiplying a number by 10 to the power of a positive exponent
(for example, (10)^3)).
For example, 4.5x(10)^3=4500.
Move the decimal in the number (the absolute value of) that many spaces to the left when multiplying a number by 10 to the power of a negative exponent
(for example, (10)^4)).
For example, (4.5x10)^4=(0.00045)
Move the decimal five spaces to the left for (3.656x 10)^-5:
0.00003656
Hence , 0.00003656 is Standard form of (3.656x 10)^-5
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Sam is installing a walkway around a rectangular flower patch in his garden. The flower patch is 12 feet long and 6 feet wide. The width of the walkway is x feet.
Sam created function A to represent the total area taken up by the flower patch and walkway by multiplying the functions modeling the new total length and width.
What does represent in this function?
A.
the area of the walkway along the width of the flower patch
B.
the total area of the walkway
C.
the total area of the flower patch
D.
the area of the walkway along the length of the flower patch
The function represents the area of the walkway along the width of the flower patch.
What is function?Rule, or law that establishes the link between an independent variable and a dependent variable is known as function.
Functions can be found everywhere in mathematics, and they are essential for building physical connections in the sciences.
The German mathematician Peter Dirichlet initially offered the contemporary definition of function in 1837.
The total area taken up by the flower patch and walkway by multiplying the functions modeling the new total length and width represents the area of the walkway along the width of the flower patch.
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THE GILBERTS PURCHASED A CAR. IF THE TOTAL COST, INCLUDING A 5% SALES TAX, WAS $14,512, FIND THE COST OF THE CAR BEFORE TAX
The cost of the car the Gilberts purchased before tax is $13,820.52.
What is the cost before tax?Tax is a compulsory amount that is levied on a good or service by the government. A sales tax is a tax that is levied on the purchase of a good and service. Taxes increase the cost of a good or service.
The equation that can be used to determine the cost of the car after tax is:
(1 + sales tax) x cost before tax = cost after tax
(1 + 0.05) x c = $14,512
1.05c = $14,512
In order to determine the value of c, divide both sides of the equation by 1.05:
c = $14,512 / 1.05
c = $13,820.52
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Aidan scored 390 points in 20 games what is his scoring rate in points per game?
Answer:
19.5
Step-by-step explanation:
HELP PLEASE!!!
In a recent year, 26% of all college students were enrolled part-time. If 4.4 million college students were enrolled part-time that year, what was the total number of college students? Round your answer to the nearest million.
Answer: 17 million
Step-by-step explanation:
We will set up a proportion to solve. We also will divide 26% by 100 to get a decimal, 0.26. We know that 26% of college students was 4.4 million, but we want to find 100%.
[tex]\displaystyle \frac{0.26}{4.4\text{ million}} =\frac{1}{x\text{ million}}[/tex]
Now, we will cross-multiply.
0.26 * x = 1 * 4.4
0.26x = 4.4
Lastly, we will divide both sides of the equation by 0.26. Then, we will round to the nearest million.
x = 16.923
x ≈ 17 million
The width of a rectangle is fixed at 5 cm. Determine (in terms of an inequality) those lengths for which the area will be less than 125 cm2.
The lengths of the rectangle for which the area will be less than 125 cm² is 5 < m < 25
In this question, we have been given the width of a rectangle is fixed at 5 cm.
We need to determine (in terms of an inequality) those lengths for which the area will be less than 125 cm²
Let 'm' be the length of the rectangle.
The area of the rectangle is:
A = length × width
The area of the rectangle should be less than 125 cm²
5 × m < 125
Divide both the sides of the inequality by 5
m < 25
This means, the length of rectangle should be less than 25 cm
But length is always greater than the width of the rectangle.
So, we get an inequality 5 < m < 25
Therefore, the lengths of the rectangle for which the area will be less than 125 cm² is 5 < m < 25
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Simplify -16.26-(-5.82)-(4.20) - (-6.85).
Answer:
Step-by-step explanation:
=−10.44−4.2−(−6.85)
=−14.64−(−6.85)
=−7.79
Answer:
-7.79
Step-by-step explanation:
Given problem,
→ -16.26 - (-5.82) - (4.20) - (-6.85)
Let's simplify the problem,
→ -16.26 - (-5.82) - (4.20) - (-6.85)
→ -16.26 + 5.82 - 4.20 + 6.85
→ -10.44 + 2.65 = -7.79
Hence, the answer is -7.79.
So I’m doing this assignment and got stuck on this question can anyone help me
Explanation:
The question involves dividing radicals
To resolve the question, we will follow the steps below
Step 1: Write the expression
[tex]\sqrt{50x^3}\div\sqrt{32x^2}[/tex]Step 2: simplify the expression in parts and apply the laws
[tex]\begin{gathered} \sqrt{50x^3}=\sqrt{25\times2\times x^2\times x} \\ =\sqrt{25\times2\times x^2\times x}=\sqrt{5^2\times2\times x^2\times x}=\sqrt{5^2}\times\sqrt{x^2}\times\sqrt{2x} \end{gathered}[/tex]Thus
[tex]\begin{gathered} \sqrt{50x^3}=\sqrt{5^2}\times\sqrt{x^2}\times\sqrt{2x}=5\times x\times\sqrt{2x} \\ Therefore \\ \sqrt{50x^3}=5x\sqrt{2x} \end{gathered}[/tex]For the second part
[tex]\sqrt{32x^2}=\sqrt{16\times2\times x^2}[/tex]simplifying further
[tex]\sqrt{16\times2\times x^2}=\sqrt{16}\times\sqrt{x^2}\times\sqrt{2}[/tex]Hence, we have
[tex]\sqrt{16}\times\sqrt{x^2}\times\sqrt{2}=4\times x\times\sqrt{2}=4x\sqrt{2}[/tex]Finally, we will combine the simplified terms, so that we will have
[tex]\sqrt{50x^3}\div\sqrt{32x^2}=5x\sqrt{2x}\div4x\sqrt{2}[/tex]Hence, we will have
[tex]\frac{5x\sqrt{2x}}{4x\sqrt{2}}=\frac{5}{4}\times\frac{x}{x}\times\frac{\sqrt{2}}{\sqrt{2}}\times\frac{\sqrt{x}}{1}[/tex]By canceling out the common parts, we will have the answer to be
[tex]\frac{5}{4}\sqrt{x}[/tex]
If the quotient of a number and 8 is added to 1/4 the result is 7/8. Find the number.
Answer:
5
Step-by-step explanation:
Let n be the unknown number.
The quotient is the result obtained by dividing one number by another.
Therefore, the quotient of a number and 8 is ⁿ/₈.
If the quotient of a number and 8 is added to 1/4 the result is 7/8:
[tex]\implies \dfrac{n}{8}+\dfrac{1}{4}=\dfrac{7}{8}[/tex]
To solve, make the denominators of all the fractions the same:
[tex]\implies \dfrac{n}{8}+\dfrac{1 \cdot 2}{4 \cdot 2}=\dfrac{7}{8}[/tex]
[tex]\implies \dfrac{n}{8}+\dfrac{2}{8}=\dfrac{7}{8}[/tex]
[tex]\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:[/tex]
[tex]\implies \dfrac{n+2}{8}=\dfrac{7}{8}[/tex]
Multiply both sides by 8:
[tex]\implies \dfrac{8(n+2)}{8}=\dfrac{7 \cdot 8}{8}[/tex]
[tex]\implies n+2=7[/tex]
Subtract 2 from both sides:
[tex]\implies n+2-2=7-2[/tex]
[tex]\implies n=5[/tex]
Therefore, the number is 5.
Name the rule for this sequence.
27, 21, 15, 9, 3,…
A. divide the previous term by 0.06
B. divide the previous term by 0.6
C. add 6 from the previous term
D. subtract 6 from the previous term
C. add 6 from the previous term
To get the next term in the sequence, you subtract 6 from the previous term.
Complete.
:14=15:21
Someone please answer how to solve
Answer:
The missing number is 10Step-by-step explanation:
Given ratiox : 14 = 15 : 21Multiply both sides by 14 to find the missing value:
x = 14*15/21 x = 10Write an equation for each line
The equation for each line will be y=-x+2.
What is a linear equation?It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
It is given that,
The coordinate of the points are (2,0) and (0,2)
The slope of the line is,
[tex]\rm m =\dfrac{y_2-y_1}{x_2-x_1} \\\\ m = \frac{2-0}{0-2} \\\\ m = -1[/tex]
The standard equation of the line is,
y-y₁ = m(x-x₁)
y-0=-1(x-2)
y=-x+2
Thus, the equation for each line will be y=-x+2.
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point a of a triangle is at 2, to point via that a reflection of a point across the X axle a c is 5 unit directly to the left of the point B what are the triangles Dimensions you may you wish to plot the point on your own piece of graph paper
From the question;
Point A is at (2,2)
Point B is the reflection of point A across the x-axis;
The rule for reflection across the x-axis is;
[tex](x,y)\rightarrow(x,-y)[/tex]So, point B will be;
[tex]A(2,2)\rightarrow B(2,-2)[/tex]The point C is 5 units directly left of point B;
So, point C will be;
[tex]\begin{gathered} (x,y)\rightarrow(x-5,y) \\ B(2,-2)\rightarrow C(2-5,-2) \\ B(2,-2)\rightarrow C(-3,-2) \end{gathered}[/tex]Therefore, the coordinates of the Points A, B and C are;
[tex]\begin{gathered} A(2,2) \\ B(2,-2) \\ C(-3,-2) \end{gathered}[/tex]Shown as;
So, the length AB is;
[tex]AB=2-(-2)=4[/tex]The length BC is;
[tex]undefined[/tex]Tanisha earns $3,000 per month
after taxes. She saves $720. What
percent of her budget is savings?
Answer:
[tex]{ \tt{\% savings = \frac{savings}{total \: income} \times 100\%}} \\ \\ { \tt{ = \frac{720}{3000} \times 100\%}} \\ \\ = { \tt{24\%}}[/tex]
Answer:
24%
Step-by-step explanation:
[tex]\boxed{\sf Percent=\left(\dfrac{Value}{Total\:value}\right) \times 100}[/tex]
Given information:
Value (savings) = $720Total value (earnings) = $3,000Substitute the given values into the formula and solve for percent:
[tex]\begin{aligned}\implies \textsf{Percent} & =\dfrac{720}{3000} \times 100\\\\& = \dfrac{720\times 100}{3000} \\\\& = \dfrac{72000}{3000} \\\\& = \dfrac{72}{3} \\\\& = 24\% \end{aligned}[/tex]
Therefore, 24% of Tanisha's budget is savings.
Determine the values of m in the equation m2 = 16. m = ±4 m = 4 m = ±8 m = 8
The values of m that can fit into the equation m² = 16 will be m = ±4.
How to compute the value?It should be noted that a equation is simply used to illustrate the relationship between the variables that are given. From the information, it should be noted that the equation is illustrated as m² = 16.
Since m² = 16, we need to find the square root. This will be illustrated as:
m² = 16
m = ✓16
m = 4
It should be noted that (-4) × (-4) = 16 and 4 × 4 = 16.
Therefore, the correct option is m = ±4
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Jaxon was taking his boat out around the lake. The boat is able to drive for 18 minutes for every gallon of gas. Jaxon has 8 gallons of gas in his boat so he bought another 12 gallons. How long can the boat run for now? (In minutes)
Answer:
hi
Step-by-step explanation:
i dot no because i dot spak in english because im frach
out of water park 243 out of 675 tickets were sold child tickets what percentage of the tickets were child tickets
Total ticket = 675
Child tickrt sold = 243
percentage of child tickets sold
[tex]\begin{gathered} =\text{ }\frac{243}{675}\text{ x 100\%} \\ \\ =\text{ }\frac{243\text{ x 100}}{675} \\ =\text{ }\frac{24300}{675} \\ =\text{ 36\%} \end{gathered}[/tex]Factor the trinomials:
1) [tex]x^2 -2x-2[/tex]
2)[tex]x^2-6x+4[/tex]
Given that equation
1) [tex]x^{2} - 2x - 2[/tex] using the general quadratic equation, x = 1
2)[tex]x^{2} -6x -4[/tex] using the general quadratic equation, x= [tex]\frac{6 - \sqrt{20} }{2}[/tex]
According to the question, given that
1) [tex]x^{2} - 2x - 2[/tex]
2)[tex]x^{2} -6x -4[/tex]
this equation cannot be factored but using general quadratic equation. we solved it easily.
When asked to solve a quadratic equation that you just can’t seem to factor (or that just doesn’t factor), you have to employ other ways of solving the equation, such as by using the quadratic formula. The quadratic formula is the formula used to solve for the variable in a quadratic equation in standard form.
Given a quadratic equation in standard form ax2 + bx + c = 0,
[tex]x = \frac{- b - \sqrt{b^{2} - 4 ac } }{2a}[/tex] and [tex]x = \frac{- b + \sqrt{b^{2} - 4 ac } }{2a}[/tex]
solve [tex]x^{2} - 2x - 2[/tex] = 0, you first say that a = 1, b = –2, and c = 2. The a, b, and c terms simply plug into the formula to give you the values for x:
1) [tex]x^{2} - 2x - 2[/tex]
[tex]x = \frac{- (-2) + \sqrt{(-2)^{2} - 4 (1)(1) } }{2(1)}[/tex]
[tex]x = \frac{2 + \sqrt{4 -4} }{2}[/tex]
x = [tex]\frac{2}{2}[/tex]
[tex]x = 1[/tex]
and [tex]x = \frac{- (-2) - \sqrt{(-2)^{2} - 4 (1)(1) } }{2(1)}[/tex]
[tex]x = \frac{2 - \sqrt{4 -4} }{2}[/tex]
x = [tex]\frac{2}{2}[/tex]
[tex]x = 1[/tex]
equation [tex]x^{2} - 2x - 2[/tex] and x= 1
2)[tex]x^{2} -6x -4[/tex]
solve [tex]x^{2} - 6x - 4[/tex] = 0, you first say that a = 1, b = –6, and c = 4. The a, b, and c terms simply plug into the formula to give you the values for x:
[tex]x^{2} -6x -4[/tex]
[tex]x = \frac{- (-6) + \sqrt{(-6)^{2} - 4 (1)( 4) } }{2(1)}[/tex]
[tex]x = \frac{6 + \sqrt{36 - 16} }{2}[/tex]
x = [tex]\frac{6 \sqrt{20} }{2}[/tex]
and [tex]x = \frac{- (-6) - \sqrt{(-6)^{2} - 4 (1)(4) } }{2(1)}[/tex]
[tex]x = \frac{6 - \sqrt{36 - 16} }{2}[/tex]
x = [tex]\frac{6 - \sqrt{20} }{2}[/tex]
equation [tex]x^{2} - 6x + 4[/tex] and x= [tex]\frac{6 - \sqrt{20} }{2}[/tex]
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3. A rectangle that is 2 cm by 3 cm has been scaled by a factor of 5. What are the dimensions of the new rectangle?
New width: 10 cm, new length: 15 cm
Or new width 15 and new length 10
1) Since this rectangle, has been scaled up by a factor k=5 (since 5 >1 then the rectangle has been enlarged)
2) Then we can write the following about their new dimensions:
w = 2 x 5 = 10
l = 3 x 5 = 15
3) So the answer is 10 x 15
A model rocket is launched straight up into the air. The height y (in feet) of the rocket after t seconds can be modeled by y=-16t^2+128t. How many seconds is the rocket in the air?
Answer:
8
Step-by-step explanation:
To find the time the rocket is in the air, we can find the time when the height is 0 (remember this time is not 0).
[tex]-16t^2+128t=0 \\ \\ t^2-8t=0 \\ \\ t(t-8)=0 \\ \\ t=0,8 \\ \\ t \neq 0 \implies t=8[/tex]
The area of a rectangle is solved by multiplying the length and width of a rectangle. A rectangular field has an area of 57,600 square feet. If its width is 160 feet, what is its length?
Answer:
360ft
Step-by-step explanation:
Here,
Given,
→Area=57600ft²
→Width=160ft
Now,
→Length=Area/Width
→Length=57600ft²/160ft=360ft
A designer has designed different tops, pants, and jackets to create outfits. How many different outfits can the models wear if she has designed the following pieces?
seven tops, two pants, eight jackets
There are a total of different outfits
The most appropriate choice for combination will be given by-
Models can wear 112 different types of outfit.
What is combination?
Combination determines the number of ways of selecting some number of particular items from a group of given item, here the order of selection do not matter.
If there are n objects and from there, r objects are chosen, number of ways will be given by
[tex]n \choose r[/tex] = [tex]\frac{n!}{(n - r)! \times r!}[/tex]
Here,
Number of tops = 7
Number of pants = 2
Number of jackets = 8
From 7 tops the designer can choose 1 top in [tex]7 \choose 1[/tex] ways
= [tex]\frac{7!}{(7-1)!\times 1 !}[/tex]
= [tex]\frac{7!}{6!}[/tex]
= [tex]7[/tex]
From 2 pants the designer can choose 1 pant in [tex]2 \choose 1[/tex] ways
= [tex]\frac{2!}{(2-1)!\times 1 !}[/tex]
= [tex]\frac{2!}{1!}[/tex]
= [tex]2[/tex]
From 8 jackets the designer can choose 1 jacket in [tex]8 \choose 1[/tex] ways
= [tex]\frac{8!}{(8-1)!\times 1 !}[/tex]
= [tex]\frac{8!}{7!}[/tex]
= [tex]8[/tex]
Total number of different outfits models can wear = [tex]7 \times 2 \times 8[/tex]
= 112
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Choose the expression that is equivalent to a fraction with six raised to the negative third power in the numerator and the quantity three raised to the negative second power times six squared end quantity in the denominator and the entire fraction is cubed.
three raised to the sixth power divided by six raised to the fifteenth power
three squared divided by six raised to the fifth power
negative three raised to the sixth power divided by six raised to the fifteenth power
negative three squared divided by six raised to the fifth power
The value of the expression in the options is (a) three raised to the sixth power divided by six raised to the fifteenth power
How to determine the equivalent expression of the expression?The expression is given as
A fraction with six raised to the negative third power in the numerator and the quantity three raised to the negative second power times six squared end quantity in the denominator and the entire fraction is cubed.
Rewrite the expression properly
So, we have
[6^-3/(3^-2 x 6^2)]^3
Apply the law of indices to the expression
So, we have
[6^-3/(3^-2 x 6^2)]^3 = [6^(-3 - 2)/(3^-2)]^3
Evaluate the difference
[6^-3/(3^-2 x 6^2)]^3 = [6^-5/(3^-2)]^3
Apply the change of power rule
[6^-3/(3^-2 x 6^2)]^3 = [3^2/6^5]^3
Evaluate the product of exponents
[6^-3/(3^-2 x 6^2)]^3 = 3^6/6^15
In words, the result is (a) three raised to the sixth power divided by six raised to the fifteenth power
Hence, the value of the expression is (a)
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Lerato begins a new cycling programme with 2 km on the first day. Each day, he will increase his cycling by 500 m. How many kilometres will he cycle on day 30 of his programme?
He will cover total 247.5 kilometers on day 30 of his programe .
What is arithmetic progression ?When there are identical differences between every two next words, the series is known as an arithmetic progression (AP). There is a chance to find a formula for the nth term of the AP using this kind of development. The series 2, 6, 10, 14, etc., for instance, is an example of an arithmetic progression (AP) because it follows a pattern in which each number is acquired by adding 4 to the preceding word. Nth term in this series equals 4n-2.
Given that :Lerato begins a new cycling programme with 2 km on the first day. Each day, he will increase his cycling by 500 m.
The formula to find Sum of an arithmetic progression is
S = [tex]\frac{n}{2}[2a+(n-1)d][/tex]
here , a = 2km
n = 30
d = 0.5km
S =[tex]\frac{30}{2}[2(2)+(30-1)0.5][/tex]
S = 247.5 km
He will cover total 247.5 kilometers on day 30 of his programe
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The formula to show the height and time an object is in the air is given byh(t) = -16t2 + 48t + 50 where h(t) is the height of an object and t is the timein seconds. Find how long the object is in the air before it hits the ground.
The formula to show the height and time an object is in the air :
[tex]h(t)=-16t^2+48t+50[/tex]when the object hits the ground the height will become 0
so, put h(t) = 0
and simplify :
[tex]\begin{gathered} h(t)=-16t^2+48t+50 \\ 0=-16t^2+48t+50 \\ -16t^2+48t+50=0 \end{gathered}[/tex]Simplfy the equation by using discrimination rule :
The general form of quadratic equation is : ax² + bx + c
and the roots are express a s :
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]On compare the given equation with the general equation we get :
a = -16, b = 48 and c = 50
Substitute the value and simplify :
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