Riders in an amusement park ride shaped like a Viking ship hung from a large pivot are rotated back and forth like a rigid pendulum. At each end of the swing the ship hangs motionless for a moment before the ship swings down under the influence of gravity. Assume that this motionless point occurs when the bar connecting the pivot point and the ship is horizontal.

Required:
a. Assuming negligible friction, find the speed of the riders at the bottom of its arc, given the system's center of mass travels in an arc having a radius of 14.0 m and the riders are near the center of mass.
b. What is the centripetal acceleration at the bottom of the arc?
c. Draw a free body diagram of the forces acting on a rider at the bottom of the arc.
d. Find the force exerted by the ride on a 60.0 kg rider and compare it to her weight.
e. Discuss whether the answer seems reasonable.

Answer:

They each have one single proton (Z = 1), but differ in the number of their neutrons. Hydrogen has no neutron, deuterium has one, and tritium has two neutrons. The isotopes of hydrogen have, respectively, mass numbers of one, two, and three.

Explanation:

Answer:

C

Explanation:

Answer: The correct answer is formation of four haploid nuclei.

The event occurring during telophase II includes formation of four haploid daughter cells. Telophase II is the final and the fourth stage in meiosis II when the chromosomes reach the opposite poles of the nuclear spindle. During this stage both the daughter cells get divided forming four haploid cells. The development of the nuclear envelope around each set of the chromosome and cytokinesis also takes place during telophase II.

Explanation:

???

Explanation:

Our solar system formed about 4.5 billion years ago from a dense cloud of interstellar gas and dust. The cloud collapsed, possibly due to the shockwave of a nearby exploding star, called a supernova. When this dust cloud collapsed, it formed a solar nebula—a spinning, swirling disk of material.

Answer:

x = 1, y = 1 and z = 0

Explanation:

Given equation;

[tex]P^x V^y T^z = constant[/tex]

Boyle's law states that at constant temperature, the volume of a fixed mass of gas is inversely proportional to its pressure.

Mathematically the law is written as;

[tex]PV = constant[/tex]

From the given equation, the values of x, y and z that will match this law is calculated as follows;

[tex]P^1 V^1 T^0 = constant\\\\P^1 = P\\\\V^1 = V\\\\T^0 = 1\\\\P \times V \times 1 = PV = constant\\\\Thus, x = 1, \ y = 1 \ \ and \ z = 0[/tex]

Answer:2.23 m/s

Explanation:

Given

Mass of person and vehicle is [tex]m=1600\ kg[/tex]

Total work done is [tex]W_t=6000\ J[/tex]

Friction consumes one-third of the energy

The remaining two-third is consumed to increase the kinetic energy

[tex]\Rightarrow \dfrac{2}{3}\times 6000=\dfrac{1}{2}\times 1600\times v^2\\\\\Rightarrow 4000\times 2=1600\times v^2\\\\\Rightarrow v=\sqrt{5}\ \approx 2.23\ m/s[/tex]

Answer:

A.

Explanation:

Electrons

Explanation:

force=35

distance=18

time=30

power=f×d/t

p=35×18/30

p=21

Answer:

.lyrjhg.

Explanation:

qqlqfgtjnfh

Answer:

The nephew

Explanation:

The nephew has a seeing eye dog which means the nephews tracks are the dogs tracks, and the dog tracks are not covered by anything which means the dog was last and stole the butterfly.

Hope this helps!

Answer:

Weight of car = 36034.88 lb.ft/s²

Explanation:

We are told the pressure of the four tires of your car is; P = 35.0 psi

Also, the surface area of contact is; A = 32 in²

Thus;

Weight of tires = Pressure × Area

W_tires = 35 × 32

Weight_tires = 1120lb.

To get the weight of the car, we will multiply the tire weight by acceleration due to gravity.

It's value in ft/s² is g = 32.174 ft/s²

Thus;

Weight of car = 1120 × 32.174

Weight of car = 36034.88 lb.ft/s²

Answer:

Wavelength

Explanation:

A vibration can cause a disturbance to travel through a medium, transporting energy without transporting matter. This is what a wave is.

Answer:

True.

Explanation:

Science can be defined as a branch of intellectual and practical study which systematically observe a body of fact in relation to the structure and behavior of non-living and living organisms (animals, plants and humans) in the natural world through experiments.

A concept is the general idea of objects, events, animals, or people based on common features, traits, or characteristics. It is typically considered to be an abstract idea or general notion that is formed by the mental combination of all the characteristics pertaining to the idea.

Generally, concepts are used in the problem-solving process as it serves as a benchmark or yardstick for the solutions. Some examples of concepts in physics are conservation of energy and momentum, electromagnetic waves, heat, motion and forces, electricity and magnetism, gravity, etc.

Answer:

TRUE

Explanation:

edge

Answer:

Light Winds

Explanation:

Answer:

(a) Q = 142.67 W

(b) Basal Metabolic Rate = 178.33 W

Explanation:

(a)

We can find the heat radiated by the person by using Stefan-Boltzman's law:

[tex]Q = \sigma A (T^4 - T_{s}^4)\\[/tex]

where,

Q = heat radiated per second = ?

σ = Stefan-Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴

A = Surface Area = 2 m²

T = Temperature of Skin = 30° C + 273 = 303 k

Ts = Temperature of room = 18° C +273 = 291 k

Therefore,

[tex]Q = (5.6703\ x\ 10^{-8}\ W/m^2.k^4)(2\ m^2)[(303\ k)^4-(291\ k)^4][/tex]

Q = 142.67 W

(b)

Since the heat calculated in part (a) is 80 percent of basal metabolic rate. Therefore,

[tex]Q = (0.8)(Basal\ Metabolic\ Rate)\\Basal\ Metabolic\ Rate = \frac{Q}{0.8}\\\\Basal\ Metabolic\ Rate = \frac{142.67\ W}{0.8}[/tex]

Basal Metabolic Rate = 178.33 W

(a)  The  excess heat just through radiation Q = 142.67 W

(b) Basal Metabolic Rate = 178.33 W

Basal metabolic rate is the number of calories your body needs to accomplish its most basic (basal) life-sustaining functions.

(a) We can find the heat radiated by the person by using Stefan-Boltzman's law:

[tex]Q=\sigma A(T^4-T_s^4)[/tex]

where,

Q = heat radiated per second = ?

σ = Stefan-Boltzman Constant = 5.6703 x 10⁻⁸ W/m².k⁴

A = Surface Area = 2 m²

T = Temperature of Skin = 30° C + 273 = 303 k

Ts = Temperature of room = 18° C +273 = 291 k

Therefore,

[tex]Q=(5.6703\times 10^{-8}\times (2)\times[(303)-(291)][/tex]

Q = 142.67 W

(b) Since the heat calculated in part (a) is 80 percent of basal metabolic rate. Therefore,

[tex]\rm Q=0.8\times (Basal\ Metabolic\ Rate)[/tex]

[tex]\rm Basal\ metabolic \ Rate = \dfrac{Q}{0.8}[/tex]

[tex]\rm Basal\ Metabolic\ Rate = \dfrac{142.67}{0.8} =178.330W[/tex]

Basal Metabolic Rate = 178.33 W

Hence the  excess heat just through radiation Q = 142.67 and Basal Metabolic Rate = 178.33 W

To know more about Basal metabolic rate Follow

https://brainly.com/question/14095049

Answer:

its b

Explanation:

Amplitude, in physics, the maximum displacement or distance moved by a point on a vibrating body or wave measured from its equilibrium position. It is equal to one-half the length of the vibration path.

Answer:

10

Explanation:

i dont know this is right answer

0.35

0.91

1.26

1.57

Explanation:

I did it on ed2020 and got it correct

Solution :

Let [tex]$m_1=m_2=4$[/tex] kg

[tex]$u_1 = 5$[/tex] m/s

Let [tex]$v_1$[/tex] and [tex]$v_2$[/tex] are the speeds of the disk [tex]$m_1$[/tex] and [tex]$m_2$[/tex]  after the collision.

So applying conservation of momentum in the y-direction,

[tex]$0=m_1 .v_1_y -m_2 .v_2_y $[/tex]

[tex]$v_1_y = v_2_y$[/tex]

[tex]$v_1 . \sin 60=v_2. \sin 30$[/tex]

[tex]$v_2 = v_1 \times \frac{\sin 60}{\sin 30}$[/tex]

[tex]$v_2=1.732 \times v_1$[/tex]

Therefore, the disk 2 have greater velocity and hence more kinetic energy after the collision.

Now applying conservation of momentum in the x-direction,

[tex]$m_1.u_1=m_1.v_1_x+m_2.v_2_x$[/tex]

[tex]$u_1=v_1_x+v_2_x$[/tex]

[tex]$5=v_1. \cos 60 + v_2 . \cos 30$[/tex]

[tex]$5=v_1. \cos 60 + 1.732 \times v_1 \cos 30$[/tex]

[tex]$v_1 = 2.50$[/tex] m/s

So, [tex]$v_2 = 1.732 \times 2.5$[/tex]

          = 4.33 m/s

Therefore, speed of the disk 2 after collision is 4.33 m/s

Answer:

5.94 N·s

Explanation:

F = 132 N

t = 0.045 s

Impulse = Ft = (132 N)(0.045 s) = 5.94 N·s

Answer:

link

Explanation:

ww.comhwhelp

Answer:

interest point:

1) Point on the left side

2) Point within the radius r₁ of the first sphere

3) Point between the two spheres

4) point within the radius r₂ of the second sphere

5) Right side point

Explanation:

In this case, the total electric field is the vector sum of the electric fields of each sphere, to simplify the calculation on the line that joins the two spheres

We will call the sphere on the left 1 and it has a positive charge Q with radius r1, the sphere on the right is called 2 with charge -Q with radius r2. The total field is

          E_ {total} = E₁ + E₂

          E_{ total} = [tex]k \frac{Q}{x_1^2} + k \frac{Q}{x_2^2}[/tex]

the bold indicate vectors, where x₁ and x₂ are the distances from the center of each sphere. If the distance that separates the two spheres is d

          x₂ = x₁ -d

          E total = [tex]k \frac{Q}{x_1^2} - k \frac{Q}{(x_1 - d)^2}[/tex]

Let's analyze the field for various points of interest.

1) Point on the left side

in this case

            E_ {total} = [tex]k Q \ ( \frac{1}{x_1^2} - \frac{1}{(x_1 +d)2} )[/tex]

            E_ {total} = [tex]k \frac{Q}{x_1^2}[/tex]   [tex]( 1 - \frac{1}{(1 + \frac{d}{x_1} )^2 } )[/tex]

We have several interesting possibilities:

* We can see that as the point is further away the field is more similar to the field created by two point charges

* there is a point where the field is zero

            E_ {total} = 0

             x₁² =  (x₁ + d)²

2) Point within the radius r₁ of the first sphere.

In this case, according to Gauus' law, the charge is on the surface of the sphere at the point, there is no charge inside so this sphere has no electric field on its inner point

              E_ {total} = [tex]-k \frac{Q}{x_2^2} = -k \frac{Q}{((d-x_1)^2}[/tex]

this expression holds for the points located at

                  -r₁ <x₁ <r₁

3) Point between the two spheres

                E_ {total} = [tex]k \frac{Q}{x_1^2} + k \frac{Q}{(d+x_1)^2}[/tex]

This champ is always different from zero

4) point within the radius r₂ of the second sphere, as there is no charge inside, only the first sphere contributes

                  E_ {total} = [tex]+ k \frac{Q}{(d-x_1)^2}[/tex]+ k Q / (d-x1) 2

point range

                  -r₂ <x₂ <r₂

5) Right side point

            E_ {total} = [tex]k \frac{Q}{(x_2-d)^2} - k \frac{Q}{x_2^2}[/tex]

             E_ {total} = [tex]- k \frac{Q}{x_2^2} ( 1- \frac{1}{(1- \frac{d}{x_2})^2 } )[/tex]- k Q / x22 (1- 1 / (x1 + d) 2)

we have two possibilities

* as the distance increases the field looks more like the field created by two point charges

* there is a point where the field is zero

Answer:

x(t) = -8sin2t

Explanation:

See the attachment for solution

From my solving, we can deduce that w² = 4, and thus, w = 2

Therefore, the general solution is

x(t) = c1 cos2t + c2 sin2t

Considering the final variable, we can conclude that

x(0) = 0

x'(0) = -8 m/s

The final solution, thus

x(t) = -8sin2t

Answer:

B

Explanation:

Answer:

the nephew

Explanation:

because we need to First find the trails that is on top of all the others in order to find who was the last to leave, since the person that was last to leave would most likely step on another person's trail that has been theirs before them.

by looking at this picture I noticed that the butler's footprint was the latest one but the dogs footprint steps over it therefore making it the last to leave, and the person who owns a dog is her nephew so therefore the nephew is the one that stole the butterfly trophy.

Answer: A. The reactants must collide in a certain way for the reaction to  occur.

Explanation: I did the quiz :)

Answer:

A) The reactants must collide in a certain way for the reaction to

occur.

Explanation:

A.P.E.X

Answer:

Explanation:

Gdvxhvdygshxvgxgvvvvgehcbjdhvshchbeukshcvgdferfacsxzdwlf!?ñpdjabdjcbdjshfhfgdsfadqewstgdvdhsvchsxh

The principle of lateral continuity works, because they are continuous. Rocks that are alike but were separated by an erosional feature, can be originally continuous.