Hi there!
We can use the following equation (Newton's Second Law):
∑F = ma
m = mass of object (kg)
a = acceleration (m/s²)
We can rearrange to solve for 'a':
F/m = a
Remember to convert grams to kg.
1000g = 1 kg
0.035/(0.0114) = 3.07 m/s²
Which statement indicates that motion has occurred?
A. The reference point has changed.
B. The position of the object has changed.
C.The object has not changed.
D. The object being described has changed
There are no risks when taking medication to treat anxiety.
Please select the best answer from the choices provided.
T
F
Answer:
False
Explanation:
Answer:
The answer is False
Explanation:
1. If the mass of an object is measured in kg and the velocity is measured in m/s, what is the unit for momentum?
The unit for momentum is equal to Kgm/s.
Given the following data:
Unit of mass = Kilogram (kg).Unit of velocity = meter per seconds (m/s).To determine the unit for momentum:
What is momentum?In Science, momentum can be defined as a multiplication of the mass of an object and its velocity.
Mathematically, momentum is giving by this formula;
[tex]Momentum = mass \times velocity[/tex]
Substituting the given parameters into the formula, we have;
[tex]Momentum = kg \times m/s\\\\[/tex]
Momentum = Kgm/s.
Read more on momentum here: brainly.com/question/15517471
A fan operating at 260V with a current being supplied at 13A. What is the effective resistance at which it is being operated?
Answer:
20 ohms
Explanation:
Resistance=Potential difference÷Electric current
X=260÷13
X=20
What are nucleic acids, and what are their function and structure? Give an example
A deer runs 5 km through the woods in 9 min and then walks 7 km in 2 hours. Find its average speed in km/h.
How to find resistance
Answer:
R = V/I
Explanation:
Example:
V = IR
R = V/I
If we were to use V = 120 and I = 0.25
R = 120/0.25
R = 480 Ohms
Your resistence would equal Ohms
....................................
Answer:
yeah
Explanation:
How much force is needed to accelerate a 70 kg rider and the 200kg motorcycle the
rider is on at 4m/s?
Answer: F = (200 kg + 70 kg) * 4 m/s² = 270 kg* 4m/s² = 1080 N
Answer:
F = 1080 N
Explanation:
A taxi is travelling at 20 m/s. Its driver accelerates with acceleration 5 m/s2 for 4 s. What is its new velocity?
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
If a 5.00 kg box slides down a ramp inclined at 60.0° above the horizontal, what is the
acceleration of the box
Answer:
A 70 kg box is slid along the floor by a 400 n force. The coefficient of friction between the box and the floor is 0. 50 when the box is sliding
Image credit: The Hubble Heritage Team (AURASTSCI/NASA)
To which category does galaxy #2 belong? Why does it belong in this category?
WRITER
Can i ask u a question
how to do the next ques for moreBrainliest me please
What event has inspired your life so far? How has this event changed you?
Easy pts! I will give Brainliest. :)
An object with a mass of 90 grams, moving at a constant velocity of 6 meters per second, has __________. A. A momentum of 540 gram meters per second B. An acceleration of 10 meters per second squared C. A momentum of 90 gram meters per second D. An acceleration of 6 meters per second squared Please select the best answer from the choices provided. A B C D.
Answer: 540 g m/s.
Explanation:
Answer: A.
A momentum of 540 gram meters per second!
Explanation: On Edge!!
PLEASE ANSWER ASAP
A 5 kg bowling ball traveling at 2 m/s hits a motionless 10 kg bowling ball. If the smaller ball bounces back at a speed of -1 m/s, what will be the speed of the larger ball after the collision?
Hi there!
Recall the conservation of momentum:
m1v1 + m2v2 = m1v1' + m2v2'
Let m1 = 5 kg ball and m2 = 10 kg ball
Since m2 is at rest, we can rewrite:
m1v1 = m1v1' + m2v2'
Plug in the given values:
5(2) = 5(-1) + 10v2'
Solve for v2':
10 = -5 + 10v2'
15 = 10v2'
15/10 = 1.5 m/s
We know that,
m1v1 + m2v2 = m1v1' + m2v2'
5 x 2 + 0 = 5 x -1 + 10 x v2'
10= -5 +10 x v2'
15 = 10 x v2'
v2' = 15/10
v2' = 1.5 m/s
hence , the speed of the larger ball after the collision will 1.5m/s
help with this question
Answer:
D and B.
Explanation:
The wavelength must be taken from the same corresponding point. D and B are both at the crests of a wave, with no other crests in between, which means the distance between them is equal to one wavelength.
How long will it take to travel 150km at an average speed of 40 km/h
Answer:
6,000 minutes
Explanation:
To calculate distance u multiply speed and time or speed and rate
If the resistor is connected in series, the voltage across the wire changes. (true or false)
the homogenvity of s=ut+1/2at^2
please answer this don't go on the one which is choosed coz i bymistakely choosed it
Answer:
(B) B is travelling fastest
Explanation:
slope of xt graph = speed.
Slope of B is greater than a and c.
BRAINLIST PLS
NEED ANSWER ASAP!
Which statement about a converging lens is not correct?
A ray parallel to the principal axis of the lens is refracted through the principal focus.
B All rays of light refracted by the lens pass through the principal focus.
C The distance between the centre of the lens and the principal focus is the focal length
D The principal focus of the lens is a point on the principal axis.
Geometric optics allows you to find which the correct answer about which false statement is:
B) All rays of light refracted by the lens pass through the principal focus.
Geometric optics studies the formation of images using the light geometric properties of optical systems, the main expression for this is:
[tex]\frac{1}{f} = \frac{1}{p} + \frac{1}{q}[/tex]
Where f is the focal length, p and q the distance to the object and the image respectively.
There are some points of special interest:
Object at infinity (p = ∞). In this case of the expression we see that the image is at the focal length. Image at infinity (q = ∞). In this case the object is at the focal point.
Let's analyze the claims.
A) True. A parallel ray comes from infinity and the image is formed at the focal point.
B) False. The image point is given by the expression above and depends on the distance to the object.
C) True. This is the definition of focal length.
D) True. All distances are measured from the main axis.
In conclusion, using geometric optics we can find that the correct answer about which false statement is:
B) All rays of light refracted by the lens pass through the principal focus.
Learn more about geometric optics here: brainly.com/question/2548694
What substance is a polymer found in nature?
Silk,wool, DNA, cellulose and protein
HELP PLEASE
2. What is the potential energy of a 2000 g basketball that is stuck on the rim of a 3m hoop?
Answer:
[tex]U_g=58.86 J[/tex] or [tex]U_g=60 J[/tex]
Explanation:
Answer is attached. I do not know if you needed to use 9.81 or 10 for the acceleration due to gravity, so both solutions are attached.
A boy drops a stone in a well and finds it takes 2.60 seconds to hit the water.
A) How deep is the well?
B) With what speed does the stone hit the water?
Answer:
(i) How deep is the well (Height)
=> t = √(2H/g)
=> √2H = t × g
=> 2H = t² × g²
=> 2H = (2.60)² × (10)²
=> 2H = 6.76 × 100
=> 2H = 676
=> H = 676 ÷ 2
=> H = 338 m
(ii) speed of the stone:
=> v = √(2Hg)
=> v = √(2 × 338 × 10)
=> v = √6760
=> v = 26√10 m/s
A crate of mass 50kg is pulled up a rough inclined plane, inclined at an angle of 60° to the horizontal. Determine the total work done in moving the crate to the top of the inclined 200m high.
Answer:
Wc = m*g = 50kg * 9.8N/kg = 490 N = Wt.
of crate.
Fc = 490N 60o = Force of crate.
Fp = 490*sin60 = 424.4 N. = Force
parallel to incline.
Fv = 490*cos60 = 245 N. = Force perpendicular to the incline.
Ff = u*Fv = u*245 = Force of friction.
Fap-Fp-Ff = m*a
Fap-424.4-u*245 = m*0 = 0
Fap = 424.4 + 245u. = Force applied.
L = 200m/sin60 = 231 m. = Length of
incline.
Work = Fap * L=(424.4+245u) * 231.
Explanation:
A child is stationary on a swing.(a)The child is given a push by his brother to start him swinging.His brother applies a steady force of 84 N over a distance of 0.25 m.(i) Calculate the work done by this force.(2)..............................................................................................................................................(ii) State how much energy is transferred by this force.(1)..............................................................................................................................................(iii) After several more pushes, the child has a kinetic energy of 71 J.The mass of the child is 27 kg.Show that the velocity of the child at this point is about 2.3 m/s.(2)(iv) Which one of these quantities changes in both size and direction while he is swinging?Put a cross ( ) in the box next to your answer.(1)Ahis gravitational potential energyBhis momentumCthe force of gravity acting on himDhis kinetic energy
Answer:
Work done = Fs
Explanation:
(i) W = Fxs
= 84N x0.25m
= 21 Joules
(ii) Ek = 1/2mv^2
71 = 1/2×27×v^2
71×2/27 = v^2
v = 23m/s
The work done by this force is 21 Joule.
Energy transferred by the force is 21 Joule.
The boy's momentum changes periodically, that is, in both size and direction.
What is force?An external force is an agent that has the ability to change the resting or moving condition of a body. It has a direction and a magnitude. So, it is a vector quantity. Newton is the SI unit of force (N).
(i) Given parameter:
Steady force applied by his brother, F = 84 N.
Displacement, d = 0.25 m.
The work done by this force, W = F.d = 84×0.25 = 21 Joule.
(ii) Amount of work done is transferred by this force as an energy. So, amount of energy transferred by the force is 21 Joule.
(iii) Given parameter:
Mass of the child, m= 27 kg.
Kinetic energy, E = 71 J.
Let, velocity of the child = v, then kinetic energy is,
E = 1/2 × mv²
⇒ v = √(2E/m)
= √(2×71/27)
= 2.3 m/s.
Hence, the velocity of the boy is 2.3 m/s. (proved).
(iv) During swing, his velocity changes periodically. That's why, his momentum changes periodically, that is, in both size and direction.
Learn more about force here:
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Dhdjrjfbjsjfnsmctejzbrnj
The answer is D
I hope this helps :)
Consider the dot diagrams for Objects A, B, and C. The arrow-
represents the direction of motion. Match the motion of
Objects A, B, and C to one of the lines on the graph.
Numbers can be used only one time.
A
2
B
Pos'n
3
С
-t
Tap
A matches graph:
B matches graph:
C matches graph:
4
5
6
--
Pos'n
t
What force would be required to accelerate a 1,100 kg car to 0. 5 m/s2? N.
Answer:
550 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 1100 kg
acceleration = 0.5 m/s²
We have
force = 1100 × 0.5 = 550
We have the final answer as
550 NHope this helps you
Answer:
If your filling in the blank on edge then its 550
Explanation:
The following diagram shows a person exerting a
300.-newton force on the handle of a shovel that
makes an angle of 60. with the horizontal ground.
Determine the magnitude of the component of the
force perpendicular to the ground.
Answer:
260 Newtons
Explanation:
Okay, so what you have to do is know what the question is asking. It wants to know the force perpendicular to the ground. We know perpendicular makes a right angle, so we use the diagram to make it into a right triangle with a degree of 60, and hypotunese of 300 newtons. Now, we use basic trigonometry, we place x on the horizontal side since it perpendicular to the ground. We know it´s sin because x is opposite to 300 which is the hyp.
Sin= opp/hyp
x/300
sin(60)= x/300
300*sin(60)= 259.8, which rounds to
260 Newtons
There is your answer :D. Happy to help.
The component of the force which is perpendicular to the ground is → F [y] = 261 a[y].
What are the components of a Vector?A vector V making an angle θ with the x - axis, can be resolved into two two components along the x and y - axes respectively as →
V = Vcosθ a[x] + Vsinθ a[y]
where -
a[x] is the unit vector along the +x axis
a[y] is the unit vector along the +y axis.
Given is a force of magnitude 300 N acting on the handle that makes an angle of 60° with the horizontal ground.
The component normal to the ground will be the component along the y - axis. The component along the y - axis is the sine component. Suppose that vector F represents the force of magnitude (|F|) 300 N. The component perpendicular to the ground will be -
F [y] = |F| sinθ a[y]
F [y] = 300 x sin(60°) a[y]
F [y] = 300 x 0.87
F [y] = 261 a[y]
Therefore, the component of the force which is perpendicular to the ground is → F [y] = 261 a[y].
To solve more questions on Vector Resolution, visit the link below-
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