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Answer:

[tex]\sqrt{53}[/tex]

Step-by-step explanation:

Use the distance formula:

[tex]\sqrt{(x1-x2)^2+(y1-y2)^2}[/tex]

plug in (-5,6) for (x1,y1) and (-3,-1) for (x2,y2)

[tex]\sqrt{(-5-(-3))^2+(6-(-1))^2}[/tex]

[tex]\sqrt{4+49}[/tex]

[tex]\sqrt{53}[/tex]

Hope that helps :)

Answer:

A, The probability that it will rain is 0.09 and the probability that the flight will be delayed is 0.18.

Step-by-step explanation:

Answer: 0.154

Step-by-step explanation:

Answer:

Explanation:

320.29 × 7 = 2,242.03 m = 1.39313285413187 miles ≈ 1.393

I'm on my school computer so the picture is blocked sorry :(

Answer:

the answer is in the photo hope it help

Step-by-step explanation:

36 is your answer

I hope.it helps mate

have a nice day

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Answer:

circle: ( 1, 0.5 )

square: ( 4.5, 3.5 )

triangle: ( 0, 2.5 )

Step-by-step explanation:

Answer:

The answer is 3/4

Step-by-step explanation:

The value of the F-statistic for the test of overall significance of this regression relationship is approximately 11.245.

Given:SST = 2326.9523 SSR = 1632.8843 Independent variables = 7

Observations = 66Formula used:F = (SSR/K) / (SSE / (n-K-1))

Where SSR = Regression sum of squares SSE = Error sum of squaresK = Number of independent variables n = Number of observations

To calculate the F-statistic, we first need to calculate SSE which is given by:SSE = SST - SSR = 2326.9523 - 1632.8843 = 693.068

The degrees of freedom for the regression are K and the degrees of freedom for the error term are n - K - 1 = 66 - 7 - 1 = 58

The value of the F-statistic is given by:F = (SSR/K) / (SSE / (n-K-1))= (1632.8843/7) / (693.068 / 58)= 11.245

Therefore, the value of the F-statistic for the test of overall significance of this regression relationship is approximately 11.245.

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Answer: The horizontal extent of the graph is -3 to 1, so the domain of f is (-3,1]

Step-by-step explanation:

The range is [-4,0]

Answer:

80 percent of 70 is 56, so you were 20% wrong?

The percent error is 20%

let me know if you need anything else :)

The probability of selecting  a girl to read the poem out loud in her class is 46.4% .

To calculate the probability of selecting a girl to read a poem out loud in a class of 28 students, we can use the formula:

Probability = Number of Desirable Outcomes / Total Number of Outcomes

Here, the desirable outcome is selecting a girl to read the poem, and the total outcomes are all the students in the class.

Number of Desirable Outcomes:

Mrs. Avery has 13 girls in her class, so there are 13 desirable outcomes.

Total Number of Outcomes:

Mrs. Avery has 28 students in her class, so there are 28 total outcomes.

Probability = Number of Desirable Outcomes / Total Number of Outcomes

Probability = 13 / 28

Probability = 0.464 or 46.4%

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Note: The complete question is -Mrs. Avery is planning to have one student read a poem out loud in class. She has a class of 28 students, consisting of 15 boys and 13 girls. What is the probability that she will select a girl to read the poem out loud?

Answer:

option B should be correct

As per the given values, the after-tax salvage value is $435,200.

Amount required = $3,200,000

Time = 6 years

Calculating the accumulated depreciation -

Amount/ Number of years

=  $3,200,000 / 6

= $533,333.3.

Calculating the accumulated depreciation at project end -

= 6 x $533,333.33

= $3,200,000.

Calculating the book value of the fixed assets -

Book value = Cost of fixed assets - Accumulated depreciation

= $3,200,000 - $3,200,000

= $0

Calculating the taxable gain or loss on the sale of the fixed assets -

Taxable gain/loss = Selling price - Book value

= $640,000 - $0

= $640,000

Calculating the tax liability -

Tax liability = Tax rate x Taxable gain

= 0.32 x $640,000

= $204,800

Calculating the after-tax salvage value -

After-tax salvage value = Selling price - Tax liability

= $640,000 - $204,800

= $435,200

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What is the LCM of 64 and 72?

Find the prime factorization of 64.

Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.

Multiply each factor the greater number of times it occurs in steps i) or ii) above to find the LCM: LCM = 2 × 2 × 2 × 2 × 2 × 2 × 3 × 3.

LCM = 576.

What is the GCF of 64 and 72?

Find the prime factorization of 64. 64 = 2 × 2 × 2 × 2 × 2 × 2.

Find the prime factorization of 72. 72 = 2 × 2 × 2 × 3 × 3.

To find the GCF, multiply all the prime factors common to both numbers: Therefore, GCF = 2 × 2 × 2.

GCF = 8.

Answer:

8x8 and 8x9

Step-by-step explanation:

because 8x8 is 64 and 8x9 is 72

Answer:

First term = 12

Step-by-step explanation:

A4 = 24

A12 = 56

An = A1 + (n-1)d; this defines the formula of an arithmetic series

A4 = 24 = A1 + (4-1)d

A4 = 24 = A1 + 3d

A12 = 56 = A1 + (12-1)d

A12 = 56 = A1 + 11d

Subtract A4 from A12 to get d (distance)

(56 = A1 + 11d) - (24 = A1 +3d)

32 = 8d

d = 4

Substitute d = 4 into A4

A4 = 24 = A1 + 3(d)

24 = A1 + 3(4)

24 = A1 + 12

24 - 12 = A1

12 = A1

The requried, there are 495 possible combination lineups with eight bands out of twelve for the benefit concert.

To determine the number of possible lineups with eight out of twelve bands performing, we need to calculate the combination.

The number of ways to choose eight bands out of twelve without considering the order is given by the combination formula:

[tex]C(n, r) = \dfrac{n!}{ (r! * (n-r)!)}[/tex]

where n is the total number of bands (12 in this case) and r is the number of bands to be chosen (8 in this case).

Let's calculate it:

[tex]C(12, 8) =\dfrac {12!}{(8! * (12-8)!)}[/tex]

            [tex]= \dfrac{12!} {(8! * 4!)}[/tex]

            = (12 * 11 * 10 * 9) / (4 * 3 * 2 * 1)
            = 495

Thus, there are 495 possible combination lineups with eight bands out of twelve for the benefit concert.

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Answer:

45

Step-by-step explanation:

x = -30/2(-5)

x = -30/(-10)

x = 3 sec

.

Plug above into equation to find height:

h=-5t^2 + 30t

h=-5*3^2 + 30(3)

h=-5*9 + 30(3)

h=-45 + 90

h=45

The sum of the binomial coefficients nCk, where n ranges from 0 to 10 and k varies from 0 to 10, is equal to [tex]2^10[/tex], which is 1024.

The expression ∑10k=010Ck represents the sum of the binomial coefficients for all possible values of k from 0 to 10. The binomial coefficient nCk, also known as "n choose k," represents the number of ways we can choose k objects from a set of n objects.

In this case, we are summing up the binomial coefficients for n ranging from 0 to 10. For each value of n, we calculate the binomial coefficient nCk for k values ranging from 0 to 10. The formula to calculate the binomial coefficient is n! / (k!(n-k)!), where "!" denotes the factorial operation.

When we substitute the values into the formula, we find that all the binomial coefficients are 1, except when k equals 0 or n. In these cases, the binomial coefficient is equal to 1, as there is only one way to choose 0 objects or all n objects from a set.

Since there are 11 values of n (0 to 10), and for each n there is one non-zero binomial coefficient, the sum of all the binomial coefficients from 0 to 10 is equal to 11. Therefore, the expression simplifies to ∑10k=010Ck = 11.

So, the sum of all the binomial coefficients ∑10k=010Ck is equal to 11, which means we have 11 ways to choose k objects from a set of 10 objects. Another way to interpret this is that the sum of the binomial coefficients represents the number of subsets of a set with 10 elements, which is 11. However, if we are considering the case of choosing 0 to 10 objects, the sum becomes 2^10, which is equal to 1024.

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Approximately 0.11 percent of all samples have mean heights of at least 64.76 inches.

Given: 50 years prior, the mean level of ladies in a specific country in their 20s was 62.9 inches. With a standard deviation of 2.87 inches, women in their 20s today have heights that are roughly typical. We must determine the proportion of all 21 samples that have mean heights of at least 64.76 inches among today's women in their 20s. Bit by bit clarification:

Let μ be the mean level of ladies in this day and age and allow n to be the example size. We can find the likelihood of an example mean being more prominent than or equivalent to 64.76 inches utilizing the z-score recipe, as follows: z = (x - μ)/(σ/√n) = (64.76 - 62.9)/(2.87/√21) = 3.06The likelihood that an example of 21 ladies will have a mean level more noteworthy than or equivalent to 64.76 inches is equivalent to the likelihood that a typical irregular variable Z is more noteworthy than or equivalent to 3.06.

This probability is approximately 0.0011, or 0.11 percent, according to a typical normal table or calculator. This means that approximately 0.11 percent of all samples have mean heights of at least 64.76 inches.

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Answer:

A) 90°

Step-by-step explanation:

if lines b and c are perpendicular then all 8 angles measure 90 degrees

Answer:

18 units to the right.

Step-by-step explanation:

Hope this helps!

Assuming the profit of one airport is regulated by a rate-of-return (ROR) based regulation of 2% and the estimated airport asset for 2020 is about $100 million, the maximum profit the airport can generate is $2 million.

The maximum profit of the airport is a function of the multiplication of the estimated asset and the allowed maximum rate of return.

The rate of return is the percentage of total returns expressed as a quotient of the total assets multiplied by 100.

The allowed maximum rate of return = 2%

Estimated asset of the airport for 2020 = $100 million

The maximum profit = $2 million ($100 million x 2%)

Thus, the airport's maximum profit for 2020 is $2 million.

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Multiply the discount percent to the marked price and subtract from the marked price.

As we know that the discount is always given on the marked price of the product.

We will take one example to understand it supposes the marked price of any object is MP= 100 and the discount =15% so to find the SP

First, find the discount amount

[tex]MP\times Discout \ percent =100\times \dfrac{15}{100} =15[/tex]

Now to find the SP subtract the discount from the MP

[tex]SP=MP-Discount[/tex]

[tex]SP=100-15=75[/tex]

So for finding SP multiply the discount percent to the marked price and subtract from the marked price.

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Answer:

what should i answer?

Step-by-step explanation:

Answer: The number of hens are 4 and number of sheeps are 6

Step-by-step explanation:

Given : Total animals = 10

Total number of legs = 32

Let number of hens = h  and number of sheep = s

Thus h+s = 10    (1)

Now each hen has two legs and each sheep has 4 legs :[tex]2\times h+4\times s=32[/tex]   (2)

Solving for h and s we get:

s = 6 , h =4

Thus number of hens are 4 and number of sheeps are 6

(a) The complete graph [tex]K_n[/tex] has an Euler cycle if and only if n is an even number greater than or equal to 2.

(b) There are no complete graphs [tex]K_n[/tex] that have Euler trails but not Euler cycles. A complete graph always has an Euler cycle if it has an Euler trail.

(c) The bipartite graph [tex]K_r[/tex],s has an Euler cycle if and only if both r and s are even numbers greater than or equal to 2.

(a) To determine the values of n for which the complete graph [tex]K_n[/tex] has an Euler cycle, we need to understand the conditions for an Euler cycle to exist in a graph.

An Euler cycle is a closed walk in a graph that visits every edge exactly once and starts and ends at the same vertex. In order for a graph to have an Euler cycle, it must satisfy the following conditions:

All vertices in the graph have even degrees (an even number of edges incident to them).

The graph is connected, meaning there is a path between any two vertices.

Now let's apply these conditions to the complete graph [tex]K_n[/tex].

Degree of Vertices: In a complete graph [tex]K_n[/tex], each vertex is connected to every other vertex. Therefore, each vertex has a degree of n-1, as it is connected to n-1 other vertices. Since n-1 is always an odd number, it means that all vertices in [tex]K_n[/tex] have odd degrees. Hence, [tex]K_n[/tex] does not have an Euler cycle for any value of n.

Connectivity: A complete graph [tex]K_n[/tex] is always fully connected, meaning there is a direct edge between every pair of vertices. Therefore, the connectivity condition is satisfied for any value of n.

Based on these conditions, we can conclude that the complete graph [tex]K_n[/tex] does not have an Euler cycle for any value of n.

(b) since [tex]K_n[/tex] does not have an Euler cycle for any value of n, it also implies that there are no [tex]K_n[/tex] graphs that have Euler trails but not Euler cycles.

(c) The bipartite graph [tex]K_r[/tex],s is a complete bipartite graph with two sets of vertices, one with r vertices and the other with s vertices. To have an Euler cycle in this bipartite graph, the following conditions must be met:

All vertices in each set have even degrees.

The number of vertices in each set must be equal.

Since the complete bipartite graph [tex]K_r[/tex],s has all vertices with degree s in one set and degree r in the other set, it means that both r and s must be even numbers for all vertices to have even degrees. Additionally, the number of vertices in each set must be equal for the graph to be bipartite. Therefore, an Euler cycle exists in the bipartite graph [tex]K_r[/tex],s if and only if both r and s are even numbers.

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The given initial value problem using the method of undetermined coefficients. The final solution to the initial value problem is y = cos(2x) + x - (1/9)*sin(3x).

To solve the given initial value problem, we begin by finding the general solution to the associated homogeneous equation. The homogeneous equation is given by y'' + 4y = 0. The characteristic equation is obtained by substituting y = e^(mx) into the equation, resulting in the quadratic equation m^2 + 4 = 0. Solving this equation yields two distinct roots: m_1 = 2i and m_2 = -2i. Thus, the general solution to the homogeneous equation is y_h = c_1cos(2x) + c_2sin(2x), where c_1 and c_2 are arbitrary constants.

Next, we assume a particular solution in the form of y_p = Ax + B + Csin(3x) + Dcos(3x), where A, B, C, and D are undetermined coefficients. We substitute this particular solution into the given differential equation and solve for the coefficients. Comparing the coefficients of like terms, we find A = 0, B = 1, C = -1/9, and D = 0.

The particular solution is y_p = x - (1/9)*sin(3x), and the complete solution is obtained by adding the particular solution to the homogeneous solution: y = y_h + y_p. Applying the initial condition y(0) = 1, we find that c_1 = 1 and c_2 = 0. Therefore, the final solution to the initial value problem is y = cos(2x) + x - (1/9)*sin(3x).

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Answer:

-18+ 13

-6 + 1

-20 + 15

-7 + 2

Step-by-step explanation:

Answer:

10*5 or 25*2

Step-by-step explanation:

There are other answers but those involve decimals and I'm assuming they want whole numbers.