Computers And Technology High School

Select the phrases that apply to Java classes or methods.

chart a list of inputs
hide the information
passing by reference
order of operations
passing by value
break a loop
testing conditions
specific computer action
create a new object

Answers

Answer 1

Answer:

graficar una lista de entradas

crear un nuevo objeto

condiciones de prueba

romper un ciclo

Explanation:

Related Questions

Why would someone use a credit card to purchase goods?

Answers

Online transactions involving credit cards are often easier to track than those involving debit, money orders, or checks.These cards frequently offer some protection against fraudulent purchases.

Why do people buy stuff with credit cards? When compared to debit, money orders, or checks, credit card transactions are often easier to track online.These cards frequently include some coverage for unauthorized purchases, which can be quite beneficial to cardholders if their credit card information is ever compromised.When compared to cash, credit cards are safer to carry and provide better fraud protections.Without altering your spending patterns, you can earn substantial rewards.It's simpler to keep tabs on your spending.One of the simplest and quickest ways to improve credit is to use credit cards responsibly.Using a credit card can make you feel safer, you may be given certain safeguards on your purchase, and you may be able to receive cash or points back on your purchases thanks to credit card benefits.

To learn more about credit cards refer

https://brainly.com/question/28800758

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the speed of cpu is measured in terms of what?

Answers

Answer:

Megahertz (MHz) or Gigahertz (GHz)

1 GHz = 1000 MHz

2. Busy intersection There is a busy intersection between two one-way streets: Main Street and 1st Avenue. Cars passing through the intersection can only pass through one at a time. When multiple cars arrive at the intersection at the same time, two queues can build up - one for each street. Cars are added to the queue in the order at which they arrive. Unfortunately, there is no traffic light to help control traffic when multiple cars arrive at the same time. So, the local residents have devised their own system for determining which car has priority to pass through the intersection: - If in the previous second, no car passed through the intersection, then the first car in the queue for 1 st Avenue goes first. - If in the previous second, a car passed through the intersection on 1st Avenue, then the first car in the queue for
1st
Avenue goes first. - If in the previous second, a car passed through the intersection on Main Street, then the first car in the queue for Main Street goest first. Passing through the intersection takes 1 second. For each car, find the time when they will pass through the intersection. Function Description Complete the function getResult in the editor below. getResult has the following parameters: int arrival [n]: an array of
n
integers where the value at index
i
is the time in seconds when the
i th car arrives at the intersection. If arrival[i]
=
arrival[j] and
i , then car
i
arrives before car
j
. int street[n]: an array of
n
integers where the value at index
i
is the street on which the
t th car is traveling: Street and 1 for 1 st Avenue. Returns:
int[n]:
an array of
n
integers where the value at index
i
is the time when the
i th car will pass through the intersection Constraints -
1≤n≤10 5
-
0≤arrival[i]≤10 9
for
0≤i≤n−1
- arrival[i]
≤
arrival[i
+1]
for
0≤i≤n−2
-
0≤s
street
[i]≤1
for
0≤i≤n−1

Answers

The program that can be used to illustrate the information of busy intersection between two one-way streets is given below.

The program that features the cars will be:

def getResult(arrival, street):

# Write your code here

result = []

# The first car arrives on Main Street at time 0. The first car arrives on 1st Avenue at time 0. The second car arrives on Main Street at time

1. The third car arrives on 1st Avenue at time 5.

time = 0

main_street_queue = []

first_avenue_queue = []

while len(main_street_queue) > 0 or len(first_avenue_queue) > 0:

if len(main_street_queue) == 0:

car_to_add_to_result = first_avenue_queue.pop(0)