They both flow in currents. Water has a pump that works like a battery and pipes that work like a circuit.
a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3
Answer: 1.6 N
Explanation:
The weight of an object is calculated as:
W = g*m
where:
g = gravitational acceleration = 9.8m/s^2
m = mass of the object.
We also know that:
mass = density*volume.
or:
m = d*v
Let's start:
The weight of the beaker is 0.4N
And the weight of the beaker filled with water is 1.4N
Then the weight of the water alone will be:
1.4N - 0.4N = 1N = (d*v)*9.8m/s^2
And we know that the density of the water is:
1 g/cm^3
But we are working with Newtons, then we need to rewrite this with kilograms as the mass unit, we can use that:
1000g = 1kg
Now we can rewrite the density as:
d = 1 g/cm^3 = 1*(1/1000) kg/cm^3 = 0.001 kg/cm^3
Replacing that in the above equation, we get:
With this, we can find the volume that the water occupies.
W = 1 N = v* 0.001 kg/cm^3*9.8m/s^2
1 N /( 0.001 kg/cm^3*9.8m/s^2 ) = 102.04 cm^3.
Now, when we fill it with a brine with a density of 1.2 g/cm^3, the mass of this brine in a volume of 102.04 cm^3 be:
M = (1.2 g/cm^3)*( 102.04 cm^3) = 122.448 g
Rewriting this in kg we get:
M = 122.448 g = (122.448/1000) kg = 0.122448 kg
Then the weight of this brine is:
M = 0.122448 kg*9.8m/s^2 = 1.2 N
And the beaker weighs 0.4N, then the beaker filled with this brine will weight:
1.2 N + 0.4N = 1.6 N
A crate is being pulled down an incline as shown in the figure. With respect to the crate's direction of motion, which of the following forces does only negative work on the crate?
Answer:Fn
Explanation:
Explain why different types of musical instruments sound different, even though they play the same notes.
A train going 14m/s moves 250 m while accelerating to a stop. What is the train’s deceleration?
Answer:
-0.056 is the deceleration
A shopper in a supermarket pushes a loaded 32 kg cart with a horizontal force of 12 N.
a) How far will the cart move in 3.5 s, staring from rest? (Disregard any friction)
b) How far will the cart move in 3.5 s if the shopper places an 85 N child in the cart before pushing?
Answer: A
Explanation:
3) A school bus traveling at 12 m/s has a momentum of 144,000 kg.m/s.
What is the mass of the bus?
Answer:
does this have picture so I can solve
The mass is 12,000
144,000 divided by 12 = 12,000
Momentum = mass × velocity
Brainliest would be appreciated. :)
how many teeth shows signs of decay?
Answer:
what do you mean
Explanation:
4. Bob creates his personal profile collage by drawing his favorite things. This is his ___________.
A. artistic self
B. social self
C. professional self
D. private self
An electrically charged atom is called an
Answer:
It's called an ion. Excuse me if I'm wrong.
Explanation:
A skier skids to a stop at the bottom of a mountain.
What is the equal and opposite force for the force of the skier's friction pushing on the mountain as
described by Newton's third law?
Answer:
Friction of the mountain on the skier in the opposite direction
Explanation:
answered it on khan academy
Friction of the mountain on the skier in the opposite direction.
What is Newton's third law?A force is a push or a pull that acts upon an object as a results of its interaction with another object. Forces result from interactions.
Forces result from contact interactions (normal, frictional, tensional, and applied forces are examples of contact forces) and other forces are the result of action-at-a-distance interactions (gravitational, electrical, and magnetic forces).
There are two forces resulting from this interaction - a force on the chair and a force on your body. These two forces are called action and reaction forces and are the subject of Newton's third law of motion.
Therefore, Friction of the mountain on the skier in the opposite direction.
To learn more about Friction, refer to the link:
https://brainly.com/question/13000653
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There is an accident up the road from your car. You see other cars ahead of you. Who will stop first?
A fully-loaded big rig truck
An empty truck
A midsized van
A small car
Answer:
According to the 2010 U.S. Census, there are approximately 8 million people living in Virginia. This is 2.8 million less than 4 times the population of Nevada.
What is the population of Nevada?
The first step is to on both sides.
The second step is to on both sides.
The population of Nevada is million.
Explanation:
Help i will do anything for this. its a serious grade
Answer: 10 has more potential energy because its longer
1 has less potential energy because its shorter
Explanation:
Potential energy directly depends on height of body as
[tex]\\ \sf\longmapsto P.E=mgh[/tex]
[tex]\\ \sf\longmapsto P\propto h[/tex]
Higher the height higher the potential energy
Object at height 10m has more potential energy.
which number is larger value : 5.6*10^23 or 8.9*10^6
Need Help
Answer:
5.6*10^23. if 10^n is greater, that means its the larger value. hope dis helps
Explanation:
Can u anser 5,6 on the picture
Answer: Number 6 is Periods
Explanation:
why is physics to study the heat absorbed by the ocean
Answer:
Heat is a source of energy
Explanation:
Just took the test
how much force would be needed to move a 100 kg object at the acceleration rate of 2 m/s
Answer: 200 N
Hope this helps! :)
If 200 ml of a gas at 27 degrees celsius is cooled to -33 degrees Celsius at a constant pressure , the volume will be
A 250ml
B 204ml
C 196ml
D 160ml
Given that,
Volume of gas, V₁ = 200 mL
Initial temperature, T₁ = 27°C
Final temperature, T₂ = -33°C
To find,
New volume of the gas.
Solution,
Initial temperature, T₁ = 27°C = 300 K
Final temperature, T₂ = -33°C = 240 K
Let V₂ is the new volume.
The relation between volume and temperature is given by :
[tex]\dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}\\\\V_2=\dfrac{V_1T_2}{T_1}\\\\=\dfrac{200\times 240}{300}\\\\=160\ mL[/tex]
Hence, the volume will be 160 mL.
A student releases a marble from the top of a ramp and the marble increases speed steadily and travels 190 cm in 4.10 s what's the marbles final speed
Answer:
The value is [tex]v = 92.68 \ cm/s[/tex]
Explanation:
From the question we are told that
The distance traveled is [tex]d = 190 \ cm = 1.9 \ m[/tex]
The time taken is [tex]t = 4.10 \ s[/tex]
Generally from kinematic equation we have that
[tex]s = ut + \frac{1}{2} at^2[/tex]
Here u is the initial velocity of the marble and the value is [tex]u = 0 \ m/s[/tex]
So
[tex]1.90 = 0* t + \frac{1}{2} a (4.10 )^2[/tex]
=> [tex]1.90 = 0* t + \frac{1}{2} a (4.10 )^2[/tex]
=> [tex]a = 0.226 \ m/s^2[/tex]
Generally from kinematic equations we have that
[tex]v = u + at[/tex]
=> [tex]v = 0 +0.226 * 4.10[/tex]
=> [tex]v =0.9268 \ m/s[/tex]
Converting to cm/s
=> [tex]v =0.9268 * 100[/tex]
=> [tex]v = 92.68 \ cm/s[/tex]
A 5-kg object is sliding to the right and encountering a friction force that slows it down. The coefficient of friction (μ) between the object and the surface is 0.1. What is the acceleration of the object? Note: There is no applied force here.
Answer:
The friction force is 4.9 N
[tex]a = 0.98\ m/s^2[/tex]
Explanation:
Friction Force
When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration or speed because the friction force opposes motion.
The friction force when an object moves on a horizontal surface is calculated by:
[tex]Fr=\mu N[/tex]
Where [tex]\mu[/tex] is the coefficient of static or kinetics friction and N is the normal force.
If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:
N = W = m.g
Thus, the friction force is:
[tex]Fr=\mu W[/tex]
The object has a mass of m=5 Kg, calculate the weight:
W = 5 * 9.8 = 49 N
It encounters a friction force that slows it down. We are given the coefficient of friction μ = 0.1, thus the friction force is:
Fr=0.1 49 N = 4.9 N
The friction force is 4.9 N
Since the only force acting on the object is the friction force, thus the net force is F = 4.9 N, and the acceleration can be calculated by using the equation of Newton's second law:
F = m.a
Solving for a:
[tex]\displaystyle a = \frac{F}{m}[/tex]
[tex]\displaystyle a = \frac{4.9}{5}[/tex]
[tex]\mathbf{a = 0.98\ m/s^2}[/tex]
a force of 50 newtons pulls a rope attached to a 150 newton sled across a horizontal surface at a constant velocity of 5 meters per second. The rope is at an angle of 35 degrees above the horizontal. calculate the magnitude of the frictional force acting on the sled? Show all work, including the equation and substitution with units.
Answer:
I don't know the answer I hope you find it tho good luck##
An object that falls and accelerates solely as a result of gravity is said to be in
(2 points)
A. terminal velocity
B. free fall
C. air resistance
D. terminal acceleration
a snowball thrown at an ice cream truck at Valley Forge in January sticks to the side. Into what form of energy was the mechanical energy changed
Answer:
Thermal Energy
Explanation:
I majored in Physics
When a snowball thrown at an ice cream truck at Valley Forge in January sticks to the side, the mechanical energy was changed into thermal energy.
What is law of conservation of energy?
Energy cannot be created or destroyed, according to the rule of conservation of energy. However, it is capable of change from one form to another. An isolated system's total energy is constant regardless of the types of energy present.
The law of energy conservation is adhered to by all energy forms. The law of conservation of energy essentially says that all energy is conserved in closed systems, or systems that are isolated from their surroundings.
When a snowball thrown at an ice cream truck at Valley Forge in January, the mechanical energy was changed into thermal energy and the edges of the ice melts and again due to temperature of the surrounding they freezes together and the snowball sticks to the side.
Learn more about energy here:
https://brainly.com/question/1932868
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The magnitude of vector vector A is 84.9 m and it points in the +y axis direction. The magnitude of vector vector B is 195.0 m and it points at an angle of 41.0° counterclockwise from +x axis. The magnitude of vector vector C is 126.2 m and it points in the +x axis direction.
Solution:
The magnitude of A vector is 84.9 m in the positive y-axis direction.
So the X component of A =0
the Y component of A = 84.9 m
Now the magnitude of B vector is 195 m and it makes an angle of 41° in the direction from the positive x-axis direction.
So the X component of B = B cos 41°
= 195 x cos 41°
= 195 x 0.75 = 146.25 m
the Y component of B = B sin 41°
= 195 x sin 41°
= 195 x 0.65 = 126.75 m
Now it is given that vector C has a magnitude of 126.2 m and it makes a direction towards the positive x-axis.
So the X component of C =126.2 m
the Y component of C = 0
Comparing all these, we get
1. B vector has the largest X component
2. B vector has the largest Y component
What disease did Isaac Newton barely escape?
Answer:
the great plague
Explanation:
where is the centre of mass of a system of two particles is situated?
Answer:
In a two particle system, the center of mass lies on the center of the line joining the two particles.
Question 6 of 15
6
The rate at which work is done is called power.
O A True
O B. False
I believe it’s true?
Answer: A) True, you are correct
==================================================
Explanation:
Power in physics is defined as
power = (change in work)/(change in time)
which shows that power is basically the rate of work done. We can think of it like a speed of sorts.
------------
For example, if you apply 100 joules of work over 2 seconds, then,
power = (100 joules)/(2 seconds)
power = (100/2) joules per second
power = 50 watts
A watt is defined to be a joule per second, and it's often used to measure how much electricity is consumed, but it has broader uses in physics as well.
If it requires E joules of energy to raise a mass from the surface of the Earth to an altitude of 6,000 km above the Earth, how much energy is required to raise it from the surface to an altitude of 12,000 km?
Answer:
To raise the mass to an altitude of 12,000 Km 2E joules are required.
Explanation:
Gravitational Potential Energy
It's the energy stored in an object because of its vertical position or height in a gravitational field.
It can be calculated with the equation:
U=m.g.h
Where:
m = mass of the object
h = height with respect to a fixed reference
g = acceleration of gravity, or [tex]9.8 m/s^2[/tex].
If a mass has a height h1, its potential energy is
[tex]U_1=m.g.h_1[/tex]
If a mass has a height h2, its potential energy is
[tex]U_2=m.g.h_2[/tex]
The ratio of both potential energies is:
[tex]\displaystyle \frac{U_2}{U_1}=\frac{m.g.h_2}{m.g.h_1}[/tex]
Simplifying:
[tex]\displaystyle \frac{U_2}{U_1}=\frac{h_2}{h_1}[/tex]
Solving for U2:
[tex]\displaystyle U_2=U_1.\frac{h_2}{h_1}[/tex]
Since U1=E:
[tex]\displaystyle U_2=E.\frac{12,000~Km}{6,000~Km}[/tex]
[tex]U_2 = 2E[/tex]
To raise the mass to an altitude of 12,000 Km 2E joules are required.
an object has an mass of 15 kg and is falling at a rate of 2.0 m/s what is the momentum?
Answer:
30 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 15 × 2
We have the final answer as
30 kg.m/sHope this helps you
A student attaches a block to a force sensor and pulls it across a frictionless table. The sensor measures the block's acceleration What type of mass does the student measure ?
a. gravitational mass
b. inertial mass
c. neither
Answer:Inertial mass
Explanation:When we measure gravitational mass we find the strength of an object's interaction with a gravitational field.
When we measure inertial mass we find an object's resistance to being accelerated by a force.
An object's gravitational mass and inertial mass are the same.
We apply a force and measure the resulting acceleration, so we can use Newton’s second law to find the inertial mass.
can you answer the b. thanks
Answer:
current going into a junction in a circuit is EQUAL TO the current comming out of the junction.
Explanation:
Krichhoff's Current Law
Kirchhoff's current law (1st Law) states that current flowing into a node (or a junction) must be equal to current flowing out of it.