Simplify. Show all steps
-25y - (5y - 41)

9−8.4=6

0.6≠6

False

I don't know...

Answer:

0.6 his answer is false.

Step-by-step explanation:

...

Answer:

y=88

Step-by-step explanation:

Answer:

156/12=13

so makes 13 dollars a hour

Hope This Helps!!!

Answer:

y = 3x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 3x - 5 ← is in slope- intercept form

with slope m = 3

Parallel lines have equal slopes , then

y = 3x + c ← is the partial equation

To find c substitute (- 2, - 7 ) into the partial equation

- 7 = - 6 + c ⇒ c = - 7 + 6 = - 1

y = 3x - 1 ← equation of parallel line

Answer:

Step-by-step explanation:

Average force is (19 + 0)/2 = 9 lb

2 inches = 1/6 ft

W = Fd = 9(1/6) = 1.5 ft•lb

Answer:

f(-18) = -5

Step-by-step explanation:

Substitute−18forxiny=

1/3 x+1:

y= 1/3x+1

y= 1/3(−18)+1

y=−5(Simplify both sides of the equation)

Answer:

*See below*

Step-by-step explanation:

Identify and Explain Error

The method shown is using fractions to compare costs. This strategy does not work due to the fact that they have not factored in the $55 he pays for the car before hand. Also, 150 divided by 0.5 does not equal 30, it equals 300 so, even if he did not pay $55 beforehand, the equation is still incorrect.

Correct Work/Solution

$55 to rent

$0.50 per mile

Let's start by removing $55 from $150 to see how many dollars is left over for gas.

150 - 55 = 95

Then, divide 95 by 0.5

95 ÷ 0.5 = 190

He can drive at least 190 miles.

Share Strategy

Since he starts off paying $55 dollars out of $150, we need to subtract $55 by $150 to see how much cash he has left over for mileage. $150 minus $55 equals $95 so, he has $95 left over for mileage. $95 will then be divided by $0.50 to find out how many miles he can drive. We are dividing by $0.50 because that's the cost per mile. $95 divided by $0.50 equals 190 so he can drive at least 190 miles.

Note:

Hope this helps :)

Have a great day!

Answer:

The expression is unclear so:

If the denominator is [tex]\sqrt{x}-1[/tex] then your set of existence is given by

[tex]\left \{ {{x\ge0} \atop {x\ne1}} \right.[/tex]

since you want the quantity inside both square roots to be positive (and it happens for both to be simply [tex]x\ge0[/tex] and you don't want a zero at the denominator so you have to rule out 1.

If the square root includes the whole denominator [tex]\sqrt{x-1}[/tex] the condition becomes [tex]\left \{ {{x\ge0} \atop {x>1}} \right.[/tex]

where you don't include the extreme in the second condition since, again, you don't want to divide by 0. The answer in this case is simply [tex]x>1[/tex] since values between 0 and 1 will give a negative root which is not a real number.

Answer: 60

Step-by-step explanation:

list all of the multiples and choose the least common number

10:   10  20  30  40  50  60  70  80  90  100

12:   12  24  36  48  60  72  84  96

find a number that shares all the prime factors of the two numbers

prime factors of 10: 2, 5

prime factors or 12: 2, 2, 3

LCM = 60

Answer:

there is many ways but he could put them side to side or top and bottom

Step-by-step explanation:

Answer:

It grows at a rate  

4/9 ft/second

Step-by-step explanation:

Answer:

Go download CameraMath on playstore that how

I is get my answer

I like anime and sleeping✌

Answer:

i like food, money, and games

Step-by-step explanation:

E

Answer:

19.228

Step-by-step explanation:

multiply 2.2*2.3*3.8 to get 19 yd^3

Step-by-step explanation:

[tex]\overline{DA} \text{ bisects } \overline{EB}[/tex]     is given

[tex]\overline{BC} \cong \overline{EC}[/tex]  definition of bisect

[tex]\overline{EB} \perp \overline{ED}, \, \overline{EB} \perp \overline{BA}[/tex]  are both given

[tex]\angle B, \, \angle E \text{ are right angles}[/tex]  definition of perpendicular

[tex]\angle B \cong \angle E[/tex]   because all right angles are congruent

[tex]\angle{ACB} \cong \angle{DCE}[/tex]  vertical angles are congruent

[tex]\triangle{ACB} \cong \triangle{DCE}[/tex]   ASA (angle-side-angle)

[tex]\overline{ED} \cong \overline{BA}[/tex]  CPCTC (corresponding parts of congruent triangles are congruent)

Step-by-step explanation:  

x²+ y² -12x - 18y +17 = 0 means : (x²-12x+36)-36+(y²-18y+81)-81-27 =0

(x-6)²+(y-9)² =12²....standard form when the center is (-6 , 9) and radius 12

Answer:

The center is at (1, 6) and the radius is 1.

Step-by-step explanation:

x^2 + y^2 - 2x - 12y +36 = 0

Convert to standard form:

x^2 - 2x + y^2 - 12y = -36

(x - 1)^2 - 1 + (y - 6)^2 - 36 = -36

(x - 1)^2 + (y - 6)^2 = -36 + 36 + 1

(x - 1)^2 + (y - 6)^2 =  1

The center is at (1, 6) and the radius is 1.

Answer:

I’m not sure what that means but I think it’s the one with the blue

Step-by-step explanation:

Answer:

eeeeeeeeeeeeeeeeeeeeeeeeeeeee

Step-by-step explanation:

Applying the triangle sum theorem, m∠N = 41°

Triangle sum theorem states that the sum of the three interior angles of any triangle equals 180°.

Given the following interior angles of ΔMNO:

m∠M = (6x+1)°

m∠N = (3x-10)°

m∠O = (x+19)°

Find the value of x:

m∠M + m∠N + m∠O = 180°

6x+1 + 3x-10 + x+19 = 180

10x + 10 = 180

10x = 180 - 10

10x = 170

x = 17

m∠N = (3x-10)°

m∠N = 3(17) - 10

m∠N = 41°

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Answer:

10

Step-by-step explanation:

it is 10 cause 634+10=644

Answer:

10

Step-by-step explanation:

What is the missing addend?

We can fill in the blank with x

634+x=644

Now we need to get x to the other side

The rule to do this is what we do on one side we have to do the same thing to the other side

so if we subtract 634 on one side we also have to do that on the other side as well:

634-634+x=644-634

634-634 is 0

So it is

x=644-634

644-634 is 10

x=10

So the missing addend is 10

Hope this helps!

Answer:

9 = x + y

1x + 1.5y = 12

Step-by-step explanation:

9 (number of items) = x (number of pencils) + y (number of pens)

1x (cost of x number of pencils) + 1.5y (cost of y number of pen s)= 12 (total cost)

Answer:

A

Step-by-step explanation:

Commission: 22264*0.12=2671.68

Total pay: 14250+2671.68=16921.68

The total pay of Sara after adding the commission is: Option A:  AED 16921.68

Sara's total pay consists of her basic salary plus the commission on her sales.

Basic salary = AED 14250

Commission on sales = 12% of AED 22264

Commission = 0.12 * 22264

Now, calculate the commission:

Commission = 0.12 * 22264 = AED 2671.68

Total pay = Basic salary + Commission

Total pay = 14250 + 2671.68 = AED 16921.68

So, Sara's total pay is AED 16921.68

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We have to convert the units. 1 mile = 1.60934km, 1 gallon = 3.78541km

Since it's mile per gallon, we divide the units mentioned above.

1 mile / 1 gallon = 1 km / 1 gallon = 1.60934 / 3.78541 = 0.4251

Now multiply this result as a factor to 22

That is 22 * 0.4251 = 9.3522

So the answer is 9.3522

Answer:

[tex]\displaystyle b = -22[/tex]

Step-by-step explanation:

We are given the function:

[tex]\displaystyle f(x) = (x^3+bx+6)(g(x))[/tex]

Where b is a constant and g is a differentiable function.

And we want to determine the value of b such that f'(2) = 0.

Find f' using the product rule:

[tex]\displaystyle \begin{aligned} f'(x) & = \frac{d}{dx}\left[ (x^3+bx+6)(g(x))\right] \\ \\ & = \frac{d}{dx}\left[ x^3 + bx + 6\right] g(x) + (x^3+bx+6)\frac{d}{dx}\left[ g(x)\right] \\ \\ & = (3x^2+b)(g(x)) + (x^3 + bx + 6)(g'(x))\end{aligned}[/tex]

Substitute using known values and solve for b:

[tex]\displaystyle \begin{aligned}f'(2) = 0 & = (3(2)^2+b)(g(2)) + ((2)^3+b(2)+6)(g'(2)) \\ \\ 0 & = (12+b)(3) + (14+2b)(-1) \\ \\ 0 & = 22 +b \\ \\ b & = -22\end{aligned}[/tex]

In conclusion, the value of b is -22.

The function f is given b is a constant and g is a differentiable function the value b (-8.4),

Let's start by finding the derivative of the given function f(x) with respect to x:

f(x) = (x³ + bx + 6) × g(x)

Using the product rule for differentiation, the derivative of f(x) is:

f'(x) = (x³ + bx + 6) × g'(x) + g(x) × (3x² + b)

Now we are interested in finding the value of b for which f'(2) = 0. So, let's plug in x = 2 and use the information given about g(2) and g'(2):

f'(2) = (2³ + 2b + 6) × g'(2) + g(2) × (3 × 2² + b)

Since g(2) = 3 and g'(2) = -1,

f'(2) = (8 + 2b + 6) × (-1) + 3 × (3 × 4 + b)

= (2b + 14 - 8) + 3× (12 + b)

= 2b + 6 + 36 + 3b

= 5b + 42

Now, we want to find the value of b for which f'(2) = 0:

5b + 42 = 0

Subtracting 42 from both sides:

5b = -42

Dividing both sides by 5:

b = -8.4

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Complete question:

The function f is given by f(x)=(x^{3}+bx+6)(g(x)), where b is a constant and g is a differentiable function satisfying g(2)=3 and g′(2)=−1. For what value of b is f′(2)=0?

7

10

12

22

-8.4

Answer:

true!!!!!!!!!!!!!!!!!!!!!!!!!

Answer:

True.

Step-by-step explanation:

They are equivalent expression because if you distribute the 3 in 3(x-2), you will get the same expression as 3x-6.

3(x-2) =

(3*x) - (3*2) =

3x - 6

Hope this helps.