simplify the fraction 56/100

Answer:

10

Step-by-step explanation:

42-2=40(since 2 extra)

=>For each bag=40/10=4

To determine which ratio would result in a valid proportion when set equal to StartFraction 7 over 3 EndFraction, we need to find the ratio that is equivalent to StartFraction 7 over 3 EndFraction.

To do this, we can cross-multiply. When we cross-multiply StartFraction 7 over 3 EndFraction and another ratio, the product of the numerator of StartFraction 7 over 3 EndFraction and the denominator of the other ratio should be equal to the product of the denominator of StartFraction 7 over 3 EndFraction and the numerator of the other ratio.

Let's check each option:

1. StartFraction 9 over 49 EndFraction:

7 x 49 = 343

3 x 9 = 27

These values are not equal, so it is not a valid proportion.

2. StartFraction 18 over 42 EndFraction:

7 x 42 = 294

3 x 18 = 54

These values are not equal, so it is not a valid proportion.

3. StartFraction 42 over 18 EndFraction:

7 x 18 = 126

3 x 42 = 126

These values are equal, so it is a valid proportion.

4. StartFraction 49 over 9 EndFraction:

7 x 9 = 63

3 x 49 = 147

These values are not equal, so it is not a valid proportion.

Therefore, the ratio that results in a valid proportion when set equal to StartFraction 7 over 3 EndFraction is StartFraction 42 over 18 EndFraction.
Hope It Helps :)

Answer:

Step-by-step explanation:

20x+5y=15

Subtract 20x from both sides.

5y=15−20x

Divide both sides by 5.

__5y_  = _15-20x_____

    5                5

y=  __15-20______

            5

Divide 15−20x by 5.

y=3−4x

Answer:

number 3. is wrong you can reduce once more and it will equal 3/5. and number 4 would be 5/7.

Step-by-step explanation:

divide 12/20 by 2 on the top and bottom. you should get 6/10. you can divide that once more by 2 on the top and bottom and you should get 3/5. thats simplest form.

divide 25/35 by 5 on the top and bottom youll get 5/7. thats the simplest form.

hope this helped :)

Answer:

2 is the answer

Step-by-step explanation:

2x/3+x/3-2=0

Now take lCM of all the three term,

3x/3-2=0

Now you have solve it

x=2

Answer:

No solution

Step-by-step explanation:

[tex] \frac{2}{3} x + \frac{1}{3} x - 2 = 0[/tex]

Collect like terms and simplify

[tex] \frac{2}{3} x + \frac{1}{3} x = 2 [/tex]

[tex] \frac{2}{3} + \frac{1}{3} = \frac{2 + 1}{ 3} = \frac{3}{3} = 1[/tex]

[tex]1 = 2[/tex]

I hope this helps you

Answer:

the answer is 2.38

Step-by-step explanation:

Answer:

2 7/18 if you need it in fraction form.

Answer:

107 cm

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Answer:

107 cm

Step-by-step explanation:

To find this you just first add the 26cm three times because thats the length of 3 sides and you get 78 then you multiply 14.5 times 2 for the other two sides that length and you get 29. Next you add 78+29 and you get 107cm

Answer:

add 13 to both sides

Step-by-step explanation:

4x-13=43

4x=56

x=14

Answer:

Step-by-step explanation:

D

Answer:

A. (x+12)(x-12)

Step-by-step explanation:

Use foil method

x * x = x^2

x * - 12 = - 12x

12 * x = 12 x

12 * - 12 = - 144

x^2 [- 12x + 12x= 0x = 0] - 144

x^2 + 0 - 144 =

x^2 - 144 #

Answer:

What are the factors of x2 – 144?

✔ (x – 12)

 and

✔ (x + 12)

Step-by-step explanation:

Answer:

yo no se pero ahorita yo te ayudo

Answer:

B.

Step-by-step explanation:

A trapezoid is NOT a parallelogram because a parallelogram have 2 pairs of parallel sides. But a trapezoid/trapezium only has 1 pair of parallel sides.

[tex]:\implies\sf\:x-\dfrac{3}{4}=2x-\dfrac{9}{7}[/tex]

[tex]:\implies\sf\:\dfrac{9}{7}-\dfrac{3}{4}=2x-x[/tex]

[tex]:\implies\sf\:\dfrac{36-21}{28}=x[/tex]

[tex]:\implies\boxed{\bf{\red{x=\dfrac{15}{28}}}}[/tex]

Answer:

Step-by-step explanation:

Using the equation of motion S = ut + 1/2at² where;

S is the distance travelled = 20m

u is the initial velocity = 0m/s (car starts from rest)

a is the acceleration = ?

t is the time taken = 4s

To get the acceleration of the car, we will substitute the given parameters into the given equation.

S = ut + 1/2at²

20 = 0(4)+1/2a(4)²

20 = 0+ a/2*16

20 = 8a

divide both sides by 8

20/8 = 8a/8

20/8 = a

a = 20/8

a = 2.5m/s²

Hence the acceleration of the car is 2.5m/s²

Answer:

31/100

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

Answer:

Here are the answers:

Step-by-step explanation:

C. 4.6x10^7 = 4.6x 10x10x10x10x10x10x10 = 46,000,000

D. 4.6x10x10x10x10x10x10x10

E. You Simplify your expression by mutiplying 10x10x10x10x10x10x10 to get rid of the exponent. You find the sum by multiplying 10x10x10x10x10x10x10 first. You get 10,000,000. Then Multiply 4.6 by 10,000,000. You should get 46,000,000. The sum is 46,000,000.

Answer:

x=-5

Step-by-step explanation:

Answer:

B.) 50.91 kilograms

Step-by-step explanation:

Write an equation that looks like this:

[tex]\frac{kilogram}{pound}= \frac{kilogram}{pound}[/tex]

Insert the information in the appropriate section, with 1 kilogram and 2.2 pounds on the same side:

[tex]\frac{1}{2.2}=\frac{x}{112}[/tex]

Solve for x, which is the number of kilograms for 112 pounds if there is 1 kilogram per 2.2 pounds.

Solve for x. Cross multiply:

[tex]1(112)=2.2(x)\\\\112=2.2x[/tex]

Isolate the variable. Divide both sides by 2.2:

[tex]\frac{112}{2.2}=\frac{2.2x}{2.2}\\\\x= 50.909090...[/tex]

Round to the nearest hundredth (two decimal places to the right):

50.909 → 50.91

If 1 kilogram is equal to 2.2 pounds, then 50.91 kilograms is equal to 112 pounds.

:Done

Answer:

b bc the oter guy is alomost as smort as walter

Step-by-step explanation:

Answer: (a) ([tex]x_{2},y_{2}[/tex]) = (3,2)

              (b)  ([tex]x_{2},y_{2}[/tex]) = (19,-7)

Step-by-step explanation: Midpoint of a segment is halfway between 2 endpoints. It is calculated using the formulas:

[tex]x_{m}=\frac{x_{1}+x_{2}}{2}[/tex]

[tex]y_{m}=\frac{y_{1}+y_{2}}{2}[/tex]

Isolating [tex]x_{2}[/tex]:

[tex]2x_{m}=x_{1}+x_{2}[/tex]

[tex]x_{2}=2x_{m}-x_{1}[/tex]

And [tex]y_{2}[/tex]:

[tex]2y_{m}=y_{1}+y_{2}[/tex]

[tex]y_{2}=2y_{m}-y_{1}[/tex]

(a) Replacing values and calculating [tex]x_{2}[/tex]:

[tex]x_{2}=(2*2)-1[/tex]

[tex]x_{2}=3[/tex]

Calculating [tex]y_{2}[/tex]:

[tex]y_{2}=[2*(-1)]-(-4)[/tex]

[tex]y_{2}=2[/tex]

[tex](x_{2},y_{2})=(3,2)[/tex]

(b) [tex]x_{2}=(2*5)-(-9)[/tex]

[tex]x_{2}=19[/tex]

[tex]y_{2}=(2*6)-19[/tex]

[tex]y_{2}[/tex] = -7

[tex](x_{2},y_{2})=(19,-7)[/tex]

Answer:

D is the Right answer got it right on test and teacher said it was right

Step-by-step explanation:

Ym

Answer:

Step-by-step explanation:

From the problem statement, from the score which is given as  15._66.

it is only one digit that is missing and not a combination of two digits.

This makes our guess easier as we have a range of 0-9 to guess from

therefore the list of possible digits to select from can be given as

from between 0-9 which is

{0,1,2,3,4,5,6,7,8,9}

Answer:

0

Step-by-step explanation:

First of all, simplify the equation on both sides. You will get 5x - 2 = 2x - 2. Add two to both sides, and you get 5x=2x. Subtract 2x from both sides to get 3x=0, so x will equal 0.

Answer:

5x = 2x

Step-by-step explanation:

5x- 2 = 2 + 2x

5x - 2+ 2 = -2 + 2x +2

Answer:

0.10

Step-by-step explanation:

between 1980 and 2010 : 30 years

the change of price:3.99-0.99= 3 dollars

the average rate : 3/30=0.10 or 10 %

Answer:

367.87

Step-by-step explanation:

the 100th place is the 2nd digit in the decimal. After the "7" is "27" so it rounds down to just ".8700." We don't include the "infinite zeros" or whatever so therefore your answer is 367.87.

Hope this helps and have a nice day!

Answer:  see proof below

Step-by-step explanation:

Use the following Product to Sum Identities:

2 sin A · cos B = sin (A + B) + sin (A - B)

2 cos A · cos B = sin (A + B) + sin (A - B)

Given:  cos A + cos B = 1/2      and      sin A + sin B = 1/4  

Proof LHS → RHS

[tex]\text{LHS:}\qquad \qquad \qquad \tan\dfrac{A+B}{2}[/tex]

[tex]\text{Expand:}\qquad \qquad \dfrac{\sin\frac{(A+B)}{2}}{\cos\frac{(A+B)}{2}}[/tex]

[tex]\text{Multiplication:}\qquad \quad \dfrac{\sin\frac{(A+B)}{2}}{\cos\frac{(A+B)}{2}}\bigg(\dfrac{2\cos\frac{A-B}{2}}{2\cos \frac{A-B}{2}}\bigg)[/tex]

[tex]\text{Simplify:}\qquad \qquad \quad \dfrac{2\sin \frac{A+B}{2}\cdot \cos \frac{A-B}{2}}{2\cos \frac{A+B}{2}\cdot \cos \frac{A-B}{2}}[/tex]

[tex]\text{Product to Sum:}\qquad \dfrac{\sin A+\sin B}{\cos A+\cos B}[/tex]

[tex]\text{Given:}\qquad \qquad \qquad \quad \dfrac{\frac{1}{4}}{\frac{1}{2}}[/tex]

[tex]\text{Simplify:}\qquad \qquad \qquad \dfrac{1}{2}[/tex]

LHS = RHS:    1/2 = 1/2  [tex]\checkmark[/tex]