Solve for 2. Round to the nearest tenth of a degree, if necessary.
L
90
K
80
J

Answer:

Period: [tex]\pi[/tex]

Phase shift: n

Step-by-step explanation:

Tangent function:

Has the following format:

[tex]f(x) = \tan{ax - n}[/tex]

In which the period is [tex]\frac{\pi}{x}[/tex] and the phase shift is n.

In this question:

[tex]f(x) = -4\tan{(x-n)}[/tex]

[tex]a = 1[/tex], and thus, the period is [tex]\pi[/tex], with a phase shift of n.

Answer:

5 13 and 10

blue cheese

Answer:

angle M = 60

angle Q = 70

Step-by-step explanation:

M 180/3 = 60

Q 180-40 = 140/2 = 70

Answer:

630 feets

Step-by-step explanation:

From the triangle attached :

Using trigonometry, the height h, which is the height of climber to your eye level :

Tan θ = opposite / Adjacent

Tan 32 = h / 1000

h = tan 32 * 1000

h = 0.6248693 * 1000

h = 624.86935

Height from the ground :

624.86935 + 5.5

= 630.369 feets

= 630 feet

Answer:

0.44117647058824

15/34 as a decimal is 0.44117647058824.

Answer:

0,4411764706

Step-by-step explanation:

15/34=0,4411764706

Answer:

Step-by-step explanation:

y=[tex]\frac{3}{2} x\\[/tex]-3

Answer:

the answer is ( -8,-8 )

Step-by-step explanation:

the first point is in -8 and the second point is also in -8 , therefore the answer is ( -8,-8 )

Answer:

this question Simple form is 1/4

Step-by-step explanation:

yes

6/24= 1/4

2/8= 1/4

so 6/24=2/8

Answer:

3.75

Step-by-step explanation:

DF = 6/24 × 15 = 3.75

________________

Answer:

i believe the pre-tax subtotal would be 1890.69

Step-by-step explanation:

the 2,033 represents 100%. to remove that 7% you would do

.93 • 2,033 which gives you 1890.69

Answer:

m<F = 95°

Step-by-step explanation:

We'll begin by calculating the value of x. This can be obtained as follow:

m<C = 50

m<A = (10x – 5)

m<B = m<G = (2x + 15)

m<C + m<A + m<B = 180 (Sum of angles in a triangle)

50 + (10x – 5) + (2x + 15) = 180

50 + 10x – 5 + 2x + 15 = 180

50 – 5 + 15 + 10x + 2x = 180

60 + 12x = 180

Collect like terms

12x = 180 – 60

12x = 120

Divide both side by 12

x = 120 / 12

x = 10

Finally, we shall determine the value of m<F. This can be obtained as follow:

m<F = m<A

But

m<A = 10x – 5

x = 10

Therefore,

m<F = 10x – 5

m<F = 10(10) – 5

m<F = 100 – 5

m<F = 95°

Answer:

Mean  372.14285714286

Median 379

Mode 379

Range 427

Step-by-step explanation:

I hope this helps uwu. Goodluck with your work.

Answer:

Both B and C should be correct

Step-by-step explanation:

I'm assuming the x in Expression A is a multiplication symbol. If it is not, please tell me and I will change my answer.

Expression B has the value of 8+4 or 12.

Expression A is 3 times (8+4). You could also say that Expression A is 3 times Expression B.

Since both answer B and C say this, they should both be correct.  

Answer:

1.

[tex]midpoint = ( \frac{ - 4 + 6}{2} , \: \frac{ - 12 + 8}{2} ) \\ = (1, \: - 2)[/tex]

2.

[tex]distance = \sqrt{ {( - 4 - 6)}^{2} + {( - 12 - 8)}^{2} } \\ = \sqrt{500} \\ = 22.4 \: units[/tex]

No they aren't

___________

Answer:

The maximum volume of the box is:

[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]

Step-by-step explanation:

Given

[tex]Surface\ Area = 10m^2[/tex]

Required

The maximum volume of the box

Let

[tex]a \to base\ dimension[/tex]

[tex]b \to height[/tex]

The surface area of the box is:

[tex]Surface\ Area = 2(a*a + a*b + a*b)[/tex]

[tex]Surface\ Area = 2(a^2 + ab + ab)[/tex]

[tex]Surface\ Area = 2(a^2 + 2ab)[/tex]

So, we have:

[tex]2(a^2 + 2ab) = 10[/tex]

Divide both sides by 2

[tex]a^2 + 2ab = 5[/tex]

Make b the subject

[tex]2ab = 5 -a^2[/tex]

[tex]b = \frac{5 -a^2}{2a}[/tex]

The volume of the box is:

[tex]V = a*a*b[/tex]

[tex]V = a^2b[/tex]

Substitute: [tex]b = \frac{5 -a^2}{2a}[/tex]

[tex]V = a^2*\frac{5 - a^2}{2a}[/tex]

[tex]V = a*\frac{5 - a^2}{2}[/tex]

[tex]V = \frac{5a - a^3}{2}[/tex]

Spit

[tex]V = \frac{5a}{2} - \frac{a^3}{2}[/tex]

Differentiate V with respect to a

[tex]V' = \frac{5}{2} -3 * \frac{a^2}{2}[/tex]

[tex]V' = \frac{5}{2} -\frac{3a^2}{2}[/tex]

Set [tex]V' =0[/tex] to calculate a

[tex]0 = \frac{5}{2} -\frac{3a^2}{2}[/tex]

Collect like terms

[tex]\frac{3a^2}{2} = \frac{5}{2}[/tex]

Multiply both sides by 2

[tex]3a^2= 5[/tex]

Solve for a

[tex]a^2= \frac{5}{3}[/tex]

[tex]a= \sqrt{\frac{5}{3}}[/tex]

Recall that:

[tex]b = \frac{5 -a^2}{2a}[/tex]

[tex]b = \frac{5 -(\sqrt{\frac{5}{3}})^2}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{5 -\frac{5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{\frac{15 - 5}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{\frac{10}{3}}{2*\sqrt{\frac{5}{3}}}[/tex]

[tex]b = \frac{\frac{5}{3}}{\sqrt{\frac{5}{3}}}[/tex]

Apply law of indices

[tex]b = (\frac{5}{3})^{1 - \frac{1}{2}}[/tex]

[tex]b = (\frac{5}{3})^{\frac{1}{2}}[/tex]

[tex]b = \sqrt{\frac{5}{3}}[/tex]

So:

[tex]V = a^2b[/tex]

[tex]V =\sqrt{(\frac{5}{3})^2} * \sqrt{\frac{5}{3}}[/tex]

[tex]V =\frac{5}{3} * \sqrt{\frac{5}{3}}[/tex]

[tex]V =\frac{5}{3}\sqrt{\frac{5}{3}}[/tex]

The maximum volume of the box which has a 10 m² surface area is given below.

[tex]\rm V_{max} = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]

The rate of change of a function with respect to the variable is called differentiation. It can be increasing or decreasing.

We want to construct a box with a square base and we currently only have 10 m² of material to use in the construction of the box.

The surface area = 10 m²

Let a be the base length and b be the height of the box.

Surface area = 2(a² + 2ab)

  2(a² + 2ab) = 10

      a² + 2ab = 5

Then the value of b will be

[tex]\rm b = \dfrac{5-a^2}{2a}[/tex]

The volume of the box is given as

V = a²b

Then we have

[tex]\rm V = \dfrac{5-a^2 }{2a}* a^2\\\\V = \dfrac{5a - a^3}{2}\\\\V = \dfrac{5a}{2} - \dfrac{a^3}{2}[/tex]

Differentiate the equation with respect to a, and put it equal to zero for the volume to be maximum.

[tex]\begin{aligned} \dfrac{dV}{da} &= \dfrac{d}{da} ( \dfrac{5a}{2} - \dfrac{a^3}{2} ) \\\\\dfrac{dV}{da} &= 0 \\\\\dfrac{5}{2} - \dfrac{3a^2 }{2} &= 0\\\\a &= \sqrt{\dfrac{5}{2}} \end{aligned}[/tex]

Then the value of b will be

[tex]b = \dfrac{5-\sqrt{\dfrac{5}{2}} }{2*\sqrt{\dfrac{5}{2}} }\\\\\\b = \sqrt{\dfrac{5}{2}}[/tex]

Then the volume will be

[tex]\rm V = (\sqrt{\dfrac{5}{2}} )^2*\sqrt{\dfrac{5}{2}} \\\\V = \dfrac{5}{3} *\sqrt{\dfrac{5}{2}}[/tex]

More about the differentiation link is given below.

https://brainly.com/question/24062595

Answer:

Step-by-step explanation: She has 2 more nickels then dimes not 2 times more therefore answers B and D are incorrect. C is incorrect because it has that there are 2 more dimes than nickels. A is correct because it says that there are c dimes, and then c +2 nickels.

Answer:

86 boxes

Step-by-step explanation:

trust me its right

Answer:

0.2x+5>2

Step-by-step explanation:

0.2 is the same as 2/10;

(2/10)x>2-5

(2/10)x>-3

2x>-30

X>-15( since -15 is lesser than -14,-13,-12 and so on. the sign should be >

9514 1404 393

Answer:

  A. perhaps 0 to 7 days

  B. the radius in mm at the start of the study

  C. 0.114 mm/day

Step-by-step explanation:

A. It is always problematic to determine the reasonable domain for an exponential growth function. You can always limit the domain to the length of time for which the function is said to model the growth. It is difficult to say how much beyond that time period the exponential growth can be extrapolated, as most systems run into limits to growth.

Here, the base of the exponential term is 1.01 = 1 + 1%. This tells you the growth rate is 1% per day. The study concludes when the radius was 11.79/11.00 = 1.071818... ≈ 1 + 7.2% times the original size. That is, the study lasted approximately 7 days.

The question in part C has you look at the size on day 7, which is apparently the last day of the study. It is not clear that the model is at all useful beyond the end of the period it is intended to describe.

A reasonable domain for the growth function is 0 to 7 days.

__

B. The function gives the radius of the algae after d days. When d=0 (the y-intercept), the function gives the radius of the algae after 0 days. That is the meaning of the y-intercept is the initial radius of the algae (at the beginning of the study).

The y-intercept is always the "initial value", the value when the independent variable is zero. You have to look at the function definition to see what it is the initial value of.

__

C. The average rate of change is the difference in function values divided by the difference in time between them. Here, the attached table tells us that is ...

  (f(7) -f(2))/(7 -2) = (11.793 -11.221)/5 = 0.572/5 = 0.1144 . . . mm/day

The units of the "average rate of change" are the units of the slope of the curve on the graph: the y-axis units divided by the x-axis units. Here, that is mm/day.

Answer:

Equation: 4x + 30 + 2x + 6 = 180

Answer: x = 24

Step-by-step explanation:

The sum of the measures of supplementary angles is 180 deg.

Equation:

4x + 30 + 2x + 6 = 180

Solution:

4x + 30 + 2x + 6 = 180

Add like terms on the left side.

6x + 36 = 180

Subtract 36 from both sides.

6x = 144

x = 24

Answer:

X=24

Step-by-step explanation:

Supplementary angles = 180°

4x+30+2x+6=180

Combine like terms> 4x+2x=6x

Add: 30+6=36

6x+36=180.

Subtract 36 on both sides. > 36-36=0. 180-36=144.

Drop what you have left> 6x   144

Divide by 6. > 6/6= 1. 144/6=24.

X=24

Answer:

(A) [tex]5\frac{1}{4}*4\frac{1}{5}[/tex]

Step-by-step explanation:

The area of a parallelogram is the same as the area of a rectangle which is A=bh where b is the base and h is the height. Therefore, Erica can use the expression [tex]5\frac{1}{4}*4\frac{1}{5}[/tex] to find the area of the parallelogram.

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