Solve for M and show work

Answer:

the missing side is 6

Step-by-step explanation:

Using the Pythagorean theorem, ([tex]a^{2} + b^{2} = c^{2}[/tex]), for right triangles, you get [tex]4^{2} + (2\sqrt{5}) ^{2} = c^{2}[/tex].  Since the square cancels the square root for side b you get [tex](2^{2})*(5)[/tex] which equals 20. This makes your equation go to 16+20 = [tex]c^{2}[/tex]. Then add the numbers to make [tex]36=c^{2}[/tex]  solve for c by taking the square root of both sides to get c = 6.

Find k if (x+1) is a factor of 2x³ + kx² + 1

k = 1

The factor of a polynomial F(x) is another polynomial that divides evenly into F(x). For example, x + 3 is a factor of the polynomial x² - 9.

This is because;

i. x² - 9 can be written as (x - 3)(x + 3) which shows that both (x - 3) and (x + 3) are factors.

ii. If x = -3 is substituted into the polynomial x² - 9, the result gives zero. i.e

=> (-3)² - 9

=> (9) - 9 = 0

Therefore, if (x + a) is a factor of a polynomial, substituting x = -a into the polynomial should result to zero. This also means that, if x - a is a factor of a polynomial, substituting x = a into the polynomial should give zero.

From the question

Given polynomial: 2x³ + kx² + 1

Given factor: x + 1.

Since x + 1 is a factor of the polynomial, substituting x = -1 into the polynomial should give zero and from there we can calculate the value of k. i.e

2(-1)³ + k(-1)² + 1 = 0

2(-1) + k(1) + 1 = 0

-2 + k + 1 = 0

k - 1 = 0

k = 1

Therefore the value of k is 1.

Answer:

Each side is 10 inches because the perimeter is 80 inches, you will have to divide 80 by 8 because octagon is a shape with 8 sides. So 80 divided by 8 is 10..... So the answeer is 10 inches.

Step-by-step explanation:

80÷8=10

brainliest!!!!?

Answer:

Answer:

The answer is below

Step-by-step explanation:

∠EFG and ∠GFH are a linear pair, m∠EFG = 3n+ 21, and m∠GFH = 2n + 34. What are m∠EFG and m∠GFH?

Solution:

Two angles are said to form a linear pair if they share a base. Linear pair angles are adjacent angles formed along a line as a result of the intersection of two lines. Linear pairs are always supplementary (that is they add up to 180°).

m∠EFG = 3n + 21, m∠GFH = 2n + 34. Both angles form linear pairs, hence:

m∠EFG + m∠GFH = 180°

3n + 21 + (2n + 34) = 180

3n + 2n + 21 + 34 = 180

5n + 55 = 180

5n = 125

n = 25

Therefore, m∠EFG = 3(25) + 21 = 96°, m∠GFH = 2(25) + 34 = 84°

Answer:

[tex](x +10)^2 + (y+6)^2 = 121[/tex]

Step-by-step explanation:

Given equation :

                        [tex]x^2 + y^2 + 20x +12y + 15 = 0[/tex]

Standard equation of circle :

                                            [tex](x - a)^2 + (y-b)^2 = r^2[/tex]

We will consider the x terms in the equation first to find a.

[tex](x-a)^2 = x^2 - 2ax + a^2[/tex]

-2ax = 20x

a = -20x/2x = -10

a = -10

Next consider the y terms to find b.

[tex](y - b)^2 = y^2 -2by + b^2[/tex]

-2by = 12y

b = -12y /2y = -6

b = -6

[tex](x+10)^2 + (y-6)^2 = x^2 +20x +100 + y^2 +12y + 36[/tex]

                             [tex]=x^2 + y^2 + 20x +12y + 136\\[/tex]

But the given equation constant is 15. So find the difference between 136 and 15 to find the radius : 136 - 15 = 121

Therefore, radius = √121 = 11

Equation in standard form :

                                         [tex](x +10)^2 + (y+6)^2 = 121[/tex]

Answer:

Side-Side-Side (SSS) Congruence - if three sides of one triangle are congruent to three sides of  another triangle, then the triangles are congruent.

Side-Angle-Side (SAS) Congruence - If two sides and the included angle of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

Angle-Side-Angle (ASA) Congruence - If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

Angle-Angle-Side (AAS) Congruence - If two angles and the non-included side of one triangle are congruent to the corresponding parts of another triangle, the triangles are congruent.

u see which one fits

Answer:  SAS

Step-by-step explanation: because there are Two sides and the angle between them are congruent.

Step-by-step explanation:

The formula for the lateral area of a right cone is :

LA = rs

Where

r is the radius of the base and s is the slant height of the cone

Equivalent expression,

[tex]r=\dfrac{LA}{s}[/tex]

or

[tex]s=\dfrac{LA}{r}[/tex]

Hence, this is the required solution.

Answer:

The answers are C & E

Answer:

y = -3

Step-by-step explanation:

y = -0.5(6)

y = -3

Answer:

Step-by-step explanation:

for y

take 30 degree as reference angle using sin rule

sin 30=opposite/hypotenuse

1/2=9/y (do cross multiplication)

2*9=y

18=y

for x

using pythagoras theorem

a^2+b^2=c^2

9^2+x^2=18^2

81+x^2=324

x^2=324-81

x^2=243

x=[tex]\sqrt{243[/tex]

x=9[tex]\sqrt{3[/tex]

Answer:

A. 52

Step-by-step explanation:

Find how many months are in 4 years, since there are 4 years between her 13th and 17th birthdays.

There are 12 months in a year, so multiply 12 by 4:

12(4)

= 48

So, there are 48 months in 4 years. Since she buys a new teacup every month, this means she will have bought 48 more teacups.

Add this to the 4 teacups she got on her 13th birthday:

48 + 4

= 52

So, on her 17th birthday, she will have A. 52 teacups

Answer:

Surds. Note: a root we can't simplify further is called a Surd. So √3 is a surd.

Answer:

the value of increase each time is 1,571.43

Step-by-step explanation:

Given;

original value of the number, A = 1000

final value of the number, N = 12,000

Assuming the number increased equally each time, let the value of increase each time = x

The following linear equation will be obtained to solve for x;

7x + 1000 = 12,000

7x = 12,000 - 1,000

7x = 11,000

x = 11,000/7

x = 1,571.43

Therefore, the value of increase each time is 1,571.43

Answer:

b = x - y

Step-by-step explanation:

Given the expression x - y = b

We are to rewrite the value of b;

We can simply do this by swapping both sides that are putting b at the Left hand side and x - y at the right as shown

b = x - y

Hence the correct expression will be b = x - y

Answer:

x=46 degree

Step-by-step explanation:

32 +x=Angle ABC

32 + x =78 degree

x=78 - 32

x=46 degree

answer:

N(t)=2×[tex]1.7^{t}[/tex]

17

15

step by step explain:

before lesson (t=0), she knows 2 words.

after a week (t=1), she knows

2×(1+70%)=3.4 words

after one more week (t=2), she knows

3.4×(1+70%)=5.78 words

one more week later (t=3), she knows

5.78×(1+70%)=9.826 words

and so on ...

from pattern shown above, we know that she knows

2×[tex]1.7^{t}[/tex] words after t weeks

so N(t)=2×[tex]1.7^{t}[/tex]

after 4 weeks (t=4), she knows 2×[tex]1.7^{4}[/tex]=16.7042≈17 words

for learning 5000 words, she need:

2×[tex]1.7^{t}[/tex]=5000

   [tex]1.7^{t}[/tex]=2500

t log(1.7)=log(2500)

         t=[tex]\frac{log(2500)}{log(1.7)}[/tex]

          =14.7448727

          ≈15 (round up)

Answer:

(a) N(t) = 2(1.7)^t

(b) 17

(c) 15

Step-by-step explanation:

(a) N(t) = 2(1.7)^t

There is a 2 because she starts with 2 words. The 1.7 is since her vocabulary grows by 70%. Finally, t represents the weeks. (it is an exponent)

(b) Just plug in the equation

N(4) = 2(1.7)^4

N(4) = 2(8.3521)

N(4) = 16.7042

Round, so it is 17

(c) Once again, plug in the equation

5000 = 2(1.7)^t

2500 = (1.7)^t

use a calculator for the part below

log1.7(2500) = log1.7(1.7)*t

t = log1.7(2500)

t = 14.7448

Round, so it is 15

Answer:

69.47%

Step-by-step explanation:

Calculation to determine Find the percent of markup

Using this formula

Percent of markup=New price-Old price/Old price

Let plug in the formula

Percent of markup=$15.95-$4.87/$15.95

Percent of markup=$11.08/$15.95

Percent of markup=0.6947*100

Percent of markup=69.47%

Therefore the percent of markup is 69.47%

Answer:

a. i. sinθ = +0.941

ii. cosθ = +0.339

b. i. sinθ = -0.842

ii.  cosθ = +0.540

Step-by-step explanation:

a. Given that tanθ almost equal to≈ 2.773 where 0<θ<π/2, find the values of sinθ and cosθ.

i. sinθ

Given that 1 + cot²θ = cosec²θ

cotθ = 1/tanθ

Since tanθ = 2.773, cotθ = 1/tanθ = 1/2.773 = 0.3606

So, 1 + cot²θ = cosec²θ

1 + (0.3606)² = cosec²θ

1 + 0.13 = cosec²θ

1.13 = cosec²θ

cosec²θ = 1.13

cosecθ = ±√1.13

cosecθ = ±1.063

1/sinθ = ±1.063

sinθ = ±1/1.063

sinθ = ±0.9407

sinθ ≅ ±0.941

Since we have 0<θ<π/2, sinθ is in the first quadrant, so we choose the positive value.

So, sinθ = +0.941 where 0<θ<π/2

ii. cosθ

Given that 1 + tan²θ = sec²θ

Since tanθ = 2.773,

So, 1 + tan²θ = sec²θ

1 + (2.773)² = sec²θ

1 + 7.6895 = sec²θ

8.6895 = sec²θ

sec²θ = 8.6895

secθ = ±√8.6895

secθ = ±2.9478

1/cosθ = ±2.9478

cosθ = ±1/2.9478

cosθ = ±0.3392

cosθ ≈ ±0.339

Since we have 0<θ<π/2, cosθ is in the first quadrant, so we choose the positive value.

So, cosθ = +0.339 where 0<θ<π/2

b. Given that tanθ ≈ -1.559 where 3π/2<θ<2π, find the values of sinθ and cosθ.

i. sinθ

Given that 1 + cot²θ = cosec²θ

cotθ = 1/tanθ

Since tanθ = -1.559, cotθ = 1/tanθ = 1/-1.559 = -0.6414

So, 1 + cot²θ = cosec²θ

1 + (-0.6414)² = cosec²θ

1 + 0.4114 = cosec²θ

1.4114 = cosec²θ

cosec²θ = 1.4114

cosecθ = ±√1.4114

cosecθ = ±1.1880

1/sinθ = ±1.1880

sinθ = ±1/1.1880

sinθ = ±0.8417

sinθ ≈ ±0.842

Since we have 3π/2<θ<2π, sinθ is in the fourth quadrant, so we choose the negative value.

So, sinθ = -0.842 where 3π/2<θ<2π

ii. cosθ

Given that 1 + tan²θ = sec²θ

Since tanθ = -1.559,

So, 1 + tan²θ = sec²θ

1 + (-1.559)² = sec²θ

1 + 2.4305 = sec²θ

3.4305 = sec²θ

sec²θ = 3.4305

secθ = ±√3.4305

secθ = ±1.8522

1/cosθ = ±1.8522

cosθ = ±1/1.8522

cosθ = ±0.5399

cosθ ≈ ±0.540

Since we have 3π/2<θ<2π, cosθ is in the fourth quadrant, so we choose the positive value.

So, cosθ = +0.540 where 3π/2<θ<2π

Answer: B)  [tex]0 \le y \le 100[/tex]

====================================================

Explanation:

The range is the set of possible y outputs. Visually, we look for the highest and lowest points to determine that range of y values. The lowest point occurs when y = 0, which is the left-most point of the graph. The highest point is when y = 100 where the peak is.

So we say that y is between 0 and 100, including both endpoints to lead to the inequality [tex]0 \le y \le 100[/tex]

The range in interval notation is [0, 100]. The square brackets say to include the endpoints.

------------

Side note: The domain appears to be [tex]2.5 \le x \le 9.5[/tex] since the left-most point seems to have the x coordinate x = 2.5 and the right-most point seems to have the x coordinate x = 9.5. The domain is the set of all possible x inputs. So if your teacher was asking about the domain, then the answer would be C.

Answer:

-10

Step-by-step explanation:

i think this is the answer

Answer:

x=-14

Step-by-step explanation:

because -2(-14)=-26

Answer:

ummmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm   and i Oop

Step-by-step explanation:

Answer:

B.6

Step-by-step explanation:

3 + 2x + 22 = x + 17

Combine like terms

25 + 2x = x + 17

Subtract 17 from both sides

8 + 2x = x

Subtract 2x from both sides

8 = -x

Divide both sides by -1

x = -8

Substitute -8 for x in 2x + 22 to find value of QR

2(-8) + 22

Multiply

-16 + 22

Add

QR = 6

The length of QR in the given figure by combining like terms and applying the substitution method, QR = 6

Used the concept of addition and combining like terms in the mathmatical expression.

Given that,

The length of line segments is,

PQ = 3

QR = (2x + 22)

PR = (x + 17)

Now, from the figure,

PQ = QP + QR

Substitute the given values,

x + 17 = 3 + 2x + 22

Combine like terms

x + 17 = 25 + 2x

Subtract 17 from both sides

x = 8 + 2x

Subtract 2x from both sides

x - 2x = 8

- x = 8

Divide both sides by -1

x = -8

So, for the length of QR,

Substitute - 8 for x in the length of QR,

QR = 2x + 22

= 2(-8) + 22

= -16 + 22

= 6

Learn more about the line segment visit:

https://brainly.com/question/280216

#SPJ4

Answer:

No

Yes

Step-by-step explanation:

Let's find the inclination of the 3 lines.

m:

((-4) -3)/(0 - (-4))

-7/4

n:

((-2) -2)/(3 - 1)

-4/2

-2

k:

(1 -(-3)/(4 -(-3)

(1 +3)/4 +3

4/7

Okay, we find the inclination of all the three lines. For two lines be parallel, they have to have the same inclination. The inclination of m = -7/4 and the inclination of n = -2, so they're not parallel. And now, to know if m is perpendicular to k, they inclination have to be the opposite of the inverse of each other, so it means that they have to have opposite signals, and they need to be inverted fractions (for example a/b are inverted to b/a), and they are these two things: m = -7/4 and n = 4/7, so they're perpendicular

Answer:

No, the slopes are not equal.

Yes, the slopes are negative reciprocals.

Step-by-step explanation:

Just did it on edge.

Answer:

Two real distinct solutions

Step-by-step explanation:

Hi there!

Background of the Discriminant

The discriminant [tex]b^2-4ac[/tex] applies to quadratic equations when they are organised in standard form: [tex]ax^2+bx+c=0[/tex].

All quadratic equations can be solved with the quadratic formula: [tex]x = \frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}}[/tex].

When [tex]b^2-4ac[/tex] is positive, it is possible to take its square root and end up with two real, distinct values of x.

When it is zero, we won't be taking the square root at all and we will end up with two real solutions that are equal, or just one solution.

When it is negative, it is impossible to take the square root and we will end up with two non-real solutions.

Solving the Problem

[tex]3x^2+5x=-1[/tex]

We're given the above equation. It hasn't been organised completely in [tex]ax^2+bx+c=0[/tex], but we can change that by adding 1 to both sides to make the right side equal to 0:

[tex]3x^2+5x+1=0[/tex]

Now that we can identify the values of a, b and c, we can plug them into the discriminant:

[tex]D=b^2-4ac\\D=(5)^2-4(3)(1)\\D=25-4(3)(1)\\D=25-12\\D=13[/tex]

Therefore, because the discriminant is positive, the equation has two real, distinct solutions.

I hope this helps!

Answer:

16 and 56

Step-by-step explanation:

gcf of 24 and 48 is 24

gcf of 14 and 32 is 2

gcf of 16 and 28 is 4

Let's find one by one

#1

24 and 48

No

#2

14 and 32

No

#3

GCF is 4

No

#4

16 and 56

Yes

d = 17.3 m

Step-by-step explanation:

We can extend Pythagorean theorem to 3 dimensions by writing

[tex] {d}^{2} = {x}^{2} + {y}^{2} + {z}^{2} [/tex]

or

[tex]d = \sqrt{ {x}^{2} + {y}^{2} + {z}^{2} } [/tex]

Since we are dealing with a cube of side 10 m, then

x = y = z = 10 m

so we get

[tex]d = \sqrt{ {10}^{2} + {10}^{2} + {10}^{2} } [/tex]

or

[tex]d = \sqrt{3 \times {10}^{2} } = 10 \sqrt{3} \: m[/tex]

This becomes

d = 17.3 m