Solve for X to the nearest tenth.

Answer:

is there anymore to the question because this doesn't make sense

Step-by-step explanation:

Answer:

at first put the value of X

after that do the equation.

Step-by-step explanation:

hope it will help you

Answer:

a = 2

Step-by-step explanation:

substitute x with the number 5.

5+8a=25+5a-7a

subtract 5a from both sides

5+3a=25-7a

add 7a to both sides

5+10a = 25

subtract 5 from both sides

10a=20

divide both sides by 10

a = 2

Answer:

0.7888 = 78.88% probability that the first machine produces an acceptable cork.

0.9772 = 97.72% probability that the second machine produces an acceptable cork.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

First machine:

Mean 3 cm and standard deviation 0.08 cm, which means that [tex]\mu = 3, \sigma = 0.08[/tex]

What is the probability that the first machine produces an acceptable cork?

This is the p-value of Z when X = 3.1 subtracted by the p-value of Z when X = 2.9. So

X = 3.1

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3.1 - 3}{0.08}[/tex]

[tex]Z = 1.25[/tex]

[tex]Z = 1.25[/tex] has a p-value of 0.8944

X = 2.9

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.9 - 3}{0.08}[/tex]

[tex]Z = -1.25[/tex]

[tex]Z = -1.25[/tex] has a p-value of 0.1056

0.8944 - 0.1056 = 0.7888

0.7888 = 78.88% probability that the first machine produces an acceptable cork.

What is the probability that the second machine produces an acceptable cork?

For the second machine, [tex]\mu = 3.04, \sigma = 0.03[/tex]. Now to find the probability, same procedure.

X = 3.1

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{3.1 - 3.04}{0.03}[/tex]

[tex]Z = 2[/tex]

[tex]Z = 2[/tex] has a p-value of 0.9772

X = 2.9

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{2.9 - 3.04}{0.03}[/tex]

[tex]Z = -4.67[/tex]

[tex]Z = -4.67[/tex] has a p-value of 0

0.9772 - 0 = 0.9772

0.9772 = 97.72% probability that the second machine produces an acceptable cork.

Answer:

17

Step-by-step explanation:

12+5

Answer:

Solution given:

B: 9x - 4/x^2 - 4

Step-by-step explanation:

.k

Answer:

The smaller number is 4√2 and the larger number is (4√2 + 1).

Step-by-step explanation:

Let the two numbers be x and y, where y is the larger of the two numbers.

Since y is the larger number, it is one more than the smaller number. So:

[tex]y=x+1[/tex]

When negative two times the smaller is added to the square of the larger, the result is 33. In other words:

[tex]-2x+y^2=33[/tex]

Substitute:

[tex]-2x+(x+1)^2=33[/tex]

Solve for x. Square:

[tex]-2x+(x^2+2x+1)=33[/tex]

Simplify:

[tex]x^2+1=33[/tex]

Subtract one from both sides:

[tex]x^2=32[/tex]

And take the square root of both sides:

[tex]x=\pm\sqrt{32}=\pm 4\sqrt{2}[/tex]

Since y is positive, we can ignore the negative case. So, the smaller number is:

[tex]x=4\sqrt{2}\approx5.66[/tex]

And the larger number is:

[tex]y = 4\sqrt{2} + 1 \approx6.66[/tex]

Answer:

x=in5

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Base area = side^2 = 3^2 = 9 m^2

Base perimeter = side x 4 = 3 x 4 = 12 m

LA = (base perimeter x slant height)/2 = (12 x 5)/2 = 30 m

SA = base area + LA = 9 + 30 = 39 m^2

Answer:

approximately Normal with a mean of 3.2 million and a standard deviation of 0.32 million

Step-by-step explanation:

For normal distribution conditions

1) Sample size is greater than 30

2) Population standard deviation is known

3) population is normal distributed

Above any condition given problem if satisfied than it's distribution will approximately normal.

n = 40 > 30

Sample size(n) greater than 30 and population standard deviation is known.

So the distribution will approximately be normal

Hope this helps!

The shape  of the distribution of the sample mean for all possible random samples of size 40 from this population is approximately Normal

The following any or all conditions should be there for normal distribution:

Now  

n = 40 > 30

Here  

Sample size(n) more than 30 and population standard deviation is known.

Learn more: brainly.com/question/17429689

Answer:

[tex]a_5 = 120[/tex]

Step-by-step explanation:

Given

[tex]a_1 = 1[/tex]

[tex]a_n = n(a_{n-1})[/tex]

Required

[tex]a_5[/tex]

This is calculated as:

[tex]a_5 = 5(a_{5-1})[/tex]

[tex]a_5 = 5*a_4[/tex]

Calculate [tex]a_4[/tex]

[tex]a_4 =4(a_{4-1})[/tex]

[tex]a_4 =4*a_3[/tex]

Calculate [tex]a_3[/tex]

[tex]a_3 =3*a_2[/tex]

Calculate [tex]a_2[/tex]

[tex]a_2 = 2 * a_1[/tex]

[tex]a_2 = 2 * 1[/tex]

[tex]a_2 = 2[/tex]

So:

[tex]a_3 =3*a_2[/tex]

[tex]a_3 = 3 * 2 = 6[/tex]

So:

[tex]a_4 =4*a_3[/tex]

[tex]a_4 = 4 * 6 =24[/tex]

Lastly;

[tex]a_5 = 5*a_4[/tex]

[tex]a_5 = 5 * 24[/tex]

[tex]a_5 = 120[/tex]

Answer:

maybe the answer is 63cm...

Answer:

9.74418019cm=h

~ 9.7442

Step-by-step explanation:

volume of a cylinder=πr²h

radius=½of diameter

=½×140cm

=70cm

1l=1000cm³

150l=150l/1l×1000cm³

=150000cm³

150000cm³=π(70cm)²×h

150000cm³=15393.8040cm²h

150000cm³/15393.8040cm²=15393.8040cm²h/15393.8040cm²

150000cm³/15393.8040cm²=h

9.74418019cm=h

Answers:

===================================================

Explanations:

Problem 7)

There are 2 red aces (hearts, diamonds) out of 52 cards total, so 2/52 = 1/26 is the probability of picking a red ace.

---------------------------

Problem 8)

There are 4 kings out of 52 cards total, so 4/52 = 1/13 are the odds of picking a king.

This is the same as say focusing on one suit (eg: clubs) and finding the probability of pulling out a king.

---------------------------

Problem 9)

There are 3 face cards per suit (Jack, Queen, King) so 3*4 = 12 face cards in all. The odds of picking a face card are 12/52 = 3/13. That makes 10/13 the odds of not picking a face card, since 3/13+10/13 = 1.

---------------------------

Problem 10)

The answer is 1/2 because half of the cards are red.

You could say 26/52 = 1/2 since there are 26 red cards out of 52 cards total.

---------------------------

Problem 11)

There are 4 copies of '2' and 4 copies of '3', so there are 4+4 = 8 cards we want to avoid. The probability of picking either of them is 8/52 = 2/13. The odds of not picking any of these cards is 11/13  (refer to problem 9).

---------------------------

Problem 12)

We have 4 copies each of '7', '8' and '9'

That gives 4*3 = 12 cards total we want to pick.

So 12/52 = 3/13 is the answer.

Answer:

1/4= 3/12 & 2/6 = 4/12

Step-by-step explanation:

Answer:

Its simply B

Step-by-step explanation:

If we are to express both ratios in their simplest form, we will have the ratio of Michael’s lemonade is 1:4 and that of Sondra is 1:3. The denominator that can be used in order to compare the ratios is that which can be divided by both ratios. For example, we have 12 as a denominator. The ratios can be expressed as 3/12 and 4/12. Also, the denominator can be 24 such that the ratios can be expressed as 6/24 and 8/24.

Answer:

Actual growth of population - Birth - Death + In migration - Out Migration. ...

Answer:

The 1st graph is the answer and matches

-x/2 + 2   -2  ≤ x < 2 because it is equal to -2

The 4th graph is incorrect slightly at = 2x - 3   x  ≥ 2

as  the graph is descending and shows x = -1/2 as the gradient 4/-2 = -1/2

m = -1/2 would be the equation.

Therefore 2 (-1/2) = -1 and  -1 - 3 = -4 and 4 is not  greater than 2 so is wrong/.

Step-by-step explanation:

Answer:

8. cos(58) = 20/x

x · cos(58) = 20

x = 20/cos(58)

= 37.742

≈ 37.7

9. tan(69) = 324/x

x · tan(69) = 324

x = 324/tan(69)

= 124.372

≈ 124.4

Answer:

2 is the same as 4

Step-by-step explanation:

Answer:

Parent's share would be : 28%

Step-by-step explanation:

Cost of the computer = $2000

Anya's share = $1200

Brother's share = $240

Parents paid rest. That will be : 2000 - 1200 - 240 = $560

Percentage of parents share :

                                             [tex]\frac{560}{2000} \times 100 = 28 \%[/tex]

Answer:

0.872

Step-by-step explanation:

Given that :

P(cloudy) = P(C) = 0.94

P(cloudy and rainy) = P(C n R) = 0.82

Probability that a given day will be rainy if it is cloudy ; this is a conditional probability problem:

Recall ; P(A|B) = P(AnB) / P(B)

P(R|C) = P(C n R) / P(C) = 0.82 / 0.94 = 0.872

Answer:

because i decided that

Step-by-step explanation:

Answer:

dh/dt =  0.4 m/min

Step-by-step explanation:

The volume of the cone is:

V(c) = (1/3)*r² *h              if always  h = 3r    then    r = h/3

The volume of the cone as a function of h will be:

V(h)  =  (1/3)* (h/3)²*h

V(h) =  (1/27)*h³

The increasing rate of the volume is equal to the rate of sand added the:

D(V)/dt   = (1/27)*3*h²*dh/dt

D(v) / dt  =  10 m³/min

h =  15 m      and   dh/dt is the rate of increasing of the height

By substitution

10 m³/min  = ( 1/9)* 225 * dh/dt  (m²)

dh/dt =  90 / 225   m/min

dh/dt =  0.4 m/min

Answer:

1)x=−3/5y+17/5  

2)x=−3/8y+−9/8

Step-by-step explanation:

Let's solve for x.

5x+3y=17

Step 1: Add -3y to both sides.

5x+3y+−3y=17+−3y

5x=−3y+17

Step 2: Divide both sides by 5.

5x/5=−3y+17/5

x=−3/5y+17/5

Answer:

x=−3/5y+17/5  

Let's solve for x.

−8x−3y=9

Step 1: Add 3y to both sides.

−8x−3y+3y=9+3y

−8x=3y+9

Step 2: Divide both sides by -8.

−8x/−8=3y+9/−8

x=−3/8y+−9/8

Answer:

x=−3/8y+−9/8

I HOPE THIS IS CORRECT IF NOT TELL ME AND ILL FIX IT.

Answer:

x =74

Step-by-step explanation:

540 degrees is the sum of all the angles

90 +90 + 2x+10 + x + 2x-20 = 540

Combine like terms

5x+170=540

Subtract 170 from each side

5x = 370

Divide by 5

5x/5 = 370/5

x =74

Answer:

as we know Sara need 8 tube in 3 experiment

she will use 2 tube in 1 experiment

now she have 6 tube in other experiments

so the question said to find how many tube were used in both experiment equally so 3,3 test tube were needed for each of the other two experiment

Step-by-step explanation:

total tube=8 (3 experiment)

used =2tube (1 experiment)

remaining=8-2=6

now ,

dividing 6 into 2 equal part

so,=6/2=3

so 3 tube were used in 2nd experiment and 3in 3rd experiment

Answer:

Volume of cone = 686π/3 or 718.67 in³

Step-by-step explanation:

Given the following data;

Radius, r = 7 in

Height, h = 14 inches

From the diagram, we can see that the object is a cone

To find the volume of a cone;

Mathematically, the volume of a cone is given by the formula;

[tex] V = \frac{1}{3} \pi r^{2}h[/tex]

Where;

V is the volume of the cone.

r is the radius of the base of the cone.

h is the height of the cone.

Substituting into the equation, we have;

[tex] Volume = \frac{1}{3} * \frac {22}{7} *7^{2}*14 [/tex]

[tex] Volume = \frac{1}{3} * 22 * 7 * 14 [/tex]

[tex] Volume = \frac{1}{3} * 2156 [/tex]

[tex] Volume = 718.67 [/tex]

Volume of cone = 718.67 in³ or 686π/3 in³

Answer:

[tex] \orange{ \bold{\frac{dy}{dx} =\frac{ 5{x}^{2} + 3 }{3\sqrt[3]{(1 + {x}^{2})^{2} } }}}[/tex]

Step-by-step explanation:

[tex]y = x \sqrt[3]{1 + {x}^{2} } \\ assuming \: log \: both \: sides \\log y = log(x \sqrt[3]{1 + {x}^{2} } ) \\ \therefore log y = logx + log(\sqrt[3]{1 + {x}^{2} } ) \\ \therefore log y = logx + \frac{1}{3} log({1 + {x}^{2} } ) \\ differentiating \: both \: sides \: w.r.t.x \\ \frac{1}{y} \frac{dy}{dx} = \frac{1}{x} + \frac{1}{3} . \frac{1}{(1 + {x}^{2}) } (0 + 2x) \\ \frac{1}{y} \frac{dy}{dx} = \frac{1}{x} + \frac{2x}{3(1 + {x}^{2}) }\\ \frac{1}{y} \frac{dy}{dx} =\frac{3(1 + {x}^{2}) + 2 {x}^{2} }{3x(1 + {x}^{2}) }\\ \frac{1}{y} \frac{dy}{dx} =\frac{3 + 3{x}^{2} + 2 {x}^{2} }{3x(1 + {x}^{2}) }\\ \frac{1}{y} \frac{dy}{dx} =\frac{3 + 5{x}^{2} }{3x(1 + {x}^{2}) }\\ \frac{dy}{dx} =\frac{y(3 + 5{x}^{2} )}{3x(1 + {x}^{2}) } \\ \\ \frac{dy}{dx} =\frac{x \sqrt[3]{1 + {x}^{2} } (3 + 5{x}^{2} )}{3x(1 + {x}^{2}) }\\ \\ \frac{dy}{dx} =\frac{(3 + 5{x}^{2} )\sqrt[3]{1 + {x}^{2} } }{3(1 + {x}^{2}) }\\ \\ \purple{ \bold{\frac{dy}{dx} =\frac{ 5{x}^{2} + 3 }{3\sqrt[3]{(1 + {x}^{2})^{2} } }}}[/tex]