Solve the equation with the help of laplace transform (d^2y+dx=2 ,when x(0)=3, x’(0)=1, where d=d/█(dtà)​

Answers

Answer 1

Correct Question:-

Solve the following differential equation using Laplace transformation.

[tex]\rm{x''(t)+x'(t)=2,\quad x(0)=3,\quad x'(0)=1}[/tex]

where [tex]\rm{x'(t)=\dfrac{dx}{dt},\quad x''(t)=\dfrac{d^2x}{dt^2}.}[/tex]

[tex]\quad[/tex]

Solution:-

Let,

[tex]\cal{L}\{\rm{x(t)}\}=X(s)[/tex]

[tex]\cal{L}^{\rm{-1}}\{\rm{X(s)}\}=x(t)[/tex]

Given,

[tex]\longrightarrow\rm{x''(t)+x'(t)=2}[/tex]

We take Laplace transformation of both sides of the equation.

[tex]\longrightarrow\cal{L}\{\rm{x''(t)+x'(t)}\}=\cal{L}\{\rm{2}\}[/tex]

[tex]\longrightarrow\cal{L}\{\rm{x''(t)}\}+\cal{L}\{\rm{x'(t)}\}=\cal{L}\{\rm{2}\}[/tex]

We have,

[tex]\cal{L}\{\rm{x''(t)}\}=\rm{s^2\,X(s)-s\,x(0)-x'(0)}[/tex]

[tex]\cal{L}\{\rm{x'(t)}\}=\rm{s\,X(s)-\,x(0)}[/tex]

[tex]\cal{L}\{\rm{2}\}=\rm{\dfrac{2}{s}}[/tex]

Then,

[tex]\small\text{$\longrightarrow\rm{\big[s^2\,X(s)-s\,x(0)-x'(0)\big]+\big[s\,X(s)-x(0)\big]=\dfrac{2}{s}}$}[/tex]

[tex]\longrightarrow\rm{s(s+1)\,X(s)-(s+1)\,x(0)-x'(0)=\dfrac{2}{s}}[/tex]

Given that [tex]\rm{x(0)=3}[/tex] and [tex]\rm{x'(0)=1.}[/tex] Then,

[tex]\longrightarrow\rm{s(s+1)\,X(s)-3(s+1)-1=\dfrac{2}{s}}[/tex]

[tex]\longrightarrow\rm{s(s+1)\,X(s)-3s-4=\dfrac{2}{s}}[/tex]

[tex]\longrightarrow\rm{s(s+1)\,X(s)=\dfrac{2}{s}+3s+4}[/tex]

[tex]\longrightarrow\rm{X(s)=\dfrac{2}{s^2(s+1)}+\dfrac{3s+4}{s(s+1)}}[/tex]

[tex]\longrightarrow\rm{X(s)=\dfrac{3s^2+4s+2}{s^2(s+1)}\quad\dots(1)}[/tex]

We will factorise this expression by partial fractions.

Assume,

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{As+B}{s^2}+\dfrac{C}{s+1}}[/tex]

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{(As+B)(s+1)+Cs^2}{s^2(s+1)}}[/tex]

[tex]\longrightarrow\rm{3s^2+4s+2=(As+B)(s+1)+Cs^2}[/tex]

[tex]\longrightarrow\rm{3s^2+4s+2=(A+C)s^2+(A+B)s+B}[/tex]

Equating corresponding coefficients,

[tex]\rm{A+C=3}[/tex]

[tex]\rm{A+B=4}[/tex]

[tex]\rm{B=2}[/tex]

Solving each equation we get,

[tex]\rm{A=2}[/tex]

[tex]\rm{B=2}[/tex]

[tex]\rm{C=1}[/tex]

Therefore,

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{2s+2}{s^2}+\dfrac{1}{s+1}}[/tex]

[tex]\longrightarrow\rm{\dfrac{3s^2+4s+2}{s^2(s+1)}=\dfrac{2}{s}+\dfrac{2}{s^2}+\dfrac{1}{s+1}}[/tex]

Then (1) becomes,

[tex]\longrightarrow\rm{X(s)=\dfrac{2}{s}+\dfrac{2}{s^2}+\dfrac{1}{s+1}}[/tex]

Now we will inverse Laplace transformation to obtain the solution.

[tex]\longrightarrow\cal{L}^{\rm{-1}}\{\rm{X(s)}\}=\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{2}{s}+\dfrac{2}{s^2}+\dfrac{1}{s+1}}\right\}[/tex]

[tex]\small\text{$\longrightarrow\rm{x(t)}=\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s}}\right\}+\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s^2}}\right\}+\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s+1}}\right\}$}[/tex]

[tex]\small\text{$\longrightarrow\rm{x(t)}=\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s}}\right\}+\rm{2}\,\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1!}{s^{1+1}}}\right\}+\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s-(-1)}}\right\}$}[/tex]

We have,

[tex]\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s}}\right\}=\rm{1}[/tex]

[tex]\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1!}{s^{1+1}}}\right\}=\rm{t}[/tex]

[tex]\cal{L}^{\rm{-1}}\left\{\rm{\dfrac{1}{s-(-1)}}\right\}=\rm{e^{-t}=\dfrac{1}{e^t}}[/tex]

Hence,

[tex]\longrightarrow\rm{\underline{\underline{x(t)=2+2t+\dfrac{1}{e^t}}}}[/tex]

This is the solution to our differential equation.

[tex]\quad[/tex]

Some results of Laplace Transformation:-

[tex]\boxed{\begin{array}{c|c}&\\\rm{x(t)}=\cal{L}^{\rm{-1}}\{\rm{X(s)}\}&\rm{X(s)}=\cal{L}\{\rm{x(t)}\}\\\\=============&==================\\\\\rm{\dfrac{d^nx}{dt^n}}&\rm{s^n\,X(s)}-\displaystyle\sum_{\rm{r=0}}^{\rm{n-1}}\rm{s^{n-r-1}\,\dfrac{d^rx}{dt^r}(t=0)}\\\\----------&--------------\\\\\rm{x'(t)}&\rm{s\,X(s)-x(0)}\\\\----------&--------------\\\\\rm{x''(t)}&\rm{s^2\,X(s)-s\,x(0)-x'(0)}\\\\----------&--------------\\\\\rm{a}&\rm{\dfrac{a}{s}}\\\\----------&--------------\\\\\rm{t^n,\ n}\in\mathbb{N}&\rm{\dfrac{n!}{s^{n+1}}}\\\\----------&--------------\\\\\rm{e^{at}}&\rm{\dfrac{1}{s-a}}\\&\end{array}}[/tex]


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According to the Question:

The given quadratic equation:

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Tommy and Zach will be 16 miles apart after 2.90 hours.

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The limit of h(x) as x approaches 0 is undefined.

You could also say that the function is not defined at x = 0, meaning that the limit as x approaches 0 does not exist.

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The circumference of the circle with a radius of 4 inches is 8π inches.

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Given that the radius of the circle is 4 inches. The circumference of the circle will be calculated by the formula,

Circumference = 2πr

Circumference = 2 x π x 4

Circumference = 8π inches

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In order to determine the  height of a box we can use the formula h = V/b or if the given box is a square box or a cube then we can calculate its height by finding the cube root of its volume.

In the formula , V = volume and b = base

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One card is drawn (hkv-fhyp-che) from a well-shuffled deck of 52 cards. Calculate the probability that the card will

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Answers

The probability of getting an ace from a well-shuffled deck of 52 cards is  1/13 and the probability of not getting an ace is 12/13

We can calculate the probability by the following method:

Total number of cards in a pack of cards= 52

Number of ace cards in a pack of cards= 4

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P(E)= Number of ace cards/ Total number of cards

= 4/52

(ii) Probability of any event other than E= 1- Probability of the event E=

If the drawing of a non-ace card is considered an event, suppose E', then

P(E')= 1- the probability of drawing an ace card

= 1- P(E)

= 1-1/13

= (13-1)/ 13

12/13

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Answer:

4.9 miles

Step-by-step explanation:

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— –1
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Answers

Answer:

145

Step-by-step explanation:

Cuánto es means what is the answer

35 - (-110)

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Answers

A function is continuous if it is defined for all values of the independent variable and there are no breaks, jumps, or gaps in its graph. In other words, a function is continuous if you can draw its graph without lifting your pen from the paper.

To check whether a function is continuous at a particular point, you can use the following methods:

The two-part definition of continuity: A function is continuous at a point if the following two conditions are met:

The limit of the function as it approaches the point from the left and the right exists and is equal to the function's value at that point.

The function is defined at the point.

The Epsilon-Delta definition of continuity: A function is continuous at a point if, for every epsilon (a small positive number) there exists a delta (also a small positive number) such that, for all points x within delta units of the point in question, the function's value at x is within epsilon units of the function's value at the point.

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Answer:

C. Substitution

Step-by-step explanation:

Substitution is the final answer to an equation. So, the answer is C

Answer: C. Substitution

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Answer:

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Solution:

1/cosx - tanx = 3

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and cosx = Base / Hypotenuse

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Answer: The answer is option 1

Step-by-step explanation

The given equation is [tex](p^{2} r^{3} /pr^{4} )^{2}[/tex]

 [tex](p^{2} r^{3} /pr^{4})^{2}[/tex]  =  [tex]p^{4} r^{6} /p^{2}r^{8}[/tex]  (the given equation whole square is applied)

[tex]p^{4} r^{6} /p^{2} r^{8}[/tex]  =  [tex]p^{2} /r^{2}[/tex]   (the p and r are canceled out )

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Answers

The line produced by the equation 3x + 4y=-12 has a slope of -3/4.

To find the slope of a line represented by the equation 3x + 4y = -12, you need to have the equation in the form y = mx + b, where m is the slope and b is the y-intercept (the point at which the line crosses the y-axis).

To put the equation 3x + 4y = -12 in this form, you can start by isolating the y term on one side of the equation:

3x + 4y = -12

4y = -3x - 12

y = (-3/4)x - (12/4)

The slope of the line produced by the equation 3x + 4y=-12 is therefore -3/4.

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What is the slope of the line given by the equation 3x +4y =- 12?

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The statement that is true is there are no outliers in this distribution.

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There are four different categories of distribution channels: direct selling, selling through middlemen, dual distribution, and reverse logistics networks.

The delivery of goods from manufacturers to end users is ensured by a network of distributors or intermediaries known as a distribution channel. It is also in charge of sending payments made by clients for purchases made by producers.

In this scenario, the noticeable outliers in the data sets are 200 and 210. Thus, a statement which is not true about the data provided in the box plot above, is that there are no outliers in this distribution

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The length of the iland top i 35. 5 inche. The width of the iland top i 46. 75 inche. What i the area henry' rectangular kitchen iland top? Ue paper to how etimation or fraction multiplication to upport your anwer

Answers

The area henry' rectangular kitchen island top with length 35. 5 inches and width 46. 75 inches is 1659. 625 inch².

What is area of any shape ?

The word "area" means an open area. A shape's area is calculated using its length and width. Length is one-dimensional and measured in units such as feet (ft), yards (yd), and inches (in). Area is defined as the total space occupied by a planar (2-D) surface or shape of an object. It is measured in units such as square feet (ft²) and square inches (in²)

The area of a rectangle is the space it occupies.The area of a rectangle is obtained by multiplying the length and width in equal units. So the formula is : Area of rectangle = length x width.

Let " l " be length of rectangular island top and "w" be width of it.

We have , l = 35.5 inches , w = 46.75 inches

We have to calculate the area if henry' rectangular kitchen iland top.

let "A" be area of rectangular island top .

As discuss above, Required Area , A = l × w

=> A = 35.5 inches × 46.75 inches

=> A = 1659.625 inch²

Hence, required area is 1659.625 square inches.

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Find the coordinates of point $p$ along the directed line segment $ab$ , from $a\left(8,\ 0\right)$ to $b\left(3,-2\right)$ , so that the ratio of $ap$ to $pb$ is $1$ to $4$.

Answers

The required coordinates of point P, following the given coordinate points, are (5.5, -1).

Let's assume that point P has coordinates (x, y). We want to find the coordinates of point P along the directed line segment AB, such that the ratio of AP to PB is 1 to 4.

The coordinates of point A are (8, 0), and the coordinates of point B are (3, -2).

According to the ratio given, we have:

AP/PB = 1/4

Now, we can use the midpoint formula to find the coordinates of point P. The midpoint formula states that the coordinates of the midpoint M between two points (x₁, y₁) and (x₂, y₂) are given by:

Midpoint M = ((x₁ + x₂) / 2, (y₁ + y₂) / 2)

Let's use the midpoint formula to find the coordinates of point P:

x = (8 + 3) / 2
  = 5.5

y = (0 + (-2)) / 2
  = -1

So, the coordinates of point P are (5.5, -1).

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The senior class is collecting orders for graduation, So far, 54% have ordered their yearbook, 58% have ordered their gown and 15% have ordered their gown but not their yearbook. Find that probability that a randomly selected senior...
1. has ordered both a gown and a yearbook.
2. has ordered a yearbook or a gown.
3. has ordered neither a yearbook nor a gown.
4. has ordered a yearbook but not a gown.

Answers

Answer:

1. has ordered both a gown and a yearbook: 54%

2. has ordered a yearbook or a gown: 58% + 54% = 112%

3. has ordered neither a yearbook nor a gown: 100% - (58% + 54%) = 88%

4. has ordered a yearbook but not a gown: 54% - 15% = 39%

Step-by-step explanation:

How do you know if a figure is similar or congruent?

Answers

Answer:

Congruent means the same shape but perhaps moved or rotated or reflected

Similar means a shape that has been enlarged by a scale factor

Step-by-step explanation:

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