Answer:
The answer is "0.9192".
Step-by-step explanation:
[tex]\mu=109\\\\\sigma=10\\\\n=25\\\\\to P(\bar{x}< 111.8)=P(\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}} < \frac{111.8-109}{\frac{10}{\sqrt{25}}})\\\\[/tex]
[tex]=P(2<1.4)\\\\=\phi (1.4)\\\\=0.9192[/tex]
Sarah's dad bought her a scooter that cost $89.95. He figures he can spend up to $30.05 on a helmet before he spends too much money in all. Let x represent how much money Sarah's dad wants to spend in all. Which inequality describes the problem?
Answer:
x - 89.95 ≤ 30.05= x ≤ 120
add 89.95 to both sides of the equation. Since on the right side 89.95 is already there it cancells eachother out leaving x. After adding 89.95 to 30.05 you should get an answer of 120.
The money Sarah's dad wants to spend in all if Sarah's dad bought her a scooter that costs $89.95, He can spend up to $30.05 on a helmet, which is less than or equal to $120, x ≤ 120.
What is inequality?Inequality is a relationship that compares two numbers or other mathematical expressions in an unequal way. Inequalities are the name given to certain algebraic mathematical expressions.
Given:
Sarah's dad bought her a scooter that cost $89.95,
He can spend up to $30.05 on a helmet,
Assume the x is the money Sarah's dad wants to spend in all,
Write the inequality as shown below,
x - 89.95 ≤ 30.05
Solve the inequality by adding 89.95 on both sides,
x - 89.95 + 89.95 ≤ 30.05 + 89.95
x ≤ 120
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Hi plz help, if you can ill mark you 5 starz! :)
Answer:
79 hours
Step-by-step explanation:
(5×1 )(5 1/2 ×3 )(6×4 )(6 1/2 × 3)( 7×2)= 79 hours
A property has been assessed at $225 000. The mill rate is 14.5. To find the property tax, you would multiply the mill rate by: *
a) 0.10
b) 0.001
c) 0.01
d) 0.0001
To find the property tax, you would multiply the mill rate by 0.01
To find the property tax, you would multiply the assessed value of the property by the mill rate.
Given that the assessed value is $225,000 and the mill rate is 14.5, we need to multiply these two values to calculate the property tax.
Property Tax = Assessed Value × Mill Rate
Property Tax = $225,000 × 14.5
To simplify the calculation, we can convert the mill rate to a decimal by dividing it by 1,000.
Mill Rate = 14.5 ÷ 1000 = 0.0145
Property Tax = $225,000 × 0.0145
Property Tax = $3,262.50
Therefore, to find the property tax, you would multiply the mill rate by 0.01 (option c).
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Can someone help me out
Which factored form of 10x + 120x + 320 reveals all the zeros of the function it defines?
A) 10(x + 6)^2 – 40
B) 10(x + 8) (x + 4)
C) 10x (x + 12) + 320
D) 10(x^2 + 12x +32)
Answer:
b
Step-by-step explanation:
A billing company that collects bills for doctors' offices in the area is concerned that the percentage of bills being paid by medical insurance has risen. Historically, that percentage has been 31%. An examination of 8,606 recent, randomly selected bills reveals that 32% of these bills are being paid by medical insurance. Is there evidence of a change in the percent of bills being paid by medical insurance
Answer:
Following are the responses to the given question:
Step-by-step explanation:
[tex]H_o : p =0.31\\\\H_a: p \neq 0.31\\\\n = 8606 \\\\ p^ = 0.32[/tex]
[tex]TS = \frac{(p^ - p)}{\sqrt{(\frac{pq}{n})}}[/tex]
[tex]= \frac{(0.32-0.31)}{\sqrt{(\frac{0.31\times 0.69}{8368})}}\\\\=\frac{0.01}{5.4}\\\\=0.00185\\\\[/tex]
One more question 50 points
Answer:
5 complete scarves
Step-by-step explanation:
Answer:
5
Step-by-step explanation:
Total yarn = (amount of yarn per scarf) (amount of scarfs)
(8/9) = (1/6) (amount of scarfs)
amount of scarfs = (8*6)/9 = 48/9 = 5. 33333, so the amount of complete handkerchiefs she can make is 5.
PLEASE HELP ASAP
Mr. Green has a class of 15 students. He can spend $20 on each student to buy math supplies for the year. He first buys all of his students calculators, which
costs a total of $144.75. After buying the calculators, how much does he have left to spend on each student?
Answer:
10.35
Step-by-step explanation:
He has $300 (15x$20). He spends 144.75. He has 155.25 in total. That leaves 10.35 (155.25/15) to spend on each student.
Help please and explain how to get the answerm
Answer:
147 degrees
Step-by-step explanation:
all the angles of a triangle add up to 180 degrees. so, you must perform the operation 180-(83+64) which equals 33. this is the angle supplementary to angle 1. to find angle 1, you must subtract 180 and 33 since supplementary angles add up to 180 degrees. this is equal to 147 degrees.
Solve the system of equations:
y=120x+500
y=100x−600
A.) (-5.5, -61)
B.) (-55, -6100)
C.) (-5.5, -610)
D.) (-55, -610)
Find the surface area of the prism.
Answer:
104 in
Step-by-step explanation:
Solve triangle ABC
B=56 degrees, a=14
The success of an airline depends heavily on its ability to provide a pleasant customer experience. One dimension of customer service on which airlines compete is on-time arrival. The tables below contain a sample of data from delayed flights showing the number of minutes each delayed flight was late for two different airlines, Company A and Company B.
Company A
34 59 43 30 3
32 42 85 30 48
110 50 10 26 70
52 83 78 27 70
27 90 38 52 76
Company B
46 63 43 33 65
104 45 27 39 84
75 44 34 51 63
42 34 34 65 64
(a) Formulate the hypotheses that can be used to test for a difference between the population mean minutes late for delayed flights by these two airlines. (Let μ1 = population mean minutes late for delayed Company A flights and μ2 = population mean minutes late for delayed Company B flights.)
A)H0: μ1 − μ2 = 0
Ha: μ1 − μ2 ≠ 0
B) H0: μ1 − μ2 ≤ 0
Ha: μ1 − μ2 > 0
C)H0: μ1 − μ2 < 0
Ha: μ1 − μ2 = 0
D) H0: μ1 − μ2 ≠ 0
Ha: μ1 − μ2 = 0
E) H0: μ1 − μ2 ≥ 0
Ha: μ1 − μ2 < 0
(b) What is the sample mean number of minutes late for delayed flights for each of these two airlines?
Company A______ min.
Company B______ min.
(c) Calculate the test statistic. (Round your answer to three decimal places.)
test statistic=
What is the p-value? (Round your answer to four decimal places.)
p-value =
Using a 0.05 level of significance, what is your conclusion?
A) Reject H0. There is statistical evidence that one airline does better than the other in terms of their population mean delay time
B) Do not Reject H0. There is statistical evidence that one airline does better than the other in
terms of their population mean delay time.
C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
D) Reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
Answer:
A)H0: μ1 − μ2 = 0
Ha: μ1 − μ2 ≠ 0
(b) Means
Company A___50.6___ min.
Company B___52.75___ min.
c)The t-value is -0.30107.
The p-value is 0 .764815.
C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
Step-by-step explanation:
A)H0: μ1 − μ2 = 0
i.e there is no difference between the means of delayed flight for two different airlines
Ha: μ1 − μ2 ≠ 0
i.e there is a difference between the means of delayed flight for two different airlines
(b)
Company A___50.6___ min.
Company B___52.75___ min.
Mean of Company A = x`1= ∑x/n =34+ 59+ 43+ 30+ 3+ 32+ 42+ 85+ 30+ 48+ 110+ 50+ 10+ 26+ 70+ 52+ 83+ 78+ 27+ 70+ 27+ 90+ 38+ 52+ 76/25
= 1265/25= 50.6
Mean of Company B = x`2= ∑x/n =
=46+ 63+ 43+ 33+ 65+ 104+ 45+ 27+ 39+ 84+ 75+ 44+ 34+ 51+ 63+ 42+ 34+ 34+ 65+ 64/20
= 1055/20= 52.75
Difference Scores Calculations
Company A
Sample size for Company A= n1= 25
Degrees of freedom for company A= df1 = n1 - 1 = 25 - 1 = 24
Mean for Company A= x`1= 50.6
Total Squared Difference (x-x`1) for Company A= SS1: 16938
s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75
Company B
Sample size for Company B= n1= 20
Degrees of freedom for company B= df2 = n2 - 1 = 20 - 1 = 19
Mean for Company B= x`2= 52.75
Total Squared Difference (x-x`2) for Company B= SS2=7427.75
s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93
T-value Calculation
Pooled Variance= Sp²
Sp² = ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)
Sp²= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65
s2x`1 = s2p/n1 = 566.65/25 = 22.67
s2x`2 = s2p/n2 = 566.65/20 = 28.33
t = (x`1 - x`2)/√(s2x`1 + s2x`2) = -2.15/√51 = -0.3
The t-value is -0.30107.
The total degrees of freedom is = n1+n2- 2= 25+20-2=43
The critical region for two tailed test at significance level ∝ =0.05 is
t(0.025) (43) = t > ±2.017
Since the calculated value of t= -0.30107. does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.
The p-value is 0 .764815. The result is not significant at p < 0.05.
In this exercise, it is necessary to use the knowledge given by the airlines and the flights, having as a solution:
a)[tex]H_0: \mu_1 -\mu_2 = 0\\H_a:\mu_1 -\mu_2\neq 0[/tex]
b) Means: Company A 50.6 min.
Company B 52.75 min.
c)The t-value is -0.30107.
The p-value is 0 .764815.
C) Do not reject H0. There is no statistical evidence that one airline does better than the other in terms of their population mean delay time.
A)[tex]H_0: \mu_1 -\mu_2 = 0[/tex]
There is no difference between the means of delayed flight for two different airlines:
[tex]H_a:\mu_1 -\mu_2\neq 0[/tex]
There is a difference between the means of delayed flight for two different airlines.
(b) Mean of Company A[tex]= x_1= \sum{x/n} = 1265/25= 50.6[/tex]
Mean of Company B [tex]= x_2= \sum{x/n} =1055/20= 52.75[/tex]
C) Difference Scores Calculations:
Company A:
Sample size for Company [tex]A= n1= 25[/tex]
Degrees of freedom for company [tex]A= df1 = n1 - 1 = 25 - 1 = 24[/tex]
Mean for Company [tex]A= x_1= 50.6[/tex]
Total Squared Difference for Company [tex]A= SS1: 16938\\s21 = SS1/(n1 - 1) = 16938/(25-1) = 705.75[/tex]
Company B:
Sample size for Company [tex]B= n1= 20[/tex]
Degrees of freedom for company [tex]B= df2 = n2 - 1 = 20 - 1 = 19[/tex]
Mean for Company[tex]B= x_2= 52.75[/tex]
Total Squared Difference for Company [tex]B= SS2=7427.75\\s22 = SS2/(n2 - 1) = 7427.75/(20-1) = 390.93[/tex]
T-value Calculation
Pooled Variance= Sp²
[tex]Sp^2= ((df1/(df1 + df2)) * s21) + ((df2/(df2 + df2)) * s22)\\Sp^2= ((24/43) * 705.75) + ((19/43) * 390.93) = 566.65\\s2x_1 = s2p/n1 = 566.65/25 = 22.67\\s2x_2 = s2p/n2 = 566.65/20 = 28.33\\t = (x_1 - x_2)/\sqrt{s2x_1 + s2x_2} = -2.15/\sqrt{51} = -0.3[/tex]
The t-value is -0.30107.
The total degrees of freedom is [tex]= n1+n2- 2= 25+20-2=43[/tex]
The critical region for two tailed test at significance level ∝ =0.05 is [tex]t(0.025) (43) = t > 2.017[/tex]
Since the calculated value of t= -0.30107. does not fall in the critical region t > ±2.017, null hypothesis is not rejected that is there is no difference between the means of delayed flight for two different airlines.
The p-value is 0 .764815. The result is not significant at p < 0.05.
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Someone please help me!!!!!
Ms jaegar can type 280 words in 4 minutes on her computer. If this is her average rate, How much word will she type in 10 minutes?
Show your work
Answer:
700 words
Step-by-step explanation:
280: 4
x:10
280/4 = x/10
4times x is equal to 4x and 280 times 10 is equal to 2800
4x=2800
2800 divided by x is 700.
The answer is 700 words per 10 minutes.
HELP ME PLEASEEEEEEEEEEEE
Answer: 20 cm²
Step-by-step explanation:
Brainliest pls help
Find the surface area and volume of the prism. Round your answer to nearest tenth.
With this prism, first separate it into a rectangular prism and a right triangle prism.
First, with the rectangular prism, it would have the units 5 * 5 * 6.3. Then with the right triangle prism, it would take the rest of the remaining space of it, being 3 * 5 * 6.3
The equation for the volume of a rectangular prism is L*W*H and the equation for the volume of a right triangle prism is (L*W*H) / 2.
With this, plug the numbers in for both prisms to get the volume of each of them:
Rectangular prism Volume
5*5*6.3
157.5
Right triangle prism Volume
(3*5*6.3) / 2
94.5 / 2
47.25
Lastly, combine these two values to get the total volume:
157.5 + 47.25 = 204.75 (Round Up) -->
204.8 cm^3 = Total Volume
Surface Area:Next, with the surface area of the prism. For this, lets combine all of the faces of the prism then add them all up.
First, lets do the bottom of the prism, or the base. It uses the lengths 8 cm and 6.3 cm. Lets do L * W to get the area of this face:
8 * 6.3 = 50.4
Next, lets do the slant side of it, which has the lengths 5.8 and 6.3.
5.8 * 6.3 = 36.54
Then, the top side with the lengths 5cm and 6.3 cm.
5.3 * 6.3 = 33.39
After that, the left side face that opposite to the slantly one:
5 * 6.3 = 31.5
Saving the most tedious part of it for last, the right trapezoids. Luckily, there is an equation for this:
1/2 x (Sum of parallel sides) x (perpendicular distance between the parallel sides).
So, within each of these right trapezoids, there's the parallel sides of 5 and 8. There's also a perpendicular side of 5cm. With this, we can plug this into the equation to solve for this part:
1/2 x (5+8) * (5)
1/2 x (13) * (5)
1/2 x (65)
32.5
Since there's two of them, times this by 2:
32.5 * 2 ---> 65.
Now, with the area of all of the faces, these can be added up for the total surface area:
50.4 + 36.54 + 33.39 + 31.5 + 65 ---> 216.83 (Round Down)-->
216.8 cm^2 = Total Surface Area
Can someone solve this?
Answer:
$21.60
Step-by-step explanation:
O.40 × 3.00 = 1.2
1.2 × 18 = 21.6
$21.60 was the owners profit yesterday.
The height of the equilateral triangle below is 15 units. What is the value of x?
An equilateral triangle is shown. A perpendicular bisector cuts the triangle into 2 equal parts. They hypotenuse has a measure of x.
15 StartRoot 3 EndRoot
30 StartRoot 3 EndRoot
StartFraction 15 Over StartRoot 3 EndRoot EndFraction
StartFraction 30 Over StartRoot 3 EndRoot
Answer: b
Step-by-step explanation: on edge
Answer: C. 30 StartRoot 3 EndRoot
Step-by-step explanation:
Took the test/exam
Let u=ln(x) and v=ln(y). Write the expression below in terms of u and v
=======================================================
Work Shown:
We'll apply these log rules
[tex]\text{Log Rule 1: } \ \ \ \ln\left(\frac{x}{y}\right) = \ln(x) - \ln(y)\\\\[/tex]
[tex]\text{Log Rule 2: } \ \ \ \ln\left(x^y\right) = y\ln(x)\\\\[/tex]
These log rules can be used for logs of any base, and not just natural logs.
[tex]z = \ln\left(\frac{\sqrt{x}}{y}\right)\\\\z = \ln\left(\sqrt{x}\right)-\ln\left(y\right) \text{ ... Use log rule 1}\\\\z = \ln\left(x^{1/2}\right)-\ln\left(y\right)\\\\z = \frac{1}{2}\ln\left(x\right)-\ln\left(y\right) \text{ ... Use log rule 2}\\\\z = \frac{1}{2}u-v\\\\[/tex]
Therefore,
[tex]\ln\left(\frac{\sqrt{x}}{y}\right) = \frac{1}{2}u-v\\\\[/tex]
when [tex]u = \ln(x) \ \text{ and } \ v = \ln(y)\\\\[/tex]
help me please. thank you if you do
Answer:
B
Step-by-step explanation:
Jaylin Earned $36 for 3 hours of work and $60 for 5 hours of work. What is the Constant of Proportionality?
Each quarter the marketing manager of a retail store divides customers into two classes based on their purchase behavior in the previous quarter. Denote the classes as L for low and H for high. The manager wishes to determine to which classes of customers he should send quarterly catalogs. The cost of sending a catalog is $15 per customer and the expected purchase depends on the customer’s class and the manager’s action. If a customer is in class L and receives a catalog, then the expected purchase in the current quarter is $20, and if a class L customer does not receive a catalog his expected purchase is $10. If a customer is in class H and receives a catalog, then his expected purchase is $50, and if a class H customer does not receive a catalog his expected purchase is $25. The decision whether or not to send a catalog to a customer also affects the customer's classification in the subsequent quarter. If a customer is class L at the start of the present quarter, then the probability he is in class L at the subsequent quarter is 0.3 if he receives a catalog and 0.5 if he does not. If a customer is class H in the current period, then the probability that he remains in class H in the subsequent period is 0.8 if he receives a catalog and 0.4 if he does not. Assume a discount rate of 0.9 and an objective of maximizing expected total discounted reward.
a) Formulate this as an infinite-horizon discounted Markov decision problem.
b) For ???? = 0.1, find a near-optimal policy using value iteration.
c) Find an optimal policy using policy iteration starting with the stationary policy which has greatest one-step reward.
d) Formulate the problem as a linear program, giving its primal and dual. Solve both and interpret the solutions.
Answer:
55
Step-by-step explanation:
Help me please can someone tell me how to do this
14. Which step should be placed in the blank to make the solution correct?
V25 = 5 = 51 =
= (5 - 5)2 = 25
hich
A. 5 * = 5 + 5
B.
52+2 = 52.52
C. (51)
D. 52 + 5
30 POINTS AND BRAINLIEST Alexis needs to paint the four exterior walls of a large rectangular barn. The length of the barn is 80 feet, the width is 50 feet, and the height is 30 feet. The paint costs $28 per gallon, and each gallon covers 420 square feet. What is the area of the barn Alexis needs to paint? ______________ Explain how you found your answer.
Answer:
It will cost $532 to paint the barn
Step-by-step explanation:
First we need to find the area of the barn's walls.
2 (length x height) + 2 (width x height)
=2 (80x30) + 2 (50x30)
=2 (2400) + 2(1500)
=4800+3000
=7800 ft^2
Now we can find the amount of gallons needed, then the total cost.
7800 ft^2/420 ft^2
=18.57 gallons
=19 gallons
19 gallons x $28
=$532
Answer:
520
Step-by-step explanation:
Area:
[tex]2(80*30) + 2(50*30) = 7800[/tex]
Price
[tex]\frac{7800}{420}*28 = 520[/tex]
what is 15t—7=28 + 8t
PLS HELP FOR 40 POINTS I HAVE AN EXAM!!!
You need to select a pair of socks from the draw and then a t-shirt. You have eight different colors of sock pairs and ten different color t-shirts. If you pull one from each draw, what are the possible combinations of socks and t-shirt that you will get?
Answer:
8
Step-by-step explanation:
You only have 8 socks and its a combination of both socks and t-shirts. Hope this helps!
Answer:
80
Step-by-step explanation:
10*8=80
Write one way of representing the equation of the given line in point-slope form. Then rewrite the equation in slope-intercept form.
Find the 8th term in the
sequence
-1/2,-1, -2, -4,...
Hint: Write a formula to help you.
1st term . Common Ratio desired term – 1)
Answer:
-64
Step-by-step explanation:
By looking at the numbers, we can identify that this is a geometric sequence and the ratio would be 2. The formula to find the nth term in a geometric series is:
[tex]t *r^{n-1}[/tex]
where t is the first term and r is the ratio. We can substitute in the information we know:
[tex]-\frac{1}{2} *2^{n-1}[/tex]
We are looking for the eighth term, so we substitute 8 where n is:
[tex]-\frac{1}{2}*2^{8-1}[/tex]
We can simplify:
[tex]-\frac{1}{2}*2^7[/tex]
[tex]-2^6[/tex]
[tex]-64[/tex]