Solve the question below, please

Answer:

405 calories

Step-by-step explanation:

All we have to do is:

9 × 45

I hope this helps!

Answer:

x = 7.5

Step-by-step explanation:

Note the equal sign, what you do to one side, you do to the other. Isolate the variable, x. Do the opposite of PEMDAS.

PEMDAS is the order of operation, and equals:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

First, subtract 2x from both sides of the equation:

10x (-2x) = 2x (-2x) + 60

10x - 2x = 60

8x = 60

Next, isolate the variable, x. Divide 8 from both sides of the equation:

(8x)/8 = (60)/8

x = 60/8

x = 7.5

x = 7.5 is your answer.

~

Answer:

12 hours and 50 minutes

Step-by-step explanation:

You take the 4:02 and divide it by 60 (60 seconds are in a minute) and then you take the answer you got and multiply by 115 and you get 11.80 so you take the 80 and round it to 12 and then you have 50 left over so its 12 hrs and 50 mins

Answer:

7 hours, 40 min

Step-by-step explanation:

4 minutes is 1/15 of an hour

115 x 1/15 = 7 2/3

Answer:

8*g = 8g

then,

7/8g

Answer:

the estimation of the size of the population after 20 hours is 10159

Step-by-step explanation:

The computation of the size of the population after 20, hours is shown below;

= 100  2^(20 by 3)

= 10159.36

If we divide 20 by 3 so it would give 6.66 that lies between 6 and 7

So the estimation of the size of the population after 20 hours is 10159

hence, the same is relevant

Answer:

The answer is "10159"

Step-by-step explanation:

Every 3 hours the population doubles, with an initial population of 100.

[tex]\to P(t) = 100 \times 2^{\frac{t}{3}}[/tex]

[tex]P(t)= \text{The population of bacteria}\\\\ t = \text{time in hours} \\[/tex]

when t=20

[tex]\to p(20)= 100 \times 2^{\frac{20}{3}} \\[/tex]

             [tex]= 100 \times 101.593667\\\\ =10159.3667[/tex]

Answer:

x ≈ 32.3

Step-by-step explanation:

Using the sine ratio in the right triangle

sin48° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{24}{x}[/tex] ( multiply both sides by x )

x × sin48° = 24 ( divide both sides by sin48° )

x = [tex]\frac{24}{sin48}[/tex] ≈ 32.3 ( to 1 dec. place )

Answer:

The answer is (-8/5,32) in point form or x=-8/5,y=32

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Answer:

3) 5/2

Step-by-step explanation:

2y = 5x + 4

y = 5/2x + 2

slope = 5/2

(y = mx + b, m being slope, b being y intercept)

Answer:

Step-by-step explanation:

7/8) / (1/2) .when dividing fractions, flip what u r dividing by, then multiply

7/8 * 2 = 14/8 = 1 3/4 <==

Answer:

She picked white because the board is white

Answer:

24.24... percent chance

Step-by-step explanation:

Because 6/33 is 24 percent and 6 is the amount of red shirts

Answer:

The answer to the question provided is letter D.

Answer:

funny

Step-by-step explanation:

Answer: month 7

Step-by-step explanation:

My sis did it

Answer:

The inequality x+y<1 should look like the graph attached.

It should be a dashed line, not a solid line.

Answer:

The second one you click to switch it

Step-by-step explanation:

Just did the quiz just going by every question and giving answers

Answer:

A

Step-by-step explanation:

Answer:

Sam is incorrect

Step-by-step explanation:

I am not a dependable source

Answer:

C. 52.4

Step-by-step explanation:

Answer:

a) the required percentage is 32.64%

b) the cutoff for the highest 15% of annual returns with this portfolio  is 49.02%

Step-by-step explanation:

Given that;

mean μ = 14.7 %

standard deviation σ =33%

a.) What percent of years does this portfolio lose money, i.e. have a return less than 0%?

P( portfolio lose money )

= P( x< 0) P( 0-14.7 / 33 )

P( Z < -0.45 ) =  0.3264 ≈ 32.64%

Therefore, the required percentage is 32.64%

b)

the cutoff for the highest 15% of annual returns with this portfolio will be:

P( X ≥ x) = 15%

1 - P(X ≤ x) = 0.15

P(X ≤ x) = 0.85

P(Z ≤ x-14.7 / 33 ) = 0.85 ----------let this be equation 1

form tables, P(Z ≤ 1.04) = 0.85 -----LET THIS BE EQU 2

from the equations;

(x-14.7 / 13 ) = 1.04

33 × 1.04 = x-14.7

34.32 = x-14.7

x = 34.32 + 14.7

x = 49.02%

Therefore, the cutoff for the highest 15% of annual returns with this portfolio  is 49.02%

Step-by-step explanation:

eggs used : 50-12= 38 eggs

[tex] \frac{38 \: eggs}{12 \: batches} = 3.1667eggs \: per \: batch[/tex]

Answer:

y = 4x + 5

Step-by-step explanation:

3y - 12x = 15

Add 12x to both sides.

3y = 12x + 15

Divide by 3 to isolate y.

y = 4x + 5

Answer:

ACTUALLY IT'S, y=4x-5

Step-by-step explanation:

12x-3y=15                          - Get y alone

-12x   =12x                          

-3y=-12x+15

-3y=-12x+15     - Divide.            

__________

-3           -3

y=12/3x-15/3                  -  Distribute division. Negative over a negative is positive. Positive over a negative is a negative.

y=4x-5     - Reduce fractions.

Answer:

1.718333

0.114957

12

1 3 5 7

Step-by-step explanation:

Given the following height values :

Height values : 1.55, 1.92, 1.60, 1.75, 1.58, 1.67, 1.63, 1.82, 1.76, 1.77, 1.72, 1.85

1.) Assign all height values to a vector height :

R code:

height - - -> c(1.55, 1.92, 1.60, 1.75, 1.58, 1.67, 1.63, 1.82, 1.76, 1.77, 1.72, 1.85)

2.) To compute the mean and standard deviation of "height"

R code for mean height:

mean(height)

R code for height standard deviation :

sd(height)

3.) The length of "height" ; This gives the number of data values in the vector variable "height"

R_code for length:

length(height)

4.) Number of heights less than 1.65

R_code :

which(height < 1.65)

Gives the index values where height values is less than 1.65

5.) Show if each height is larger than 1.6 and less Than 1.75

R_code :

1.6 < height < 1.75

Answer:

[tex]\frac{1}{2}[/tex] cups of flour

Step-by-step explanation:

Substitute 1 in for m.

[tex]f=\frac{1}{2}(1)[/tex]

Simplify.

[tex]f=\frac{1}{2}[/tex]

Answer:

BODMAS (Bracket Of Division Multiplication and Addition)

Step-by-step explanation:

[tex]5÷(4−3)3−2−2[/tex]

[tex]5 \div (4 - 3)3 - 2 - 2 \\ bracket \: fjrst \\ 5 \div (1)3 - 2 - 2 \\ \:second \: bracket \\ 5 \div 3 - 2 - 2 \\ division \: next \\ 5 \div 3[/tex]

bro I just stopped half way, cause my calculator says Syntax error. Maybe re check the question

Answer:

$7 a pound

Step-by-step explanation

$35 dollars in total two 2.5 pounds is 2 x 2.5 = 5 then its 35/5=$7

Answer:

0.1416

Step-by-step explanation:

The probability in a random sample of 32 times loading Twisting Thunder and 36 times loading Spiral Wonder is 0.9574.

It is also called the Gaussian Distribution. It is the most important continuous probability distribution. The curve looks like a bell, so it is also called a bell curve.

The time needed for passengers to board the Twisting Thunder roller coaster is skewed right with a mean of 49 seconds and a standard deviation of 7.1 seconds.

The probability in a random sample of 32 will be

[tex]z = \dfrac{x - \mu}{\sigma}\\\\z = \dfrac{32 - 49}{7.1}\\\\z = -2.394[/tex]

P-value from Z-Table:

P(x<32) =

The time to board the Spiral Wonder roller coaster is skewed left with a mean of 44.8 seconds and a standard deviation of 3.7 seconds.

The probability in a random sample of 36 will be

[tex]z = \dfrac{x - \mu}{\sigma}\\\\z = \dfrac{36- 44.8}{3.7}\\\\z = -2.37838[/tex]

P-value from Z-Table:

P(x<36) = 0.0086945

The probability in a random sample of 32 times loading Twisting Thunder and 36 times loading Spiral Wonder will be

[tex]\rm \dfrac{P(x < 32)}{P(x < 36)} = \dfrac{0.0083246}{0.0086945} = 0.9574[/tex]

More about the normal distribution link is given below.

https://brainly.com/question/12421652

Answer:

1 2 and 4th

Step-by-step explanation:

that is it

Answer:

x=3

please mark as brainliest

9514 1404 393

Answer:

  x ≥ 1

Step-by-step explanation:

The argument of the square root cannot be negative, so the expression is only defined for ...

  x³ -1 ≥ 0

  x³ ≥ 1 . . . . . add 1

  x ≥ ∛1 . . . .  cube root

  x ≥ 1 . . . . the domain of the expression

_____

As you can see, the graph only exists for x ≥ 1.