Solve the rational equation:
1 1 1
x-2x+3 5
O A. X=-6.09, x= 5.09
B. There is no solution.
O C. x=-3.09, x= 2.09
D. X=-3, x= 2

The solutions for the equation 23 - x² - 2x = 0 are:

x = 4

x = -6

Option A is the correct answer.

We have,

To solve the rational equation:

1/(x - 1) - 1/(x + 3) - 1/5 = 0

We need to find the common denominator and combine the fractions on the left-hand side.

The common denominator is (x - 1)(x + 3)(5).

Multiplying each term by the common denominator:

[(x + 3)(5) - (x - 1)(5) - (x - 1)(x + 3)] / [(x - 1)(x + 3)(5)] = 0

Simplifying:

[5(x + 3) - 5(x - 1) - (x - 1)(x + 3)] / [(x - 1)(x + 3)(5)] = 0

[5x + 15 - 5x + 5 - (x² + 3x  - x - 3)] / [(x - 1)(x + 3)(5)] = 0

[5x + 15 - 5x + 5 - x² - 3x + x + 3 ] / [(x - 1)(x + 3)(5)] = 0

Simplifying further:

[23 - x² - 2x ] / [(x - 1)(x + 3)(5)] = 0

Now, we set the numerator equal to zero since a fraction is zero if and only if its numerator is zero:

23 - x² - 2x = 0

To solve the quadratic equation 23 - x² - 2x = 0, we can rearrange it to the standard form:

x² + 2x - 23 = 0

Now, we can solve it using factoring, completing the square, or the quadratic formula. Let's solve it using the quadratic formula:

The quadratic formula states that for an equation in the form

ax² + bx + c = 0, the solutions for x are given by:

x = (-b ± √(b² - 4ac)) / (2a)

For our equation x² + 2x - 23 = 0, the coefficients are a = 1, b = 2, and

c = -23.

Substituting these values into the quadratic formula:

x = (-2 ± √(2² - 4(1)(-23))) / (2(1))

Simplifying:

x = (-2 ± √(4 + 92)) / 2

x = (-2 ± √96) / 2

x = (-2 ± 4√6) / 2

Simplifying further:

x = -1 ± 2√6

Therefore,

The solutions for the equation 23 - x² - 2x = 0 are:

x = -1 + 2√6 = 3.89 = 4

x = -1 - 2√6 = -5.89 = -6

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