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Balance the equation for the decomposition of aluminum chloride into its elements is 2AlCl₃ → 2Al + 3Cl₂

Decomposition reactions are processes in which chemical species break up into simpler parts and here given compound is aluminum chloride is hexahydrate is thermally decomposed to alumina by sequential treatment in two dense fluidized bed decomposers the first decomposer being operated at a temperature of about 200° to 400° C and the second at a temperature of about 900° to 1100° C

Here we have to write and balance the equation for the decomposition of aluminum chloride into its elements so balanced equation for aluminum chloride for decomposition is

2AlCl₃ → 2Al + 3Cl₂

2 mole of AlCl₃ gives 2 mole of Al and 3 mole of Cl₂

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A bigger atom  fission when a neutron smashes against it, causing it to excite and split into two smaller atoms known as fission products. A chain reaction may be initiated by other neutrons that are also released.

By dissolving large, heavy atoms, like uranium, into smaller ones, like iodine, cesium, strontium, xenon, and barium, to name just a few, fission produces energy. To create the heavier helium, fusion combines light atoms, such as the two hydrogen isotopes deuterium and tritium.

Nuclear fission fuels the explosion of nuclear weapons and creates energy for nuclear power. Due to the fact that certain compounds known as nuclear fuels undergo fission when impacted by fission neutrons and then break apart, both uses are feasible.

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The new temperature of certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm will be 300 K if its volume is doubled at the same time that its pressure is decreased to one-half its original value.

We will use combined gas law equation to find the new temperature.

We know that

Initial temperature T₁ = 27°c +273 K = 300 K

Initial pressure P₁ = 1.00 ATM

Initial volume V₁ = V

Final volume V₂ = 2 V

Final pressure P₂ = P/2 = 1/2 = 0.5 atm

Now, using the combined gas law equation, which is given as -

P₁V₁ = P₂V₂

 T₁       T₂

where,

P₁ = Initial pressure

P₂ = Final pressure

V₁ = Initial volume

V₂ = Final volume

T₁ = Initial temperature

T₂= Final temperature

Avogadro's law states that equal volumes of gases contains equal number of molecules at same temperature and pressure.

P₁V₁T₂ = P₂V₂T₁

Dividing P₁V₁ on both the sides

P₁V₁T₂  =  P₂V₂T₁

P₁V₁           P₁V₁

We get,

T₂ = P₂V₂T₁

        P₁V₁

Substituting values,

T₂ = 0.5 × 2V × 300 × V

                           1

T₂ = 300K

Hence, the new temperature is 300 K.

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The heat of combustion per gram of the material is 59.4 kJ/g

The heat of combustion per gram is the heat that is evolved when a substance is burnt in oxygen under standard condition. We know that combustion is an exothermic process thus it is clear that heat is given out.

Heat evolved = cdT

c = heat capacity

dT = temperature rise of the material

It then follows that;

Heat evolved = 45.35 * 10^3 J/degree C * (30.14 Celcius - 25.39 Celcius )

= 215412.5 J

Then;

heat of combustion per gram  = 215412.5 J * 10^-3/3.627g

= 59.4 kJ/g

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10.00 moles of H₂(g) react with 5.000 mol of O₂(g) to form 10.00 mol of H₂O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then ΔE° is 646.00kJ

Energy that is transferred from one body to another as the result of a difference in temperature called as heat

Here given data is

H₂(g) + O₂(g) → H₂O(l)

H₂(g) = 10.00 mole , O₂(g) = 5.000 mol , gives H₂O(l) = 10.00 mol and heat are released during this reaction are 683.0 kJ and PΔV is equal to -37.00 kJ then we have to find ΔE° = ?

ΔH° = 683.0 kJ

ΔE° = heat are released - PΔV

So,  ΔE° =  683.0 kJ - 37.00 kJ

= 646.00kJ

And the calculated answer is the ΔE°

So,  ΔE° = 646.00kJ

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Answer:

Explanation:

The three main radiation types are:

a) Alpha particles

b) Beta Particles

c) Gamma rays

Alpha Particles

Alpha particles are essentially helium atoms. When radiated, the value 4 is subtracted from the parent's molecule mass number while the value 2 is subtracted from the parent's molecule atomic number. Due to their heaviness, they are less penetrative, compared to other radiation types. They are positively charged.

Beta Particles

Beta particles are more energetic radiation emission with a charge equal to -1. They are negatively charged. They are high energetic electrons which can be represented generally as follows:

They weigh much more less and have a higher penetrating power when compared to alpha particles

Gamma Rays

These are the lightest and are simply radiation by products. They have more penetrating power than both beta particles and alpha particles. They are neutrally charged. They have no charge nor mass:

They have low ionizing power

20 Grams of Water.

Grams : mL

2 : 1

4 : 2

6 : 3

8 : 4

10 : 5

12 : 6

14 : 7

16 : 8

18 : 9

20 : 10

Answer:

20 grams

Explanation:

mass = Density × Volume

= M = 2g/ml × 10ml

= 20g

The liquids are less energetic than the gases. They have a definite volume unlike the gases but like the gases, they have no definite shape.

Matter is anything that has mass and occupy space. We know that matter is composed of particles. The particles that compose matter are known to differ in the way that they move about. All the particles of each of the states of matter do not have the same amount of energy. Some states of matter have particles that are more energetic than other particles of matter.

Let us note that the liquid state of matter is less energetic then the gaseous state of matter. This is because the particles that compose a gas are always moving at a very high speed. The particles that compose a liquid have lesser energy.

On the other hand, a gas has no definite volume or shape while a liquid does not have a definite shape but it has a definite volume.

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Answer:

497.97 g

Explanation:

Fe weights 55.845 g

Cl weights 35.453g

1 mole FeCl3 = 55.845 + 3(35.453) = 162.204 g

=> 3.07 moles = 3.07(162.204) = 497.96628 or 497.97 g

The molar mass of rhodonite MnSiO₃ is 131.0 g.

The molar mass of a substance is the mass of  1 mole of that substance.

The molar mass of a compound is obtained from the sum of the  product of the number of moles of atoms  and the molar masses of the elements in the compound.

The molar mass of rhodonite MnSiO₃ is calculated as follows:

Molar mass of Mn = 55 g

Molar mass of Si = 28 g

Molar mass of O = 16.0 g

Molar mass of MnSiO₃ = 55 + 28 + 16 * 3

Molar mass of MnSiO₃ = 131.0 g

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Explanation:

n=m/MM

MM of MgCl2=95.2

n=4.5/95.211

M=n/V

0.652=0.0473/V

V=0.0724 L

=72 ml

166 milligrams is equal to 0.166 grams.

If 2.28x10^-22 grams is the mass of 1 atom, then 0.166 grams would constitute how many atoms?

The equation we would make is as follows:

2.28x10^-22/1 = 0.166/x

- If we cross multiply and solve for x, we get the answer which is 7.28x10^20 atoms.

The classification of Rupatadine is H-1 receptor antagonists or H-1 blockers.

As a platelet-activating factor antagonist and second-generation antihistamine, rupatadine is used to treat allergies. It was found and developed by Uriach [es][2], and it is sold under the trade names Rupafin and a few other names as well. For the treatment of chronic urticaria and allergic rhinitis in adults and children older than 12 years, rutadine fumarate has been approved. It is offered as round, light salmon-colored tablets to be taken orally once day that contain 10 mg of rupatadine (as fumarate).

Rupatadine's effectiveness as a treatment for allergic rhinitis (AR) and chronic idiopathic urticaria (CIU) has been examined in adults and adolescents (aged over 12 years) in several controlled studies, demonstrating a rapid action onset and a great safety characteristics even in long treatment durations of a year.

The drug rupatadine, a dual antagonist of the histamine H1 and platelet activating factor receptors, is used to treat the symptoms of chronic spontaneous urticaria and seasonal and perennial rhinitis. It is available in tablet and liquid formulations for adult and pediatric usage in Canada and has received marketing approval under the trade name Rupel.

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In order of degreasing Size :

O2- > O > Ne.

Br- > Cl- > F-

Mg > Al > S

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15.2 M H3PO4 solution (in mL) do you need to make 475 mL of a 1.20 M H3PO4 solution

an H3PO4 solution be created

As a result, you must combine 0.9316 liters (931.6 ml) of water with 0.0684 liters (68.4 ml) of concentrated solution to create 1 liter of 1 M. Solution of phosphoric acid

How can I figure out what a solution's concentration is?

Subtract the solute's mass from the solution's overall volume. C = m/V, where m is the solute's mass and V is the entire volume of the solution, should be written down. To calculate the concentration of your solution, divide the mass and volume quantities you discovered by the corresponding plug-in values.

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The 12.5 g of NaCl is required to make 9.0% of the NaCl solution.

How the percentage is related to grams in terms of Chemistry?

Both percentages and grams  both  are units or parameters used to express the concentrations in chemistry.

Given:

The % of NaCl = 9.0% or = 9/10 = 0.9

The weight of the solution = 239 grams

The molar mass of the NaCl = 58.44 g/mol

Here, we use formula = 0.9 =  (Mass of the solute*1000)/(Mass of the solvent)

Let us assume the mass of the solute = x =  mass in the gram/ molecular mass of the solute.

Now, by using the above formula, we get

X=  0.9*239*58.44/1000

X = 12.5 grams

Hence, 12.5 grams is the answer

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Ideal gas equation PV =nRT

The parameters are given in problem : moles (n)  = 2.55 Volume (V) = 205L:Temperature(T) = 273K Pressure = ?kPa

Universal Gas constant  R = 8.31kPa.L/mol.K   substitue all these values in ideal gas equation in PV = nRT

PV = nRT  

Px205 = (2.55)x(8.31)x(273)

P = (3.05)x(8.31)x(273) /205 kPa

P = 33.75 kPa.

The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. An ideal gas is one that obeys the law pv=RT at all pressures and temperatures. At high temperatures and low pressure, the potential energy due to intermolecular forces becomes almost insignificant compared to the kinetic energy of the particles, and the size of the molecules increases compared to the intermolecular voids.

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Answer:

-1, 0, 1

Explanation:

for n = 4

l = 0, 1, 2, 3

p corresponds to 1

so ml of 4p is -1, 0, 1

The percent by mass of carbon in Al₂(CO₃)₃ is 15.38%.

Mass number(A) of various elements of molecule,

A of Aluminum(Al) = 27

A of Carbon(C) = 12

A of Oxygen(O) = 16

Total molecular mass or molecular weight is the sum of individual atomic masses of each atom in a molecule.

Thus, total molecular mass of molecule Al₂(CO₃)₃ is:

= 27×2 + (12 + 16 × 3)3

= 54 + 180

= 234

Hence, percent % of Carbon = (12×3/ 234)× 100

                                                = (36/ 234 )× 100

                                                = 15.38 %

Thus, the percent by mass of carbon is 15.38 %.

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The pressure of the Moxie's tank in the summer will be 110.5 atm.

The correct option is C.

According to the pressure law, if the volume remains constant, for a given mass of gas, the pressure applied to the container's sidewalls is directly proportional to the gas's absolute temperature.

This law can be expressed mathematically as

P₁/T₁ = P₂/T₂

where

P₁ is the starting pressure.

The final pressure is P₂.

The starting temperature is T₁

The final temperature is T₂

The pressure of the gas increases as its temperature does.

As a result, since summertime temperatures are higher than wintertime temperatures, the pressure within the Moxie's tank will be higher than 50 atm throughout the summer.

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The complete question is -

If the Moxie's tank has an initial pressure of 50 atm in the winter, what will be point the pressure in the summer?

A. 5.88 atm

B. 22.6 atm

C. 110.5 atm

If a population consist of large portion of reproductive Indvidual's,  then the future population size is also increase .

As previously said, populations with early reproduction have the ability to increase far more quickly than populations with later reproduction. The life tables for a certain species show how the age of first reproduction affects population growth.

Preoperative people make up a large amount of the triangular age pyramid, whereas reproductive people make up a more moderate number and post-reproductive people make up less of it. It signifies a young or populace that is expanding quickly.

In an age pyramid with an urn shape, there are more reproductive people than pre-reproductive people. It symbolises population loss or reduction and negative growth.

The proportion of pre-reproductive and reproductive people in the age pyramid has a bell shape. Comparatively fewer people are post-reproductive. It indicates a population that is steady or stationary and is neither increasing nor decreasing.

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Answer:

electron(negative)

neutron(neutral)

proton(positive)

The percent yield of carbon dioxide is 87%.

The balanced chemical equation for reaction of octane with oxygen,

CH₂(CH₂)₆CH₂+ 12O₂ → 8CO₂ + 8H₂O

We can use the mole concept here,

Mole = Given mass/molar mass.

From the reaction,

1 mole of Octane = 8 moles of carbon dioxide.

Now, moles of octane N,

N = 31.98/114.23

N = 0.2799

Moles of Carbon dioxide = 8 x 0.2799

Moles of Carbon dioxide = 2.239

Mass of CO₂ formed,

2.239 = Mass of CO₂/44

Mass of CO₂ = 98.54 grams/mole.

Percentage yield = theoretical mass/experimental mass x 100

Theoretical mass = 98.54 grams/mole.

Experimental mass = 85.8 grams/mole.

Percentage yield of CO₂ = 85.8/98.54 x 100

Percentage yield of CO₂ = 87%

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The volume (in mL) of the 0.167 M sodium hydroxide, NaOH solution needed is 26.9 mL

The balanced equation for the reaction is given below:

HClO₄ + NaOH —> NaClO₄ + H₂O

The volume of NaOH can be obtained as follow:

MaVa / MbVb = nA / nB

(0.242 × 18.53) / (0.167 × Vb) = 1

4.48426 / (0.167 × Vb) = 1

Cross multiply

0.167 × Vb = 4.48426

Divide both side by 0.167

Vb = 4.48426 / 0.167

Vb = 26.9 mL

Thus, the volume of the NaOH solution needed is 26.9 mL

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1. Balanced equation of the reaction = [tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]

2. Formulas of reactants

    solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]

    solid aluminum metal = [tex]Al(s)[/tex]

    solid manganese = [tex]Mn (s)[/tex]

    solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]

A balanced chemical equation agrees with the law of conservation. In other words, the number of participating atoms must balance between the reactants and the products of the same equation.

Formula for solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]

Formula for solid aluminum metal = [tex]Al(s)[/tex]

Formula for solid manganese = [tex]Mn (s)[/tex]

Formula for solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]

Thus, the balanced equation for the reaction is written as:

[tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]

One can see from the that the number of atoms of each element in the reactants is equal to the number of atoms of the same elements in the product.

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From the periodic table, we know that 1 mole of Krypton has a molar mass of 83.798 grams/mole.

So 10 grams would have (10/83.798) which is 0.1193345903 moles.

If we multiply this by Avogadro's number, we get the amount of Krypton atoms in 10 grams.

0.1193345903 x 6.02 x 10^23 = 7.184 x 10^22 atoms

Accounting for significant figures, the answer would be: 7 x 10^22 atoms

Alkaline earth metals are found in group 2 and tend to donate 2 electrons when combined with another element.

Now,

Now,

 As per the given question,

    Alkaline earth metals are found in group 2 and tend to donate 2 electrons when combined with another element.

Thus, from the above conclusion we can say that , alkaline earth metals are found in group 2 and tend to donate 2 electrons when combined with another element.

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Answer:

D

Explanation:

Carbon has atomic number of 6 so it has 6 protons.

The percent yield when 28.16 g of [tex]CO_2[/tex] is formed from 8.000 moles [tex]C_8H_1_8[/tex] reaction with 16.00 moles [tex]O_2[/tex] is 6.25%.

The percent yield of a reaction is given by:

Percent yield = actual yield/theoretical yield x 100%

From the equation of the reaction, the mole ratio of the two reactants is 2:25.

With 8.00 moles [tex]C_8H_1_8[/tex] , 200 moles of [tex]O_2[/tex] should be used. But only 16 moles is available. Thus, [tex]O_2[/tex] is the limiting reactant.

The mole ratio of [tex]O_2[/tex] to [tex]CO_2[/tex] is 25:16.

With 16 moles [tex]O_2[/tex], the moles of [tex]CO_2[/tex] would be:

 16 x 16/25 = 10.24 moles

Mass of 10.24 moles  [tex]CO_2[/tex] = 10.24 x 44.01

                                       = 450.7 grams

Percent yield of  [tex]CO_2[/tex] = 28.16/450.7 x 100

                                     = 6.25%

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