Answer:
0=0 1=1 2=0 3=0 4=1 5=3 6=1 7=0 8=0 9=1 10=2 11=1 12=2 13=0 14=0 15=3 16=0
Step-by-step explanation:
There was no question so here above is the Dollars spent graph in numbers not dots!
birth weights in norway are normally distributed with a mean of 3570 g and a standard deviation of 500g. if the hospital officials plan to require special treatment for the lightest 3% of newborn babies, what birth weight seperates those requiring special treatment from those who do not
Answer:
2630 g
Step-by-step explanation:
From the given information:
Given that:
mean (μ) = 3750 g
Standard deviation (σ) = 500
Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;
Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;
P(Z < z₁) = 0.03
Using the Excel Formula; =NORMSINV(0.03) = -1.88
z₁ = - 1.88
Using the test statistics z₁ formula:
[tex]z_1 = \dfrac{X-\mu}{\sigma}[/tex]
[tex]-1.88 = \dfrac{X-3570}{500}[/tex]
By cross multiply, we have:
-1.88 × 500 = X - 3570
-940 = X - 3570
-X = -3570 + 940
-X = -2630
X = 2630 g
Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not
Question 3 of 25
If f(x) = 3x + 2, what is f(5)?
O A. 10
O B. 17
O c. 1
O D. 13
Answer:
I believe it's 17 :)
Step-by-step explanation:
5×3= 15 +2 = 17
#6 - 8 ASAP first answer gets brainliest
Answer:
6. 8 in.²
7. 47.6 m²
9. 20 cm²
Step-by-step explanation:
6. Area of triangle = ½*base*height
base = 4 in.
height = 4 in.
Area = ½*4*4
Area = 2*4
Area = 8 in.²
7. Area of triangle = ½*base*height
base = 13.6 m
height = 7 m
Area = ½*13.6*7
Area = 47.6 m²
9. Area of the shaded figure = area of triangle + area of rectangle
= ½*b*h + L*W
b = 2 cm
h = 4 cm
L = 8 cm
W = 2 cm
Area of the shaded figure = ½*2*4 + 8*2
= 4 + 16
= 20 cm²
a garden and a bench cost 725 combined. the garden table cost 75 more than the bench. What is the cost of the bench
Answer: feugfberuyvfeygcreuyug
Step-by-step hththrhfhr
Can someone please answer
Answer:
6 - 5 = 7 - 61 = 1 (TRUE)Step-by-step explanation:
13 - 6 = 6 - 1
7 = 5 (FALSE)
-----------------------------
6 - 5 = 7 - 6
1 = 1 (TRUE)
------------------------------
8 - 4 = 11 - 8
4 = 3 (FALSE)
QR=15;PR=28;PQ=15,Cos_=15/28
Answer:
I don't understand any thing can you read the question
plss help me :(
Find the length of the arc.
Answer:
D 5pi/2
Step-by-step explanation:
Found the circumference then quartered. Can I have brainiest I need one more to upgrade.
Write a recursive rule for -3, -1, 2,6,11
Answer:
números enteros que comprende a los positivos y negativos
Suppose the line with slope 1 crosses the x -axis at x=2.
(a) Find the equation of the line in slope-intercept form and enter the answer in the space:
(b) What is the y -intercept of the graph of the line? Enter your answer in the space:
Answer:
a. y=x-2 b. -2
Step-by-step explanation:
a.) if the slope is 1, the x-int is always the negative of the y-int so y=x-2
b.) in y=mb+b (slope intercept form) b is the y-int so -2
Brainliest Plz??
Name
Date
Unit 2 Mid-Unit Assessment continued
Form A
6
Ben has 5 comic books. His cousin Kurt has 6 times as many comic books
as Ben has.
Part A
Draw and label a bar model to show the number of comic books
each boy has.
Answer:
das
Step-by-step explanation:
adsasc
a rectangle has a base of 10 and height of 12 what is its area
Answer:
120 units squared
Step-by-step explanation:
Which best describes the relationship between the successive terms in the sequence shown?
9, -1, -11, -21,
The common difference is -10,
The common difference is 10
The common ratio is -9)
The common ratio is 9.
Answer:
the common difference is 10
Select the values that make the inequality h < 2 true.
(Numbers written in order from least to greatest going across.)
Given:
The inequality is:
[tex]h\leq 2[/tex]
To find:
The values that make the given inequality true.
Solution:
We have,
[tex]h\leq 2[/tex]
It means the value of h must be less than or equal to 2.
In the given options, the list of numbers which are less than or equal to 2 is
-6, -3, -1, 1, 1.9, 1.99, 1.999, 2
The list of numbers which are greater than 2 is
2.001, 2.01, 2.1, 3, 5, 7, 10
Therefore, the first 8 options are correct and the required values are -6, -3, -1, 1, 1.9, 1.99, 1.999, 2.
Answer:
Step-by-step explanation:
Find the number of 3-card hands that contain the cars specified. NO LINKS!! NOT MULTIPLE CHOICE!!!
5. 3 red cards
6. 3 aces
7. 3 face cards
8. 3 hearts
9. 3 of one kind
Answer:
Step-by-step explanation:
5.
26 red cards in a 52-card deck so 3 red cards combo = 26*25*24 = 15600
6.
4 aces in a deck so 3 aces = 4*3*2 = 24
7.
12 face cards in a deck so 3 face cards = 12*11*10 = 1320
8.
13 hearts in a deck so 3 hearts = 13*12*11 = 1716
9.
4 kinds in a deck: spade, heart, diamond and club so 3 of one kind = 4*1716
= 6864
Answer:
Step-by-step explanation:
5. half deck are red; 2nd card is 1 less n 3rd card 2 less: 26x25x24 = 15600
6. 4 aces total: 4x3x2 = 24
7. 3 face cards per suit; 12 total: 12*11*10 = 1320
8. 13 heart cards: 13x12x11 = 1716
9. 4 suits: 1716x4 = 6864
Please help with this problem
Answer:
9/13 should be the answer
Explanation:
does not have a sister & has a brother / does not have a sister & has a brother + does not have a sister & does not have a brother =
9 / (9 + 4) = 9 / 13
13 of 20 QID: 26864 What is the radius of a right circular cylinder with a volume of 12 in3 if it has a minimum surface area
Answer:
r = 1,248 in
Step-by-step explanation:
v(c) = 12 in³
The surface area of a right cylinder is:
Area of the base and top + lateral area
S(a) = 2*π*r² + 2*π*r*h (1)
v(c) = 12 in³ = π*r²*h h is the height of the cylinder, then
h = 12 / π*r²
By substitution, in equation (1) we get the Surface area as a function of r
S(r) = 2*π*r² + 2*π*r* ( 12 / π*r²)
S(r) = 2*π*r² + 24 /r
Tacking derivatives on both sides of the equation we get:
S´(r) = 4*π*r - 24 /r²
S´(r) = 0 4*π*r - 24 /r² = 0 π*r - 6/r² = 0
π*r³ - 6 = 0
r³ = 1,91
r = 1,248 in
How do we know that the value r = 1,248 makes Surface area minimum??
We get the second derivative
S´´(r) = 4*π + 48/r³ S´´(r) will be always positive therefore we have a minumum of S at the value of r = 1,248 in
HELP!! these two questions I've been stuck on! Please help!
A cost accountant is developing a regression model to predict the total cost of producing a batch of printed circuit boards as a function of batch size (the number of boards produced in one lot or batch). The independent variable is:
Answer:
"Variable cost" is the appropriate answer.
Step by-step explanation:
Let an equation,
⇒ [tex]y=a+bx[/tex]
here,
y = Total costa = Fixed costx = Variable costor,
We can say that, "y" is a dependent variable as well as "x" is an independent variable.
Thus the independent variable is Variable cost.
By what percent will a fraction decrease if its numerator is decreased by 40% and its denominator is decreased by 25%?
Answer: 80%
Step-by-step explanation:
Hence, if the numerator is decreased by 40% and the denominator is decreased by 25%, the original fraction is decreased by 80 percent.
Find the missing length. The triangles in each pair are similar.
I think the answer should be 12
this is because CH length is 6 x 5 is 30 so 60/5 is 12 for BH.
PLEASE HELP I WILL GIVE BRAINLIEESTTTT
Find the sum sn of the arithmetic sequence a7=14/3 d=-4/3 n=15
Answer:
[tex]S_{15}= 50[/tex]
Step-by-step explanation:
Given
[tex]a_7 = \frac{14}{3}[/tex]
[tex]d = -\frac{4}{3}[/tex]
[tex]n = 15[/tex]
Required
The sum of n terms
First, we calculate the first term using:
[tex]a_n = a + (n - 1)d[/tex]
Let [tex]n = 7[/tex]
So, we have:
[tex]a_7 = a + (7 - 1)d[/tex]
[tex]a_7 = a + 6d[/tex]
Substitute [tex]a_7 = \frac{14}{3}[/tex] and [tex]d = -\frac{4}{3}[/tex]
[tex]\frac{14}{3} = a + 6*\frac{-4}{3}[/tex]
[tex]\frac{14}{3} = a -8[/tex]
Collect like terms
[tex]a =\frac{14}{3} +8[/tex]
Take LCM and solve
[tex]a =\frac{14+24}{3}[/tex]
[tex]a =\frac{38}{3}[/tex]
The sum of n terms is then calculated as:
[tex]S_n = \frac{n}{2}(2a + (n - 1)d)[/tex]
Where: [tex]n = 15[/tex]
So, we have:
[tex]S_n = \frac{15}{2}(2*\frac{38}{3} + (15 - 1)*\frac{-4}{3})[/tex]
[tex]S_n = \frac{15}{2}(2*\frac{38}{3} + 14 *\frac{-4}{3})[/tex]
[tex]S_n = \frac{15}{2}(2*\frac{38}{3} - 14 *\frac{4}{3})[/tex]
[tex]S_n = \frac{15}{2}(\frac{2*38}{3} - \frac{14 *4}{3})[/tex]
Take LCM
[tex]S_n = \frac{15}{2}(\frac{2*38-14 *4}{3})[/tex]
[tex]S_n = \frac{15}{2}(\frac{20}{3})[/tex]
Open bracket
[tex]S_n = \frac{15*20}{2*3}[/tex]
[tex]S_n = \frac{300}{6}[/tex]
[tex]S_n = 50[/tex]
Hence,
[tex]S_{15}= 50[/tex]
question in image attached
A sector of a circle has a diameter of 12 feet and an angle of 3pi/4 radians. Find the area of the sector.
Answer:
42.39 ft²
Step-by-step explanation:
area of sector= 3/8 × 3.14 × 6²
= 42.39 ft²
The area of the sector is 42.39 ft²
Given that, a sector of a circle has a diameter of 12 feet and an angle of 3pi/4 radians, we need to find the area of the sector,
Area of the sector = θ/360° / π·radius²
area of sector= 3/8 × 3.14 × 6²
= 42.39 ft²
Hence, the area of the sector is 42.39 ft²
Learn more about the sector of the circle, click;
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The area of a rectangle is 130 mm². The length is 3 mm greater than its width. Let x represent the width of the rectangle.
Which equation can be used to solve for x?
O A. 3x = 130
O B. x2 + 3 = 130
C. x(x + 3) = 130
D. (x+3)2 = 130
Answer:
L = 3 + x
W = x
A = L x W
130 = 3 +( x × x)
B. X2 + 3 = 130
The equation that can be used to solve for x is;
x(x + 3) = 130
Area of a RectangleWe are told that area of a rectangle is;
A = 130 mm².
We are told that length is 3 mm greater than its width.
Now, if the width is x, then
Length = x + 3
Formula for area of a rectangle is;
A = length * width
Thus;
(x + 3)x = 130
x² + 3x = 130
Read more about area of a rectangle at;https://brainly.com/question/13048427
Mr. Halsey leans a ladder against an 11.5-foot wall. The bottom of the ladder is 3.5 feet from the base of the wall, as shown.
What is the approximate length of the ladder?
A.
8 feet
B.
11 feet
C.
12 feet
D.
14 feet
Answer:
d 14
Step-by-step explanation:
how to expand (3x-4y)^6
Mars is on average 2.25 x 108 miles away from Earth. The moon is on average 2.388 x 105 miles away from Earth. Approximately how many times
farther is Mars from Earth than the moon is ?
A.0.94 times
B.9.4 times
C.94 times
D.940 times
Answer:
I believe the answer is D
Step-by-step explanation:
Mars is approximately 940 times farther away from Earth than the Moon.
What is the division operation?In mathematics, divides left-hand operands into right-hand operands in the division operation.
Mars is on average 2.25 x 10⁸ miles away from Earth.
The moon is on average 2.388 x 10⁵ miles away from Earth.
To calculate the answer, we need to divide the distance from Mars to Earth by the distance from the Moon to Earth. This gives us:
2.25 x 10⁸ miles / 2.388 x 10⁵ miles = 942.42
Rounded to the nearest whole number, this means that Mars is approximately 940 times farther away from Earth than the Moon is.
Therefore, the answer is D) 940 times.
To learn more about the division operation click here :
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Given: mĐIED = 116° and mÐJFG = 100° Find the measure of each unknown angle. (not drawn to scale) O m
Answer:
B is the answer
Step-by-step explanation:
A family of pdf's that has been used to approximate the distribution of income, city population size, and size of firms is the Pareto family. One such member of the Pareto family is the following pdf.
f(x) = { c//x^3 x≥2
0 x<2
Find the mean of X.
(a) 2
(b) 3
(c) 5
(d) 6
(e) 4
Answer:
[tex]Mean = 4[/tex]
Step-by-step explanation:
Given
[tex]f(x) =\left \{ {{\frac{c}{x^3} \ x\ge 2} \atop {0\ x<2}} \right.[/tex]
Required
The mean of x
Given that:
[tex]f(x) = \frac{c}{x^3}[/tex] [tex]x \ge 2[/tex]
First, solve for c using;
[tex]\int\limits^a_b {f(x)} \, dx = 1[/tex]
Substitute [tex]f(x) = \frac{c}{x^3}[/tex] and [tex]x \ge 2[/tex]
[tex]\int\limits^{\infty}_2 {\frac{c}{x^3}} \, dx = 1[/tex]
Isolate c
[tex]c\int\limits^{\infty}_2 {\frac{1}{x^3}} \, dx = 1[/tex]
Rewrite as:
[tex]c\int\limits^{\infty}_2 {x^{-3}} \, dx = 1[/tex]
[tex]c[\frac{x^{-3+1}}{-3 +1}]|\limits^{\infty}_2 = 1[/tex]
[tex]c[\frac{x^{-2}}{-2}]|\limits^{\infty}_2 = 1[/tex]
[tex]-\frac{c}{2} [x^{-2}]|\limits^{\infty}_2 = 1[/tex]
Expand
[tex]-\frac{c}{2} [{\infty}^{-2} - {2}^{-2}]= 1[/tex]
[tex]-\frac{c}{2} [0 - \frac{1}{4}]= 1[/tex]
[tex]-\frac{c}{2} *- \frac{1}{4}= 1[/tex]
[tex]\frac{c}{8}= 1[/tex]
Solve for c
[tex]x = 8 * 1[/tex]
[tex]x = 8[/tex]
So, we have:
[tex]f(x) = \frac{c}{x^3}[/tex] [tex]x \ge 2[/tex]
[tex]f(x) = \frac{8}{x^3}[/tex] [tex]x \ge 2[/tex]
So, the mean is calculated as:
[tex]Mean = \int\limits^a_b {x * f(x)} \, dx[/tex]
This gives;
[tex]Mean = \int\limits^{\infty}_2 {x * \frac{8}{x^3}} \, dx[/tex]
[tex]Mean = \int\limits^{\infty}_2 {\frac{8}{x^2}} \, dx[/tex]
[tex]Mean = 8\int\limits^{\infty}_2 {\frac{1}{x^2}} \, dx[/tex]
Rewrite as:
[tex]Mean = 8\int\limits^{\infty}_2 {x^{-2} \, dx[/tex]
Integrate
[tex]Mean = 8 {\frac{x^{-2+1}}{-2+1}|\limits^{\infty}_2[/tex]
[tex]Mean = 8 {\frac{x^{-1}}{-1}}|\limits^{\infty}_2[/tex]
[tex]Mean = -8x^{-1}|\limits^{\infty}_2[/tex]
Expand
[tex]Mean = -8[(\infty)^{-1} - 2^{-1}][/tex]
[tex]Mean = -8[0 - \frac{1}{2}][/tex]
[tex]Mean = -8* - \frac{1}{2}[/tex]
[tex]Mean = 8* \frac{1}{2}[/tex]
[tex]Mean = 4[/tex]