The student 2 did the MOST work because he pushed the box to a greater height.
The given parameters:
Force applied by Student 1 = 500 NHeight of table for student 1 = 1.2 mHeight of ramp for student 2 = 5 mThe work done by student 1 is calculated as follows;
Work = P.E = mgh
P.E = 1.2mg
The work done by the student 2 is calculated as;
P.E = 5mg
where;
m is the mass of the boxThus, we can conclude that the student 2 did the MOST work.
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7. a heater heating up the inside of the car
Convection conduction and radiation
when an individual charge flies through a *blank* field, a force is exerted on the charge and the path of the charge bends.
Answer:
"electric or magnetic"
F = q E force on charge q due to electric field E
F = q v x B force on charge q due to magnetic field B
A car accelerates from 10m/s to 22m/s in 10 seconds. What is the car’s acceleration?
A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s.
Explain please.
Answer:
See attachment and below
Explanation:
A car accelerates from 10m/s to 22m/s in 10 seconds.
a = (22m/s - 10m/s)/10sec
a = 12m/s/10s
a = 1.2 m/s^2
A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s
a = 98m/s - 0m/s)/10sec
a = 9.8 m/s^2
9.8 meters/sec^2 is the acceleration due to gravity.
Look at the diagram of two trains. Calculate the relative speed.
Answer:speed difference
Explanation:
Something has a mass of 40 kg and a velocity of 1 m/s
How much kinetic energy does it have?
Part 2: If it doubles its mass, will its KE also double?
[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(40)(1)^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=20J[/tex]
Part 2:-m=80kg[tex]\\ \sf\Rrightarrow K.E=\dfrac{1}{2}(80)(1)^2[/tex]
[tex]\\ \sf\Rrightarrow K.E=40J[/tex]
Yesif a 1000kg car goes from a speed of 6.5 m/s to a stop in 3 seconds what is the force acting on the car
Answer:
-6500N
Explanation:
F = ma
Note: 1N = 1 kg⋅m⋅s−2
a = (0-6.5m/s)/3s
a = -6.5m/s^2
F = 1000kg(-6.5m/s^2)
F = -6500kgm/s^2
F = -6500 N
How much work can a 22 kW (22000W) car engine do in 60 s if it is 100% efficient?
The amount of work done by the car engine if it is 100% efficient is 366.67 Joules.
Given the following data:
Time = 60 secondsPower = 22,000 WattTo determine the amount of work done by the car engine if it is 100% efficient:
Mathematically, the work done by an object with respect to power and time is given by the formula:
[tex]Work\;done = \frac{Power}{time}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = \frac{22000}{60}[/tex]
Work done = 366.67 Joules.
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What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2? ____________________
The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.
EQUATION OF MOTION:
The final velocity of a moving object can be calculated by using one of the equations of motion as follows:
V = u + at
Where;
V = final velocity (m/s)u = initial velocity (m/s)a = acceleration (m/s²)t = time (s)According to this question,
t = 5sa = 4.3m/s²u = 0 m/s (at rest)v = ?v = 0 + 4.3(5)
v = 21.5m/s.
Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.
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A 2.0 kg block rests on a level surface. The coefficient of static friction is, and the coefficient of kinetic friction is A horizontal force, X, is applied to the block. As X is increased, the block begins moving. Describe how the force of friction varies as X increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of X―before the block starts moving, at the point it starts moving, and after it is moving. Show your work.
ps. I had to change F to X because of brainly.
By Newton's second law, the net force acting on the block in the vertical direction is
∑ F [ver] = n - mg = 0
where n = magnitude of normal force and mg = weight of the block. It follows that n = mg.
When the block is at rest, the applied force X will not be enough to move the box until it can overcome the maximum mag. of static friction. If µ[s] is the coefficient of static friction, then the maximum mag. of the frictional force is
f = µ[s] n = µ[s] mg
The net horizontal force would be
∑ F [hor] = X - µ[s] mg = 0
so a minimum force of X = µ[s] mg is required to get the block moving. Any mag. smaller than this and the block stays at rest/in equilibrium.
Once the mag. of X exceeds µ[s] mg, the block will begin to move. At that point, if the coefficient of kinetic friction is µ[k], then the net force on the block is
∑ F [hor] = X - µ[k] mg = 0
so a minimum force of X = µ[k] mg would be needed to keep the block moving at constant speed, or otherwise X = µ[k] mg + ma if the block is accelerating with mag. a.
The principles here are captured in the attached plot.
what's the mass of the star rasalas?
Answer: The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg.
Explanation:
Answer:
The Rasalas's solar mass is 1.50 times that of our star, the Sun. The Sun's Mass is 1,989,100,000,000,000,000,000 billion kg. which to calculate using this website is too large. To give idea of size, the Sun is 99.86% the mass of the solar system.
Explanation:
will give brainlyiest what is the main need or want this wave technology meets to efficiently communicate with others to hear and see others in real time to efficiently store and share music with others to speak with and see others who are far away
Answer: To see objects surrounding more clearly
Explanation:
ork is done if a boat has a force 60N and travels 600 meters
I really need the Formula, substitute, answer
Answer:
This is the answer.
Explanation:
is this right?
Grass, trees, shrubs, worms, birds, and deer that live in a certain area is known as what?
Answer:they live in grass land also called forests hope the answer helps
Explanation:
Part Two: Criteria, Constraints, and Prioritizations
1. Choose one sub-problem that you will investigate further and explain which one you chose here.
o
2. List two realistic criteria for the sub-problem.
o
o
3. Explain why it is important for these criteria to be met in order to solve the problem.
o
4. List two constraints for the sub-problem.
o
o
5. Explain why these constraints exist. (How do they limit solutions to the problem?)
o
6. Prioritization of the criteria and constraints and an explanation supporting the decisions made based on research.
PLEASE HELP ME I DONT UNDERSTAND<333
Answer:
Usually, a solution can have several criteria and constraints. Even though all are important, some criteria are more important than others. The same holds true for constraints. But what do you do if it's impossible for a solution to cover every criterion while avoiding every constraint? In cases like this, you can use prioritization. Listing criteria and constraints based on priority shows the relative importance of each. You will need to prioritize the criteria and constraints for each sub-problem so that you can design a solution for each one individually. Prioritization can help you compare two different possible solutions. For example, the criterion that cars travel at 15 mph through the neighborhood might be a higher priority than the constraint that homeowners are only willing to spend $10,000 on this issue. If this is the case, you would want to generate solutions that also follow the priority in mind. All criteria are important, but engineers must sometimes make a trade-off, which is a compromise or change in one or more criteria or constraints so that they can be met at the same time. This is where prioritization comes in handy as it helps determine the trade-offs. A solution that is doing a better job of meeting one criterion may result in not completely meeting another criterion. Prioritization will help you choose which solution to go with.
Explanation:
I got this from quizlet :)
A student holds an egg outside of an open window and let's go. The window is 40 meters above the ground and the egg is falling under the acceleration of gravity, which is 9.8 m/s2. There are two equations that can be used to describe its motion over time:
How far will the egg travel after 2 seconds? Be sure to use the 5 steps to solve the problem. Show which equation you used, what each variable equals, and answer the question in a complete sentence.
The distance traveled by the egg after 2 seconds is 19.6 m.
The given parameters:
Height of the window, h = 40 mThe distance traveled by the egg after 2 seconds is calculated as follows;
[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\[/tex]
where;
[tex]v_0_y[/tex] is the initial vertical velocity of the egg = 0g is acceleration due to gravity = 9.8 m/s²t is the time of motion, = 2 s[tex]h = 0 \ + \ \frac{1}{2} \times 9.8 \times (2)^2\\\\h = 19.6 \ m[/tex]
Thus, the distance traveled by the egg after 2 seconds is 19.6 m.
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Describe the relative energies of particles in the
different States of matter.
Answer:
MATTER
ARE
OF
THREE
TYPES
SOLID
LIQUID
GAS
A student noted that the sign shown here is always associated with a wheelchair ramp at or near a staircase or entrance steps. What statement best identifies the reason why wheelchair ramps are used to move people up a staircase or steps?
The main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.
Let the height of the staircase = hLet the length of the ramp = L
The mechanical advantage of the ramp is calculated as follows;
[tex]M.A = \frac{L}{h}[/tex]
As the length of the ramp increases, people will be move up to a greater distance up the staircase.
Thus, the main reason why wheelchair ramps are used to move people up a staircase is because it has a high mechanical advantage which leads to a greater efficiency in moving people up the staircase.
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If you were traveling 60 mph and not wearing a seatbelt and collided with a fixed object, how fast would you be traveling when you hit the windshield
Your speed when your car hits a fixed object is 60 mph.
The given parameters:
Your initial speed, v = 60 mphWhat is relative velocity?Relative velocity tells us how fast we are traveling from a fixed point or reference point.
When travel at 60 mph in a car, you are moving at the same rate with the car.If you are not wearing a seat belt, when you hit a fixed object, you will move forward at the same rate as the car's speed.Thus, we can conclude that your speed when your car hits a fixed object is 60 mph.
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a 10 mh inductor is connected in series with a 10 ohm resistor, a switch and a 6 v battery. what is the time constant of the circuit
Answer:
The inductive time constant is just T = L / R
T = 10E-3 henry/ 10 ohm = 10E-2 sec = .1 sec
(.01 / 10 = .1)
Maria drove 100 miles in 2 hrs. what was marias speed?
9- Under what circumstances would a vector have components that are equal in
magnitude?
a. if the vector is oriented at 45° from the axes.
b. if the vector is oriented at 90° from the axes.
c. if the vector is oriented at 0° from the X -axis.
d. if the vector is oriented at 0° from the y-axis.
itude of 30 units Vector B is perpendicular to vector A
Explanation:
c. if the vector is oriented at 0° from the X -axis.
if a 5kg ball is traveling at 20 m/s and it’s stopped in 4s, what’s the impulse on the ball?
why does the earth get more energy from the sun than from all the other stars in the universe combined
Answer:
Explanation:
The sun is much closer than the other stars
What is the energy of a 5 kg object that is held at a height of 3 m above the ground?
I really need the Formula, substitute, answer
Answer:
a 5 kilogram mass, at a height of 3 meters, while acted on by Earth's gravity would have 147.15 Joules of potential energy, PE = 3kg * 9.81 m/s2 * 5m = 147.15 J.
Explanation:
A wave has a frequency of 2700 Hz and λ of 6m. Calculate the speed of the wave.pls help
Answer:
16,200 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question
c = 2700 × 6 = 16,200
We have the final answer as
16,200 m/sHope this helps you
Calculate amount of current flowing in wire if number of charge is 8 and e = 1.69 x10^-19 , t= 8millsec
The amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
From the question,
We are to calculate, the amount of current flowing in the wire.
From the formula,
[tex]I =\frac{nQ}{t}[/tex]
Where I is the current
n is the number of charge
Q is the quantity of charge
t is the time
From the given information
n = 8
Q = e = 1.69 × 10⁻¹⁹ C
t = 8 msecs = 8 × 10⁻³ sec
Putting the parameters into the formula, we get
[tex]I = \frac{8 \times 1.69 \times 10^{-19} }{8\times 10^{-3} }[/tex]
[tex]I = 1.69 \times 10^{-16} \ A[/tex]
Hence, the amount of current flowing in the wire is 1.69 × 10⁻¹⁶ A
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Which of the following rivers flows north in eastern Florida?
St. James
St. Johns
Mississippi
Hudson
St. John’s
_________
o0o0o0o0o0
A calculator of mass 0.11 kg is lowered from a bookshelf that is 1.6m above the floor to a desk that is 0.85m above the floor. What's the change in GPE?
Answer:
I think it would be 0.1496 but I'm not really sure sorry
What is velocity? Explain.
Answer:
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is ____?
[tex]\purple{ \longrightarrow \bf{h_m = \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} }} [/tex]
Projectile is thrown with a velocity = v Angle of projection = θVelocity of projectile at a height half of the maximum height covered be [tex] \sf{v_0}[/tex][tex]\qquad[/tex]______________________________
Then –
[tex]\qquad[/tex] [tex]\pink{ \longrightarrow \bf{ \dfrac{h_m}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }}[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2g} \times \dfrac{1}{2} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{4g} = \dfrac{ {v_0}^{2} \: {sin}^{2} \theta }{2g} }[/tex]
[tex]\qquad[/tex][tex]\longrightarrow \sf{ \dfrac{ {v}^{2} \: {sin}^{2} \theta }{2} = {v_0}^{2} \: {sin}^{2} \theta }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \sf{ \dfrac{ {v}^{2} }{2} = {v_0}^{2} }[/tex]
[tex]\qquad[/tex][tex] \longrightarrow \bf{v_0 = \sqrt{ \dfrac{ {v}^{2} }{2} } = \dfrac{v}{ \sqrt{2} } }[/tex]
Now, the vertical component of velocity of projectile at the height half of [tex] \sf{h_m}[/tex] will be –[tex]\qquad[/tex] [tex]\longrightarrow \bf{v_{(y)}=v_0 \: sin \theta }[/tex]
[tex]\qquad[/tex] [tex] \longrightarrow \bf{v_{(y)} = \dfrac{v}{ \sqrt{2} } \: sin \theta = \dfrac{v \: sin \: \theta}{ \sqrt{2} } }[/tex]
Therefore, the vertical component of velocity of projectile at this height will be–
☀️[tex]\qquad[/tex][tex] \pink {\bf{ \dfrac{v \: sin \: \theta}{ \sqrt{2} }} }[/tex]
Answer:
A projectile is thrown with velocity v at an angle θ with horizontal. When the projectile is at a height equal to half of the maximum height, the vertical component of the velocity of projectile is v sintheta / √2