Substitute equation (2) into (1) to give a new equation for p that involves only I and R

Re arrange (2) to make I the subject, and substitute your result into equation (1) to give a new equation containing only V and R

Answer:

[tex]{ \tt{average \: speed = \frac{distance}{time} }} \\ \\ { \tt{ = \frac{(6 \times 1000) \: m}{(50 \times 60) \: s} }} \\ \\ { \tt{ = \frac{6000}{3000} }} \\ \\ = { \underline{ \tt{ \: 2 \: {ms}^{ - 1} \: }}}[/tex]

You walk from chisale to st Francis a distance of 6km/h and 50minutes,  the average speed in m/s​ will be 2m/s

The average speed of a moving object is defined as the total distance covered by it divided by the total time taken.

The S.I unit of speed is meter per second. Speed is also measured in kilometer per hour.

Average speed is a scaler quantity

Average speed is the total distance travelled by an object to the total time taken. However, average velocity is the change in position or displacement (∆x) divided by the time intervals (∆t) in which the displacement occurs. No matter how many times the speed has been changed to travel the entire distance , average speed is that constant speed value with which one can travel by and reach the same distance in same amount of time .

It can be calculated with a formula average speed = distance / time

given

distance = 6 km = 6000 m

time = 50 minutes = 50 * 60 = 3000 sec

average speed = distance / time

                          = 6000 / 3000 = 2m/s

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We have that the more energy per second to radiated by the hotter  is mathematically given as

Energy per second=256

Question Parameters:

One star has a temperature of 20,000 K

and another star has a temperature of 8,000

Generally the equation for the Energy per second   is mathematically given as

Energy per second is Proportional to T^4

Where

T=20000/8000

T=4

therefore

Energy per second=4^4

Energy per second=256

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Given :-

To Find :-

Solution :-

As the man is in a accelerated frame that is non inertial frame , we would have to think of a pseudo force .

For the FBD refer to the attachment . From that ,

[tex] \implies Weight_{apparent}= mg + ma [/tex]

Hence option d is correct choice .

I hope this helps .

Electric wires/cables expand when temperature rises l

If the mass of an object is halved and its velocity remains the same, its momentum will be halved.

Momentum is the quantity of motion of a moving body, measured as a product of its mass and velocity.

We can calculate the momentum of an object using the following expression.

p = m × v

where,

The initial momentum of the object is:

p₁ = m₁ × v₁

If its mass is reduced by half but its velocity remains the same, the new momentum is:

p₂ = m₂ × v₁ = 0.5 m₁ × v₁ = 0.5 p₁

If the mass of an object is halved and its velocity remains the same, its momentum will be halved.

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The law of conservation energy

PE₁ + KE₁ = PE₂ + KE₂

From rest ⇒ v₁ = 0 ⇒ KE₁ = 0

Input the value:

PE₁ = PE₂ + KE₂

[tex]\tt mgh_1=mgh_2+\dfrac{1}{2}mv_2^2\rightarrow divide\:m\\\\gh_1=gh_2+\dfrac{1}{2}v_2^2\\\\9.8(1.226-0.126)=\dfrac{1}{2}v_2^2\\\\v_2=4.64\:m/s[/tex]

The crumple zone help protect a passenger from injury by converting some of the kinetic energy possessed by the car into a controlled deformation, or crumpling when there is a crash.

The term impact refers to a large force that acts for a short time. Passengers in a vehicles sustain injuries after an accident due to the high impact of the crash.

As such, the crumple zone help protect a passenger from injury by converting some of the kinetic energy possessed by the car into a controlled deformation, or crumpling when there is a crash.

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Answer:

It is -7.0 m/s2

Explanation:

Just did it

A baseball of mass 0.145 kg is thrown with the force of 0.4 N then the acceleration of the baseball will be equal to 2.8 m/s².

The rate of change in an object's velocity concerning time is known as acceleration in mechanics. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

Since acceleration has both a magnitude and a direction, it is a vector quantity. Velocity is a vector quantity as well. The definition of acceleration is the change in velocity vector over a time interval divided by the time interval.

As per the instructions given in the question,

Force, f = 0.4 N

Mass, m = 0.145 kg

F = ma

a = f/m

a = 0.4/0.145

a = 2.8 m/s².

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Answer:

Yes, they will also have the same acceleration. Acceleration is controlled by the amount of weight (def. amount of gravitational pull on a given object) that the ball has. For one ball to accelerate quicker than the other, it would need a propulsion element, which it does not.

Explanation:

Answer:

When two balls are equally weighted, no matter where they are placed on a ramp, they will travel at the same speed. One will just reach the ground quicker.

Explanation:

Hi there!

Given the values for α and β, we can plug these into the given equation:

[tex]v(t) = 4t - 2t^2[/tex]

Begin by solving for the velocity at t = 0 and t = 3:

At t = 0:
[tex]v(0) = 4(0) - 2(0^2) = 0 \frac{m}{s}[/tex]

At t = 3:
[tex]v(3) = 4(3) - 2(3^2) = 12 - 18 = -6 \frac{m}{s}[/tex]

Acceleration is the SLOPE of the velocity graph (its derivative), so we can use the kinematic equation:

[tex]a = \frac{v_f - v_i}{\Delta t}[/tex]

Plug in the knowns:

[tex]a = \frac{-6-0}{3 - 0} = \boxed{-2 \frac{m}{s^2}}[/tex]

Answer:

0.46 m. hope this helps.

Answer:

0.46 Meters

Explanation:

Answer:

About 6 feet or higher is recommended.  

Explanation

Answer:

maximum height =  46m

Explanation:

Vx = 20m/s

Vy = 30 m/s

gravity = 9.8 m/s/s

final velocity = initial velocity - gravity • time

0 = 30m/s - 9.8m/s/s • time

subtract 30m/s from both sides

-30m/s = - 9.8m/s/s • time

divide both sides by -9.8m/s/s

3.06 s = time

height =  initial velocity • time - 1/2 • gravity • time^2

height = 30m/s • 3.06s - 1/2 • 9.8m/s/s • 3.06s ^2

height = 46m

the maximum height is equal to 46m

Answer:

600 watts

Explanation:

Answer:

speed = wavelength * frequency

Explanation:

speed = wavelength * frequency

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

Answer:

Friction drag force causes objects to slow down as they move through a fluid, such as air or water. ... As an object's speed increases, the drag force from the fluid increases exponentially. • For example, when you drive at high speeds, the frictional force of air on the car increases, and fuel economy decreases.

Answer:

after it has hit the ground

.........

Answer: A. after it has hit the ground

The value of time needed to complete the upward and the downward motion is, T=5sec .T is the time at which the ball first hits the ground.

The time period is found as the ratio of the displacement and the velocity. Its unit is second and denoted by t

The given data in the problem is;

The time required to move upwards is,t₁

The time required to move downwards is,t₂

The distance traveled is,s= 19.6m

The gravitational acceleration is, g=9.81 m/s

At the highest position, the velocity of the ball is zero;

The time required to move upwards is found as;

[tex]\rm S_1 = ut + \frac{1}{2} at^2 \\\\ \rm S_1 = \frac{1}{2} (-g)t_1^2 \\\\ t_1= \sqrt{\frac{2S_1}{g} } \\\\ t_1= \sqrt{\frac{2 \times 19.6 }{9.81} } \\\\ t_1= 2 \ sec[/tex]

The time required to move downward is found as;

[tex]\rm S_2 = ut + \frac{1}{2} at_2^2 \\\\ \rm S_1 = \frac{1}{2} (-g)t_2^2 \\\\ t_2= \sqrt{\frac{2S_2}{g} } \\\\ t_2= \sqrt{\frac{2 \times 44.1 }{9.81} } \\\\ t_2= 3 \ sec[/tex]

The total time period is the sum of the time required to move upwards and the time required to move downwards.

T =t₁+t₂

T=2+3

T=5 sec

Hence the value of T will be 5 sec.

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Explanation:

ndndndndnndndndndndndndnndndnd

Answer:

teysyshnk

Explanation:

Answer:

M = V ρ = .03 * .2*2 cm^3 * 2.75 g / cm^3 = .0033 kg     weight

W = m g = .0033 kg * 9.80 m / s^2 = .032 N

P = F / A = W / A = .032 N / .2^2 m^2 = .80 N/m^2 = .80 Pascal

Answer:

Electrical energy and Chemical energy

Explanation:

Good luck on the quiz dawg, I'm doing the same one LOL

Answer:

787, 500 N/m

Explanation:

Work = Force • displacement

[tex]Work = (3500 N)(225 m) = 787500\frac{N}{m}[/tex]

[tex]W = (3500 N)(225 m) = 787500\frac{N}{m}[/tex]

Answer:

The field and winding

Explanation: they are both connected

Answer:

potential difference

= m × g × h

= ( 2 × 10 × 3 )

= 60 Joules

Answer:

PE = 60 J

Explanation:

Where:

PEg or PE = gravitational potential energy

m = mass of an object

g = acceleration due to gravity

h = height of the object

brnaliest

8Ω, 9Ω, xΩ are in series

[tex] \therefore \: R _{1} = 8 + 9 + x = (17 + x)Ω[/tex]

3Ω and 5Ω are in series

[tex] \therefore \: R _{2} = 3+ 5 = 8Ω[/tex]

Now equivalent resistance of R1 and R2 which are parallel in R3 = 6Ω

[See The Attachment]

[tex] \therefore \frac{1}{R _{3}} = \frac{1}{R _{1}} + \frac{1}{R _{2}} \\ \\ \therefore \: \frac{1}{6} = \frac{1}{(17 + x)} + \frac{1}{8} \\ \\ = \frac{1}{17 + x} = \frac{1}{6} - \frac{1}{8} = \frac{1}{24} \\ \\ \therefore17 + x = 24 \\ x = 24 - 17 = 7 \\ x = 7Ω[/tex]

Hope This Helps!!

The value of the resistance X is 7 ohms.

The equivalent resistance in series is calculated as follows;

R₁ = 8 + 9 + x = 17 + x

R₂ = 3 + 5 = 8

The equivalent resistance in the circuit is calculated as follows;

[tex]\frac{1}{R} = \frac{1}{R_1}+ \frac{1}{R_2} \\\\R = \frac{R_1 R_2}{R_1 + R_2} \\\\[/tex]

[tex]R(R_1 + R_2 ) = R_1 R_2[/tex]

6(17 + x + 8) = 8(17 + x)

150 + 6x = 136 + 8x

14 = 2x

x = 7

Thus, the value of the resistance X is 7 ohms.

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Answer:

I think that protection of one species can not protect its community.

Explanation:

The advantage of protecting entire ecosystems is the most effective way to save species because species confined to a small area could be wiped out by a single natural disaster. Some species require a large range to find adequate food or mate. Therefore, protecting the habitats of endangered and threatened species often means preserving or managing large areas (entire ecosystem).

The maximum compression of the spring is 0.146 m.

The work done by the block when it slides down the ramp will be converted to elastic potential energy of the spring.

W = U

Fd = U

where;

mgsin(θ) x d = ¹/₂kA²

[tex]A^2 = \frac{2mg sin(\theta)d}{k} \\\\A = \sqrt{\frac{2mg sin(\theta)d}{k}} \\\\A = \sqrt{\frac{2(5 \times 9.8) sin(30)\times 1.3}{3\times 10^3}}\\\\A = 0.146 \ m[/tex]

Thus, the maximum compression of the spring is 0.146 m.

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