Suppose a cylinder that holds 3 L of liquid must be created. Determine the radius and height of the cylinder that will minimize the amount of material used in its construction.(Note: 1 L=1,000 cm^3)
Answers
The radius and the height of the dimension that will minimize the amount of material used in the construction are [tex]\mathbf{r = \sqrt[3]{\dfrac{1500}{\pi}} }[/tex] and [tex]\mathbf{h = \dfrac{3000}{\pi ({\dfrac{1500}{\pi}} )^{2/3}}}[/tex] respectively.
How to find the dimension that minimizes a cylinder?The dimension that minimizes the surface area of a cylinder can be determined by:
Drawing the picture of the problem, Write down & identify optimization as well as the constraint equations;Use the derivative of the optimization equation to find the dimensions.Given that:
1 L = 1000 cm³3 L = 3000 cm³The area of the cylinder = (2 πr)h + 2(πr²)
A = 2πrh + 2πr²The volume of the cylinder
V = πr²hLet's identify the constraint equation and Optimization equation:
To minimize the surface area of the can, we have:
Area equation = Optimization equationThe constraint equation is the equation that limits us:
Volume equation = constraint equationSo, Let's solve for h in our volume equation, we have:
3000 = πr² h
h = 3000/πr²
Now, from the Area equation
[tex]\mathbf{A = 2 \pi r(\dfrac{3000}{\pi r^2}) + 2\pi r^2}[/tex]
Taking the derivate and setting it to zero, we have;
Derivative:
[tex]\mathbf{A = \dfrac{6000}{ r}+ 2\pi r^2}[/tex]
[tex]\mathbf{A = 6000 r^{-1} + 2\pi r^2}[/tex]
[tex]\mathbf{A' = -6000 r^{-2} + 4\pi r}[/tex]
[tex]\mathbf{A' = 4\pi r-\dfrac{6000}{ r^{2} }}[/tex]
Setting it to zero, we have:
[tex]\mathbf{0=\dfrac{ 4 \pi r^3 - 6000}{r^2}}[/tex]
Factor out 4
0 = 4(πr³ - 1500)
1500 = πr³
r³ = 1500/π
[tex]\mathbf{r = \sqrt[3]{\dfrac{1500}{\pi}} }[/tex]
The above is the radius that minimizes the surface area of the cylinder;
From [tex]\mathbf{h = \dfrac{3000}{\pi r^2}}[/tex]
[tex]\mathbf{h = \dfrac{3000}{\pi ( \sqrt[3]{\dfrac{1500}{\pi}} )^2}}[/tex]
[tex]\mathbf{h = \dfrac{3000}{\pi ({\dfrac{1500}{\pi}} )^{2/3}}}[/tex]
Thus, the radius and height that minimize the amount of material to be used in its construction are [tex]\mathbf{r = \sqrt[3]{\dfrac{1500}{\pi}} }[/tex] and [tex]\mathbf{h = \dfrac{3000}{\pi ({\dfrac{1500}{\pi}} )^{2/3}}}[/tex] respectively.
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Related Questions
julie buys a bike for $2700 and sells it a year later, making a 15% profit
How much profit did Julie make?
Answers
Answer:
$405.
Step-by-step explanation:
That would be 15% of $2700
= 2700 * 0.15
= $405
If 15% of the length of rope is 75cm what is half of the length of rope
Answers
Answer:
250 cm.
Step-by-step explanation:
Half = 50% so by proportion:
Half length of the rope = 75 *50/15
= 250
Answer:
250 cm
Step-by-step explanation:
15% to decimal:
15% = 15/100 = 0.15
Then, half of the lenght of rope is:
[tex](\frac{75}{0.15}) /2=500/2 = 250[/tex]
Hope this helps
A radio státlon réports news and weather
every 20 minutes for 4 minutes, if the
radlo is turned on at a random time, what
is the probabllty that the news
and weather report is NOT on?
E 0.2
H 0.6
G 0.4
J 0.8
Answers
[tex] \huge \tt \color{pink}{A}\color{blue}{n}\color{red}{s}\color{green}{w}\color{grey}{e}\color{purple}{r }[/tex]
[tex] \large\underline{ \boxed{ \sf{✰\:Note }}}[/tex]
➣ Timing of ràdiò station reporting news and weather is every in 20 minutes for 4 minutes➣ Probability :- An event that is likely to occur also A number, between 0 and 1, expressing the precise likelihood of an event happening.➣Denoted by :- P(A)[tex] \rule{70mm}{2.9pt}[/tex]
★ To find ★ ➣ we have to find Probability when news and weather report is not on ➣ we know that Probability[tex]{ \boxed{✠ \: \underline{ \boxed{ \sf{\: P(A) = \frac{Number \: of \: favourable \: outcomes}{Total \: number \: of \: favourable \: outcomes} }}} \: ✠}}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
✛ Here ✛
➣ Number of favourable outcomes = 4 min➣ Total number of favourable outcomes = 20 min➣ and P(A) = x ★ Now let's solve according to formula ★[tex] \qquad \sf \:➛ \: x = \frac {4 }{20} \\ \qquad \sf \:➛ \: x = \frac { \cancel4 }{ \cancel{20}} \\ \qquad \sf \:➛ \: x = 0.2min[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
★ Hence probabllty that the news and weather report is NOT on P(A)
[tex] \qquad \qquad{ \boxed{✟\: \underline{ \boxed{ \sf{\:0.2min\green ✓ }}} \:✟ }}[/tex]
[tex] \rule{70mm}{2.9pt}[/tex]
Hope it helps !
Three faces of a rectangular prism have areas 32 cm?, 40 cm?, and 20 cm? a) find the surface area of the prism. b) what are possible dimensions of the prism? how do you know? c) sketch and label the prism.
Answers
Answer:
Surface Area: 5440
Step-by-step explanation:
Volume: 25600
Surface Area: 5440
Work Volume
V = lwh
V = (32)(40)(20)
V = 25600
Work Surface Area
A = 2(wh + lw + lh)
A = 2( 40(20) + 32(40) + 32(20) )
A = 2(800 + 1280 + 640)
A = 2(2720)
A = 5440
The diagonal : 54.99
Which of the following represents the translation of R (-3, 4) along the vector
<7, -6> and then the vector < -1, 3 >?
Pls help lol
Answers
By applying concepts of linear algebra, the point P'(x, y) = (-3, 4) represents the translation of P(x, y) = (-3, 4) along the vectors <7, -6> and <-1, 3>.
How to determine the resulting point by applying translations
Translations are a kind of rigid transformation. A transformation is rigid if and only if Euclidean distances are conserved. By linear algebra, an image as a consequence of consecutive translations is described by the following formula:
[tex]P' (x,y) = P(x,y) + \left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)[/tex] (1)
Where:
P(x, y) - Original pointP'(x, y) - Image[tex]\left(\sum\limits_{i=1}^{n}x_{i}, \sum\limits_{i=1}^{n}y_{i}\right)[/tex] - Net translation vectorNow we proceed to determine the image of the given point:
P'(x, y) = (-3, 4) + (7, -6) + (-1, 3)
P'(x, y) = (-3 + 7 - 1, 4 - 6 + 3)
P'(x, y) = (3, 1)
By applying concepts of linear algebra, the point P'(x, y) = (-3, 4) represents the translation of P(x, y) = (-3, 4) along the vectors <7, -6> and <-1, 3>.
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When 1,250 superscript three-fourths is written in its simplest radical form, which value remains under the radical?
Answers
The number that still remains under the radical when the expression is in its simplest form is 8.
What is a radical?
A radical refers to a root form. In this case, we can write this number as; 1,250^3/4.
If we try to simplify this in line with the laws of indicies, we have; 4√(1250)^3. If we simpify further, we obtain; (125)4√8.
Thus, the number that still remains under the radical when the expression is in its simplest form is 8.
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Find the solutions to x² = 12.
O A. x = +2√3
OB. x=+5√2
X
C. x= +2√5
OD. x = 13√2
Answers
Answer:
[tex]x = \pm 2\sqrt3[/tex]
Step-by-step explanation:
Hello!
Let's use the square root property to solve this question
Solve:
[tex]x^2 = 12[/tex][tex]\sqrt{x^2} = \sqrt{12}[/tex][tex]x = \pm\sqrt{12}[/tex][tex]x = \pm \sqrt{4 * 3}[/tex][tex]x = \pm 2\sqrt3[/tex]The answer is option A: x = ±2√3
What is the equation for an arithmetic sequence with a first term of 7 and a second term of 3? (5 points)
an = 7 − 4(n − 1)
an = 7 + 4(n − 1)
an = 7 − 3(n − 1)
an = 7 + 3(n − 1)
Answers
Answer:
1st option
Step-by-step explanation:
the equation for an arithmetic sequence is
[tex]a_{n}[/tex] = a₁ + (n - 1)d
where a₁ is the first term and d the common difference
here a₁ = 7 and d = a₂ - a₁ = 3 - 7 = - 4 , then
[tex]a_{n}[/tex] = 7 - 4(n - 1)
Answer:
The answer is option A
Step-by-step explanation:
The solution is in the image
the pair of figures to the right are similar. what is the ratio of the perimeters and the ratio of the areas?
the ratio of perimeters is __
the ratio of the areas is __
Answers
Answer:
the ratio of perimeters is 3/5
the ratio of areas is 9/25
Step-by-step explanation:
first we divide the given sides of both figures
perimeter=side 1/side 2
=15/25
p=3/5
to find the ratios of the area
=(side 1/side 2)^2
=(3/5)^2
=9/25
Answer:
the ratio of perimeters is 3/5
the ratio of areas is 9/25
12.4 worksheet mathematics
Answers
Answer:
ok. Where is the Question
A region with a 10-mile radius has a population density of about 1500 people per square mile. Find the number of people who live in the region to the nearest ten thousand.
The number of people who live in the region is about
.
Answers
The number of people who live in the region to the nearest ten thousand will be 942000.
What is population density?
The number of the people live in the given volume is known as the population density.
(r)Region radius= 10 miles
Population density= 1500 per square mile
The area of the region is found as;
A=2πR²
A= 2π(10 x 10)
A=2(3.14) (100)
A= 628 square miles
Population density= Population/Area
1500= Population / 628 square miles
Population = 1500 x 628
Population = 942000
Hence,the number of people who live in the region to the nearest ten thousand will be 942000.
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The number of siblings for a group of sixth grade students is shown below:
0, 1, 2, 1, 6, 0, 2, 0, 1, 10
Answers
area of a circle radius 12
Answers
Answer: 3.14 x 12^2 = 452.16
Answer: 144π
Decimal Form: 452.389 (Not Rounded)
Dan had $34 to spend at the fair if the admission to the fair is $10 and the rides cost $1.50 each, what is the greatest number of rides dan can go on. write an inequality that represents dan's situation
Answers
Answer:
Equation: 1.50x + 10 [tex]\leq[/tex] 34
Amount of rides Dan can go on: 16 rides
Step-by-step explanation:
We can represent this situation using this equation:
1.50x + 10 [tex]\leq[/tex] 34
The $10 Dan has to pay as admission is the fixed number because it doesn't vary and always remains the same, so no x goes next to 10.
Each ride costs $1.50 so this is the variable number as it changes with how many rides Dan goes on, therefore an x will go next to 1.50 to represent the amount of rides Dan goes on.
Lastly, Dan has $34 to spare, so the amount spent has to be less than or equal 34.
Solve the equation for x to find the greatest amount of rides Dan can go on:
1.50x + 10 [tex]\leq[/tex] 34 Subtract 10 from 34
1.50x [tex]\leq[/tex] 24 Divide 24 by 1.50
x [tex]\leq[/tex] 16
So, Dan has enough money to go on 16 rides or less.
Let's check this answer:
1.50(16) + 10 [tex]\leq[/tex] 34 Multiply 1.50 by 16
24 + 10 [tex]\leq[/tex] 34 Add 24 and 10
34 [tex]\leq[/tex] 34
Hope this helps! Good luck and if you have any questions let me know in the comments!
NEED HELP ASAP 50 POINTS PLEASE ANSWER CORRECTLY!!!! I have 3 round stock tanks. I want to use the one with the largest volume in my cow- calf pasture. (That's where my cows that are having calves are held.) I want to use the one with the smallest volume in the corrals with the horses. It is easier to fill it when necessary. I don't mind running the hose on it everyday. I want to use the tank with the mid-sized volume in my bull pasture. I have 15 bulls for sale. I have people come by everyday so the number of animals in that pasture will go down. Please match the correct tank with the correct pasture. Mid-Sized tank. Bull Pasture 1. Tank 1: 3' tall, 10' diameter Smallest Tank. Horse/Corral Tank 2. Tank 2: 2' tall, 12' diameter + 3. Tank 3: 1.5' tall, 15' diameter Largest Tank. Cow-Calf Pasture Question 20 (10 points)
Answers
Answer:
Largest: 3
Smallest: 2
Mid-Sized: 1
Step-by-step explanation:
y=1/2x+1
how do i graph this?
Answers
Answer: Heyaa! ~
Graph the line using the slope and y-intercept, or two points.
Slope:
1/2
y-intercept: (0,1)
x ↓ y
0 ↓ 1
2 ↓ 2
Step-by-step explanation:
Hopefully this helps you! ~
Answer:
Use the Desmos graphing calculator. Look up "graphing calculator" and hit the Desmos option, then type in your equation. It works.
Please mark me Brainliest!!!
Tim tried to use Cavalieri's principle to show that the two figures have the same volume.
"The base areas are the same. Therefore, corresponding cross-sections have the same area. So the volumes must be the same."
What is the first mistake Tim made?
Answers
Answer:
The base areas aren't same
Step-by-step explanation:
The base areas arent same
Answer:
He did not establish that heights are the same.
What is the answer please?
Answers
Answer:
The figures are not similar. If the purple rectangle were to get a transformation, then it would grow. For it to be
Step-by-step explanation:
If the purple rectangle were to get a transformation, then it would grow. For it to be similar it would be stretched one way to be as long as the green rectangle, but that's not how this works. Therefore, they are not similar.
Hope this helps <3
For a particular peculiar pair of dice, the probabilities of rolling 1, 2, 3, 4, 5, and 6 on each die are in the ratio $1:2:3:4:5:6$. What is the probability of rolling a total of 7 on the two dice
Answers
Step-by-step explanation:
$ 1: 2: 3: 4: 5: 6: 7: 7: in ratio
probability on two dice
1, 2, 3, 4, 5, 6, 7, 7.
The probability of rolling a total of 7 on the two dice is 8/63 if in the particular peculiar pair of dice, the probabilities of rolling 1, 2, 3, 4, 5, and 6 on each die are in the ratio 1:2:3:4:5:6.
What is probability?It is defined as the ratio of the number of favourable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
Let x be the probability of rolling a 1.
Ratios are 1:2:3:4:5:6
Then,
x + 2x + 3x + 4x +5x + 6x = 1
21x = 1
x = 1/21
The possible combinations of two rolls that total 7 are:
{(1,6) ; (2,5) ; (3,4) ; (4,3) ; (5,2) ; (6,1)}
The probability P of rolling a total of $7$ on the two dice is equal to the sum of the probabilities of rolling each combination.
[tex]\rm P = \dfrac{1}{21}\cdot\dfrac{6}{21}+\dfrac{2}{21}\cdot\dfrac{5}{21}+\dfrac{3}{21}\cdot\dfrac{4}{21}+\dfrac{4}{21}\cdot\dfrac{3}{21}+\dfrac{5}{21}\cdot\dfrac{2}{21}+\dfrac{6}{21}\cdot\dfrac{1}{21}\\\\=\dfrac{8}{63}[/tex]
Thus, the probability of rolling a total of 7 on the two dice is 8/63 if in the particular peculiar pair of dice, the probabilities of rolling 1, 2, 3, 4, 5, and 6 on each die are in the ratio 1:2:3:4:5:6.
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explain the steps
for solving the following.
3√3+4√3
Answers
Answer:
[tex]7 \sqrt{3} [/tex]
Step-by-step explanation:
Simply combine like radicals:
[tex]3 \sqrt{3} + 4 \sqrt{3} = 7 \sqrt{3} [/tex]
Evaluate 2(5a – 2) a=3
Please solve
Answers
Answer:
26
Step-by-step explanation:
a=3
2(5x3-2)
5x3=15
15-2=13
2x13=26
The graph of a sinusoidal function intersects its midline at (0, -3) and then has a maximum point at
(2,-1.5).
Write the formula of the function, where x is entered in radians
Answers
The formula of the function when the graph is analyzed will be y =1.5sin[(pi/4)x] - 3.
How to explain the function?From the graph, the mid line is y = -3 and the amplitude will be:
= -1.5 - (-3)
= 1.5
From the mean line to the max is ¼ of a cycle. Therefore, the period will be:
= 4 × 2 = 8
Number of cycles in 2pi will be:
= 2pi/8
= pi/4
Hence, the formula of the function will be y= 1.5sin[(pi/4)x] - 3.
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Answer:
f(x)=1.5sin (pie/4 x)-3
Step-by-step explanation:
Kahn academy aproved
Two sets of data are each symmetrical and do not contain outliers. Which measures of center and
variability would be most effective to use when making comparisons between the two data sets?
A.
mean and MAD
B. mean and IQR
C. median and MAD
D. median and IQR
Answers
Solution:
As, two set of data are each symmetrical and do not contain outliers.
To find the center , the best way is to find Median of data set.Median of Data set is the mid value of Data that is center of Data.
As, you have to find variability , mean can't measure variability. Mean deviation would have been better option.
So, MAD=Median absolute Deviation , would be better tool to measure variability. Because it is Absolute difference between median and Each value of data set.
So, Option (C) median and MAD, would be best way to compare the two given data set.
What is the volume of a sphere with a diameter of 9.1 m, rounded to the nearest tenth of a cubic meter?
Answers
I need an answer to this:
Answers
Answer:
It will decrease cause there will be more deer. Deer eat blackberry bushes
Step-by-step explanation:
Answer:
It will decrease because there will be more deer
Step-by-step explanation:
Because of the lack of wolves, the deer population would increase. Since it would increase the amount of deer there would be less of the deer's food sources.
PLEASE HELP!!!!
y = 1.4 (1.02)
a =
b=
r(as a percentage)
Answers
Answer:
a = 1.4 then b = (1+0.02) and r = 2%
Walter wants to make 200 candles in the shape of a cone for his new candle business. The mold shown below will be used to make the candles. Each mold will have a height of 6 inches and a diameter of 2 inches. To the nearest cubic inch, what will be the total volume of 200 candles
Answers
Answer:
1256 cubic inches
Step-by-step explanation:
Volume of all 200 candles = volume of one mold × 200
Finding the volume of one mold:
We are given that the molds are in the shapes of cones and have a height of 6 inches as well as a diameter of 2 inches.
The volume of a cone can be calculated using the formula
V = πr²(h/3) where r = radius and h = height
Converting the diameter to radius
The volume of a cone formula requires the radius however we are only given the diameter. However we know that the radius is equal to half of the diameter or radius = diameter / 2
So if diameter = 2 then radius = 2 / 2 = 1 so r = 1
Plugging in the given values into the formula
V = πr²(h/3)
==> plug in r = 1 and h = 6 and π = 3.14 approximately
V = (3.14)1²(6/3)
==> simplify exponent
V = 3.14(1)(6/3)
==> divide 6 by 3
V = 3.14(2)
==> multiply 3.14 by 2
V = 6.28
Finding the volume of the 200 candles.
So we have calculated that the volume of one candle is about 6.28in³ and we want to find the volume of 200 of those candles.
To do so we simply multiply the volume of one of those candles by 200
So volume of 200 candles = 200 × 6.28 = 1256 cubic inches
23/2 as a mixed number
Answers
Answer:
11 1/2.
Step-by-step explanation:
23 / 2 = 11 remainder 1.
So it is 11 1/2.
Two teams, a and b, are about to play a game. previous records show that a has an 80% chance of winning, while b has a 20% of winning. spectators can either choose to buy regular tickets or special tickets. a spectator with a special ticket will receive a refund of $2 if team a wins and a refund of $5 if team b wins. how much extra, minimally, should the special ticket cost to cover the expected value of the refunds offered?
Answers
The special ticket cost to cover the expected value of the refunds would be $2.60
How to solve for the minimal extra cost.Probability of A winning = 80%
Probability of B winning = 20%
We have to solve for the rebate of the bet.
80% = 0.8, 20% = 0.2
0.8 x 2 = 1.6
0.2 x 5 = 1
The extra minimal cost of the special ticket would be calculated as: 1 + 1.6
= $2.6
Therefore the answer to the question is $2.6
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which number line shows -4 , 1,1 and 2 correctly plotted
Answers
Answer:
C
Step-by-step explanation:
The number line in option C contains the points -4, -1, 1 and 2 correctly plotted.
the answer is c :) lol it's the correct one I think