Suppose the gravitational force between two spheres is 30 N. If the magnitude of both masses doubles, and the distance between them tripled. What is the force between the masses?

Answers

Answer 1

If both masses double in size and their separation between them triples. 13..33 N will be the force between the masses.

What is gravitational force?

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

Gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

Given data:

The gravitational force = 30 N

Mass 1 =m₁

Mass 2=m₂

Distance between charges = R

Condition given:

Mass 1 = 2m₁

Mass 2= 2m₂

Distance  between charges = 3R

[tex]\rm F = \frac{Gm_1m_2}{R^2}[/tex]

Case 2;

[tex]\rm F'=\frac{G(2m_1)(2m_2)}{(3R)^2} \\\\ F'=\frac{4}{9} \frac{Gm_1m_2}{R^2} \\\\ F'=\frac{4}{9} F \\\\ F'=\frac{4}{9} \times 30 \\\\ F'=13.33 \ N[/tex]

Hence, the forces between the masses will be 13..33 N.

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Related Questions

CAN YALL GO FOLLOW MY INS PLSS yeabdagod ​

Answers

Answer:

just followed :)

Explanation:

easy one giving brainly if correct + detailed​

Answers

Answer:

to the substance being heated

calculate the density, in g/l, of sf6 gas at 27°c and 0.500 atm pressure.

Answers

The density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.

The given parameters:

temperature of the SF₆ gas, T = 27 ⁰C = 273 + 27 = 300 Kpressure of the SF₆ gas, P = 0.5 atm

The molecular mass of the SF₆ gas is calculated as follows;

M of SF₆ = 32 + (6 x 19) = 146 g/mol

The density of the SF₆ gas is calculated by applying ideal gas law as follows;

[tex]PV = nRT\\\\PV = \frac{m}{M} RT\\\\PM = \frac{m}{V} RT\\\\PM = \rho RT\\\\\rho = \frac{PM}{RT}[/tex]

where;

[tex]\rho[/tex] is the density of the gasR is the ideal gas constant = 0.0821 L.atm/mol.K

[tex]\rho = \frac{0.5 \times 146}{0.0821 \times 300} \\\\\rho = 2.96 \ g/l[/tex]

Thus, the density of the SF₆ gas at the given pressure and temperature is 2.96 g/l.

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Examples of energy conversion in daily life

Answers

Answer:

Energy conversion, also termed as energy transformation, is the process of changing one form of energy into another. Energy conversion occurs everywhere and every minute of the day. There are numerous forms of energy like thermal energy, electrical energy, nuclear energy, electromagnetic energy, mechanical energy, chemical energy, sound energy, etc. On the other hand, the term Energy Transformation is used when energy changes forms from one form to another. Whether the                                                                    energy is transferred or transformed, the total amount of energy doesn’t change and this is known as the Law of Conservation of Energy.

Explanation:

hope this   helps please give me brainly  have a great day (☞゚ヮ゚)☞(¬‿¬)( •_•)>⌐■-■ヾ(⌐■_■)ノ♪

4) An 873kg dragster, starting from rest, attains a speed of 26.3m/s in 0.590s.
A) What was the acceleration of the dragster?
B) What was the net force needed to accelerate the dragster?
C) Assume that the driver has a mass of 68.0kg. What horizontal force does the seat exert on
him?

Answers

Answer:

A.)a=44.57m/s

B.)f=38,909.61

C.)f=666.4

Explanation:

A.) A=v/t 26.3/0.590=44.57

B.) 873kg x 44.57= 38,909.61

C.) 68kg x 9.8=666.4

explain properties and importance of light and how it separates into colours

Answers

Answer:

White light can be separated into different colors using a special lens called a prism. As visible light passes from air into the glass, the change in medium causes a change in direction and speed. Refraction causing the separation of white light into its various color wavelengths is called dispersion.

hope this helps

What types of energy do you acquire when you eat a bowl of hot vegetable soup?

Answers

Answer:

you need kinetic energy because it is the energy that is used when In motion

The type of energy that one acquire when you eat a bowl of hot vegetable soup is chemical energy.

What is chemical energy?

Chemical power the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.

Some of the heat energy needed for a reaction to continue can be stored as chemical energy in newly created bonds.

Food particles go through a chemical reaction that releases chemical energy when we eat it. The body then uses this energy to carry out its regular tasks.

As a result, when you eat a cup of vegetable soup, you also consume the chemical energy it contains.

Thus, the answer is chemical energy.

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Which molecule is a high-energy output of the light reactions?.

Answers

Answer:

Gallium Arsenine

Explanation:

The half life of carbon-14 is 5730 years. How old is a bone if it presently contains 0.3125 g of carbon-14, but it was estimated to have originally contained 80 g of carbon-14?

Answers

The age of the bone is 45840 years.

We'll begin by calculating the number of half-lives that has elapsed.

Amount remaining (N) = 0.3125 g

Initial amount (N₀) = 80 g

Number of half-lives (n) =?

N × 2ⁿ = N₀

0.3125 × 2ⁿ = 80

Divide both side by 0.3125

2ⁿ = 80 / 0.3125

2ⁿ = 256

2ⁿ = 2⁸

n = 8

Thus, 8 half-lives has elapsed

Finally, we shall determine the age of the bone.

Half-life (t½) = 5730 years

Number of half-lives (n) = 8

Time (t) =?

t = n × t½

t = 8 × 5730

t = 45840 years

Therefore, the age of the bone is 45840 years.

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when you hold a spherical concave mirror with a 48.2-cm radius of curvature in front of your face, you see an image of your face that is 61.8 cm in front of the mirror. what is the distance between the mirror and your face?

Answers

The distance between the mirror and your face is 39.5 cm

Using the mirror formula 2/r = 1/u + 1/v where r = radius of curvature = - 48.2 cm, u = distance between mirror and your face = object distance and v = distance between image and your face = - 61.8 cm. The distances are negative since the image is in front of the mirror and distances to the left of the mirror are negative.

So, making u subject of the formula, we have

2/r = 1/u + 1/v

1/u = 2/r - 1/v

1/u = (2v - r)/rv

u = rv/(2v - r)

Substituting the values of the variables into the equation, wse have

u = -48.2 cm × -61.8 cm/(2 × -61.8 cm - (-48.2 cm))

u = 2978.76 cm²/(-123.6 cm + 48.2 cm)

u = 2978.76 cm²/-75.4 cm

u = -39.51 cm

u ≅ -39.5 cm (The distance is negative since it is in front of the mirror)

So, the distance between the mirror and your face is 39.5 cm

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What is the kinetic energy of a 2,000-kg boat moving at 5.0 m/s?

Answers

Answer:

25kJ

Explanation:

K = 1/2 mv^2 = 1/2 x 2000kg x (5.0m/s)^2

= 25 x 10^3 J = 25kJ

Virtual image formed by concave mirror

Answers

Answer:

yes

Explanation:

because it is a diverging mirror

learning task 2: assess your health status by using the question below try to determine if you are capable to do the physical fitness test .write your answer in your answer sheet​

Answers

To assess your health status, it is necessary to take the physical fitness test, which will determine how healthy you are, according to some questions, such as how often you have seen a doctor, how is your heart, etc.

Some sample questions to assess your health status are:

Have you seen a pshysician?

Whats your heart condition according to your physician?

Are you recommended to do some physical activity?

Do you feel any chest pain if you are not doing physical activity?

This past few days, do you feel any chest pain if you are not doing phsysical activity?

Do you ever lose consciusness or lose your balance because of dizziness?

Do you have any joint or bone injury or problem that could be made worse by performing physical activity?

Therefore, the physical fitness test is necessary so that a person can perform physical activities safely, avoiding injuries and other associated risks.

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Prove that the two equations shown below are equivalent.​

F = ma and F = p/t​

Answers

Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

[tex]\Delta p = mv - mu \\\\\implies \Delta p = m(v-u) \\\\F = \dfrac{\Delta p}{\Delta t} = \dfrac{m(v-u)}{\Delta t} = ma[/tex]

F = ma is the formula of Newton’s Second Law of Motion.

To prove Newton's second law of motion,

Given Force F = Δp/Δt

What is relation between F = ma and F = Δp/Δt?Newton’s Second Law of Motion is defined as Force is equal to the rate of change of momentum. The second law of Newton can be described as the acceleration of an object which produces a net force is directly proportional to the magnitude of the net force, in the same path i.e., direction as the net force, and inversely proportional to the mass of the object.As the acceleration has its magnitude and direction it is a vector quantity.

Proof for F=ma

     Let us consider an object of mass m, moving along a straight line with an initial velocity u, final velocity v and it has some particular time t and thus Momentum can be related as,

For initial velocity u, p1 = m × u

The final velocity v, p2 = m × v

The change in momentum can be expressed as

p2 – p1 = (m × v) – (m × u)

p2 – p1 = m (v – u)

Here, we know that the rate of change of momentum with respect to time is proportional to the applied force.

The applied force F,

F ∝ [m (v – u)]/t

F ∝ m × a

As acceleration (a) is the rate of change of velocity with respect to time.

F = k × m × a

F = ma

where k can be the constant.

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the relationship between global warming and greenhouse gases is the _______.

Answers

how both affect the ozone layer and affect temperature in a grobal way

Surface ocean currents are generated MOSTLY by A) wind. B) tides. C) water density. D) the Coriolis effect.

Answers

Answer:

I think it's D) the Coriolis Effect

Explanation:

Answer: THE ANSWER IS D) the Coriolis effect.

Explanation: I GOT A 100 ON THE TEST

help plz

Stop and go traffic means a lot of opportunities for acceleration. This assignment looks at a typical experience of a car in typical rush hour traffic. Calculate the different accelerations from the graph, interpret what your answers mean and show you really understand acceleration.

A car traveled through rush hour traffic in a city. There was a lot of starting and stopping. The graph below shows the motion of the car for a 16 second interval of time.
Explain what is going on between point B and C in terms of velocity and acceleration.

Velocity:

Acceleration:

Answers

-In terms of velocity it remains constant at 7 m/s for 4 hours (time between b and c)

- in terms of acceleration, there is no acceleration. When something has constant velocity there is 0 acceleration

What kind of force could cause this ball to not be at rest anymore, or cause it to move?

Answers

Answer:

friction

Explanation

Answer:

Friction

Explanation:

What force prevents an object at rest?

Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.

In the diagram below if bulb 2 blew out what would happen to the VOLTAGE? (it’s not decreases that’s why it’s highlighted)

Answers

Answer:

apagado, así que lo más destacado es el problema, oh, está bien, esa es la respuesta, cariño.

what is the molecular formula for the hydrocarbon in the mass spectrum above?

Answers

What is the structure of a hydrocarbon that has $\mathrm{M}^{+}=120$ in its mass spectrum and has the following $1 \mathrm{H}$ NMR spectrum? 7.25 $\delta(5 \mathrm{H}, \text { broad singlet); } 2.90 \delta(1 \mathrm{H}, \text { septet, } J=7 \mathrm{Hz}) ; 1.22 \delta(6 \mathrm{H},\text { doublet, }$ $J=7 \mathrm{Hz})$

a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time

find distance and acceleration

PLEASEEEE HELP I HAVE A PHYSICS EXAM TOMORROW AND IM STRUGGLING

Answers

Answer:

add 44m/s and 22m/s then multiply it by 11

Explanation:

A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds, Acceleration is -2 m/s² (deceleration), and distance is 242 meters.

To solve this problem, it is given:

Initial velocity ([tex]\(v_i\)[/tex] ) = 44 m/s

Final velocity ([tex]\(v_f[/tex] ) = 22 m/s

Time ([tex]\(t\)[/tex] ) = 11 s

We have two tasks: finding the acceleration (a) and then using it to calculate the distance (d).

1. Calculate Acceleration (a):

[tex]\[a = \frac{v_f - v_i}{t} \\\\= \frac{22 \, \text{m/s} - 44 \, \text{m/s}}{11 \, \text{s}} \\\\= -2 \, \text{m/s}^2\][/tex]

The negative sign indicates deceleration (slowing down).

2. Calculate Distance (d):

Using the kinematic equation:

[tex]\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\][/tex]

Plugging in the values:

[tex]\[d = (44 \, \text{m/s}) \cdot (11 \, \text{s}) + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (11 \, \text{s})^2\][/tex]

Calculating the first part:

[tex]\[d = 484 \, \text{m} - 121 \, \text{m} \\\\= 363 \, \text{m}\][/tex]

Calculating the second part:

[tex]\[d = 363 \, \text{m} + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (121 \, \text{s}^2) \\\\= 363 \, \text{m} - 121 \, \text{m} \\\\= 242 \, \text{m}\][/tex]

The total distance the race car moves during this time is 242 meters.

Thus, acceleration is -2 m/s² (deceleration), and distance is 242 meters.

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When the atmosphere is absolutely unstable, the environmental lapse rate is ________ the dry adiabatic lapse rate.

Answers

Answer: greater than

Explanation:

Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.

How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.

From edge

Answers

Answer:

like 23 or something

Explanation:

What is the number of the of significant figures in 2.50400-.pliz, help me l will mark you the brainest.(⊙_◎)​

Answers

Answer:

Number of Significant Figures: 6

The Significant Figures are 2 5 0 4 0 0

Explanation:

Non-zero digits are always significant which are in this case 2,5,4, and Any zeros between two significant digits are significant and final zero or trailing zeros are significant therefore making the entire digit significant.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

The number of significant figures in 2.50400 is ~

[tex] \boxed{6}[/tex]

A falling object with a weight of 15N is moving downwards towards earth at a steady speed. What is the size of the drag force on this object?

Answers

Answer:

15 N :D

Explanation:

The size of the drag force on this object falling at a constant speed is determined as 15 N.

Drag force on the object

The drag force on the object is determined by calculating the net force on the object;

F(net) = W - D

where;

W is weight of the objectD is the drag force of air

ma = W - D

at constant speed, acceleration, a = 0

0 = W - D

W  = D

15 N = D

Thus, the size of the drag force on this object falling at a constant speed is determined as 15 N.

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Công thức cộng vận tốc

Answers

Answer:

you are very kind except for your habit

What would a force diagram for something WHILE it is being thrown DOWNWARDS look like?

Ty

Answers

Answer:

it look the same just to tell you

With no friction, you can use the relationship between potential and kinetic energy to predict the speed of the car at the bottom of this hill from its starting height. To do this start by setting the kinetic and potential energy equations equal to one another

Answers

The speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]

According the principle of conservation of energy, the total potential energy of the car will be converted to maximum kinetic energy when the car is at the bottom of the hill.

[tex]K.E = P.E\\\\\frac{1}{2} mv^2 = mgh\\\\v^2 = 2gh\\\\v= \sqrt{2gh}[/tex]

where;

v is the speed of the car at the bottom of the hillh is the height of the hillg is acceleration due to gravity

Thus, the speed of the car at the bottom of the hill is obtained as, [tex]v = \sqrt{2gh}[/tex]

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1. An object would have a different mass on Earth as it would have on the moon.
a. True
b. False

Answers

Answer:

a.true

Explanation:

because the gravitational strength of earth and moon is different

gold is a metal angu​

Answers

Answer:

God is a metal- gold is a transition metal and a group 11 element. It is one of the least reactive chemical elements and is solid under standard condition.

•Gold is the chemical element with 79 protons in each atomic nucleus. Every atom containing 79 protons is a gold atom.

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