Suppose you identify a new element, Interactium. Interactium has three isotopes: Interactium-283, Interactium-286, and Interactium-292. In the mixture, 22% of the mixture is Interactium-283, 35% is Interactium-286, and the rest of the mixture is Interactium-292.

What is the relative atomic mass for Interactium?

The mole fraction of the water solution is 0.77.

The mole fraction or molar fraction is defined as a unit of the quantity of a constituent, nᵢ, divided by the total quantity of all parts in a combination.

Moles of water = given mass/ molar mass

Moles of water = 84/18

Moles of water = 4.6

Moles of hexane =  given mass/ molar mass

Moles of hexane = 100/76

Moles of hexane = 1.3

Total moles = Moles of water + Moles of hexane

Total moles = 4.6 + 1.3 = 5.9

Mole fraction of water = Moles of water / Total moles

Mole fraction of water = 4.6/5.9

Mole fraction of water = 0.77

Hence, the Mole fraction of water is 0.77.

The mole fraction is the same as the mole percent however in a specific shape in chemistry. Inside the given combination, the range of moles of one constituent is divided by the total number of moles is referred to as the mole fraction. Multiplying the mole fraction of the thing by then we gain the mole percentage of the aspect.

Mole fraction is a unit of awareness, described to be equal to the range of moles of an aspect divided through the whole wide variety of moles of a solution. Because it's miles a ratio, the mole fraction is a unitless expression.

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Answer:

electron(negative)

neutron(neutral)

proton(positive)

The 12.5 g of NaCl is required to make 9.0% of the NaCl solution.

How the percentage is related to grams in terms of Chemistry?

Both percentages and grams  both  are units or parameters used to express the concentrations in chemistry.

Given:

The % of NaCl = 9.0% or = 9/10 = 0.9

The weight of the solution = 239 grams

The molar mass of the NaCl = 58.44 g/mol

Here, we use formula = 0.9 =  (Mass of the solute*1000)/(Mass of the solvent)

Let us assume the mass of the solute = x =  mass in the gram/ molecular mass of the solute.

Now, by using the above formula, we get

X=  0.9*239*58.44/1000

X = 12.5 grams

Hence, 12.5 grams is the answer

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A bigger atom  fission when a neutron smashes against it, causing it to excite and split into two smaller atoms known as fission products. A chain reaction may be initiated by other neutrons that are also released.

By dissolving large, heavy atoms, like uranium, into smaller ones, like iodine, cesium, strontium, xenon, and barium, to name just a few, fission produces energy. To create the heavier helium, fusion combines light atoms, such as the two hydrogen isotopes deuterium and tritium.

Nuclear fission fuels the explosion of nuclear weapons and creates energy for nuclear power. Due to the fact that certain compounds known as nuclear fuels undergo fission when impacted by fission neutrons and then break apart, both uses are feasible.

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Step 1 - Understanding the relation of potential energy, kinectic energy and the conservation of energy

The potential energy is the energy related to a body that can start moving under the influence of a force anytime soon.

The kinf of potential energy depends on the force that could act on the body. When a body is lifted, because gravity can pull it back, we say that this body has gravitational potential energy

Kinetic energy, on the other hand, is related to actual movement. It depends on the mass as well as on the velocity of the body. When we lift an object and drop it next, all the potential energy will be converted to kinetic energy, i.e., the velocity of the object we dropped will be also proportional to the height. It cannot gain more energy.

Step 2 - Interpreting the problem

Now that we know how potential and kinetic energy work, we can start working on the problem. Since potential energy is directly proportional to height, the highest potential energy would be attained at F.

The lowest potential energy, on the other hand, woud be attained at D, i.e., the smaller height.

The highest kinetic energy would be attained when all the potential energy is converted to kinetic energy, i.e., when the bicyclist, starting at A, loses its potential energy reaching D

The speed is directly proportional to the kinetic energy: the higher the speed, the higher the kinetic energy. Since the kinetic energy, as we saw, is the greatest at D, the velocity will also be the greatest at this point.

Answer:

Explanation:

The three main radiation types are:

a) Alpha particles

b) Beta Particles

c) Gamma rays

Alpha Particles

Alpha particles are essentially helium atoms. When radiated, the value 4 is subtracted from the parent's molecule mass number while the value 2 is subtracted from the parent's molecule atomic number. Due to their heaviness, they are less penetrative, compared to other radiation types. They are positively charged.

Beta Particles

Beta particles are more energetic radiation emission with a charge equal to -1. They are negatively charged. They are high energetic electrons which can be represented generally as follows:

They weigh much more less and have a higher penetrating power when compared to alpha particles

Gamma Rays

These are the lightest and are simply radiation by products. They have more penetrating power than both beta particles and alpha particles. They are neutrally charged. They have no charge nor mass:

They have low ionizing power

10.00 moles of H₂(g) react with 5.000 mol of O₂(g) to form 10.00 mol of H₂O(l) at 25°C and a constant pressure of 1.00 atm. If 683.0 kJ of heat are released during this reaction, and PΔV is equal to -37.00 kJ, then ΔE° is 646.00kJ

Energy that is transferred from one body to another as the result of a difference in temperature called as heat

Here given data is

H₂(g) + O₂(g) → H₂O(l)

H₂(g) = 10.00 mole , O₂(g) = 5.000 mol , gives H₂O(l) = 10.00 mol and heat are released during this reaction are 683.0 kJ and PΔV is equal to -37.00 kJ then we have to find ΔE° = ?

ΔH° = 683.0 kJ

ΔE° = heat are released - PΔV

So,  ΔE° =  683.0 kJ - 37.00 kJ

= 646.00kJ

And the calculated answer is the ΔE°

So,  ΔE° = 646.00kJ

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The percent yield of carbon dioxide is 87%.

The balanced chemical equation for reaction of octane with oxygen,

CH₂(CH₂)₆CH₂+ 12O₂ → 8CO₂ + 8H₂O

We can use the mole concept here,

Mole = Given mass/molar mass.

From the reaction,

1 mole of Octane = 8 moles of carbon dioxide.

Now, moles of octane N,

N = 31.98/114.23

N = 0.2799

Moles of Carbon dioxide = 8 x 0.2799

Moles of Carbon dioxide = 2.239

Mass of CO₂ formed,

2.239 = Mass of CO₂/44

Mass of CO₂ = 98.54 grams/mole.

Percentage yield = theoretical mass/experimental mass x 100

Theoretical mass = 98.54 grams/mole.

Experimental mass = 85.8 grams/mole.

Percentage yield of CO₂ = 85.8/98.54 x 100

Percentage yield of CO₂ = 87%

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The fact that 21 g of A and 21 g of B produce 17 g of C does not obey the law of conservation of mass.

The law of conservation of mass states that the mass of a substance can neither be created nor destroyed.

This law further explains that in a chemical reaction, the amount of reactants must be equal to the amount of products in the reaction.

For example, if a substance A of mass 21g reacts with another substance B of mass 21g, the mass of the product C should be 21g + 21g = 42g in order to align with the law of conservation of mass.

However, according to this question, the product C has a mass of 17g, which shows that the law of conservation of mass is not obeyed.

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The statement 'It may include pieces of asphalt' is TRUE about soil used as evidence in forensic science (Option B).

Forensic science is a sub-discipline aimed at solving police cases based on evidence found at the crime scene, thereby being a key part of a police investigation. in this sense, pavement structural evaluation may result very useful in forensic science.

Therefore, we can conclude that forensic science is based on evidence found in the crime scene, which may include evidence in the asphalt ([pavement) that is collected by investigators in order to analyze it.

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Answer: B

Explanation:

If a population consist of large portion of reproductive Indvidual's,  then the future population size is also increase .

As previously said, populations with early reproduction have the ability to increase far more quickly than populations with later reproduction. The life tables for a certain species show how the age of first reproduction affects population growth.

Preoperative people make up a large amount of the triangular age pyramid, whereas reproductive people make up a more moderate number and post-reproductive people make up less of it. It signifies a young or populace that is expanding quickly.

In an age pyramid with an urn shape, there are more reproductive people than pre-reproductive people. It symbolises population loss or reduction and negative growth.

The proportion of pre-reproductive and reproductive people in the age pyramid has a bell shape. Comparatively fewer people are post-reproductive. It indicates a population that is steady or stationary and is neither increasing nor decreasing.

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The molar mass of rhodonite MnSiO₃ is 131.0 g.

The molar mass of a substance is the mass of  1 mole of that substance.

The molar mass of a compound is obtained from the sum of the  product of the number of moles of atoms  and the molar masses of the elements in the compound.

The molar mass of rhodonite MnSiO₃ is calculated as follows:

Molar mass of Mn = 55 g

Molar mass of Si = 28 g

Molar mass of O = 16.0 g

Molar mass of MnSiO₃ = 55 + 28 + 16 * 3

Molar mass of MnSiO₃ = 131.0 g

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Answer

the correct answer would be A

Explanation:

They were unable to find class nor individual characteristics.

Answer:

D

Explanation:

Carbon has atomic number of 6 so it has 6 protons.

Answer:

why alkali metal are called as most reactive elements?

The volume of the oxygen into a balloon is, V = 1.70 ml.

To calculate the volume of the oxygen using the formula

PV = nRT

where,

P is pressure

V is volume

n is number of moles

R is gas constant

T is temperature

So, the known values are :

P = 1183 mmHg

R = 8.314 J/mol

T = 151.4°F = 66.33°C

mass = 58.41g

n = ?

V = ?

While we don't know the value of n but we know mass so we can calculate number of mole by using formula,

n = m / M

That is,

n is number of mole

m is mass

M is molecular mass

Now, putting values in this

n = 58.41 / 15.99

n = 3.65 mol

Thus, now we know the value of n

Put the value in formula

PV =nRT

1183 mmHg x V = 3.65 mol x 8.314 J/mol x 66.33°C

V = 2012.86 / 1183

V = 1.70 ml

Hence, the volume of the oxygen into a balloon is 1.70 ml.

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The distribution of positive and negative particles was not uniform. This hypothesis of Thomson’s atomic model was later found to be not true by Rutherford.

Because positive charge particle is in center and the negative charge particle is surround to it.

J.J. Thomson proposed that an atom is a definitely charged sphere wherein negatively charged electrons are embedded in it. Neils Bohr proved it to be false as the mass of any atom is localized inside the middle of an atom which is positively charged even as negatively charged electrons revolve across the effective center.

Thomson was incorrect due to the fact he assumed that the positive charge of an atom become all one uniform blob of count number with the electrons transferring in orbits inside the nucleus. If Thomson's model had been accurate, the alpha particles could skip thru the atomic shape of the foil unimpeded.

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20 Grams of Water.

Grams : mL

2 : 1

4 : 2

6 : 3

8 : 4

10 : 5

12 : 6

14 : 7

16 : 8

18 : 9

20 : 10

Answer:

20 grams

Explanation:

mass = Density × Volume

= M = 2g/ml × 10ml

= 20g

From the periodic table, we know that 1 mole of Krypton has a molar mass of 83.798 grams/mole.

So 10 grams would have (10/83.798) which is 0.1193345903 moles.

If we multiply this by Avogadro's number, we get the amount of Krypton atoms in 10 grams.

0.1193345903 x 6.02 x 10^23 = 7.184 x 10^22 atoms

Accounting for significant figures, the answer would be: 7 x 10^22 atoms

Taking into account the reaction stoichiometry, the maximum amount of SF₆ that can be produced from the reaction of 32.1 g of sulfur with 114 g of fluorine is 146.46 grams.

In first place, the balanced reaction is:

S + 3 F₂  → SF₆

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 57 grams of F₂ reacts with 32 grams of S, 114 grams of F₂ reacts with how much mass of S?

mass of F₂= (114 grams of F₂× 32 grams of S)÷ 57 grams of F₂

mass of F₂= 64 grams

But 64 grams of F₂ are not available, 32.1 grams are available. Since you have less mass than you need to react with 114 grams of F₂, S will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 32 grams of S form 146 grams of SF₆, 32.1 grams of S form how much mass of SF₆?

mass of SF₆= (32.1 grams of S× 146 grams of SF₆)÷ 32 grams of S

mass of SF₆= 146.46 grams

Finally, 146.46 grams of SF₆ can be produced from the reaction of 32.1 g of S with 114 g of F₂.

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1. Balanced equation of the reaction = [tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]

2. Formulas of reactants

    solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]

    solid aluminum metal = [tex]Al(s)[/tex]

    solid manganese = [tex]Mn (s)[/tex]

    solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]

A balanced chemical equation agrees with the law of conservation. In other words, the number of participating atoms must balance between the reactants and the products of the same equation.

Formula for solid manganese (IV) oxide = [tex]MnO_2 (s)[/tex]

Formula for solid aluminum metal = [tex]Al(s)[/tex]

Formula for solid manganese = [tex]Mn (s)[/tex]

Formula for solid aluminum oxide = [tex]Al_2O_3 (s)[/tex]

Thus, the balanced equation for the reaction is written as:

[tex]3MnO_2(s) + 4Al (s) -- > 2Al_2O_3(s) + 3Mn(s)[/tex]

One can see from the that the number of atoms of each element in the reactants is equal to the number of atoms of the same elements in the product.

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Anhydrides are binary substances or compounds that are the result of a nonmetal with oxygen.

I leave you 2 steps to make the anhydrides:

1: To make anhydrides, write your nonmetal symbol followed by oxygen.

2: The oxidation numbers must be the same and for this the exchange of oxidation numbers or valence between its non-metallic element and Oxygen is used.

Examples of anhydrides:

1: Chlorous anhydride

[tex]\bold{ \: Cl + O₂ \rightarrow \: Cl₂ O₃}[/tex]

Keep in mind that when it ends in OSO we look for its valence, which in this case would be +3.

2: Iodic anhydride

[tex]\bold{ \: I + O₂ \rightarrow \: I₂ \: O₅}[/tex]

We take into account its symbol that in this would be me and to solve it we must look for its valence that in this case ends in ICO which is already known that its ICO valence is +5.

3: Per bromic anhydride

[tex]\bold{\:Br + O₂ \rightarrow \:Br₂ \:O₇}[/tex]

We take into account its symbol, which in this case would be Br, and to solve it we must find its valence, which in this case ends in ICO, which is already known to have an ICO valence of +7.

The Table of metals and non-metals is attached.

The percent yield when 28.16 g of [tex]CO_2[/tex] is formed from 8.000 moles [tex]C_8H_1_8[/tex] reaction with 16.00 moles [tex]O_2[/tex] is 6.25%.

The percent yield of a reaction is given by:

Percent yield = actual yield/theoretical yield x 100%

From the equation of the reaction, the mole ratio of the two reactants is 2:25.

With 8.00 moles [tex]C_8H_1_8[/tex] , 200 moles of [tex]O_2[/tex] should be used. But only 16 moles is available. Thus, [tex]O_2[/tex] is the limiting reactant.

The mole ratio of [tex]O_2[/tex] to [tex]CO_2[/tex] is 25:16.

With 16 moles [tex]O_2[/tex], the moles of [tex]CO_2[/tex] would be:

 16 x 16/25 = 10.24 moles

Mass of 10.24 moles  [tex]CO_2[/tex] = 10.24 x 44.01

                                       = 450.7 grams

Percent yield of  [tex]CO_2[/tex] = 28.16/450.7 x 100

                                     = 6.25%

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Ideal gas equation PV =nRT

The parameters are given in problem : moles (n)  = 2.55 Volume (V) = 205L:Temperature(T) = 273K Pressure = ?kPa

Universal Gas constant  R = 8.31kPa.L/mol.K   substitue all these values in ideal gas equation in PV = nRT

PV = nRT  

Px205 = (2.55)x(8.31)x(273)

P = (3.05)x(8.31)x(273) /205 kPa

P = 33.75 kPa.

The volume of gas particles is negligible. Gas particles are the same size and have no intermolecular forces as other gas particles. Gas particles move randomly according to Newton's laws of motion. An ideal gas is one that obeys the law pv=RT at all pressures and temperatures. At high temperatures and low pressure, the potential energy due to intermolecular forces becomes almost insignificant compared to the kinetic energy of the particles, and the size of the molecules increases compared to the intermolecular voids.

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Answer:

86400

Explanation:

24*24*69seconds

The new temperature of certain quantity of helium gas is at a temperature of 27°C and a pressure of 1.00 atm will be 300 K if its volume is doubled at the same time that its pressure is decreased to one-half its original value.

We will use combined gas law equation to find the new temperature.

We know that

Initial temperature T₁ = 27°c +273 K = 300 K

Initial pressure P₁ = 1.00 ATM

Initial volume V₁ = V

Final volume V₂ = 2 V

Final pressure P₂ = P/2 = 1/2 = 0.5 atm

Now, using the combined gas law equation, which is given as -

P₁V₁ = P₂V₂

 T₁       T₂

where,

P₁ = Initial pressure

P₂ = Final pressure

V₁ = Initial volume

V₂ = Final volume

T₁ = Initial temperature

T₂= Final temperature

Avogadro's law states that equal volumes of gases contains equal number of molecules at same temperature and pressure.

P₁V₁T₂ = P₂V₂T₁

Dividing P₁V₁ on both the sides

P₁V₁T₂  =  P₂V₂T₁

P₁V₁           P₁V₁

We get,

T₂ = P₂V₂T₁

        P₁V₁

Substituting values,

T₂ = 0.5 × 2V × 300 × V

                           1

T₂ = 300K

Hence, the new temperature is 300 K.

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In order of degreasing Size :

O2- > O > Ne.

Br- > Cl- > F-

Mg > Al > S

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The classification of Rupatadine is H-1 receptor antagonists or H-1 blockers.

As a platelet-activating factor antagonist and second-generation antihistamine, rupatadine is used to treat allergies. It was found and developed by Uriach [es][2], and it is sold under the trade names Rupafin and a few other names as well. For the treatment of chronic urticaria and allergic rhinitis in adults and children older than 12 years, rutadine fumarate has been approved. It is offered as round, light salmon-colored tablets to be taken orally once day that contain 10 mg of rupatadine (as fumarate).

Rupatadine's effectiveness as a treatment for allergic rhinitis (AR) and chronic idiopathic urticaria (CIU) has been examined in adults and adolescents (aged over 12 years) in several controlled studies, demonstrating a rapid action onset and a great safety characteristics even in long treatment durations of a year.

The drug rupatadine, a dual antagonist of the histamine H1 and platelet activating factor receptors, is used to treat the symptoms of chronic spontaneous urticaria and seasonal and perennial rhinitis. It is available in tablet and liquid formulations for adult and pediatric usage in Canada and has received marketing approval under the trade name Rupel.

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The heat of combustion per gram of the material is 59.4 kJ/g

The heat of combustion per gram is the heat that is evolved when a substance is burnt in oxygen under standard condition. We know that combustion is an exothermic process thus it is clear that heat is given out.

Heat evolved = cdT

c = heat capacity

dT = temperature rise of the material

It then follows that;

Heat evolved = 45.35 * 10^3 J/degree C * (30.14 Celcius - 25.39 Celcius )

= 215412.5 J

Then;

heat of combustion per gram  = 215412.5 J * 10^-3/3.627g

= 59.4 kJ/g

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The percent by mass of carbon in Al₂(CO₃)₃ is 15.38%.

Mass number(A) of various elements of molecule,

A of Aluminum(Al) = 27

A of Carbon(C) = 12

A of Oxygen(O) = 16

Total molecular mass or molecular weight is the sum of individual atomic masses of each atom in a molecule.

Thus, total molecular mass of molecule Al₂(CO₃)₃ is:

= 27×2 + (12 + 16 × 3)3

= 54 + 180

= 234

Hence, percent % of Carbon = (12×3/ 234)× 100

                                                = (36/ 234 )× 100

                                                = 15.38 %

Thus, the percent by mass of carbon is 15.38 %.

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