Suppose your metal sample is hammered into the shape of a thin coin with a diameter of 8.62 cm. Determine the thickness (in mm) of this metal sheet. Use the measured metal mass and true denisty of your metal for this calculation.
measured metal mass: 83.956 g
true density: 8.90 g/cm3

Answer:

1.593 moles

Explanation:

Therefore, 1.593 moles are equal to 89.23 g of calcium oxide.

Answer:

9.64 × 10²³ molecules

Explanation:

Given data:

Mass of calcium oxide = 89.23 g

Number of molecules = ?

Solution:

First of all we will calculate the number of moles of calcium oxide.

Number of moles = mass/molar mass

Number of moles = 89.23 g/ 56.1 g/mol

Number of moles = 1.6 mol

Number of molecules;

1 mole contain 6.022 × 10²³ molecules

1.6 mol × 6.022 × 10²³ molecules / 1mol

9.64 × 10²³ molecules

The number 6.022 × 10²³ is called Avogadro number.

Answer:

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

Answer:

Na sodium or Rb rubidium

Explanation:

Because Na is present in first group all members of group 1 have 1 electron in valence shell and show similar properties.

Answer:

52.8 Liters

Explanation:

Gay-Lussacs law states that P1/T1 = P2/T2

if:

then:

45/298.1 = P2/328.1

P2 = 52.8

The new volume of the balloon is 52.8 Liters this can be calculated by using gas laws.

Charles law states the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature. It is given by

V₁/T₁ = V₂/T₂

What information do we have?

V₁ = 45 L

T₁ = 25 + 273.1 =298.1 K

T₂ = 55 + 273.1 = 328.1 K

To find:

V₂= ?

On substituting the values:

45/298.1 = V₂/328.1

V₂ = 52.8 L

Thus, the volume of the balloon is 52.8 liters.

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Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Moles of H2O = 1.85mol * (1/2) = 0.925mol.

Mass of H2O = 0.925mol * (18g/mol) = 16.65g.

Answer:

16.65 grams of water can be produced with 1.85 moles of NaOH.

Explanation:

Mole ratio of NaOH to H2O = 2 : 1

Number of moles of water = (1/2)×1.85= 0.925 moles

Molar mass of water (H2O) = 18g/mol

Mass of the right water = 18g/mol×0.925 mol=16.65 grams

Answer:

Freezing points for water with freezing mixtures based on salt and ice: Ammonium Nitrate - Chrushed Ice or Snow in Water 1 part Ammonium Nitrate - 0.94 parts Ice/water : temperature -4 o C 1 part Ammonium Nitrate - 1.20 parts Ice/water : temperature -14 o C

Explanation:

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CH3COOH is an accepted and common form of writing the structure of acetic acid (commonly known as vinegar when diluted in water).

Answer:

A: CH4 + 2O2 -> CO2 + 2H2O

Explanation:

Count how many elements they are in all molecules for the reactants and for the products.

C = 1 element

H = 4 elements

O = 2 elements

C = 1 element

O = 2 elements

H = 2 elements

O = 1 element

2 oxygen atoms + 1 oxygen atoms = 3 oxygen atoms total on the products side.

To balance this equation, we need to add 2 more elements of hydrogen and 2 more elements of oxygen. Therefore, we add a 2 to the coefficient of O2 for the reactants side and add a 2 to the coefficient of H2O for the products side.

Now let us try it.

Count how many elements they are in all molecules for the reactants and products.

C = 1 element

H = 4 elements

O = 4 elements

C = 1 element

O = 2 elements

H = 4 elements

O = 2 elements

2 oxygen atoms + 2 oxygen atoms = 4 oxygen atoms total on the products.

All of the elements are balanced.

Hope it helped!

Answer:

3 half-lives 7. An isotope of Cesium (Cesium-137) has a half life of 30 years. If 1.0 mg of cesium-137 disintegrates over a period of 90 years, how many mg of cesium-137 would remain? of sodium-25 is 60 seconds? : 3 minutes t=601 = 3 half-lives 5.0mg ~ 2.5 mg + 1.25mg →) 625 mg.

Explanation:

Hope this helps

       where:

      [tex]N_{0}[/tex] = Initial quantity of the sample = 1.0g

       t = time in years of disintegration = 90 years

      [tex]t\frac{1}{2}[/tex] = Half life of cesium isotope = 30 years

      N(t) = Quantity of substance after disintegration = ?

N(t) =  [tex]1 ( \frac{1}{2})^ \frac{90}{30}[/tex]

N(t) =  [tex]1 (\frac{1}{2})^{3}[/tex]

N(t) = 0.125 grams

Therefore, the quantity of cesium-137 that would remain after disintegrating over a period of 90 years is 0.125 grams.

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Answer:

Heat energy can be calculated by using the specific heat of a substance multiplying it to the mass of the sample and the

change in temperature. It is expressed as:

Energy = mCAT

Energy = 100 (0.90) (150 - 30)

Energy = 10800 J

Answer:

3.4027x10^-22

Explanation:

Answer:

1 and 2

Trigonal planar

Tetrahedral

Trigonal Planar

Linear

Bent ( v- shape)

Explanation:

The highlighted atoms has a delocalized lone pair - 1 and 2

All sp2-hybridized carbon atoms have geometry- Trigonal planar

All sp3-hybridized carbon atoms have geometry - Tetrahedral

The nitrogen atom has geometry - Trigonal Planar

The oxygen atom of the C=O bond has geometry - Linear

and the other oxygen atom has geometry - Bent ( v- shape)

P.S - The correct question is -

Ramelteon has been an aromatic compound with 3 ring structure followed by the aliphatic chain.

The drug has antagonist structure to the melatonin and has been used to treat insomnia by acting as the melatonin representative.

The labelled atom in the structure is oxygen of the pentane ring, nitrogen in the aliphatic chain, and carbonyl oxygen.

The delocalized lone pair has been observed in the compound which has been contributing to the resonating structure. The delocalized lone pair ion the given structure is oxygen of the pentane ring, and nitrogen in the aliphatic chain.

The geometry of the atom has been based on the hybridization and the lone pairs.

The geometry of [tex]\rm sp^2[/tex] hybridized carbon has been trigonal planar. The geometry of [tex]\rm sp^3[/tex] hybridized carbon atom has been tetrahedral. The nitrogen in the chain has trigonal planar geometry. The C=O oxygen has been comprising  linear geometry, while the oxygen has bent v shape.

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Mass of Hydrogen chloride : 4.672 g

Given

Reaction

Fe + 2HCl ⇒ FeCl2 + H2

3.56 g of Iron

Required

mass of Hydrogen chloride

Solution

mol of Iron (Ar = 56 g/mol) :

mol = mass : Ar

mol = 3.56 : 56

mol = 0.064

mol HCl from the equation :

= 2/1 x mol Fe

= 2/1 x 0.064

= 0.128

Mass HCl :

=mol x MW HCl

= 0.128 x 36.5

= 4.672 g

Answer:

a. True.

Explanation:

Hello!

In this case, since dullness and smoothness are characteristic of materials that are not able to conduct the electricity, as they do not provide an appropriate pathway for the electrons to move around because of their amorphous structure, we realize the answer is a. True.

On the contrary, a lustrous and robust solid, is actually able to conduct electricity because it provides the pathway for the electron movements and therefore to conduct electricity.

Best regards!

Answer:

B: CaCO3 + 2HCl -> CaCl2 + H2CO3

Explanation:

Count how many elements they are in all molecules for the reactants and for the products.

Ca = 1 element

C = 1 element

O = 3 elements

H = 1 element

Cl = 1 element

Ca = 1 element

Cl = 2 elements

H = 2 elements

C = 1 element

O = 3 elements

To balance this equation, we need to add 1 more element of Chlorine and Hydrogen.  Therefore, we add a 2 to the coefficient of HCl for the reactants side.

Now let us try it.

Count how many elements they are in all molecules for the reactants and products.

Ca = 1 element

C = 1 element

O = 3 elements

H = 2 element

Cl = 2 element

Ca = 1 element

Cl = 2 elements

H = 2 elements

C = 1 element

O = 3 elements

All of the elements are balanced.

Hope it helped!

Answer:

Like other legumes, peanut plants improve the soil by adding nitrogen, even as they grow tasty, nutritious nuts for this season's harvest. But peanuts need help as they take nitrogen from the air and "fix" it into the soil via their root systems.

Explanation:

Answer:

[tex]0.1090\ \text{M}[/tex]

Explanation:

Volume of [tex]KOH[/tex] = 41.22 mL

Molarity of [tex]KOH[/tex] = 0.1322 M

Number of moles of [tex]KOH[/tex]

[tex]n=\text{Molarity}\times \text{Volume of }KOH\\\Rightarrow n=0.1322\times 41.22\times 10^{-3}\\\Rightarrow n=0.005449284\ \text{mol}[/tex]

2 moles of [tex]KOH[/tex] reacts with 1 mole of [tex]H_2SO_4[/tex]

So,

[tex]0.005449284\ \text{mol}[/tex] of [tex]KOH[/tex] reacts with M mole of [tex]H_2SO_4[/tex]

[tex]M=\dfrac{0.005449284}{2}=0.002724642\ \text{mol}[/tex]

Volume of [tex]H_2SO_4=25\times 10^{-3}\ \text{L}[/tex]

Concentration of [tex]H_2SO_4[/tex] is

[tex]M=\dfrac{0.002724642}{25\times 10^{-3}}\\\Rightarrow M=0.10898568\approx 0.1090\ \text{M}[/tex]

The concentration of the unknown [tex]H_2SO_4[/tex] solution is [tex]0.1090\ \text{M}[/tex].

Explanation:

When Reggie's car turned eastward, his books continued heading northward, causing them to slide off the top of his car and fall.

were is the opshons.

Answer:

sndnmxixixisijwiw

Explanation:

jeejndn jzjaisisp

Answer:

B. Thicker layer of blubber

Explanation:

For the leopard seals to survives this harsh environment, it must have a thicker layer of blubber

Blubber is a thick layer of fat. It is called the adipose tissues and found in most marine organisms.

Answer:

B

Explanation:

Answer:

Clouds are water

Explanation:

When a gas gathers up into a cloud,the cloud starts to rain and water comes out of the cloud.

Answer:

NaOH + HCl —> NaCl + H₂O

Explanation:

From the question given above, we obtained the following equation:

4NaOH + 4HCl —> NaCl + H₂O

The equation can be balance as follow:

4NaOH + 4HCl —> NaCl + H₂O

There are 4 atoms of Na on the left side and 1 atom on the right side. It can be balance by putting 4 in front of NaCl as shown below:

4NaOH + 4HCl —> 4NaCl + H₂O

There are a total of 8 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 4 in front of H₂O as shown below:

4NaOH + 4HCl —> 4NaCl + 4H₂O

Next, divide through by 4 to express the equation with the lowest coefficients.

NaOH + HCl —> NaCl + H₂O

Now the equation is balanced.

NOTE: Smallest coefficients are always used to represent a balanced equation.

Answer:

Every mole contains 6.022 x 10^23 atoms regardless of what type of moelcules it is (Gold, Silver). So the anwer is 1.54 times 6.022 x 10^2

Answer:

Gravitational force between two objects depends on: a. The weight of the objects c. The mass of each object b. The distance between the objects d. Both b and c Please select the best answer from the choices provided A B C D

✓d

The oxidation number of  Sulphur = +2

General formula for determining Oxidation Numbers :

1. The number of oxidation of single element atoms = 0. Examples of Ar, Mg, Cu, Fe, N₂, O₂, etc. = 0

Group I : +1

Group II : +2

H in compound = +1, except metal hydride compounds (Hydrogen which binds I or II groups) oxidation number H = -1, for example, LiH, MgH₂, etc.

2. Oxidation number O in compound = -2, except OF2 = + 2 and in peroxide (Na₂O₂, BaO₂) = -1 and superoxide, for example KO₂ = -1/2.

3 The oxidation number in a non-filled compound = 0,

The total amount of oxidation in ion = ion charge, Example NO₃⁻ = -1

Sodium thiosulphate​ - Na₂S₂O₃

Oxidation number Na = +1 ⇒x2 = +2

Oxidation number O = -2 ⇒x3 = -6

Oxidation number Na₂S₂O₃ = 0

2.Na+2.S+3.O=0

2.+1+2.S+3.(-2)=0

2+2S-6=0

-4+2S=0

2S=4

S=+2

The  concentration (in M) of SO₂ in the wine : c. 3.9 x 10⁻³

Given

Reaction

SO2(aq) + 2H2O(l) + I2(aq) → 4H+ (aq) + 21- (aq) + SO42- (aq)

Required

The  concentration (in M) of SO2

Solution

Titration ⇒ mol SO₂ = mol iodine(I)

mol iodine :

=15.62 ml x 0.00501 M

=0.078256 mlmol

From equation, mol ratio of of SO₂ : I₂ = 1 : 1, so mol SO₂=0.078256

The concentration of SO₂(in 20 ml sample) :

M = n/V

M = 0.078256 mlmol/20 ml

M = 0.0039128

M = 3.9 x 10⁻³

Answer:

a = 2m/s²

Explanation:

Given data:

Mass of sofa = 150 Kg

Force applied = 300 N

Acceleration = ?

Solution:

Formula:

F = ma

F = force

m = mass

a = acceleration

by putting values,

300 N = 150 Kg × a

a =  300 N /150 Kg

a = 300 Kg m/s² / 150 Kg   ( N = Kgm/s²)

a = 2m/s²