The category with the lowest joint relative frequency is Chocolate cupcakes with vanilla buttercream.
Relative frequency = Subgroup frequency / Total frequency
Some of the relative frequencies are given. From that we can find the remaining frequencies using basic addition and subtraction.
Vanilla Chocolate Total
Vanilla Buttercream 0.15 0.06 0.21
Cream Cheese Icing 0.19 0.14 0.33
Cookie Butter Buttercream 0.26 0.20 0.46
Total 0.60 0.40 1.00
Joint relative frequency = Joint frequency / Total frequency
The joint relative frequency of
Cupcakes with vanilla buttercream = 0.21Cupcakes that are chocolate = 0.40 Chocolate cupcakes with vanilla buttercream = 0.06Vanilla cupcakes with vanilla buttercream = 0.15Therefore, the category with the lowest joint relative frequency is Chocolate cupcakes with vanilla buttercream.
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Find the quantity of heat needed to change a 0.80- g ice cube at absolute zero (-273 ∘C ) to 0.80 g of boiling water. Express your answer in calories
The quantity of heat needed to change a 0.80- g ice cube at absolute zero (-273 ∘C ) to 0.80 g of boiling water is 253.2 Cals
q = m c ΔT
q = m L
q = Heat
m = Mass
c = Specific heat
ΔT = Change in temperature
L = Latent heat
From absolute zero to melting temperature of ice,
[tex]q_{1}[/tex] = m c ΔT
[tex]q_{1}[/tex] = 0.8 x 0.5 x ( 0 - ( - 273 ) )
[tex]q_{1}[/tex] = 109.2 Cal
Energy required to melt the ice,
[tex]q_{2}[/tex] = m * L
[tex]q_{2}[/tex] = 0.8 x 80
[tex]q_{2}[/tex] = 64 Cal
From melting temperature to boiling temperature which is 100 °C,
[tex]q_{3}[/tex] = m c ΔT
[tex]q_{3}[/tex] = 0.8 x 1 x ( 100 - 0 )
[tex]q_{3}[/tex] = 80 Cal
Total heat required = [tex]q_{1}[/tex] + [tex]q_{2}[/tex] + [tex]q_{3}[/tex]
Q = 109.2 + 64 + 80
Q = 253.2 Cals.
Therefore, the quantity of heat needed is 253.2 Cals
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Sanjay uses 225 N of force to move a wheelbarrow 18 m at a velocity of 1.8 m/s. What was the amount of power used?
The amount of power used by Sanjay when he uses a force of 225 N to move a wheelbarrow 18 m at a velocity of 1.8 m/s is 405 N
What is power?
Power can be defined as the product of force and velocity.
To calculate the amount of power used by Sanjay, we use the formula below.
Formula:
P = FV........... Equation 1Where:
P = PowerF = ForceV = Velocity.From the question,
Given:
F = 225 NV = 1.8 m/sSubstitiute these values into equation 1
P = 225×1.8P = 405 NHence, the amount of power is 405 N.
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three glasses of thickness 2cm , 4cm and 7cm are arranged adjacent .if their refractive indices arec 1.5 , 1.6 and 1.8 respectively. find the bottom of the prism to be raised above.
*Solution*
d = (2/1.5)+(4/1.6)+(7/1.8)
d =
A translucent, triangular object made of glass or plastic is referred to as a prism (or any transparent material). When white light enters a prism, a phenomenon called refraction causes the light to curve. Through the phenomenon of refraction, light is curved as it moves from one medium (like air) to another medium (like water or glass).
The efficiency with which an optical medium bends light is indicated by the medium's refractive index, which is a dimensionless quantity. The refractive index of a substance determines how much of the light that enters it is bent or refracted.
When an object is immersed in a transparent medium, the distance between its actual depth and its image is reduced by a factor equal to the medium's relative index of refraction with respect to air.
Actual depth divided by refractive index equals apparent depth.
(4/1.6) + (2/1.5) + (7/1.8) = d
d = 5.741 cm
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Zach takes out his slingshot and shoots a rock into the air at 35 m/s.
What is the total time that the rock will be in the air?
How high will the rock go?
At what velocity will the rock return to where it started from?
Answer:
take downwards as negative and upwards as positive
Explanation:
the velocity of the rock to return to where it started from will be -35m/s
A dog walks 14 meters to the east and then 20 meters back
to the west.
For this motion, what is the distance moved?
Dis ance (m) =
What is the magnitude and direction of the
displacement?
Magnitude (m) =
Dir'n =
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The distance is 34m , magnitude of the displacement is 6m and direction of displacement is towards west.
As per question, a dog walks 14 meters to the east and then 20 meters back to the west.
The distance moved for this motion is given below,
Distance = 14 + 20 m = 34m
The magnitude of the displacement and its direction are given below:
Displacement = 14 - 20 m = - 6m
negative sign indicates that the direction of displacement is towards west.
Magnitude of the displacement = 6m
Thus, the distance is 34m ,direction of displacement is towards west and magnitude of the displacement is 6m.
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You return the person tennis serve and hit a smashing winner into the corner of the backcourt. Your racket hits the tennis ball with a force of 50N
and a duration of 0.2 s. The mass of the ball is 0.5 kg. What was the velocity of the ball?
F = ma
Therefore:
F = m(v/t)
- The force is 50 N
- The mass is 0.5 kg
- Time is 0.2 seconds
50 = 0.5(v/0.2)
Solve for v and you get the velocity of the ball after it leaves the racket.
Velocity = 20 m/s
A kangaroo jumps up with an initial velocity of 36 feet persecond from the ground (assume its starting height is 0 feet).Use the vertical motion model, h-16t2 + ut + s, where vis the initial velocity in feet per second and s is the height infeet, to calculate the amount of time the kangaroo is in the airbefore it hits the ground again. Round your answer to thenearest tenth if necessary.Time in air:seconds
Given
Initial velocity:
36 ft/s
Initial height:
0 ft
Vertical motion model:
h(t) = -16t^2 + ut + s
v = initial velocity
s = is the height
Procedure
We are going to use the model provided for the vertical motion.
[tex]\begin{gathered} h(t)=-16t^2+36t+0 \\ h(t)=-16t^2+36t \end{gathered}[/tex]We know that at the maximum height the final velocity is 0.
Then we will use the following expression to calculate the maximum height:
[tex]\begin{gathered} v^2_f=v^2_o-2ah_{\max } \\ 0=v^2_o-2ah_{\max } \\ 2ah_{\max }=v^2_o \\ h_{\max }=\frac{v^2_o}{2a} \\ h_{\max }=\frac{(36ft/s)^2}{2\cdot32ft/s^2} \\ h_{\max }=20.25\text{ ft} \end{gathered}[/tex]Now for time:
[tex]\begin{gathered} 20.25=-16t^2+36t \\ 16t^2-36t+20.25=0 \end{gathered}[/tex]Solving for t,
[tex]\begin{gathered} t_1=2.25 \\ t_2=0 \end{gathered}[/tex]The total time the kangaroo takes in the air is 2.3s.
Without performing a calculation, predict which of the following compounds will have the greatest molar solubility in water.
AgCl (Ksp=1.8x10-10); AgBr (Ksp=5.0x10-15);
AgI (Ksp=8.3x10-17)
Answer:
the third one because it is greater then the other ones
3 pts. A 500-g particle moving along the x-axis experiences the force shown in the figure. The particle’s velocity is 2.0 m/s at x = 0 m. For each part, give your answer in m/s to 2 significant figures.
(a) The velocity of the particle at position x = 1 m is 3.74 m/s.
(b) The velocity of the particle at position x = 2 m is 6.63 m/s.
(c) The velocity of the particle at position x = 3 m is 9.7 m/s.
What is force constant?The force constant or spring constant of a spring is the measure of stiffness of a spring.
The force constant of the spring is the slope of the graph and it is calculated as follows;
k = F/x
k = ΔF/Δx
where;
ΔF is change in forceΔx is change in extension of the springk = (15 N - 10 N) / (3m - 2m)
k = 5 N/m
The speed of the particle at each position is determined by applying the principle of conservation of energy as follows;
ΔK.E = ΔU
where;
ΔK.E is change in kinetic energy of the particleΔU is change in potential energy of the particle¹/₂m(v² - u²) = ¹/₂k(x₂² - x₁²)
m(v² - u²) = k(x₂² - x₁²)
v² - u² = k(x₂² - x₁²) / m
v² = k(x₂² - x₁²)/m + u²
v = √[ k(x₂² - x₁²)/m + u²]
where;
v is the final velocity of the particleu is the initial velocity of the particle = 2 m/sk is spring constantm is mass of the particle = 500 g =0.5 kgx₁ is the initial position of the particle = 0 mFor x = 1 m
v = √[5 (1² - 0²)/0.5 + 2²]
v = 3.74 m/s
For x = 2 m
v = √[5 (2² - 0²)/0.5 + 2²]
v = 6.63 m/s
For x = 3 m
v = √[5 (3² - 0²)/0.5 + 2²]
v = 9.7 m/s
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What is the horizontal velocity at each point of the trajectory?
Answer:
Constant velocity across x-axis(horizontal)
a roller coaster car rapidly picks up speed as it rolls down a slope. as it starts doown the slope. its speed is 4 m/s. but 3 secondes later ,at the bottom of the slope. its speed is 22 m/s what is the avrege acceleration?
The average acceleration is 6 [tex]m/s^{2}[/tex]
Given
Initial Velocity of the roller coaster (U) = 4 m/s
Final velocity of the roller coaster (V) = 22 m/s
Time taken (t) = 3 seconds
According to the second law of motion,
Acceleration is the rate of change of velocity per unit change in time taken.
Therefore,
a = [tex]\frac{v-u}{t}[/tex]
a = [tex]\frac{22-4}{3}[/tex]
a = 6 [tex]m/s^{2}[/tex]
Hence the acceleration after 3 seconds is 6 [tex]m/s^{2}[/tex]
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Calculate the magnitude of the repulsive force between a +500μC charge and a +100μC charge which are 5 m apart. [k=9×109 Nm2C-1]
The diagram above represents the forces exerted on a box that a child is holding. FN represents the force applied by the child’s hand, and Fg represents the weight of the box. The child begins to raise the box with increasing speed. Which of the following claims is correct about force Fh that is exerted by the box on the child’s hand as the box is being raised?
Answer:
Fh=FN, where FN is larger as the box is being raised than when it was being held is correct.
Explanation:
Try to represent this phenomenon as a chain of causes and effects in a labeled diagram in
the space below:
1. Pressure sensors in your shoulder are deformed for an extended amount of time.
2. These send signals to neurons that are attached under the skin.
3. These neurons relay signals through axons to other neurons until the signal reaches
your brain.
4. You decide you should rollover.
5. Your brain sends a signal to motor neurons that relay it to other motor neurons
through axons until the signal reaches your leg muscles.
6.
The cells that make up the muscle tissue in your leg muscles contract in response to
the signal they receive.
7. This leads to your legs moving, which is what pushes your body around so that you
roll over.
system
sed dots
This phenomenon is reflex action.
Reflex action is a surprising and involuntary response to stimuli. It helps organisms to quick adapt to an damaging condition that could have the potential to cause physical damage or maybe loss of life. Pulling our palms away right now after touching a hot or cold object is a traditional example of a reflex movement.
There are two reflexes, true reflexes, and bad reflexes. Proper reflexes assist with exercising, sports, and ordinary bodily activities such as driving, crossing the street, and working, however terrible reflexes can lead to damage and harm.
In a reflex action, the brain performs no element. The spinal cord, which reacts with out thinking about how to reply to stimuli, is in rate of those automated moves. It elicits no meaningful response inside the mind.
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Energy is the ability to cause ________________ . Your goal is to avoid change to the structure of the egg. Kinetic energy is the energy of ____________. In order to save your egg, you will need to lower the kinetic energy of the egg just before the egg strikes the ground. The formula for kinetic energy is ___________. You can’t change the mass, so you must try to adjust the __________. How can we do this? Think about forces we studied in our first unit. The force that can lower the velocity of a falling object is _________________. The two factors that affect this force are __________ and ____________.I’m not sure if this is even a type of question you could do
ANSWER:
Work
Movement
1/2*m*v^2
Velocity
Weight.
Mass
Gravity
STEP-BY-STEP EXPLANATION:
Energy is the ability to cause work .
Your goal is to avoid change to the structure of the egg. Kinetic energy is the energy of movement.
In order to save your egg, you will need to lower the kinetic energy of the egg just before the egg strikes the ground. The formula for kinetic energy is 1/2*m*v^2. You can’t change the mass, so you must try to adjust the velocity. How can we do this?
Think about forces we studied in our first unit. The force that can lower the velocity of a falling object is weight. The two factors that affect this force are mass and gravity.
The maximum amount of pulling force a truck can apply when driving on
concrete is 10,560 N. If the coefficient of static friction between a trailer and
concrete is 0.8, what is the heaviest that the trailer can be and still be pulled
by the truck?
The truck needs to draw the trailer with 13200 N of force at its maximum capacity.
What Does Static Friction Mean?Every physical object has a small amount of "stickiness," which is where friction gets its power. Where two surfaces touch, there will be some resistance to motion in that direction. When two surfaces are stationary in relation to one another, there is static friction. Because static friction creates resistance, a certain amount of force must be exerted to get objects moving. There won't be any movement at all if the force applied to one of the surfaces does not surpass the static friction force.
Let the weight of the truck be W . reaction force R = W
Maximum frictional force = μ R
= .8 x W
So for movement of truck
Pulling force = frictional force
10560 = .8W
W = 13200 N
weight of heaviest truck required = 13200 N .
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Calculate how much energy is transferred as useful energy in the following:
A plant that transforms 0.5% of the 200 J of light energy transferred from the Sun.
The formula that connects energy transferred, power, and time, as well as the formula that helps you calculate energy transferred, are as follows: Power multiplied by time equals transferred energy. For example, the energy-saving lamp's efficiency is 75 100 = 0.75. (or 75 per cent). This means that 75% of the electrical energy supplied is converted into light energy (25 per cent is transferred as heat energy).
What exactly is light energy?Light energy is a type of electromagnetic radiation that the human eye can perceive. Photons are the particles that make up light, and they are like tiny packets of energy. The Sun is the closest star to Earth and emits light energy.Light is defined as electromagnetic radiation visible to the human eye with wavelengths ranging from 380 to 750 nm.One type of radiant energy is light. Sunshine is radiant energy that provides the fuel and warmth that allow life to exist on Earth. Thermal energy, also known as heat, is the energy released by the movement of atoms and molecules in a substance. Heat builds up as these particles move faster.Light energy travels in the form of rays, which are emitted from the light source. Most light energy waves are invisible to the human eye and have different wave frequencies than visible light. Photons are the particles that carry light waves.To learn more about light energy refer to:
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a girl pushes a light snow shovel at a uniform velocity across a sidewalk. if the handle of the shovel in inclined 55 degress to the horizontal and she pushes the handle with a force of 100 N. what is the force of friction? what is the coefficeint of friction.
Answer:
0.565
Explanation:
The displacement
of a particle from a
reference point at any instant is given
by s = 31² 4t + 5, where s is in
metres and t is time in seconds.
Calculate the average velocity of the
particle in the time interval between 3
s and 5 s, and its instantaneous
velocity at 4 s.
The average velocity of the particle in the time interval between 3 s and 5 s is 28 m / s. The instantaneous velocity at 4 s is 28 m / s.
Average velocity = ( s2 - s1 ) / ( t2 - t1 )
s = 3t² + 4t + 5
At t = 3s,
s1 = 3 ( 3 )² + 4 ( 3 ) + 5
s1 = 27 + 12 + 5
s1 = 44 m
At t = 5 s,
s2 = 3 ( 5 )² + 4 ( 5 ) + 5
s2 = 75 + 20 + 5
s2 = 100 m
Average velocity = ( 100 - 44 ) / ( 5 - 3 )
Average velocity = 28 m / s
At t = 4 s, the instantaneous velocity,
v ( t ) = ds / dt
v ( t ) = d ( 3t² + 4t + 5 ) / dt
v ( t ) = 6t + 4
v ( 4 ) = 6 ( 4 ) + 4
v ( 4 ) = 28 m / s
Therefore,
The average velocity of the particle = 28 m / s. The instantaneous velocity = 28 m / s.To know more about Instantaneous velocity
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What is the total amount of heat needed to change 31g of silver at 0.0°C to 1°C? The specific heat of silver is 0.129 J/g∙°C
Explanation
o solve this , we need to use the formula:
[tex]\begin{gathered} Q=m*c*(T_f-T_0) \\ where \\ m\text{ is the mass measured in kg} \\ c\text{ is the specific heat of silver=0.129 J/\degree C} \\ T_f\text{ and T}_o\text{ are the final and initial temperatures} \end{gathered}[/tex]so
Step 1
) Let
[tex]mass=31\text{ gr}[/tex]so, we need to convert from grams to kilograms ,to do that, divide the amount in grams by 1000
so
[tex]mass_{kg}=\frac{31}{1000}=0.031\text{ kg}[/tex]and
[tex]\begin{gathered} T_f=\text{1\degree C} \\ T_0=0°\text{ C} \end{gathered}[/tex]b) now, replace in the formula
[tex]\begin{gathered} Q=mc(T_{f}-T_{0}) \\ Q=0.031gr*0.129\frac{J}{g°C}(1°C-0°C) \\ Q=0.003999\text{ Joules} \end{gathered}[/tex]so, the answer is 0.003999 Joules
hope this helps you
A 200 lb crate hangs at the end of a rope. Find its acceleration when the tension in the rope is 250lbs
Answer:
5. A 200 lbs crate hangs at the end of a rope. Find its acceleration when the tension in the rope is 250 lbs. (a, = 8 ft/s2) 6. An 1800 lbs car is drawn vertically up a mine shaft, accelerating at a rate of 20 ft/s?. Determine the tension in the cable that will produce this acceleration. (F= = 2925 lbs) 7. A steel cable carries a 3,000 lbs load which is descending with a speed of 12 ft/s. It slows down uniformly and comes to a halt in 9ft. Compute the tension in the cable during this motion. (F, = 3,750 lbs)
Explanation:
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Assuming motion is on a straight path, what would result in two positive components of a vector?
a train moving north of east at an angle of 25°
a bus moving north of east at an angle of 95°
a boat moving south of west at an angle of 40°
a car moving south of west at an angle of 10°
Answer:
Last one is a right answer.
Explanation:
a car moving south of west at an angle of 10 ⁰
In the particle model, the object in motion is represented by a series of single points.
Answer:
In the particle model, the object in motion is represented by a series of single points. A time interval is the difference between two locations. A vector has both location and direction. The zero point in a coordinate system is called the resultant.
An object has a velocity (4.04 m/s)i + (-4.96 m/s)j + (4.44 m/s)k. In a time of 3.84 s its velocity becomes (-3.75 m/s)i + (0.00 m/s)j + (4.44 m/s)k. If the mass of the object is 2.97 kg, what is the magnitude of the net force on the object, in N, during the 3.84 s? Assume the acceleration is constant.
The magnitude of the net force on the object is 7.15 N.
What is the resultant velocity of the object?The resultant velocity of the object is calculated as follows;
|v| = √[(x₂ - x₁)² + (y₂ - y₁)² + (z₂ - z₁)² ]
where;
x₂ is final velocity in x directionx₁ is initial velocity in x directiony₂ is final velocity in y directiony₁ is initial velocity in y directionz₂ is final velocity in z directionz₁ is initial velocity in z direction|v| = √[(-3.75 - 4.04)² + (0 - -4.96)² + (4.44 - 4.44)² ]
|v| = 9.24 m/s
The net force experienced by the object is calculated as follows;
F = ma
F = (mv)/t
F = (2.97 kg x 9.24 m/s) / (3.84 s)
F = 7.15 N
Thus, we can conclude that the object will experience a net force of 7.15 N.
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mary cassatt has manipulated light and color in in the loge to emphasize the
Mary Cassatt has manipulated light and color in in the loge to emphasize the Division between male and female species.
The soft, blinking lighting fixtures of fireflies aren't just lovely—they'll additionally play a function in growing new species. A brand new observe suggests that the use of mild-up powers for courtship makes species break up off from every other at a faster tempo, presenting some of the clearest proof yet that the conflict to find mates shapes the range of life.
Males are extra colourful or ornamented than women in most, however no longer all, chook species. know-how this phenomenon calls for a primary draw close of the evolutionary forces that shape the conduct and morphology of people and species. Charles Darwin evolved plenty of the idea that allows explain this.
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11. What is the final velocity of a boat that accelerates at 3 m/s² for twelve seconds if it started with a
velocity of 4 m/s?
20 m/s is the final velocity of a boat that accelerates at 3 m/s² for twelve seconds if it started with a velocity of 4 m/s.
What is velocity and example?The speed at which that moves in a direction is known as its velocity. as the velocity of a car driving north on a road or even the pace at which a rocket takes off. Because the velocity vector was scalar, its integrand magnitude will always equal the motion's velocity.
Briefing:Using the first equation of motion
V = U + at
where V = Final Velocity
U = Initial Velocity
a = Acceleration
t = Time
V = 4 + 3*12
V = 40 m/s.
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Give three examples of object in equilibrium in the classroom and draw an approximate scale diagram for the object
Three examples of object in equilibrium in a classroom are table at rest, book on a desk at rest and a chalk on a chalk holder at rest.
Equilibrium is the state in which all the individual forces acting on the object are balanced and so the net force will be zero. An object not necessarily be in a state of rest to be at equilibrium. If an object is moving with constant velocity it is in a state of equilibrium unless interfered with an outside force.
Examples of object in equilibrium in a classroom are:
Table at restBook on a desk at rest Chalk on a chalk holder at restTherefore, three examples of object in equilibrium in a classroom are table at rest, book on a desk at rest and a chalk on a chalk holder at rest.
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The vertical component of the acceleration of a projectile remains constant during the entire trajectory of the projectile is True or False
True because the vertical acceleration of a projectile is the acceleration due to gravity which is either 9.8 m/s/s or -9.8 m/s/s depending on perspective.
what is a major impact of global climate change?
Answer: Pollution and humans
a skateboarder starts moving 8 m/s and accelerate at 6 m/s2 to reach a speed 10 m/s at the bottom of rail how long is the rail
The length of the rail is 3 m.
What is the length of the rail?
The length of the rail is determined by calculating the distance travelled by the skateboarder.
v² = u² + 2as
where;
v is the final velocity of the skateboarderu is the initial velocity of the skateboardera is the acceleration of the skateboarders is the distance travelled10² = 8² + 2(6)s
100 = 64 + 12s
36 = 12s
s = 36/12
s = 3 m
Thus, the length of the rail is equal to the distance travelled by the skateboarder.
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