Tasha has mass 20 kg and wants to use a 4. 0-m board of mass 10 kg as a seesaw. Her friends are busy, so tasha seesaws by herself by putting the support at the system's center of gravity when she sits on one end of the board. How far is she from the support point?.

Explanation:

density = mass / volume

96.4 g of aluminum / volume = 2.7

therefore,

96.4 = 2.7 × volume

volume = 96.4 / 2.7 = 35.7037037... ml

back to iron :

7.87 = mass / 35.7037037...

mass = 7.87 × 35.7037037... = 280.9881481... g

it would be 280.9881481... g of iron in the same volume.

Considering the definition of enthalpy of vaporization, the amount of heat that would be involved in condensing 15.8 g of CH₃OH is 18.8 kJ.

When a material changes phase from solid to liquid, or from liquid to gas, a certain amount of energy is involved in this phase change.

In case of phase change from liquid to gas, this amount of energy is known as enthalpy of vaporization (symbolized as ∆Hvap).

So, the enthalpy of vaporization is the amount of energy required to change a unit of mass (for example, moles or kg) of a substance from phase liquid to phase gas at constant temperature and pressure.

In this case, you know that enthalpy of vaporization is ∆Hvap = 38.0 kJ/mol.

On the other side, you want to vaporize 15.8 g of CH₃OH.  Then, being the molar mass of the compound 32 [tex]\frac{g}{mole}[/tex] (that is, the amount of mass contained in one mole), the number of moles to be vaporized is:

[tex]15.8 gramsx\frac{1 mole}{32 grams} =0.49375 moles[/tex]

Then, the amount of heat that would be involved in condensing 15.8 g of CH₃OH is calculated taking into account the enthalpy of vaporization by:

0.49375 moles× 38.0 [tex]\frac{kJ}{mol}[/tex]= 18.76 kJ ≅ 18.8 kJ

Finally, the amount of heat that would be involved in condensing 15.8 g of CH₃OH is 18.8 kJ.

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We have

x = t³   ===>   dx/dt = 3t²

y = t⁴   ===>   dy/dt = 4t³

Then with the given parameteriztion, the line integral along C of x/y is

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^3}{t^4} \sqrt{(3t^2)^2 + (4t^3)^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac1t \sqrt{9t^4 + 16t^6} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{\sqrt{t^4}}t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 \frac{t^2}t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \int_1^4 t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 32t \sqrt{9 + 16t^2} \, dt[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \int_1^4 \sqrt{9 + 16t^2} \, d\left(9+16t^2\right)[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{32} \cdot \frac23 \left(9+16t^2\right)^{\frac32}\bigg|_1^4[/tex]

[tex]\displaystyle \int_C \frac xy \, ds = \frac1{48} \left(265^{\frac32} - 25^{\frac32}\right) = \boxed{\frac{265\sqrt{265}-125}{48}}[/tex]

The line integral will be "[tex]\frac{265\sqrt{265} - 125 }{48}[/tex]". To understand the calculation, check below.

According to the question,

Curves, x = t³ or,

            [tex]\frac{dx}{dt}[/tex] = 3t²

             y = t⁴ or,

            [tex]\frac{dx}{dt}[/tex] = 4t³  

Now, the line integral along C will be:

→ [tex]\int\limits_C {\frac{x}{y} } \, ds[/tex] = [tex]\int\limits^4_1 {\frac{t^3}{t^4} }[/tex] √(3t²)² + (4t³)² dt

             = [tex]\int\limits^4_1 {\frac{1}{t} }[/tex] √9t⁴ + 16t⁶ dt

             = [tex]\int\limits^4_1 {\frac{t^4}{t} }[/tex] √9 + 16t² dt

             = [tex]\int\limits^4_1 {\frac{t^2}{t} }[/tex] √9 + 16t² dt

             = [tex]\int\limits^4_1[/tex] t√9 + 16t² dt

             = [tex]\frac{1}{32}[/tex] [tex]\int\limits^4_1[/tex] √9 + 16t² d (9 + 16t²)

             = [tex]\frac{1}{32}\times \frac{2}{3}[/tex] [tex](9+16t^2)^{\frac{3}{2} } |_1^4[/tex]

             = [tex]\frac{1}{48}[/tex] ([tex]265^{\frac{3}{2}} - 25^{\frac{3}{2}[/tex])

             = [tex]\frac{265 \sqrt{265 } -125 }{48}[/tex]

Thus the above approach is correct.

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Do you ever wish your dreams could come true?

Dream of things that won't make you boo.

Dreams can come real,

just make sure you make them feel.

If it's a nightmare make sure you hide up the back stairs,

and if it's a good dream make sure you make it seen.

So I really wish dreams were real,

that way I could start to feel.

Explanation: Sorry it isn't that good I did the best I could. It's also rrrreeeealllllllyyyyy short sooo.......

Answer:

A is the correct answer

Explanation:

EDGE

A centroid in a triangle, is the point where all the medians meet.

now a peculiar thing about the centroid is that, it cuts all medians in a 2:1 ratio. So, if that's true, then the median AE, is being cut in two segments AD and DE and AD : DE are on a 2 : 1 ratio.

In a triangle, the centroid is the point of intersection of the three medians, which are line segments joining each vertex to the midpoint of the opposite side.

The centroid divides each median into two segments, with the distance from the centroid to the vertex being twice the distance from the centroid to the midpoint of the opposite side.

Let M be the midpoint of side AB, N be the midpoint of side AC, and P be the midpoint of side BC. Then, we have:

CD = 2DP

CE = 2DN

We are also given that DE = 15. Since D is the centroid, we have:

AD = BD = CD/3

AE = CE/3

DC + DP = PC

CE + DN = NE

AD + AE = DE

Using these relationships, we can find CD and CE:

CD = 2DP = 2(PC - DC) = 2((AD + DP) - (AD/3)) = 2(2AD/3) = 4AD/3

CE = 2DN = 2(NE - CE) = 2((AE + DN) - (AE/3)) = 2(2AE/3) = 4AE/3

To find AD and AE, we can use the fact that AD + AE = DE and AD = BD:

AD + BD = DE

AD + (2AD/3) = 15

5AD/3 = 15

AD = 9

AE = DE - AD = 15 - 9 = 6

Substituting these values into the equations for CD and CE, we get:

CD = 4AD/3 = 4(9)/3 = 12

CE = 4AE/3 = 4(6)/3 = 8

Therefore, CD = 12 and CE = 8.

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From the options given, the only option which would result on having a reduced error margin, is to increase the sample size.

Recall :

Margin of Error = Zcritical × σ/√n

Hence, only the sample size will cause a decrease in the margin of error of the interval.

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Answer:

By their names. If the names are not known you should mark them as speaker 1, speaker 2, speaker 3, etc.

Explanation:

Answer:

Yes every cell undergoes mitosis

Answer:

10385877.377477km

Explanation:

kasi po i plas lang po

Government often makes laws that aim for the betterment of its people. Cesar Chavez worked with government in the 1960s to get laws passed to help noncitizens and farm workers.

Cesar was known to be a man who use nonviolent means as used by Mahatma Gandhi and Martin Luther King Jr. in all his works.

He was known to be the founder of the National Farm Workers Association (later the United Farm Workers of America)

He won a lot of significant victories so as the pay and improve working conditions for farm workers is improve in the late 1960s and 1970s

See full question below

Which of the following people worked with government in the 1960s to get laws passed to help noncitizens and farm workers?

Huey Newton

Bobby Seale

Cesar Chavez

Dolores Huerta

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Answer:

Explanation:

Dolores huerta

Answer: old major is based on Karl Marx and partially Vladimir Lenin

Explanation:

The historical figure that old major most likely to represent is Vladimir Lenin. The correct option is C.

The pig Snowball represents the intellectual revolutionary Leon Trotsky, while Old Major represents either Karl Marx or Vladimir Lenin.

Old Major represents Karl Marx and Vladimir Lenin, who promoted the Communist Party but died before their vision could be realized.

As a result, those who did not fully comprehend the dream were able to twist it to their advantage.

Old Major describes a dream he had the night before in which animals are free, happy, well fed, and treated with dignity in a world free of human tyranny.

He exhorts the animals to do everything possible to make this dream a reality, including overthrowing the humans who claim to be their owners.

Thus, the correct option is C.

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Stokes' theorem says that the surface integral of the curl of the vector field F across the surface S is equal to the line integral of F along the boundary of S.

In this case, the boundary is a circle in the x,y-plane with radius 2. (To see this, set z = 0 and rearrange the equation for the paraboloid as x² + y² = 4.)

Then

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_{\partial S} \vec F \cdot d\vec r[/tex]

where

[tex]\vec r = 2\cos(t) \,\vec\imath + 2\sin(t) \,\vec\jmath[/tex]

parameterizes the circular boundary of S with 0 ≤ t ≤ 2π. Then

[tex]d\vec r = \dfrac{d\vec r}{dt}\,\dt = (-2\sin(t)\,\vec\imath + 2\cos(t)\,\vec\jmath)\,dt[/tex]

and the integral becomes

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_{\partial S} \vec F \cdot d\vec r[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} \vec F(\vec r(t)) \cdot \frac{d\vec r}{dt}\,dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s \\= \int_0^{2\pi} ((2\cos(t))^2 \sin(0)\,\vec\imath + (2\sin(t))^2\,\vec\jmath + (2\cos(t))(2\sin(t))\,\vec k) \cdot(-2\sin(t)\,\vec\imath + 2\cos(t)\,\vec\jmath)\,dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} 8\sin^2(t)\cos(t) \, dt[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \int_0^{2\pi} 8\sin^2(t) \, d(\sin(t))[/tex]

[tex]\displaystyle \iint_S (\nabla\times\vec F)\cdot d\vec s = \frac83 (\sin^3(2\pi)-\sin^3(0)) = \boxed{0}[/tex]

It looks like the integral is

[tex]\displaystyle \int_C xy \, dx + x^2y^3 \, dy[/tex]

Let's close the loop by adding a line integral over the line segment joining (1, 4) to (0, 0). Then the closed loop is the triangular region

T = {(x, y) : 0 ≤ x ≤ 1 and 0 ≤ y ≤ 4x}

Since the integrand has no singularities over or on the boundary of T, we have by Green's theorem

[tex]\displaystyle \int_C xy \, dx + x^2y^3 \, dy = \iint_T \left(\frac{\partial(x^2y^3)}{\partial x} - \frac{\partial(xy)}{\partial y}\right) \, dx \, dy = \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx[/tex]

Compute the double integral:

[tex]\displaystyle \int_0^1 \int_0^{4x} (2xy^3 - x) \, dy \, dx = \int_0^1 \int_0^{4x} \left(128x^5 - 4x^2\right) \, dx = \frac{60}3[/tex]

From this result, we subtract the line integral over the extra line segment we added. Parameterize this path by

C' : {(1 - t, 4 - 4t) : 0 ≤ t ≤ 1}

The line integral over C' is

[tex]\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 (1-t)(4-4t)(-dt) + (1-t)^2(4-4t)^3(-4\,dt)[/tex]

[tex]\displaystyle \int_{C'} xy \, dx + x^2y^3 \, dy = \int_0^1 \left(256 t^5-1280 t^4+2560 t^3-2564 t^2+1288 t-260 \right) \, dt = -44[/tex]

so that the line integral over C alone is 60/3 - (-44) = 64.

Answer:

does not,

does not,

and has not

Explanation:

Dark matter doesn't absorb light, doesn't emit radiation and has not been observed directly.

Dark matter can be defined as often invisible substances that are difficult to spot and observed because they don't absorb, emit or reflect light.

This ultimately implies that, dark matter doesn't affect human view because they do not interact or interfere with electromagnetic radiation.

However, humans can see through the (weakly interacting) dark matter but it has not been observed directly by scientists and astronmers.

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Answer:

12

Explanation:

speed=distance÷time

The answer to your question is:

Taking into account the Doppler efect, the speed of the bat is closest to 5.02 [tex]\frac{m}{s}[/tex].

The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.

The following expression is considered the general case of the Doppler effect:

[tex]f1=f\frac{v+-vR}{v+-vE}[/tex]

Where:

In the numerator if the receiver approaches the sender

In the denominator if the sender moves away from the receiver

In the numerator if the receiver moves away from the emitter

In the denominator if the sender approaches the receiver

In this case, a bat emits a sound at a frequency of 3.00×10⁴ Hz= 30,000 Hz as it approaches a wall.

The bat detects beats such that the frequency of the echo is 900 hz higher than the frequency the bat is emitting.

So, you know:

Replacing in the expression is considered the general case of the Doppler effect:

[tex]30900 Hz=30000 Hz\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}[/tex]

Solving:

[tex]\frac{30900 Hz}{30000 Hz} =\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}[/tex]

[tex]1.03=\frac{340 \frac{m}{s} +vbat}{340\frac{m}{s} -vbat}[/tex]

1.03×( 340[tex]\frac{m}{s}[/tex] -vbat)= 340 [tex]\frac{m}{s}[/tex] + vbat

1.03×340[tex]\frac{m}{s}[/tex] - 1.03×vbat= 340 [tex]\frac{m}{s}[/tex] + vbat

350.2[tex]\frac{m}{s}[/tex] - 1.03×vbat= 340 [tex]\frac{m}{s}[/tex] + vbat

350.2[tex]\frac{m}{s}[/tex] - 340 [tex]\frac{m}{s}[/tex]= vbat + 1.03×vbat

10.2 [tex]\frac{m}{s}[/tex]= 2.03×vbat

10.2 [tex]\frac{m}{s}[/tex]÷ 2.03 = vbat

5.02 [tex]\frac{m}{s}[/tex]= vbat

In summary, the speed of the bat is closest to 5.02 [tex]\frac{m}{s}[/tex].

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Answer:

It lets people practice their faith in their own way and

It prevents the government from establishing a national religion.

Explanation:

WWW is an abbreviation for World Wide Web ...

Corporation, Customer, Competitors (3C's) Model is a business model that focuses on the three key factors needed for success. This model was conceived by the famous business strategist, Kenichi Ohmae.

Answer:

Explanation:

The expression that represents the difference of squares for this situation is [tex]x^2-c^2[/tex]

Given the generic x by x grid has c blocks moved to create an (x-c) by (x+c) grid, to get the difference of two squares, we will take the product of the expressions as shown:

[tex]=(x-c)(x+c)\\=x^2+xc-xc-c^2\\=x^2 -0-c^2\\=x^2-c^2[/tex]

Hence the expression that represents the difference of squares for this situation is [tex]x^2-c^2[/tex]

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Considering the whole question, the perimeter of the porch is 30 feet.

This is because the whole question is, "Bill's new porch is rectangular, with an area of 50 square feet. if the length of the porch is two times the width, what is the perimeter of the porch?"

Therefore to find the perimeter of the porch, here is the step by step:

Given that the length of the porch is two times the width.

Hence, assume that the width = X

Also, assume that the length = 2X

The general formula here:

50 = X × 2X

X × 2X50 = 2x²

2x²X² = 50 ÷2

50 ÷2X² = 25

25X = √25

√25X = 5

Hence, width = 5 feet.

Given that length of the porch is two times the width = 5 × 2 => 10 feet

Therefore Perimeter of a rectangle = 2 (Length + Breadth)

Put all the values in the formula

Perimeter of the porch = 2 × (5 + 10)

= 2 × (15)

= 30 feet.

Hence, in this case, it is concluded that the correct answer is 30 feet.

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Based on the given value of sample size and the population standard deviation, the required test for the null hypothesis is the Z test of population mean.

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Answer:

The three consecutive integers are 12, 13 & 14

Explanation:

Let the three consecutive integers be x, x + 1, x + 2

According to the question,

If sum of the first and third integers is increased by 8, the result is 5 less than triple the second integer.

[tex] \therefore [/tex] x + x + 2 + 8 = (x + 1) × 3 - 5

2x + 10 = 3x + 3 - 5

2x + 10 = 3x - 2

10 + 2 = 3x - 2x

x = 12

So, The three consecutive integers are 12, 13 & 14

Answer:

the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

Explanation:

Entropy is defined as the measure of possible arrangement of the atoms or molecules. Entropy change for the the freezing process mole of 1 liquid methanol at -97.6 degree celcius and 1 atm will be -18.07 J/mol.

The entropy change can be calculated by the given formula:

Thus, the value of change in entropy for freezing process of 1 mole of liquid methanol is -18.07 J/mol.k

(Hope this helps can I pls have brainlist (crown)☺️)

For the freezing of 1 mole of liquid methanol, the change in entropy value is -18.07 J/mol.

The measure of atoms' or molecules' potential arrangements is known as entropy. Entropy change for one mole of liquid methanol frozen at -97.6 degrees Celsius and one atmosphere is -18.07 J/mol.

The range of entropy is 0 to 1. Depending on the number of classes in your dataset, entropy can be greater than 1, but it still indicates a very high level of chaos. For the sake of convenience, the examples in this blog will have entropy values between 0 and 1.

The "information" a variable contains is measured by its entropy. Now, based on the surprise that this value of the bholds and the number of distinct values that are present in the variable, this amount is approximated.

Thus, it is -18.07 J/mol.

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...

Thats really nice

Considering the situation described in the question, the type of sample Inspector used is called Simple Random Sampling

Simple Random Sampling is a random sampling technique in which participants are taken randomly from a given population.

Here, the given population is the hospital chain with multiple locations; since the inspector only randomly selects some of their locations, this is a simple random sampling.

Hence, in this case, it is concluded that the correct answer is Simple Random Sampling

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The area of the rectangle formed by the intersection of the plane and cube is [tex]4\sqrt{2}cm^2[/tex]

The diagram of the cube and the cutting plane is shown in the figure.

Since the cube has a volume of [tex]8cm^3[/tex], the sides are [tex]2cm[/tex] each.

From the diagram, the red rectangle is the rectangle formed from the intersection of the plane and the cube. It has an area given by

[tex]A_R=\text{side of cube}\times \text{diagonal}=2d[/tex]

and, using Pythagoras' theorem,

[tex]d=\sqrt{2^2+2^2}\\d=\sqrt{8}=2\sqrt{2}\text{ cm}[/tex]

Substituting the value of [tex]d[/tex] into the formula for [tex]A_R[/tex]

[tex]A_R=2\times d\\=2\times 2\sqrt{2}\\=4\sqrt{2}[/tex]

The area of the rectangle formed by the intersection of the plane and cube is [tex]4\sqrt{2}cm^2[/tex]

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Answer:

4 square root of 2cm

Explanation:

cool stuff

Answer:

Fossils helped teach scientist by giving information of the species that lived back then.

Explanation:

The fossils have clues on them help identify what they are.

The character trait that defines the boy in Casabianca is: his loyalty.

Casabianca is the name of the young boy who is one of the major character sin "Casabianca".

In Casabianca, the boy, out of loyalty and having a strong sense of duty, had to put up bravery to remain at his post on a French ship that caught fire during the attack of the British.

In spite of the obvious dangers, he remained at his post while waiting for orders from the captain (his dad).

Therefore, the character trait that defines the boy in Casabianca is: his loyalty.

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