Answer:
MEDIA: 4.8
MEDIANA: 5
MODA: 5
espero que te ayude :)
Helpp please… due at 12:00
Answer:alternate exterior angles
Step-by-step explanation:
Since they’re on the outside of the parallel lines that makes them exterior
please help me please
9514 1404 393
Answer:
payment: $960.82; interest: $203,918balance: $317,306.36; interest: $227,306.36Step-by-step explanation:
The sum of payments made n times per year for t years and earning annual interest rate r is the value of a single payment multiplied by k, where ...
k = ((1 +r/n)^(nt) -1)/(r/n)
__
Problem 1
The multiplier k is ...
k = ((1 +0.08/4)^(4·25) -1)/(0.08/4) ≈ 312.232306
Then the quarterly deposit needs to be ...
$300,000/312.232306 ≈ $960.82
The sum of the 100 quarterly payments is ...
100 × $960.82 = $96,082
So, the amount of interest earned is ...
$300,000 -96,082 = $203,918
Quarterly payments are $960.82Interest earned is $203,918__
Problem 2
The multiplier k is ...
k = ((1 +0.072/12)^(12·30) -1)/(0.072/12) ≈ 1269.22544
Then the balance resulting from monthly deposits of $250 will be ...
$250 × 1269.22544 = $317,306.36
The total of the 360 payments is $90,000, so the interest earned is ...
$317,306.36 -90,000 = $227,306.36
Account in 30 years is $317,306.36Interest earned is $227,306.36_____
Additional comment
In the case of Problem 1, the deposit amount is rounded down to the nearest cent. This means that the account balance at the end of 25 years will be slightly less than $300,000. The difference is on the order of $0.96. This means both the account balance and the actual interest earned are $0.96 less than the amounts shown above.
In many of these school calculations, we ignore the effect of rounding the payment values. Similarly, we ignore the effect of rounding the account balance values for each monthly or quarterly statement. In real life, the final payment of a series is often adjusted to make up the difference caused by this rounding.
Also worthy of note is that the calculations here assume the payments are made at the end of the period, not the beginning. That makes a difference.
Use the substitution method or the elimination method to solve the following system.
2x−20y
=
10
−7x+70y
=
−35
9514 1404 393
Answer:
x -10y = 5 . . . . . infinite number of solutions
Step-by-step explanation:
We can put each equation into standard form by dividing it by its x-coefficient.
x -10y = 5 . . . . first equation
x -10y = 5 . . . . second equation
Subtracting the second equation from the first eliminates the x-variable to give ...
(x -10y) -(x -10y) = (5) -(5)
0 = 0 . . . . . . . true for all values of x or y
The system has an infinite number of solutions. Each is a solution to ...
x -10y = 5.
A line passes through the point (4, -3) and has a slope of -3. Write an equation in slope-intercept form for this line.
y=-3x+9
explanation
m=-3 (X1,Y1) = (4,-3)
(y-y1)= m×(x-x1)
(y-(-3))=-3(x-4)
y+3= -3x+12
y=-3x+12-3
y=-3x+9
Question attached please answer brainliest to best answer
Answer:
B
Step-by-step explanation:
Have a nice day :)
can someone please please answer this
Answer:
720 degrees
Step-by-step explanation:
sum of interior angles of any polygon is given by the equation
[tex]sum \: = (n - 2) \times 180[/tex]
where n is the number of sides of the polygon. in the question the polygon has 6 sides. hence n = 6 and
[tex]sum \: = (6 - 2) \times 180 \\ = 4 \times 180 \\ = 720 \: degrees[/tex]
What is the value of log √10?
Answer:
0.5
Step-by-step explanation:
Answer:
.5
Step-by-step explanation:
calculator
what Will You nota miss about remote learning
Answer:
using brainly
Step-by-step explanation:
Answer:
waking up everyday and listening to them fuss about calling home even though im already home
here is the picture!
someone please answer ASAP!!
i need to know if my math is right
Answer:
good luck
Step-by-step explanation:
you will get answers after some time
Answer:
base 48
width 8 and length 6
pls brainliest. should work and you get points back
12.) The FAA has to periodically revise their rules regarding weight estimates that vary by
season. Airlines currently use an estimate for the weight of an adult male passenger of 190 lbs.
in the summer that assumes
he carries sixteen pounds of baggage and has five pounds of
clothing. According to your textbook, assume that men (not clothed nor carrying baggage) have
weights that are normally distributed with a mean of 188.6 lbs. and a standard deviation of 38.9
lbs.
a.) If one adult male is randomly selected and is assumed to be also carrying 21 lbs. due to
clothing and baggage, find the probability that the total weight is greater than 190 lbs.
b.) What total weight would separate the lower 20% of men carrying 21 lbs. of clothing and
baggage from the top 80%?
Answer:
a) 0.4856 = 48.56% probability that the total weight is greater than 190 lbs.
b) A total weight of 155.9 lbs.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Mean of 188.6 lbs. and a standard deviation of 38.9 lbs.
This means that [tex]\mu = 188.6, \sigma = 38.9[/etx]
21 lbs of baggage are taken into consideration in this estimate.
a.) If one adult male is randomly selected and is assumed to be also carrying 21 lbs. due to clothing and baggage, find the probability that the total weight is greater than 190 lbs.
This is 1 subtracted by the the p-value of Z = 190. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{190 - 188.6}{38.9}[/tex]
[tex]Z = 0.036[/tex]
[tex]Z = 0.036[/tex] has a p-value of 0.5144.
1 - 0.5144 = 0.4856.
0.4856 = 48.56% probability that the total weight is greater than 190 lbs.
b.) What total weight would separate the lower 20% of men carrying 21 lbs. of clothing and baggage from the top 80%?
This is the 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-0.84 = \frac{X - 188.6}{38.9}[/tex]
[tex]X - 188.6 = -0.84*38.9[/tex]
[tex]X = 155.9[/tex]
A total weight of 155.9 lbs.
Calculate 18t -t +6q-6
Answer:
17t+6q-6
Step-by-step explanation:
18t -t +6q-6
Combine like terms
17t+6q-6
Answer:
17t+6q-6
Step-by-step explanation:
18t-t =17t
others don't change as they are not the factors of the same character
A past study claims that adults in America spend an average of 17 hours a week on leisure activities. A researcher wanted to test this claim. She took a sample of 10 adults and asked them about the time they spent per week on leisure activities. Their responses (in hours) are as follows:13242137152518224032Assume that the times spent on leisure activities by all adults are normally distributed. At the 5% significance level, can you conclude that the claim of this earlier study is true
Answer:
The claim is false.
Step-by-step explanation:
Given the data :
13 24 21 37 15 25 18 22 40 32
The sample mean and standard deviation can ben calculated for the given sample.
Using calculator :
Sample mean, xbar = 24.7
Sample standard deviation, s = 9.04
Sample size, n = 10
The hypothesis :
H0 : μ = 17
H1 : μ ≠ 17
The test statistic :
(xbar - μ) ÷ (s/√(n))
(24.7 - 17) ÷ (9.04/√(10))
7.7 / 2.8586990
Test statistic = 2.694
We can obtain the Pvalue, at α = 0.05 ; df = n-1 = 9
Pvalue = 0.0246
Since Pvalue < α ; we reject the null ; Hence, there is significant evidence to conclude that an adult American does not spend average of 17 hours in leisure
Jeffery has two pets that he feeds daily. His dog eats 3/4 cup of food. His cat, on the other hand, eats 1/2 of what his dog eats. How much food does his cat eat?
Answer:
3/8 cup
Step-by-step explanation:
Dog : 3/4 cup
Cat: 1/2 (Dog) = 1/2 (3/4 cup) = 3/8 cup
Hope this helps!!!
Have a great day!!!
What is the probability that a randomly selected
purchase has less than two tickets?
Answer:
The answers for your question is 0.17
Which of the following triangles have three sides of different length?
A. acute
B. scalene
C.equilateral
D. right
Answer:
C
Step-by-step explanation:
correct me if iam wrong
the answer of
82.4 - 25
Answer:
57.4
Step-by-step explanation:
82.4 - 25 is too easy, a calculator can solve this.
What is the least common multiple (LQM) of 8 and 12?
Answer:
24
Step-by-step explanation:
The LCM of 8 and 12 is 24. Find least common multiple (LCM) of: 16 & 24 4 & 6 24 & 36 40 & 60 56 & 84 16 & 12 8 & 24 24 & 12 8 & 36 40 & 12 8 & 60 56 & 12 8 & 84
Someone please help with this ASAP!!! I will give brainliest
Answer:
12m
7m
2520 m³
Step-by-step explanation:
Answer:
h=7m
top width=12m
v=l*w*h
=28*12*10=3360
volume of the top=3*20*12
720
v of the shape is= 3360-720
=2649
Solve y = x + 6 for x.
Ox = y + 6
Ox= -y + 6
O x = y - 6
Ox= -y-6
Answer:
x = y - 6
Step-by-step explanation:
y = x + 6 (Given)
y - 6 = x (Subtracted 6 on both sides)
Adam is 9 years old and Billy is 11 years old. What will be the ratio of Adams’ age to Billy’s age in exactly one year’s time? Give your answer in its simplest form. *
Answer:
10 / 12
simplified:
5/6
since 5 is a prime number, we can't simplify this ratio any further
$6300 is invested, part of it at 11% and part of it at 6%. For a certain year, the total yield is $533.00. How much was invested at each rate?
$___ was invested at 11%
Answer:
Invested at 11% : 3100
Invested at 6% : 3200
Step-by-step explanation:
let x= amount invested at 11%
let y= amount invested at 6%
we can write
Equation 1: x+y=6300
Equation2: .11x+.06y=533
Divide equation 2 by .06 to get
1.8333333x+y=8883.33333333
Subtract equation 2 from equation 1
.8333333x= 2583.33333333
x= 3100
Plug in x= 3100 into equation 1
3100+y= 6300
y= 3200
HELPPP!!! PLEASEEEEEEE
Answer:
Step-by-step explanation:
37
15. Mr Muthu bought some apples and oranges. The price of the fruits were as shown below. Fruit Price Apples 60¢ each Oranges 80€ aach The ratio of the number of apples bought to the number of oranges bought was 3:4. He spent $75 on the apples and oranges. How many apples did he buy?
Answer:
40
Step-by-step explanation:
you mutiply then take away the 2 last digits
Answer:
Step-by-step explanation:
0.6*3t+0.8*4t=75
so t=15
apple=3t=45
orange=4t=60
can anybody help me please?! I'll give brainlest for correct answer
Yes I can help you. what do you want the help for?
Answer:
AOB = 65 degree angle
DOE = 35 degree angle
AOC = 90 degree angle
EOB = 115 degree angle
DOB = 80 degree angle
Step-by-step explanation:
Use the protractor to measure. Each dash around the edge is equal to 5 degrees.
Maya read 40 pages in 60 minutes
help me pleaseeeeeeeeeeeeeeeeeee
Answer:
answer a and d
Step-by-step explanation:
one thing i could say it would not be C because if it were symetric, i already see 2 lines that are not symetrical in anyway
sure the graph could extend to infinity and negative infinity and if you see the right arrow, it is pointing down-wards, so if it goes bellow 0, point (0,0) would not be your expected number to see as the minimum
and between -1 and 1, yes, we can already see that the line from -1 and 1 is exponentially increasing
i need help plz
i will mark you brainlest
Answer:
[tex] \frac{7}{4} - \frac{3}{4} = \frac{4}{4} [/tex]
Step-by-step explanation:
To find the number midway between 3/2 and 4/2, add them up and divide by 2
we have, 3/2 + 4/2 = 7/2
7/2 ÷ 2 = 7/4
Repeat the same for the number midway between 1/2 and 2/2 to get 3/4
The answer then is, 7/4 - 3/4 = 4/4
12. The heights of 53 students at Park School are shown in the histogram below.
Height of Students
18
Number of Students
NA ON
44 46 48 50 52 54 56 58 60
Height (inches)
Based on the data in the histogram, which statement is true?
A There are 12 students between 46 and 50 inches in height.
B. Exactly 18% of the students are between 52 and 54 inches in height.
C. More students are between 54 and 60 inches than between 46 and 50 inches in height.
Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.
D
Answer:
Fewer students are between 44 and 52 inches than between 52 and 60 inches in height.
Step-by-step explanation:
Given
See attachment for histogram
Required
Select the true statement
Option A: Class 46-50 = 12 students
From the histogram, we have:'
[tex]Class\ 46 - 48 = 8; Class\ 48 - 50 = 3[/tex]
So:
[tex]Class\ 46 - 48 = Class\ 46 - 48 + Class\ 48 - 50[/tex]
[tex]Class\ 46 - 48 = 8+ 3[/tex]
[tex]Class\ 46 - 48 = 11[/tex]
(a) is false
Option B: %Class 52-54 = 18%
From the histogram, we have:'
[tex]Class\ 52-54 = 18[/tex]
and
[tex]Total = 53[/tex]
So, the percentage is:
[tex]\% Class\ 52-54 = \frac{Class\ 52-54}{Total}[/tex]
[tex]\% Class\ 52-54 = \frac{18}{53}[/tex]
[tex]\% Class\ 52-54 = 0.3396[/tex]
Express as percentage:
[tex]\% Class\ 52-54 = 33.96\%[/tex]
(b) is false
Option C: Class 54-60 > Class 46 - 50 students
From the histogram, we have:'
[tex]Class\ 54-60 =Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]
[tex]Class\ 54-60 = 4 + 4+3[/tex]
[tex]Class\ 54-60 = 11[/tex]
In (a), we have:
[tex]Class\ 46 - 48 = 11[/tex]
By comparison:
[tex]Class\ 54-60 =Class\ 46 - 48 = 11[/tex]
(c) is false
Option D: Class 44-52 < Class 52 - 60 students
From the histogram, we have:'
[tex]Class\ 44-52 =Class\ 44-56 + Class\ 46-48 + Class\ 48-50 +Class\ 50-52[/tex]
[tex]Class\ 44-52 = 4+8+3+9[/tex]
[tex]Class\ 44-52 = 24[/tex]
[tex]Class\ 52-60 =Class\ 52 - 54 + Class\ 54-56 + Class\ 56-58 + Class\ 58-60[/tex]
[tex]Class\ 52-60 = 18+ 4 + 4+3[/tex]
[tex]Class\ 52-60 = 29[/tex]
By comparison:
[tex]24 < 29[/tex]
i.e.
[tex]Class\ 44 - 55 < Class\ 52 - 60[/tex]
(d) is true
Sam puts $10,000 in an account earning 4% interest, compounded monthly. If he adds 5100 to the account each month, how much
will the account be worth in 10 years?
A. $26,489.23
B. $29,633.31
C. $32,722.56
D. $34,693.81
The pair of linear equations 2x-3y = 14 and 3x - 2y = 4 has solution(s).
answer plz....
Answer:
2x -3y =1 and 3x-2y= 4 has
Step-by-step explanation:
The pair of linear equations 2x-3y=1 and 3x-2y=4 has one unique solution. , then it has a unique solution other wise not. Since , , it means the pair of linear equations has only one unique solution. Hence, the pair of linear equations 2x-3y=1 and 3x-2y=4 has only one unique solution.
a1/a2= 2/3
b1/b2= 3/-2 (-) cancle so it remains
c1 / c2 = 1/4
a1/a2 = b1/b2 not equal to c1/c2 as no solution